When I am using the Alexa Developer console display tool screen animation work perfectly. When I try and use the Echo Show, all the images are projected really quickly then the animation starts.... What am I doing wrong.
I have already tried changing the opacity and tried switching to pager. Pag...
since ← is already heavily special-cased in my impl it should just be a couple boolean changes to make it go rtl if everything else gets changed to ltr (+ argument swapping, - modified assignment), but as that'd be horrible inline, → could be a regular-order version. i'll play around with this at home
@dzaima True, but 1) is that really an issue? 2) that's no worse than TI-BASIC 3) that's an IDE/presentation problem 4) no worse than end-of-line comments' (mis)alignment 5) spaces/tabs can fix
@Adám 1) depends; 2) and C has operator precedence, but that doesn't mean APL should; 3 & 5) sure, but it'd still result in it being way harder to decipher whether a line is assignment or not if reading LTR; 4) i don't necessarily like that either; now lines without comments would be forced to be padded to be quickly understandable, further increasing the artificial need to make lines be of approximately the same length as to not allow getting lost in the alignment
I am working on a compiler pass and want to remove redundant movq For example, this sequence:
(movq a b)
(movq b c)
(movq c d)
(movq d e)
should become (movq a e).
My (current, working) approach fuses the current and next movq instructions if the destination of the current matches the source ...
Hey @Adám, I'm trying to get the .dws file for Mastering Dyalog APL working and macOS RIDE says there's a TRANSLATION ERROR. Would you happen to know what the problem is?
Dyalog 17.1.36845 64-bit Unicode, BuildID 6b18dda9
OS Darwin 18.7.0 Darwin Kernel Version 18.7.0: Tue Aug 20 16:57:14 PDT 20
SALT 2.805
UCMD 2.4
.NET (unavailable)
WS 17.1
19; root:xnu-4903.271.2~2/RELEASE_X86_64 x86_64
I am working on a compiler pass and want to remove redundant movq For example, this sequence:
(movq a b)
(movq b c)
(movq c d)
(movq d e)
should become (movq a e).
My (current, working) approach fuses the current and next movq instructions if the destination of the current matches the source ...
