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17:03
not really lol
sigh ..
@LeakyNun was there anything in that thet made sense to you?
@Rudi_Birnbaum when you say "eigenfunction", what is the linear operator?
$\hat{H}$ the Hamilton operator
$\hat{H}(c_1 \Psi_1 + c_2 \Psi_2) = c_1 E_1 \Psi_1 + c_2 E_2 \Psi_2 $ with $\Psi_i$ e.f.
or in general
$\hat{H}(c_1 \Psi_1 + c_2 \Psi_2) = c_1 \hat{H} \Psi_1 + c_2 \hat{H} \Psi_2 $
what is that operator?
sum of kinetic(=$c \nabla$) and potential energy of the electrons in the field of the nuclei (and themselves)$\hat{H} = \hat{T} + \hat{V}$
:46352612 I have subsumed that under potential ...
17:16
dangit mathematica
didn't i figure out how to fix this before
0
Q: Show that if a self-complementary graph contains a pendant vertex, then it must have at least another pendant vertex.

Math geek Show that if a self-complementary graph contains a pendant vertex, then it must have at least another pendant vertex. $\exists v\in V (G):d_G(v)=1 (\because \text{self-complementary graph contains a pendant vertex})$ $\implies \exists w \in V (G):d_G(v)=odd.(\because {\sum_{v\in V (G) }d_...

If DSolve can solve it, why can't NDSolve
how do i prove that the degree of w is 1
where can i use self-complementary condition
@Semiclassical in the worst case ask in mathematica SE, people there are really great and quickly help even those who didnt f.r.t.m...
17:20
yeah, i just don't want to bother them with an issue i've fixed before
@Semiclassical lol
@LeakyNun happy with the operator? Orbitals are functions from which you can build approximate n-electron wave functions (by anti-symmetrised (Slater) product formation of all of them). Those approx wave functions also can be interpreted to be actual eigenfunctions but to approximate Hamilton operators (only).
That is called for example Hartree-Fock approximation.
But funnily they are eigenfunctions to the one-particle component parts of the operator for the whole n-electron system as well.
Though their individual eigenvalues (of the one (=2 electron upon spin pairing) particle subsystems) are not physical in general (except the HOMO energy from Hartree-Fock that is a crude approximation to the ionisation energy)...
arbitrary unitary rotations of the orbitals lead however always to the same total energy and electron density, and thats all there is measurable ..
In that sense there really are no individual orbitals in many elelctron systems
Hello. Given two subspaces $W_{1}$ and $W_{2}$ of a vector space $V$, and if we are to find $W_{1} \cap W_{2}$, what should be the general method for this?
17:35
on that note, the first colloquium talk of the coming semester is entitled "Walter Kohn and the Creation of Density Functional Theory"
I had DFT already in the text but deleted it again because I was not completely sure if it strictly can be summarised under the method I explained.
I mean if the Kohn-Sham orbitals can be formally regarded as eigenfunctions? I'm ab-initio guy ...
user131753
Let $(H,\circ)$ and $(H,\ast)$ be two groups such that they have precisely the same subgroups. Are they isomorphic?
@user170039 Not necessarily
math.stackexchange.com/questions/2875767/… shows that even with a much stronger condition, this still can fail
DFT is a bit ugly ..
Some theoretical chemist said last year in a big conference: "We [meaning ab-initio people] try to actually calculate the solutions of the Schrödinger equation and not guess it [meaning the DFT people]."
17:45
@Semiclassical exactly :-)
@user21820 i want to talk to you.
What's the snarky DFT response?
some people on math.stackexchange are very heartless and don't have any feelings.
user131753
@TobiasKildetoft But here I am not talking about same in the sense of being isomorphic.
something like "Useful results are more important than exact results?"
17:48
@user170039 They don't get to be more the same than the setup in that question, do they?
user131753
@TobiasKildetoft To be more precise, let $(H,\circ)$ and $(H,\ast)$ be two groups such that they have exactly the same subgroups, i.e., $S$ is a subgroup of $(H,\circ)$ iff it is a subgroup of $(H,\ast)$.
@user170039 So the two groups are subgroups of some larger group?
@Semiclassical in a way, but then DFT is nowhere near exact ...
user131753
@TobiasKildetoft Sorry but I don't understand your point. Can you clarify a bit?
@user170039 If the groups are not subgroups of some larger group, it makes no sense for a subgroup of one to also be a subgroup of the other
user131753
17:51
Which groups are you talking about?
@Rudi_Birnbaum is there any relation between Mock theta function and riemann zeta function?
user131753
@TobiasKildetoft I see your point.
user131753
Ok then. Let me modify my question a bit.
@AdarshKumar I am not the one who can answer that, I am very sorry!
anyone else know about it?
17:54
@AdarshKumar I would guess @MatheinBoulomenos for example?
@MatheinBoulomenos is online?
Afaik he recently passed an exam on modular forms (which could be the right corner of maths ... maybe)
@AdarshKumar look to the right where these funny colorful "devices" are.
@Rudi_Birnbaum means?
Each such a "device" (dunno what else to call them) corresponds to a loged-in user
point your mouse at it and the name appears.
I think he is not
user131753
Let $(H,\circ)$ and $(H,\ast)$ be two groups and $S\subseteq H$. Let $[S]$ and $(S)$ be the subgroups generated by $S$ in $(H,\circ)$ and $(H,\ast)$ respectively. If $[S]=(S)$ for all $S\subseteq H$, are they isomorphic @TobiasKildetoft?
17:58
This is a very weird question
Usually we don't care about having two group structures on the same set
@user170039 one way to identify two groups is "isomorphism"
user131753
@Rudi_Birnbaum Yeah I know that. But that's not my point.
if you don't want "isomorphism" to be how you identifiy two groups then you have to exactly define how else
But this does seem like it might be an even stronger condition that in the linked question (as I don't think the bijection given there can be extended to be defined on the elements)
also what if the sets of groups are the same (isomorphic) but one occurs in one group "more often"?
user131753
18:02
@Rudi_Birnbaum For example?
no idea, just trying to make you get the piont that your question is not really formulated very good
@Rudi_Birnbaum I understand the question now. But it feels very unnatural, so I have no idea what the answer might be
@TobiasKildetoft OK! sorry then @user170039
user131753
@TobiasKildetoft I think that $\ast=\circ$ (as functions) and that's what I was trying to prove but couldn't.
Do you have an example in mind?
user131753
18:06
@Semiclassical Was this asked to me?
@user170039 Now that sounds much stronger than I would expect
user131753
@TobiasKildetoft Yeah indeed.
I guess one way to pose it: Can two different operations on a given group produce the same subgroup?
I would imagine the answer is a definite yes.
@user170039 Right, the operations will not be equal as functions (just take a prime number of elements and permute the non-identity elements)
18:11
Hi @MatheinBoulomenos! How are you?
Hi @Rudi_Birnbaum
I'm well, thanks. I'm on vacation right now, that's why I haven't been online for a while
user131753
@TobiasKildetoft So then we are left with isomorphisms.
@MatheinBoulomenos great!
@AdarshKumar @Rudi_Birnbaum mock theta functions are related to Maass forms (non-holomorphic generalizations of modular forms) through the work of Ken Ono and Kathrin Bringman
Maass forms are generalizations of modular forms and modular forms are related to certain L-functions via the Hecke Converse theorem. L-functions are generalizations of the Riemann zeta function
that's a relation between mock theta functions and the Riemann zeta function, but it seems a bit vague and far-fetched
18:16
@MatheinBoulomenos I need to draw that ...
Are among these "certain L-functions" those which can be "concretised" to $\zeta(s)$?
Hello. Let $W_{1}$ be a $3$x$3$ matrix such that for all rows the sum of elements in any row sums to zero. Similarly let $W_{2}$ be a $3$x$3$ matrix such that for all columns the sum of elements in any column sums to zero. Then i need to find $W_{1} \cap W_{2}$.
I started by finding the respective basis of $W_{1}$ and $W_{2}$ then a matrix will belong to their intersection if it can be represented a$s a linear combination of basis vectors of both spaces, then i equated those two representations to get a set of equations.
This method is very long and not elegent at all. I also know that to find a basis for intersection of two spaces i can row reduce the matrix formed by basis of both spaces as rows and the rows not having pivot element would be the basis of the intersection, but here, the basis are themselves matrices makaing the procedure very long. Any other good method?
A thought: If $u$ is a column vector of ones, then the matrix elements of the vector $Wu$ are the row sums of $W$.
@Rudi_Birnbaum no, I don't think the Riemann zeta function corresponds to a modular form
Hi @Alessandro
18:22
so $W_1$ should satisfy $W_1 u=0$ and $W_2$ should satisfy $u^\top W_2=0$
So you're looking for all matrices such that $u$ is both a right- and a left-eigenvector with eigenvalue zero
How is it going?
Note that, at the least, such a matrix will have to be singular
@AlessandroCodenotti enjoying myself in France :) just hopped into the chat because I was pinged. How's it going for you?
how does that help me find $W_{1} \cap W_{2}$?
18:24
Well, it reduces W_1 and W_2 to spectral problems
That seems handy
Ohh, nice, which part of France? I'm reading about local fields so that's probably great from your point of view
Hey everyone!
Equivalently, you're looking for all matrices $W$ such that $Wu=0$ and $W^\top u=0$
Whats the $\dim$ of $W_1$ and $W_2$?
@Alessandro learning about local fields is great, indeed! I'm in the French part of Catalonia at the Mediterranean Sea
18:26
Not prescribed.
Presumably it's some fixed $n$.
@MatheinBoulomenos yeah but their topology is all weird
@MatheinBoulomenos Sounds like a great location, is the water nice?
@Rudi_Birnbaum yeah the water is really clean and nice.
@MatheinBoulomenos You might like this discussion
@MatheinBoulomenos I'm envious!!
18:28
My impulse is to observe that any vector $e_j-e_k$ will be orthogonal to $u$
@Alessandro I don't think about their topology too much
Hi @MikeMiller I'll have a look
and therefore any outer product $W_{jk}=(e_j-e_k)(e_j-e_k)^\top$ will satisfy $W_{jk}u=W_{jk}^\top u = 0$
additionally, any linear combination of such matrices will also have this property
the only problem is that this restricts to symmetric W
@MatheinBoulomenos local fields like $p$-adic numbers?
so probably one needs to also ask about skew-symmetric $W$ such that $Wu=0$
@Rudi_Birnbaum p-adic numbers are the most well-known example, yes
@MikeMiller that was an interesting read, thanks!
18:30
Is that why you study them?
@MatheinBoulomenos yeah but then people want to complete them and you need to look at the topology
@AlessandroCodenotti Oh I meant I don't try to visualize the topology
I do think about it
@Rudi_Birnbaum they can help us to understand global fields like $\Bbb Q$
Can the topology on $\Bbb Z_p$ be described more explicitely than the inverse limit construction? I don't feel comfortable with it
18:34
@MatheinBoulomenos would that be a direction of the Scholze research?
@AlessandroCodenotti it's induced by the p-adic metric
@Rudi_Birnbaum yes, Scholze studies local fields in a lot of detail (that much I can understand)
instead of the inverse limit you can just complete $\Bbb Z$ wrt the p-adic metric
Hello, I confess, I'm only an undergraduate so please bear with me. How would one formally/mathematically describe the following? I have a binary string which I split into $k$ substrings of equal length. I define $x$ to be the number of $0$s required for a substring to be declared as 'valid'. so if my substring $sub$ has exactly $x$ $0$s, it's valid. I want to look at the sequences of solely invalid substrings, add up their sum of zeroes together, for each sequence of invalid substring. I want to find the first sequence such that this sum is $\geq x$. I am doing all this to find within that
@Mathei I want to take this course, apart from local fields, which I'm learning about (I'm reading chapter 7 of Milne's notes if you're familiar with them) is there something in ANT I should absolutely know and I don't?
@MatheinBoulomenos I have read yesterday some introduction parts in texts on perfectoid spaces and I was completey struck by not feeling completely clueless ... lol
@MatheinBoulomenos Oh, sure, this is much nicer to think about but still kinda strange
18:37
@Alessandro you should be fine based on the number theory course you had
The fact that the metric has a discrete range in $\Bbb R$ has some weird consequences
$\Bbb Z_p$ is the closed unit ball of $\Bbb Q_p$
rofl
hi @ÍgjøgnumMeg
Hey @Mathein :)
@ÍgjøgnumMeg O..o
18:39
I know that, I also know that it's the closure of $\Bbb Z$ (or $\Bbb Z_{(p)}$) in $\Bbb Q_p$, but that doesn't help my intuition
Sure, I was just making an unhelpful addition
@MatheinBoulomenos I see, thanks
@Rudi i.e. $\Bbb Z_p = \lbrace a \in \Bbb Q_p : \lvert a \rvert_p \leq 1\rbrace$
@ÍgjøgnumMeg Yes, I just had to quickly check the norm ...
:D
It's the birthday of Claude Debussy today btw!
18:42
@Semiclassical i understand how you reduced it to the problem of solving Wu = 0 = u^{T}W for u = (1,1,1)^{T}. I need W satisfying both of these equations after that you talked about outer product and thinks thats where i lost you. Explain again please.
@Rudi_Birnbaum by the question $dim W_{1} = dim W_{2} =6$
The closed unit ball, which is also open!
clopen
lel
Waaaait is $\Bbb Q_p$ totally disconnected?
@AlessandroCodenotti here's some intuition based on Riemann surfaces and algebraic geometry (or just complex analysis if you want)
you can think of elements in $\Bbb Z$ as functions on $\mathrm{Spec}(\Bbb Z)$, similarly you can think of elements in $\Bbb Q$ as meromorphic functions on $\mathrm{Spec}(\Bbb Z)$. a rational number $\frac{a}{b}$ (completely reduced form) has a "pole" at a prime $p$ if $p$ divides $b$, think about it as analogous to rational functions $\Bbb C(z)$ the p-adic valuation just gives you the order of the pole or the zero at $p$
@ÍgjøgnumMeg never heard of him, but a good occasion to open some bottle of wine :-)
18:44
that's for the p-adic valuation, not $\Bbb Z_p$ itself
@Rudi do you know the piano piece Clair de Lune?
@ÍgjøgnumMeg That rings a bell!
@Rudi he is the genius who composed this piece! lol
Oh, Mathein has returned to answer all of Alessandro's algebra beasts. :)
@ÍgjøgnumMeg just listening to it
18:45
Hi @Ted! Greetings from France
How do you think about elements of $\Bbb Z$ as functions on the Spec? (I never properly learned any AG, I just know how the Zariski topology works from commutative algebra)
Hi @Ted
Hey @TedShifrin :)
salut, @Mathein. Warum bist Du en France?
hi @Perturb
@TedShifrin Urlaub
18:47
@AlessandroCodenotti the integer $n$ sends $p$ to $\frac{n}{1}$ in $\Bbb Z_{(p)}$
Claude Débussy very famous if one knows classical music (particularly piano) ....
@AlessandroCodenotti hm, but for the analogy it's better if $n$ (as a function) sends $p$ to $n \pmod{p}$
Isa
Isa
@TedShifrin one of the angles $\theta_1$ ,for the i point, is in the interval $(\pi/2,5\pi/2)$ and the other angle $\theta_2$, for the point -i, is in the interval $(-\pi/2,3\pi/2)$ ?
@Shobhit: Perhaps someone answered your linear algebra question? I don't understand what you mean by the intersection of two matrices.
@MatheinBoulomenos I see that this works but I have no idea why it should be a natural thing to consider!
18:50
@Isa: So what branch cuts are you making when you do this? I.e., what rays are you removing from the plane? You do have one of the two possible solutions, yes.
@Shobhit: Do you mean that $W_1$ is the set of all matrices with that property, etc.?
Okay so correct me if I'm wrong but there's two ways to think about CW Complexes. The first way (sort of taking a big space and breaking it down into smaller pieces) if you're given a Hausdorff space $X$, you construct a cell decomposition of it, provide some characteristic maps and if the cell decomposition is finite we automatically get ourselves a CW Complex. of your familiar space $X$
The second way (sort of like taking a small space and making it bigger by adding cells of increasing dimension) is if we start with a discrete set of points, provide some cells of dimension one and some attaching maps, and do this for as many dimensions as we need. So given a situation where we want to prove some topological space is a CW Complex and we can show that it is a CW Complex through the first method, why would we want to use the second method?
Because in the second method if you want to make an inductive cell construction of some familiar space, then once you make the cell construction you'd still need to show that what you constructed is actually homeomorphic to that familiar space under consideration
Isa
Isa
@TedShifrin one ray start at point i and goes to infinity and the other ray start at -i and goes to -infinity
@AlessandroCodenotti hm, maybe that's a bit too much to explain for now, I don't have that much time. the idea maybe is that if you look at $\Bbb C(z)$, a rational function $\frac{f}{g}$ may be evaluated a point $z_0 \in \Bbb C$ if $g(z_0)\neq 0$, by considering it as an element of $\Bbb C[z]_{(z-z_0)}$ and then reducing modulo the (unique) maximal ideal $(z-z_0)$, the quotient is isomorphic to $\Bbb C$
I just noticed it, but I find the two facts that $\Bbb Q_p$ is totally disconnected yet complete extremely counterintuitive!
@Perturbative: CW complexes don't have to be finitely many cells, but they do have to have a relatively nice topology.
18:52
hi @TedShifrin sorry i was away. Yes i meant set, mistake.
@Isa, right!
Do you see another way you could do it, @Isa?
@TedShifrin You're right, I was only talking about the finite case above
@MatheinBoulomenos Sure, I need time to digest this stuff anyway, I'll think about what you wrote
So @Shobhit: For a matrix $A$ to belong to $W_1$, what simple equation must it satisfy?
Isa
Isa
@TedShifrin Do you mean for the intervals for $\theta$ ?
18:54
@AlessandroCodenotti thinking about elements of $\Bbb Z$ as functions on $\mathrm{Spec}(\Bbb Z)$ is something a lot of other people have written about
$Wu =0$ for $u = (1,1,1)^{T}$ @TedShifrin
@Isa: Yes, or think about removing a different subset that will still make things work.
OK, and for it to belong to $W_2$, @Shobhit?
$u^{T}W=0$ @TedShifrin
Right.
OK, so that's the way to understand it.
@MatheinBoulomenos I clearly don't know nearly enough to see why this is a fruitful point of view, but it's surely an interesting one
18:56
So you have two linear equations on the 9-dimensional space of $3\times 3$ matrices. Are you trying to give a basis for the resulting 7-dimensional space?
You should be able to describe the row space and column space of your matrix quite precisely.
@AlessandroCodenotti the keyword for what I said is "function field analogy" (in a broad sense, if you include Riemann surfaces in the analogy)
Isa
Isa
@TedShifrin why to think about different intervals for $\theta$? What is the problem with $(\pi/2,5\pi/2)$ and $(-\pi/2,3\pi/2)$
@Isa: I had told you there were two different solutions to the problem. I was just asking you to find the second. Don't bother if you don't want to.
i need to find $W_{1} \cap W_{2}$, matrices satisfying both of the above equations. Yes, i was able to find basis of both sets and for a matrix to belong to both sets implies that it can be represented as linear combination of basis of both sets, i then equated these two representation to get a system of equations. @TedShifrin
No, not quite right.
18:59
but this method took much time, is there no other method?
Oh, I see what you mean.
I'm suggesting thinking about the rows as linear combinations of $(-1,0,1)$ and $(0,-1,1)$. What are the possible linear combinations that will make the columns have the right properties?
Isa
Isa
@TedShifrin ah ok :)
Kind of the moral of modern AG is that every ring should be thought of as functions on some space (turns out this is Spec) - in the classical case this is more intuitive with fg k-algebras
Oh, I lied, @Shobhit. $W_1$ is a $6$-dimensional space and $W_2$ is a $6$-dimensional space. Their intersection will turn out to be $4$-dimensional.
Did you get a $4$-dimensional solution?
yes, 4 -dimensional
19:03
Cool. Do you understand the approach I'm suggesting?
thinking
A f.g. k-algebra is the ring of rational functions on the variety associated to the ideal I quotiented $k[x_1,\cdots,x_n]$ by, right? @loch
i like this description better than the half-baked “outer product” approach I had
No read yet @Ted
LOL, I figured that cryptic message was to me, @MikeM.
19:05
(The latter does work if used properly, but I don’t like it as much)
Are you talking to me and Shobhit, Semiclassic, or about something else?
Can someone clarify this definition for me? Given a sequence $\{E_n\}_{n=1}^\infty$, we set $\lim\sup E_n := \{x \in E_n : \textrm{for infinitely many n}\}$. It doesn't make sense to me
hi @Ted
You, yeah. (I had attempted to help a little earlier but my brain wasn’t working(
Hi Leaky
I just came back from shopping at three places, Semiclassic, so I have no brain.
19:07
@AlessandroCodenotti looks like I missed some dank algebra
You left your brain there? Sounds legit
@Martin: That's not written in a way that makes sense. You're correct.
@Mike apparently a space is compactly generated iff it is the quotient of a locally compact space, proof on Dan Ma's blog
@TedShifrin I mean your writeup.
Yes, @MikeM, I understood :P
19:08
@TedShifrin i dont understand what you are suggesting but i was able to find a W that satisfies both equations.
I have been writing like crazy ... good pace
All day which is not good for me but if I only do it for a month...
@TedShifrin ok
@AlessandroCodenotti That's insane
@Martin: All your $E_n$ live in some big space $X$. It should be $\{x\in X: x\in E_n \text{ for infinitely many }n\}$?
That's good, though, @MikeM. I'll forgive you ... temporarily.
@LeakyNun There will be more if I keep learning about this stuff, I always have plenty of questions!
19:09
I see, @AlessandroCodenotti, the point is that the locally compact space is indeed gigantic
@Shobit: All the rows are orthogonal to $(1,1,1)$, hence a linear combination of $(-1,0,1)$ and $(0,-1,1)$.
36 mins ago, by Alessandro Codenotti
Can the topology on $\Bbb Z_p$ be described more explicitely than the inverse limit construction? I don't feel comfortable with it
@AlessandroCodenotti I'll do you one better...
Just like you said before, a set $S$ is open iff for every $x \in S$ there is $n$ such that $x + p^n \Bbb Z_p \subseteq S$ @AlessandroCodenotti
Any topological space is the quotient of some Haursdorff space
19:10
The approach I had in mind works for symmetric W but I wasn’t seeing a clever way to do skew-symmetric W
Hey everybody!
@AlessandroCodenotti so it's basically the $p\Bbb Z_p$-adic topology
hi @Daminark
Yo @Daminark
So the first row is $a(-1,0,1)+b(0,-1,1)$ for some $a,b$. The second row ... the third row. @Shobhit ... Now what do the column conditions tell you about $a,b,c,d,e,f$?
But the approach Ted is pointing to, I think, takes care of both at oncr
19:10
@MikeMiller Indeed. This is the neat direction imho, but "quotients of locally compact spaces are compactly generated" looks like the useful direction
hi Demonark
@Perturbative really?
So bottom line is you should ignore me :/
Semiclassic: Are you talking to anyone?
19:12
I dunno.
How's it going everybody?
Yeah @LeakyNun, I remember reading it somewhere, see here : math.stackexchange.com/questions/1569130/…
Demonark, is Eric still alive?
is there a rule that say only square numbers can have odd number of divisors?
@TedShifrin I saw him earlier
19:13
@yasar it's not a rule, it's a theorem
On h-bar I think?
Ah, ok.
For other numbers they come in pairs
I dunno, SPDE prognosis isn't always the best (also I'm back in Texas)
He wouldn't be there, Semiclassic!
19:14
@TedShifrin did you mean (-1,1,0) , (-1,0,1) ?
Oh, you escaped to hot, reactionary Texas, Demonark. I'm hoping for some political upheaval there soon.
@LeakyNun So, is it proven?
@Shobhit: Either one is a basis.
@yasar yes, every theorem is proven
I'm using the usual pivot/free variable algorithm to give my basis, but it doesn't matter.
19:14
those that aren't are called conjectures
@TedShifrin didn't he appear yesterday when we were talking about harmonic functions?
Yes, he was here yesterday, @Alessandro, but quite ill :(
a+c+e=0 , b+d+f=0 @TedShifrin
Right. Good. So now you have an easy way to give a basis for the space of matrices.
I thought I saw Eric earlier but maybe I was imagining it
19:17
@Perturbative I've been so many answers on MSE that for some topics I guess the author of the answer before reaching the end of it, this was one of them!
Maybe you've been overdoing Heisenberg, Semiclassic.
yes, thanks. I'll do some more related examples now. @TedShifrin
You're welcome, Shobhit. I think that's the best approach to the problem.
The Uncertainty Principle is a very dangerous drug
19:18
lmao @AlessandroCodenotti Did you guess Brian or Eric?
@Alessandro: I'm hurt you don't recognize my answers :(
my classes have started and by the time you come online its already 1:00 am here and i have classes at 7:00 am, so i am asleep most of the time :( @TedShifrin
Can anyone tell me in a nutshell what the reason is for why $p-adic$ numbers are not defined the other way round I mean summing to $-\infty$ and starting from finite positive powers.
"I have classes at 7AM"
Time differences are amusing, @Shobhit. :) You don't need me ;P
19:19
@Rudi_Birnbaum was bedeutet das?
I do not envy you
Demonark: In the US I think we generally start at 8 AM, although I think I once started teaching at 7:50.
@Perturbative Brian
@TedShifrin I only follow a few tags and they are almost disjoint from the ones you usually write answers in
First year I was gonna take chemistry, ended up not doing it because I didn't want the labs, but that was gonna be an 8:30 class MWF
You need better taste, clearly, @Alessandro :)
19:21
@LeakyNun they run from positive infinity in powers of p to finite negative. Why isnt it more/similarly useful to study objects which go the other way round?
@TedShifrin you explain SO WELL. Whenever i am stuck at something in class or otherwise i am relieved that i can always ask you :)
I had an Honors advisee once, Demonark, who refused to take classes from me because they were (in those cases) before 11. I think he did finally take one.
Aside from that one week schtick, I think the earliest I've ever had a class was at 9AM T-R, which was manifolds
LOL, @Shobhit. Thanks for the nice words.
19:22
I usually recognize Asaf's and Noah's style because I mostly read set theory and logic questions
@Rudi_Birnbaum in the p-adic metric, large powers of p is small
@Rudi_Birnbaum if you go the other way round, then you're just dealing with $\Bbb R$
I've had a number of 9:30s, and I don't think I've ever gone a quarter without a 10:30
@LeakyNun Yes, but you could "turn the metric round", instead couldn't you?
Demonark: I didn't care that much when I taught, but I didn't like afternoons. I liked having lectures done before lunch. The few classes I taught at lunchtime or after, students were falling asleep — either from having eaten or from starving. Office hours in afternoons worked fine, though.
The crucial answer is what Leaky said in his second sentence. Independent of the metric, if you do finitely many positive terms you're just doing usual decimals base $p$.
@Rudi_Birnbaum yes, but it would just be $\Bbb R$
19:24
See what I just wrote and didn't ping.
Hmmm, looks like there are wild boars in the nearby fied, I guess I should go back inside, they get closer to the houses during the night every year... Bye everyone!
Whoa, where are you, Alessandro?
Alessandro is a wildebeast :P
My grandparents house in Tuscany, it's pretty much in the middle of nowhere
@LeakyNun really?
Oh, cool, @Alessandro.
19:26
@Daminark Early classes have their advantages, you are free by 12:00 and can study play or whatever. I know people having classes at 10:00 and they come back by 3:00 or 4:00 tired and with no energy to do anything.
But they have internet :P
@Rudi_Birnbaum yes, really.
2 mins ago, by Ted Shifrin
The crucial answer is what Leaky said in his second sentence. Independent of the metric, if you do finitely many positive terms you're just doing usual decimals base $p$.
Something like 4Km from the nearest vilage and 12Km from the nearest hospital (all distances measured on small mountain roads where two cars can barely pass side by side)
How do they have internet there? :)
Must be beautiful, nevertheless.
@TedShifrin I use the wifi of a nearby agriturismo, which is one of the three buildings here
19:28
Oh ...
But it's not strong enough to be used inside
Hence you risk life and limb tangling with boar.
Either that or I have internet on my phone, which also doesn't work inside :D
@TedShifrin It is indeed
Well, lunchtime for me. Back later.
I'm going now though, maybe I'll be back later! Bye
19:29
Bye.
@LeakyNun oh I see, you get either "discrete" or $\Bbb R$ then. strange.
@Rudi_Birnbaum indeed, every place (i.e. norm / valuation) on $\Bbb Q$ is either the p-adic place or the archimedean place
@LeakyNun Oh that sounds deep ..
what do you mean
19:35
@Shobhit I guess I'm kind of a night person is the thing
@LeakyNun involved to get a proof
me too but just on weekends and exams XD
@Rudi_Birnbaum indeed
Though summers have taught me that having classes even strictly in the afternoon doesn't really help much
@Rudi_Birnbaum why would you both be a chemist and care about algebra?
19:36
@LeakyNun I am a human and curious about the world we inhabit
By the looks of it, this fall I'll have 9:30 TR, 11 TR, and 12:30 MWF
4th class is TBD
TR? MWF?
@Rudi_Birnbaum so what do you study in university?
Tuesday-Thursday, Monday-Wednesday-Friday
@LeakyNun Well my official function in university is docent, so officially I'm not kind of student. Though I think I study sciences still
19:39
oh
@Rudi_Birnbaum then what did you study?
@LeakyNun Chemistry
@LeakyNun surprised?
19:41
in how far?
for finite dimensional vector spaces i can say that $dim (W_{1} + W_{2}) \le dim W_{1} + dim W_{2}$, any lower bound for $dim (W_{1} + W_{2})$ ?
@Shobhit well $\dim W_1 \le \dim (W_1 + W_2)$
@Shobhit there's actually a formula for the dimension of the sum, which does imply your bound but it's wise to work through it, and there's a lower bound but it's not too satisfying
so a lower bound is $\max(\dim W_1, \dim W_2)$
and this is achievable
so this is a precise lower bound
I think I might have misinterpreted "lower bound"
Actually, the question was if V is a vector space of dimension n and given that the intersection of any two subspaces of dimension (n-1) is nonzero, find n. I was thinking of using this bound to find n. @Daminark @LeakyNun
19:49
don't try to solve the problem
try to understand it
ok. thinking.
cool
hints please
For this I'd recommend trying out some values of n to see what happens

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