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12:20 AM
@Thorgott yo
 
sup
 
you can unambiguously defined an abstract smooth manifold as a smooth submanifold $X \subset \Bbb R^n$ with the diffeology being the sheaf $i_X^* C^\infty_{\Bbb R^n}$
upto isomorphism of sheaved spaces
 
wtf is diffeology
is that like a differential space
 
i just made that up
 
ok, so what you're saying is that a manifold is up to diffeomorphism determined by its sheaf of smooth functions
 
12:30 AM
which you can define apriori as restriction sheaf
no need to do charts
 
@BalarkaSen en.wikipedia.org/wiki/Diffeology you also wrote a wiki article to make it more convincing
 
lmao
its an actual thing nice
 
xposed
 
LMAO a diffeology is a differential space but backwards
 
but a manifolds already determined just by the ring of smooth functions on it, right
 
12:32 AM
@Thorgott the sister site of xhamst...
 
$[\Bbb R^n, X]$ not $[X, \Bbb R]$
@Thorgott thats for ad hoc reasons
 
heh
its for partition of unity reasons, isnt it
 
prolly right
 
12:45 AM
To anger both the algebraists and topologists here
A physics professor's notation, not mine
 
Insane
 
im shook
 
$$S_2 = \{\mathbf{u} \in \Bbb R^3 ; \mathbf{u} \overline{\mathbf{u}} = 1\}$$
 
@Thorgott stunning and brave
 
$S_1, S_2, S_3, S_4, S_5, S_6, S_7, S^8, S^9, \cdots$
 
12:52 AM
${}^2S$
 
$T_2$ Ad(Rees) $C^u$
 
@BalarkaSen still can't get over this one's beauty
you should change the $\mathbf{u}$ to $\vec{\mathbf{u}}$
 
You're right
$$S_2 = \{\vec{\mathbf{U}} \in \Bbb R^3 ; \vec{\mathbf{U}} \overline{\vec{\mathbf{U}}} = 1\}$$
2
 
perfect
 
you are allowed to star this now
 
1:02 AM
that was the plan all along
 
god's plan, not mine
the lord sayeth mysterious things
 
lmao gotta resist the urge to make a giant floating physicists $S^2$
the evil twin of the almighty torus
 
lool
$\underset{\sim}{X} \underset{\sim}{X}^\dagger = 1$
probabilist's sphere
like the topologist's sine curve
 
whut
what's with the tildes and the cross
is that just stupid notation
 
in my experience probabilists write X undertilde all the time
 
1:13 AM
who uses a cross for a transpose that's just trying to use cool symbols
 
they also like dagger for dual
on the board
not necessarily on papers
 
never saw anyone do that. thankfully
probabilists use awful notation at times
 
undertilde should be illegal
 
1:29 AM
what's the "geodesic opposite" of a geodesic
 
cisedoeg
 
2:01 AM
@EdwardEvans I see you ensure the presence of quality contributions in my absence
 
Truth
 
*truf
 
Just ate sweet popcorn drizzled with honey out of a pan with a spoon
depression is
 
was the pan coated?
(not with the honey, I mean teflon)
 
2:03 AM
thank god
 
it's an old pan with a layer of burnt junk across the bottom
 
lol oof
 
Guys I'ma quit my master
 
F indeed
 
2:04 AM
whats the exit plan
 
this deserves a big one
$\mathcal{F}$
 
Applying to jobs in software development
 
I'll now light a doobie in your honor
 
@Thorgott you mean $\mathfrak{F}$
 
@EdwardEvans sounds good to me
 
2:04 AM
p-adic Hodge theory finished me off
it's super effective
exit plan was getting a big fat "he too psycho" letter from my psychiatrist
 
I mean, you could also try not doing number theory, since that is godforsakenly hard I think
 
so I don't get a fail, I can just.. take an indefinite sabbatical
 
Ah yeah that's totally fair. Also, not a problem at all at german unis
 
aye, can just finish at another time when I'm more of a stable human being and read about stuff I like as a hobby
 
$\digamma$
 
2:06 AM
yeah
this is a good idea
 
Also, extra money surely makes life easier
 
I'ma still hang around here and make quality contributions though
also yeah, a trainee software developer earns like 40k+ on average
 
sus
 
lmao
 
iirc @Krijn quit for some time and did crypto and then joined back academia
totally do that i mean
 
2:08 AM
Yeah my plan is kinda to work in software development for a while and see what I can get in crypto after I have some experience tbh
 
isnt crypto just less cool number theory
 
literally
 
step 1: wait for crypto to crash
step 2: invest in crypto
step 3: wait till it goes up again
step 4: profit
 
you forgot ???????
 
this guy solved economy
 
2:09 AM
I wanted to do the ??? but it was just too clear how it works
 
I need 5 more years in Germany to get citizenship and then I'ma apply to the Bundesnachrichtendienst
 
@EdwardEvans proper patriot, reading the citizens' mails
 
you should've thrown in a feint
 
lool
 
Bundesnichtverdächtigendienst
 
2:11 AM
my brother does his stats phd on crypto and he's pissed that he doesn't instead have money to invest in crypto
 
Edward, I wish you the bestest in the next chapter.
 
Thanks @Ted !
I hope to finish in the future though, now just isn't my time hehe
plus I just got Washington's book on cyclotomic fields which I've been wanting to read for a while
but for which I have had 0 time
 
Too many people do grad school as default. That said, not having sound academic advice and doing ill-advised courses is shitty.
 
Tbh my undergrad course was not at all good enough preparation for the courses here at Heidelberg
 
We had lots of students at UGA in that position, way more at Berkeley.
 
2:14 AM
@user2103480 @Edward todays fun fact: there's a mathematical object called "eierlegende Wollmilchsau"
 
Gesundheit!
 
indeed, Ted, indeed
 
@TedShifrin I think I'll go back over prereqs when I can be bothered and then finish my master's part time when I'm in the position to do so
 
@Thorgott why
 
2:15 AM
Feels like a much more sane plan
 
what object earned the right for that name
 
@Thorgott and was zum Deifl isch des
 
Part-time is harder than you think, but take your time and for sure get mentally strong.
 
I quote from a paper
"Acknowledgement: The results in the first section were obtained together with Martin Möller. We would like to thank him for allowing us to include this part. When he visited Karlsruhe and we discovered one remarkable property of this origami after the other, we called it “eierlegende Wollmilchsau”. We still call it W in this paper."
 
@TedShifrin Yeah I'll be wary haha, but I think one can take as long as one wishes here
 
2:17 AM
My deutsch isn't good enough.
 
I think "W" is the highest voted answer on math.stack
 
amazing
 
its the german pendant of a perpetuum mobile.... in farm animal form
 
@EdwardEvans yeah, should be that way. ive heard stories of people that never took a course and just kept being students to get the cheaper train ticket.
 
2:19 AM
@Thorgott approximately half of my friends who finished their studies
 
There's a dude in my block who does that
 
nice nice
 
174
A: Construct a function which is continuous in $[1,5]$ but not differentiable at $2, 3, 4$

user7530$|x|$ is continuous, and differentiable everywhere except at 0. Can you see why? From this we can build up the functions you need: $|x-2| + |x-3| + |x-4|$ is continuous (why?) and differentiable everywhere except at 2, 3, and 4.

 
tried to do the same after being enrolled in berlin but living in NRW due to covid. But they just hand out große zweithörerschaften instead of full enrollment so people dont get the ticket
 
woops I meant the answer below that
 
2:20 AM
Man, that's a tough one.
 
@user2103480 sad
 
@EdwardEvans indeed
 
yeah, that answer's famous
 
große Zweithörerschaft is very German
 
Idiotic votes.
 
2:21 AM
Oh man I have to register at the Ausländerbehörde now
 
hey @Ted, do you have any clue what a "geodesic opposite" might mean?
 
Thanks, Brexit?
 
Right
 
Opposite point on a given geodesic?
 
run backwards along the geodesic
 
2:23 AM
Assuming we know the base point.
 
@BalarkaSen you can't tell me what to do smh
 
Sure he can!
 
@user2103480 do you know the phrase "sorry ard"
that's supremely English
 
nahh I forgot all the vernacular I was taught
 
Ard?
 
2:24 AM
it's "hard" without the h
 
@user2103480 your mom can tell you what to do
 
I don't think that's it, let me add context
 
o w n e d
 
it's used when someone says a smartass answer
 
Oh oh ... I hope copper isn't here.
 
2:25 AM
or when someone pretends to be tough
Like "you can't tell me what to do smh" gets the reply "alright sorry ard"
 
lol
 
@BalarkaSen it hurts so much
 
ignorant
 
oh nvm
 
@EdwardEvans alright sorry ard
 
2:26 AM
Nvm?
 
I'm too stupid to read symbols
 
@EdwardEvans that comeback will get you dogpiled in the school yard by all the kids
 
Grrr....
 
and you'll be known as sorrytard for the rest of your life
 
My answers bring all the kids to the yard and they're like "alright sorry ard"
 
2:28 AM
@BalarkaSen that's what mom calls me
 
it was supposed to be the geodesic opposite to an angle inside a geodesic triangle and my reading comprehension was just bad, for the record
 
@Balarka just wrote a nice DSBM riff
gonna upload for your enjoyment
 
yes, please do!
@Thorgott lol opposite geodesic
this is what happens if your functors are all contravariant
 
Lol ... i would have said opposite side, so Thor gets partial credit
 
2:31 AM
why cant i reach this site, @edward
 
@EdwardEvans I'll never find the version again that ends with "I can teach you, but I have to charge MAH LAZER"
 
wait i cant reach soundcloud
what the hell
did india ban soundcloud
lol
 
wtf hahahah
 
lmao
 
2:32 AM
switched from mobile hotspot to router and works fine now
very strange
 
India banned a @Balarka
 
India Bans the Ownership of Dolphins - SoundCloud
2nd result on google
 
Oh wow what
stupid idiots man
they're banning chinese stuff because they want to show off
if you ban china you're banning half of technology
 
lel
and half the world's population
 
2:35 AM
at this rate ill need a VPN someday
 
@EdwardEvans the other half being in india?
 
right
 
lol
 
how do i focus
 
music
 
2:37 AM
i waste so much time aimlessly working on weird but interesting problems
 
magnifying glass
 
instead of sitting down and reading textbooks like the real deal mathematicians
 
listening now @EdwardEvans
 
i am going to go study magnifying glasses
 
write weird interesting problems down on little bits of paper and throw them into a fire
 
2:37 AM
@frogeyedpeas "ctrl" + "+"
 
weyy
 
@frogeyedpeas find textbooks which has weird problems
 
any recommendations?
i like unexpected coincidences
 
what do you want to read
 
and unusual cross field connections
 
2:38 AM
@frogeyedpeas play CSS
 
CSS?
 
ok enough gonna sleep now instead of trolling sorry
 
gn
 
goodnite
 
Guats Nächtle
 
2:40 AM
@EdwardEvans ?
 
to you guys as well
 
night
 
It means Gute Nacht in farmer
 
Oh, farmer.
🙄🤷‍♂️🙄🤷‍♂️🙄
 
My german is that of a farmer
 
2:41 AM
That was good, @Edward!
 
tyty
 
Your English is only slightly better.
 
Oioiiiii
 
LOL
 
I'm never sure what to capitalise in English
anymore
since the germans just capitalise everything
 
2:42 AM
Every noun?
 
nothing lol
 
yeah
 
CAPITALISM
 
Happy Trump second impeachment day
send him to gwonton-oh-moe
 
do you think trump matters anymore
 
2:45 AM
Ofc I do, why else would thousands upon thousands of knuckleheads have stormed the Capitol
 
what do discs in the hyperbolic plane look like?
 
this will continue to happen even after he's gone
@Thorgott in the Poincare model? just normal disks
 
by plane i mean half-space model
 
still a normal Euclidean disk, right?
the center can be off
circles are circles in all these models
its normal disks in Poincare and Poincare maps to half space by a Mobius transformation
which preserve circles
its normal disks in poincare because if origin is center it obviously is and you can push disks around by changing center using Blaschke factors, which are Mobius transformations
 
Balarka be right.
Centers are very off.
 
2:51 AM
yeah
 
hmm ok, so in which directions are the centers usually off?
 
towards the boundary circle.
 
LOL
 
I meant not of the disk, of the ideal boundary of the Poincare disk! whoops
lol
 
@TedShifrin I've been off-center for quite a while.
 
2:56 AM
Think distances on the half-plane, Thor. Draw a vertical ray.
 
but the ideal boundary of the Poincare disk corresponds to the x-axis in the half-plane model, no?
 
We know, @robjohn, trust me. But we won’t impeach you
 
and infinity
 
Yes. But think about vertical distances, Thor.
 
it makes sense that if your disk is reasonably close to the x-axis then the center will be skewed towards the x-axis, because... what Ted says
 
2:59 AM
$\log b/a = \log c\b$.
 
what I'm thinking right now is that the Euclidean center of the disk can't lie on the same vertical ray as the hyperbolic center, because the ray is a geodesic and you can move the same Euclidean distance along it both up and down while staying inside the hyperbolic ball, so if the Euclidean center was on the same ray as the hyperbolic center, they'd have to be the same and that cannot be
 
that is nonsense right? what about disks on the y-axis?
the euclidean center and the hyperbolic center lie on a geodesic for any disk. just shift that geodesic to be a vertical line by an isometry
 
what about them?
 
Huh?
Damn categorical Thor.
 
ok, but do you agree that the hyperbolic center of the disk is the midpoint of the intersection between that disc and the vertical ray it lies on?
 
3:03 AM
No what you said is false and I wont read anymore
Do the geometry correctly
 
Midpoint how?
 
ah, it isn't, I see now
 
Midpoint hyperbolically,,of course. That’s the equation Ted wrote.
 
Right ^^^
 
right, I was mixing up hyperbolic and Euclidean distance on the ray
 
3:06 AM
You two have the weirdest BDSM relationship I have ever seen in print
5
 
ah ok, the Euclidean center lies on the same ray as the hyperbolic one, because you can just reflect geodesics across the ray, right?
 
@Thorgott Sorry to tell you the diagram ray -> H^2, ray -> H^2, R^2 -> H^2 doesn't commute
 
@MikeMiller you haven't seen much in print then
 
lol
 
the 51st shade
 
3:08 AM
and going off to infty along a vertical ray, the Euclidean distances behave logarithmically, so of course the Euclidean center has to lie below the hyperbolic center
 
wait let me find 50 shades of (J P) may
 
bruh
 
cant find it
 
It's been made private
 
3:14 AM
Amin might have access dunno
 
yeah ill ask
 
3:25 AM
wait no, that was wrong
the Euclidean center has to lie above the hyperbolic center, not below
 
this depends on where the disk is man
it could be near infinity, or it could be near x-axis
 
on the vertical ray, the distance between two points with fixed Euclidean distance becomes smaller and smaller as you move them up the ray, so the part of a disk lying above the hyperbolic center is longer in the Euclidean metric than the part lying below, whence the Euclidean center has to lie above
 
Again, this is as you move to infinity. What if you move to $0$?
The hyperbolic disks at $i$ for example all have Euclidean center $i$ as well
If you move down the hyperbolic center shifts towards the $x$-axis, so goes below the Euclidean center
 
the picture should be the same, log is monotonic everywhere, so Euclidean distance above the center will always be bigger than Euclidean distance below the center
I've done the computation too, the intersection of the $r$-ball centered at $ix$ with the $y$-axis ranges from $ie^{-r}x$ to $ie^rx$, so the Euclidean midpoint is $i\cosh(r)x$, which always lies above $ix$
 
I can tell you, doing 0 computation, that what you have done is hot garbage
Does the Euclidean center lie below the hyperbolic center?
 
3:37 AM
@BalarkaSen why are you so mean towards thor?
 
sure looks like it, but I have more reasons to believe in my calculation than to believe in some random picture
 
You think the Euclidean center there lies below the hyperbolic center? Are you blind?
What does below mean to you
The hyperbolic center is the red fucking point
 
wait, but then you're not even disagreeing with me
I've been saying the Euclidean center lies above the hyperbolic one all along
 
That's not true if you move above $i$
At $i$ they're the same. Above they exchange positions
Just reflect along a geodesic you'll see it
Your computations are hot garbage
Sorry
 
so tell me whats wrong with my reasoning
 
3:46 AM
No but do you understand mine? Take a huge fucking arc from $-10^{10}$ to $10^{10}$ and reflect the above picture
The red point is mapped way above the image of the Euclidean center of the circle in the image
Because reflections switches order along the $y$-axis
 
I get it and it somehow should be that way, because $i$ corresponds to the center of the Poincaré disk and there should be some symmetry or whatever
 
Exactly
So your computations are nonsense
 
whatever, but tell me what's wrong with my reasoning, cause I don't see that
 
I don't know how to compute, @RyanUnger will help you
Only pure geometry here
 
3:48 AM
I mean the reasoning, not the computations
take a point on the y-axis
take two points the same hyperbolic distance from the given point on the ray, one above, one below
the Euclidean distance from the one above to the reference point is bigger than the Euclidean distance to the reference point from the one below, agree or not?
 
No, depends on where you are. I think it's log but offset by $i$.
$d_{Poincare}(i, iy) = |\log y|$
 
maybe that absolute value sign is fucking me up
 
Yeah corrected it
That's what's fucking you up
$|\log(1/2)| = |\log(2)|$
 
@BalarkaSen Not really.
 
@TedShifrin What is the claim?
 
3:56 AM
The hyperbolic center is always lower.
 
Take a large arc from $-10^{10}$ to $10^{10}$ and reflect the disk?
In the image how does it stay lower?
 
Huh?
I'm still in the half-plane.
 
Take a geodesic arc from $-N$ to $N$, $N$ extremely large, which contains your disk on one side.
Reflect along this geodesic arc. Hyperbolic reflection that is
I am in the half-plane as well
 
I have no idea what you're talking about.
 
What is hard about what I am saying? Look at arc $x^2 + y^2 \leq N^2$ for a large $N$ such that your disk is contained in it
 

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