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Bubbler
Bubbler
01:16
@Adám APLcart has a typo on the top: C, D: chara_ra_cter array
 
4 hours later…
Bubbler
Bubbler
05:00
Any idea to improve this?
 
5 hours later…
Sherlock9
Sherlock9
10:12
@Bubbler Why is there an issue with length-1 arrays?
Sherlock9
Sherlock9
10:25
⋄⎕←(⍴-0(⊥⍨=)⊢⌹∘⍉∘↑1+⍴⍴¨(⊢,1+⌽)∘⍳¨∘⍳∘⍴)1⋄⎕←(⍴-0(⊥⍨=)⊢⌹∘⍉∘↑1+⍴⍴¨(⊢,1+⌽)∘⍳¨∘⍳∘⍴)1 1
Dyalog APL
Dyalog APL 
@Sherlock9
DOMAIN ERROR
Sherlock9
Sherlock9
Ack should have split them up 
⎕←(⍴-0(⊥⍨=)⊢⌹∘⍉∘↑1+⍴⍴¨(⊢,1+⌽)∘⍳¨∘⍳∘⍴)1
Dyalog APL
Dyalog APL 
@Sherlock9
DOMAIN ERROR
Bubbler
Bubbler
Using ≢ in place of every monadic ⍴ will fix that
Sherlock9
Sherlock9
Ahh right
Bubbler
Bubbler
10:27
⎕←(≢-0(⊥⍨=)⊢⌹∘⍉∘↑1+≢⍴¨(⊢,1+⌽)∘⍳¨∘⍳∘≢)1
Dyalog APL
Dyalog APL 
@Bubbler
1
Sherlock9
Sherlock9
Ah and I see that the other way you've gotten around that in the test cases is by using 1⍴1. Pardon me, I should have read the test cases more carefully
 
2 hours later…
Bubbler
Bubbler
12:44
No problem, your question made me recall the "tally" function :)
dzaima
dzaima
12:55
dfnifier yay
it probably doesn't work on (m)any other cases, might get in an infinite loop and is pretty damn slow, but i'm happy
Ven
Ven
The opposite of pointle^W pointfree.io?
dzaima
dzaima
@Ven well i do have a trainifier too, but it's way more simple
 
3 hours later…
rcabaco
rcabaco
16:04
is there a way to see a train tree in the interpreter like we can see here?
dzaima
dzaima
@rcabaco ]box on -trains=tree
rcabaco
rcabaco
thank you!
(~'='⍷¨⊢)args
this works as i expect, for each of the arguments it gives me a boolean vector where the data is not '='
now i want to partition each argument with this result
(⊢⊆⍨~'='⍷¨⊢)args
this was obviously my first approach, which does not work
⎕←(⊢⊆⍨~'='⍷¨⊢)
Dyalog APL
Dyalog APL 
@rcabaco
┌─┴─┐
⊢ ┌─┼─────┐
  ⍨ ~ ┌───┼─┐
┌─┘   '=' ¨ ⊢
⊆       ┌─┘
        ⍷
H.PWiz
H.PWiz
(⊢⊆⍨(~'='⍷¨⊢)) should work
rcabaco
rcabaco
i still get a domain error
but looking at the tree i cannot spot the problem
H.PWiz
H.PWiz
16:15
Well, I'm not sure what '='⍷¨⊢ is supposed to do. What sort of argument do you have? Maybe you want (⊢⊆⍨(~'='⍷⊢))¨
rcabaco
rcabaco
i am missing an each for the partition enclosed
or i can try that
you are right, one each is enough
thank you
H.PWiz
H.PWiz
It might make more sense to remove the ⍨ like ((~'='⍷⊢)⊆⊢)¨
rcabaco
rcabaco
(⊢⊆⍨∘~'='⍷⊢)¨ also works
H.PWiz
H.PWiz
yep :)
ngn
ngn
16:56
@Bubbler ≢{⊃⌽⍋0≠⍵⌹⍉1+↑(⍺⍴⍳,⊢-⍳)¨⍳⍺}⊢ with ⎕io←0
 
1 hour later…
rcabaco
rcabaco
18:24
how can i break a vector in groups of two?
reshape!!!
i have been on this for an hour and didn't think of reshape
 
2 hours later…
voidhawk
voidhawk
20:40
⎕←(⊢⊂⍨2|⍳∘≢)⍳10
voidhawk
voidhawk
20:51
⍨
dzaima
dzaima
21:02
@voidhawk the bot doesn't understand backticks, you must prepend 4 spaces to monospacify for it to work

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