I have a large document with multilevel numbered headings
4.1.7. Level 3 heading
4.2. Level 3 heading
4.2.1. Level 3 heading
I noticed that 4.2. level 3 heading there that really should be level 2 heading. I changed it to level 2 by using the appropriate style.
Then the "4.2.1" change...
Good morning.... I've recently learned about oxidation states in class, and something was not clear to me: H_2O_2 has a net oxidation state of 2*+1, and 2*-2 leading to an unbalanced oxidation state correct?. If that is the case... then what are the other possible oxidation states of H/O... and where can I find the oxidation states for the rest of the elements?
This is a list of known oxidation states of the chemical elements, excluding nonintegral values. The most common states appear in bold. The table is based on that of Greenwood and Earnshaw, with additions noted. Oxidation state 0, which occurs for all elements, is implied by the column with the symbol of the element. The format of the table, which was devised by Mendeleev in 1889, shows the periodicity of the oxidation states of the elements.
== List ==
A figure with a similar format (shown below) was used by Irving Langmuir in 1919 in one of the early papers about the octet rule. The periodicity...
thus, knowing the exact discrete oxidation states that each compound can take on becomes critical, because H 2*+1, and O 2*-2 becomes unbalanced and breaks the machine ^
> "Oxidation state" is defined as the charge an atom might be imagined to have when electrons are counted according to an agreed-upon set of rules:
1. the oxidation state of a free element (uncombined element) is zero 2. for a simple (monatomic) ion, the oxidation state is equal to the net charge on the ion 3. hydrogen has an oxidation state of +1 and oxygen has an oxidation state of −2 when they are present in most compounds. Exceptions to this are that hydrogen has an oxidation state of −1 in hydrides of active metals, e.g. LiH, and oxygen has an oxidation state of −1 in peroxides, e.g. …
You probably meant dimolybdenum.
Its electronic configuration is given in Dimolybdenum: nature of the sextuple bond, Bruce E. Bursten, F. Albert Cotton, Michael B. Hall, J. Am. Chem. Soc., 1980, 102 (20), pp 6348–6349:
$$\ldots\mathrm{
9\sigma_g^{1.88}
5\pi_u^{3.78}
2\delta_g^{3.42}
10\sigma...
this is to eliminate computing things that don't need to be computed ;)
So there are 5 assignments to the pair of (C,O) in CO: [ (0,0), (-1,+1), (-2,+2), (+1,-1), (+2,-2)] which would be the 'correct' assignment of oxidation states?
@roscoe_casita The oxidation number of a free element is always 0. The oxidation number of a monatomic ion equals the charge of the ion. Fluorine in compounds is always assigned an oxidation number of -1. The alkali metals (group I) always have an oxidation number of +1. The alkaline earth metals (group II) are always assigned an oxidation number of +2. Oxygen almost always has an oxidation number of -2, except in H2O2 (when it is -1) and in OF2 (when it is +2). Hydrogen has an oxidation number of +1 when combined with non-metals, but it has an oxidation number of -1 when combined with metals.
I don't know if all the statements are true everytime
Wrong statements: The alkali metals (group I) always have an oxidation number The alkaline earth metals (group II) are always assigned an oxidation number of +2. Oxygen almost always has an oxidation number of -2, except in H2O2 (when it is -1) and in OF2 (when it is +2). Hydrogen has an oxidation number of +1 when combined with non-metals, but it has an oxidation number of -1 when combined with metals.
DHMO, the point is, it's fun showing off inaccuracies, but what you, I, and everyone else is studying is an approximation of reality, so after a certain degree, it becomes meaningless.
@Loong I think I still have that answer somewhere, but I saw there wasn't a hype at the time to write canonical posts, and MS word kept messing with SE's editor. I'm ready to finish it whenever we start writing some canonical posts in an organized manner.
Well when I worked at GIVAUDAN when I had to make samples for an order, it was possible from the software to create the software to ask at the maxium 5000 samples. We cannot use any engin to help us. So 5000 samples doesn't make sense for that. So here I'm asking for the num of a pseudo. If I put 5000 caraters if you "@" me it will flood the chat lol
Hi Josh, and welcome to Chemistry Stack Exchange! On homework questions, we usually prefer to give a hint rather than a direct solution… — F'xOct 25 '12 at 7:27