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2:00 AM
I was given a 'hint' to set u^2 = 5x. I tried that and got the wrong answer
 
What, exactly, happened when you tried $u^2 = 5x$?
 
I may have done something wrong
 
@BalarkaSen thanks for the info. Maybe I'll see him next time.
See you all and good luck with the integrals!
 
Hope to see you around again.
 
I subbed in the U, then I integrated using U substitution (using the letter B) where B = 1+u
dB = 1
and then I have int u^-1 * dB
which becomes ln(u)
 
2:04 AM
I'm wondering about your dx from the first "layer" of the substitution. (I'm pretty sure--though I'm just doing it in my head, no scrap at hand--that you never "did the u-substitution" correctly.)
 
@10Replies You mean dB = du, right?
 
Yo yo yo
 
Hey hey hey
 
@BalarkaSen dB = dB i don't think I ever had a du which might be my problem
 
You need to set u=sqrt(5x)
My other hint is, remember 1-1=0
 
2:06 AM
U^2 = 5x is equivalent to that, and I was told to set u^2 to 5x
 
Don't do it that way. I just did it both ways and it's easier with the root
 
Doing it with or without the root is honestly equivalent.
 
My second hint is honestly more important.
 
@10Replies Here's the problem: you've said you want $\int \frac{7}{1+\sqrt{5x}}$. But that's nonsense. You really want $\int \frac{7}{1+\sqrt{5x}} dx$.
 
2:08 AM
What does the dx mean?
I never had to deal with dx in calc I
It was just kinda there
And I ignored it, as I was doing now.
 
@logical123 It doesn't seem to be much of a hint, but, erm, sure.
 
@10Replies I want to punch your teacher. Possibly you, but definitely your teacher.
3
 
Oh I'm an awful person, you have two fists, might as well kill two birds with two stones
 
=)
(Thanks for taking that in the mostly-humor it was intended.)
 
Hahaha
 
2:10 AM
@nitsua60 it is rather my kind of humor, indeed
aw, you edited out semi
 
You don't integrate functions; you integrate differentials. Must be a horrifying calc I class if it hasn't taught that.
 
When I do the u sub, I get $/int$
 
It was AP calc. I learned how to take a test, not how to do calc
 
When I do the u sub, I get integral of (14/5)*(u/(1+u))
 
The way I put it to my students is that the substitution isn't "complete" if you do what you've said: $\int \frac{7}{1+\sqrt{5x}} dx, u=1+\sqrt{5x} \rightarrow \int \frac{7}{u}dx.$
 
2:13 AM
Ugh AP Calc... Pick up Spivak Calculus
 
@logical123 Oh I see what you meant by your hint.
That was cryptically written, but yeah.
 
Factor the constant out, then add 1 and subtract 1 to the numerator
I wanted it to be super cryptic
Back in Calc I pounded my head into the wall for at least minutes until I thought of that.
 
I don't know that you can blame AP for this bit... there are plenty of problems on that test where neglecting the differential in a substitution would bite you. The teacher, even if solely "teaching to the test" should have been hammering that home.
 
Where is du in 7/(1+sqrt(5x))? I can quite clearly see the U, but not the du
 
You need to solve for dx in your substitution
 
2:15 AM
@logical123 What does that mean?
 
@logical123 I'm not clever--I would have just long-divided the thing (and ended up in the same place).
 
I'm not super clever, but I love the clever solutions.
 
Subtracting and adding the same stuff is actually a pretty useful (and standard) trick.
 
In physics, that trick is routine
In your u = root(5x)
 
@BalarkaSen Yeah, just not one that I'd necessarily even think of when the obvious, two-line method that will always work is also staring me in the face.
 
2:17 AM
Differentiate both sides and solve for dx
 
@logical123 "And why should I do that?" he asks, rhetorically?
 
du = (5/2)x^(-1/2) .... dx?
 
Yep, now get dx alone.
 
(5/2)*du*sqrt(x) = dx
 
Can you express the left hand side as a function of u?
 
2:19 AM
(And I say "rhetorically" in a specific manner: intended to advance the rhetoric, not the current colloquial meaning of "not expecting an answer.")
 
The way I think about why you solve for dx is, you want to see 'how big ' the old differential is
In terms of the new one
Perfect
Wait, no, (5/2)*sqrt(5x)du=dx
Now, recall what your u is.
 
sqrt(5x)
 
@nitsua60 I guess so.
 
U=root(5x), which is on the left side right?
Plug in u there
 
@BalarkaSen (nvm--I was thinking of the wrong line--I was the one thinking three steps ahead--you were absolutely correct. Sorry!)
 
2:21 AM
Now you have (5/2)udu =dx
 
You can plug u into du?
 
You substitute u for root(5x)
You follow me?
 
@nitsua60 (I thought you were quibbling amount the use of the my word "function", and maybe I should have said "plug in" instead.)
 
yeah
 
(Also why are we using parenthesis to communicate)
 
2:23 AM
(not sure but i feel left out)
 
Cool, so now plug in the entire left side into dx into the original integral
As well as u in for root(5x) into the denom
 
@BalarkaSen (No, I was thinking ahead to the algebra that'll have to be done on the u-space integrand and assumed you were setting up a shortcut there, rather than noticing that you were just prompting him to complete the substitution from x-space to u-space.)
 
(iseewhatyoumean.jpeg)
 
@BalarkaSen (I blame SE: it all started with "(removed)")
 
2:27 AM
(7/(1+u))-5/2udu
 
No minus sign lol
 
Should be "*", right?
 
And I flipped the fraction, should be 2/5 right?
Corect
 
yeah
wait, why is the fraction flipped?
because we devided both sides of du by (5/2)x^-.5 ?
 
Yes
My bad, on my phone so not being hyper careful lol
Now, just factor out the constant in front of the integral, and what we want to integrate is u/(1+u) du
 
2:36 AM
Ok, so now I have u/(1+u) du (and I took out all the constants)
 
Perfect
Now my thought process is, if only we got 1+u / 1+u, then that would just be the integral of 1...
What do I have to do to retain equality of an expression if I just choose to add something? You better subtract that something as well!
'Make' the integral (1+u-1)/(1+u) du
 
Sure. We'll pretend that I understand why this works...
So (u+1-1)/(1+u)
 
@10Replies The alternative is polynomial division... most people prefer logical's path =)
 
I don't remember polynom division so I guess we are taking the other way
 
No
Do not pretend
What makes you think that isn't 'legal'
 
2:42 AM
It is perfectly legal, it just is the same thing as it was before lol
as you said, 1-1 =0
 
Ok, I understand what you meant. Not sure why this get the answer quicker
Hopefully it becomes obvious
Next bit would be to separate out the expression like ((1+u) - u )/ (1+u), then expand as (1+u)/(1+u) - 1/(1+u)
 
I frequently tell my students that a surefire method to tackle a problem you don't know how to solve is "make it look like a problem you do know how to solve." That's what logical's walking you through right now. You don't know how to integrate $\int \frac{u}{1+u}du$ off the top of your head (we assume), but you would totally know how to integrate $\int \frac{1+u}{1+u}du$. (With some setting-aside of a sticky bit for a moment.)
 
Which is 1-(1/(1+u))
Yes! Nitsua gets it. The idea is to fudge stuff to make it like things you know how to deal with, and unfudge it 'later'
 
How am I "separating" out the expression?
 
Distribute the denominator over the expression on top
Like
 
2:47 AM
hello
got some strange messages
 
(1/(1+u))((1+u)-1)
 
I'm still not quite understanding this operation.
 
If you have (7+x)/5
 
@Dodsy Without really knowing you, I'm going to quote Bachman Turner Overdrive and advise you to "slide, slide, slide, let it slide."
 
Isn't that 7/5 + x/5 ?
 
2:50 AM
Ok
 
Same operation as in the actual problem, distribution
But you can choose to group however you want in the numerator
 
(u/(1+u)) + (1/(1+u)) - (1/(1+u))
Oh I think i get it
 
@nitsua60 kk
 
Remember the associative property? That's what allows us to group into (1+u) and -u in the numerator
Bing bang boom
 
(u/(1+u)) + (1/(1+u)) - (1/(1+u)) = (u+1)/(u+1) - (1/(1+u)
right?
 
2:52 AM
You're starting to see it, you got this. Finish it off. Last hints are you'll get a log, and don't forget to back sub what u actually is
 
@Dodsy But you know the history better than I--this is "casual bystander" talking, not "diamond" talking =)
 
You got it mate.
 
@nitsua60 I don't know anything, been gone for so long.
=)
happy to have a place to talk about math
 
@logical123 (And double-check the domain. Never hurts, IMO.)
@Dodsy Starting a class on Chaos/Dynamical Systems on Monday. Excited about that =)
 
oh nice!
 
2:57 AM
But I've got a weird artifact of the schedule where my students'll have only one meeting in 12 days at one point. It's around the time I'd usually assign a partner- or group-project, but assuming they'll be traveling some I really should make that one a solo. But that means I need to re-think some other one or ditch one or something, and I've not yet found any combination that makes me happy =\
 
The domain of what? The denominator?
 
(14/5)*(sqrt(5x)-ln|sqrt(5x)+1|) + c
 
Wammy
Full marks.
Lol
 
Thanks!
 
Next problem lmao
 
2:59 AM
@logical123 The result vs. the integrand. It's a habit I try to instill in my students.
 
Oh absolutely
I like to think about what the restriction on u is give the restriction on x
X is bounded below by 0, and so is u
 
Calculus 1 was easy. No wonder people said calculus was hard. Calc II is awful.
 
Because sqrt is a strictly increasing function, you know you're all good and no tomfoolery may occur where u goes negative when it isn't supposed to
Yeah calc the second bites everyone in the bottom it seems.
 
@10Replies enjoy diff eq.
 
Calc 3 is easier I think.
Diffy q is love, Diffy q is life
 
3:03 AM
@nitsua60 I'm hoping that wasn't sarcasm, but, if it was, I'm planning on not taking more calc as I want to major in CS.
 
My degree is in physics, odes and pdes are in my sleep
 
Nothing'll make sure you understand I and II better than the method of froboenioueus =)
(I'm pretty sure I spelled that right.)
 
Well, for a good cs program, you need calc 1-3, Diffy q, and linear algebra
Plus a discrete mathematics course
 
I have looked at the requirements and the ones I want to attend don't need diffyq or calc 3
 
If your program doesn't require that, do it anyways.
2
 
3:04 AM
I already took linear algebra. That was a fun class.
 
That's my bottom line advice.
 
Lets see if I pass calc II first.
 
If you have a cs major and can't whip up a sim of the strange attractor in an hour, you suck.
 
@logical123 I get to teach Griffith's intro QM this term--I'm super-excited =)
 
No need to understand the strange attractor, but that project is super easy.
I love that text.
 
3:05 AM
Differential equations? Eh... I've had about 2 weeks of them and I'm not terribly fond lmao
 
@logical123 That was the one that took me beyond "this is my subject" to "these are my volk."
 
I wrote a 3D engine with linear algebra. I'll have to google what a strange attractor is... after I finish my calc II homework thats due in 1 hour
 
I am supposed to be learning ODE's
 
Well, my ap calc teach in high school literally said the universe is one big differential equation.
 
@nitsua60 I've read a few pages of that book. Was nice.
 
3:06 AM
Just to see who would look into them
The world is associated with change. We model things with derivatives and equality, so naturally solving models of the world requires an understanding of these... differential equations
 
@nitsua60 oh hey, me too
well, TA for it
 
@Semiclassical Sweet =)
 
mostly i'm just happy about the workload
 
@BalarkaSen, will you please look at (this)[math.stackexchange.com/questions/2421663/… question?
 
Wait a minute... how many of us are actually physicists just hanging out in the math-lounge?
o/
 
3:08 AM
lol
 
I appreciate ODEs, don't get me wrong, just that it's not something I enjoy spending my time doing
 
I'm definitely in that category.
 
I'll count that ^^ as a o/
 
Secret does computational chemistry, which I'll count as close enough for this purpose.
 
@Semiclassical Oh yeah. The P Chem colloquia were held in the physics complex in grad school, because so many more physics-people were interested in attending than were the chem-people.
 
3:10 AM
Oh huh, I knew he was into chem of some sort but I didn't know it was computational. That stuff sounds pretty nifty
 
hah
well, 'computational chemistry' isn't very descriptive
I know he does DFT calculations, though
 
(Then someone set up a slackline between the two buildings. I don't know if that encouraged or discouraged the chem-folk from coming over?)
 
@Silent I don't think you need the increasing hypothesis. It comes to play in higher dimensions, where to do change of variables you must compose with an actual diffeomorphism, I think.
 
I honestly don't know what I am lol.
 
Same lol
 
3:13 AM
I have a physics major and math minor but was reading grad level material on atmospheric sci my sophomore year, and right now I have a database dev internship
 
@Daminark a higher category theorist?
 
Don't bring categories... OR SHEAFS... into this place
 
@BalarkaSen yesterday a comment appeared saying that $g$ must be injective. Is that necessary?
 
I don't see any such comment.
You don't need injectivity or even monotonicity in one dimensional change of variables.
 
@10Replies the strange attractor is a fractal like Chaotic system
 
3:15 AM
@BalarkaSen That comment was taken down
 
@Daminark
 
@BalarkaSen @Silent I think you're both overthinking it.
 
@nitsua60 how?
 
That hypothesis allows the author not to futz about the ordering of endpoints of the interval in sentence 2.
 
@Secret Am I right in calling you a computational chemist? I vaguely remember DFT stuff
 
3:16 AM
If the room is filled with physics people, mind if I ask what y'all got on the physics gre?
 
@Semiclassical Indeed I am a computational chemist because I have some experience with ab inito and DFT calculations
 
whats a gre
 
I want to say 70th percentile
 
@nitsua60 Yes, but that's easy to deal with.
 
but that was back in 2010
 
3:17 AM
?
 
though I usually just said I am a computational and organometallics chemist PhD
 
@BalarkaSen Yeah, but they don't. The monotone hypothesis lets them just slap it down and not get into the interval.
 
There wasn't much overthinking on my part; in one dimensions there is no need for monotonicity and the sort, just differentiability suffices.
 
I got 54th, but that was a 720/990 which is usually a decent score
 
in high dimensions you get rekt precisely because of what you said
 
3:18 AM
monotonicity makes things easier, though.
 
@Balarka I mean I like the categorical mindset for sure but I'm really closer to a number theorist, also I might end up getting into theoretical compsci
 
I basically knew nothing about atomic and particle physics on the test.
 
@logical123 tbh, very high 90s.
 
I'm still in highschool. Rip.
 
@Faust GRE is basically the grad school SAT
 
3:19 AM
@Daminark Learn this and teach it to me, then :)
Categorical quantum mechanics is the study of quantum foundations and quantum information using paradigms from mathematics and computer science, notably monoidal category theory. The primitive objects of study are physical processes, and the different ways that these can be composed. It was pioneered in 2004 by Abramsky and Coecke. == Mathematical setup == Mathematically, the basic setup is captured by a dagger symmetric monoidal category: composition of morphisms models sequential composition of processes, and the tensor product describes parallel composition of processes. The role of the dagger...
 
I had and have a very nontraditional path in education lol
 
@Semiclassical Sure. The question was if I need it. I don't :)
 
do they do the same thing for math?
 
Working 35 hours a week plus 4 classes, studying for the gre was a bit on the back burner lol
 
@10Replies when I say I'm a ____, I mean more like, I'm into it. I'm an undergrad, and we've got a few people here who are high schoolers as well
 
3:20 AM
Yes, there is a math subject gre
Chem and bio
 
@Daminark HoTT then
 
wierd
 
They axed the cs one about 5 years ago
 
wonder if they do it in canada
 
@Semi that sounds cool as shit
 
3:21 AM
@logical123 We had pretty serious comps in undergrad (28 hours written and 2 hours oral all in one week), so senior year was basically six months of studying punctuated by brief trips to visit grad schools. And studying on the plane.
 
I'll admit, I mostly find it interesting to read that stuff because it comes with diagrammatic calculations :)
 
I mean, you pretty much have to take the general gre to get into any grad program in the states
 
i see
 
The general is literally the grad school version of the sat/act
 
merica
 
@Daminark You might find this interesting if you've got time: math.ucr.edu/home/baez/rosetta.pdf
 
@nitsua60 yeah I went to uiuc for one year, couldn't afford it, took a year off and worked a delivery job then paid for the rest of undergrad working and schooling, at a small unranked public on the north side of Chicago
I was the curve breaker in every single class, needless to say lol
 
oh yeah you guys have spencive schools
 
Lmao nice, rub it in.
 
student debt is a harsh mistress
 
3:25 AM
any debt is.
 
im over half a mil in debt m8
 
did you click the link
 
I'd like a diagram that drew all feymann diagrams with the correct contribution all at once, just like how instead of drawing resonance contributors in chemistry, one can drew the overall structure with dotted line bonds
 
Yummy, I don't envy you. Sounds like my parents. I'm like 60k in
 
@BalarkaSen I did. and then I backed away.
 
3:26 AM
well i didnt say what my nw was :P
 
I'm 0k, but, I also have no money, so theres that.
 
They made exactly enough to get no aid for my ed, which is a common occurrence in the lovely 'murica
 
@Semiclassical the n-point of view is mind blowing, indeed
 
i was thinking of maybe working down there when im done all my schooling
 
tbh I mostly view QFT in general as black magic though
 
3:28 AM
I dunno how it works
 
Most of physics is black magic.
 
@Silent well, I posted my first answer here--hope it goes okay. (cc: @BalarkaSen)
 
Spontaneous symmetry breaking hooha coupling stuff to other stuff
 
I should learn some physicist's gauge theory
 
eh, spontaneous symmetry breaking isn't bad
 
3:29 AM
There's not many sources that I know unfortunately
 
I know it isn't that bad, its just spooky
@10Replies finish the problem set yet? Calc 2 integrals are my favorites lol, so many tricks
 
No ;(
 
Go go go, 29 min left I assume
 
@nitsua60 I gave a +1
 
Stupid webassign
 
3:31 AM
Yup
 
@BalarkaSen Aw, shucks. I'm blushing. (You just can't tell under the wool.)
 
I got lucky and had an old school teacher for ap calc in high school, and my calc 3 and diffy q were honors level at uiuc so, absolutely no webassign
 
Homework is only 10% of my grade, so if I get like a 70% on homework it shouldn't be too bad.
I'm hoping the homework is super hard compared to the tests and quizzes
 
Yeah that wouldn't be a disaster but I'm not your teacher, idk how devilish they can be.
@nitsua60 what is your favorite chapter in Griffiths?
 
most of my crap nowadays is just hw weight
 
3:35 AM
It's a college class, I don't really interact much with the professor, so I hope he isn't evil
 
i got 2 classes with 60% hw weight
 
RIP in pieces
damn
 
and one of them has 3 take home midterms on top of that no final
 
@logical123 No recollection! It's probably been about fifteen years since I cracked it open! And I start class on Wed!
 
Hahahahaha brilliant.
 
3:36 AM
(Dear students in the room: you're not the only procrastinators in your classroom.)
 
I like the operators chapter, especially the raising and lowering section
Oh boy, I actually got into it with a prof once because of that
 
@logical123 I didn't even remember that Griffiths got that far--I think of Sakurai when I think of raising and lowering operators.
 
@nitsua60 i caught my analysis prof with a mistake today in proving the rational zeros theorem i know =)
 
Sounds lime you used the old edition.
 
Is it Griffiths' QM or E&M that gets heavy into Green's functions? It must be QM, right? If so, that was definitely my least favorite chapter at the time. (I'm fine with them now, but tackling Green's for the first time...? Ugh.)
 
3:38 AM
My prof raged at the class because of procrastination, and later I was cracking wise in another classroom to a few classmates about how he can yell at us for not finishing the p set but if he gets an exam back in 5 weeks it's a miracle.
E/M
 
ah, green's functions...ugh
 
I don't recall any greens in qm at all in his book
 
what's green's functions again
 
there not that bad
@Semiclassical think christ aweful symbols thats bad
 
$LG(x,x')=-\delta(x-x')$
 
3:39 AM
Yeah
 
oh so they're not really functions
 
Green's functions show up in quantum mechanics when you do scattering theory
 
Solutions to the impulse response
 
gr8
 
Is the most basic answer I can give
 
3:40 AM
(where $L$ is some differential operator above)
 
'Some'
Yeah greens are funky, but their use is far reaching.
It's not just qm, signal processing uses em
 
what's funny is how easy the simplest green's function is
 
I don't really know how distributions work in real life
 
$\nabla^2 \phi = \delta^{3}(\vec{x}-\vec{x}')$---oh hey, a point charge generates an electric potential
@balarka In the case of Laplace's equation in 3D without boundary conditions, Green's function is literally just the electric potential of a point charge.
 
Most indubitably
 
3:43 AM
it's boundary conditions which make life miserable, alas
that's my recollection from Jackson anyways.
 
Matching solns at boundaries is jackson
Indeed.
 
Oh, Jackson. It's on my bucket-list to re-work Jackson on my own. Because I didn't pay it the proper respect the first time.
I have memories of rectangular wave-guides that largely block out anything else =\
(Oh, and memories of going skiing when I should have been spending more time with Jackson.)
 
"The algebra is tedious but straightforward."
 
@Semiclassical I see. Doesn't the Gauss's law tell me that the PDE corresponding to the electric potential of a test charge considered as uniformly distributed over a Gaussian surface in the 3-space given by $\nabla^2 V = \rho/\epsilon_0$? I guess that's the thing there
 
Right.
 
3:48 AM
In any case, sorry to hijack the physicists-pretending-to-be-mathematicians room with a physics discussion. It's been fun, but I'm off for the night. Be well, all!
 
Except you're making the limit of the radius of the Gaussian sphere to be 0.
@nitsua60 See you.
 
well, you're taking the charge density to be a delta function. so yeah, can make the gaussian sphere as small as you want without ever getting inside the charge
 
Gotcha. I get triggered by delta function not really being a function :P
It's limit in the approximate identity sense I suppose
 
And because you end job with the delta in this situation, it is a greens function, because the delta is exactly the impulse he spoke of.
 
Makes sense.
 

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