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02:00 - 16:0016:00 - 22:00

4:00 PM
@DHMO But I need it to stay at level 3
It's subordinate to heading 4.2
 
@CowperKettle what do you want it to become?
make it level 2, and then level 3 again
 
@DHMO It worked for it, but all the rest of the level 3 headings did not follow the numbering
 
@CowperKettle then do it again on the rest of the level 3 headings
 
What's the point of it all then?
I might as well print it by hand
 
@CowperKettle I thought you can just select all and then shift-tab
 
4:08 PM
@DHMO "Extended Hückel" is no good method today ... better search for some multiconfigurational methods
 
@pH13-YetanotherPhilipp ok
 
@DHMO they are dispersed across dozens of pages
 
@CowperKettle then you might as well print it by hand
 
Thank you, Microsoft, for automatic numbering
Here it is.
0
Q: Multilevel numbered headings in Word 2007

CopperKettleI have a large document with multilevel numbered headings 4.1.7. Level 3 heading 4.2. Level 3 heading 4.2.1. Level 3 heading I noticed that 4.2. level 3 heading there that really should be level 2 heading. I changed it to level 2 by using the appropriate style. Then the "4.2.1" change...

 
4:26 PM
@Loong yes it is :)
The teacher told me I can buy it to sigma aldrich
yield = 95% and 99.97 of purity
That's not so bad
@Hippalectryon comment vas-tu? (how are you?)
 
@9-BBN Ca va et toi ?
 
Ca va, tu es à l'ENS du coup ?
 
@9-BBN Non à l'X finalement, c'est compliqué >.>
 
4:41 PM
What does "2" mean in $2\delta_u$?
@Hippalectryon
 
@DHMO in what context ?
 
@Hippalectryon molecular electronic configuration
 
I've never seen $\delta_u$ used for that so I'm not sure
 
@Hippalectryon Then what does the "9" in $9\sigma_g$ mean?
 
second MO of such symmetry
or ninth
or whatever
 
4:42 PM
never seen $\sigma_g$ either :( we didn't use those notations
 
@orthocresol ok, thanks
 
I didn't do any group theory
 
@Hippalectryon you use something like $\mathrm{a_1}$?
 
just $\sigma_1,\sigma_1^*,\pi_1,\dots$
 
I see
Basically, $\sigma_g$ and $\pi_u$ and $\delta_g$ are bonding, while their opposites are anti-bonding, right? @orthocresol
 
4:45 PM
@9-BBN very good :-)
 
For diatomics, yeah.
 
@orthocresol ok, thanks
@orthocresol for 0 electron density, do you mark 0 or mark nothing?
$5\pi_g^0$
 
$(5\pi_g)^0$
 
but for other numbers you don't need the parentheses?
 
but you would only do that if you are trying specifically to show
that it is empty
 
4:52 PM
ok, thanks
 
theoretically, everything should have paentheses
 
well...
 
Good morning.... I've recently learned about oxidation states in class, and something was not clear to me: H_2O_2 has a net oxidation state of 2*+1, and 2*-2 leading to an unbalanced oxidation state correct?. If that is the case... then what are the other possible oxidation states of H/O... and where can I find the oxidation states for the rest of the elements?
 
@roscoe_casita no, each O has -1 oxidation state
H can be -1, 0, or 1
O can be -2, -1, 0, 1, or 2
 
@DHMO interesting. Are these standard tables that can be looked up somewhere?
 
4:55 PM
This is a list of known oxidation states of the chemical elements, excluding nonintegral values. The most common states appear in bold. The table is based on that of Greenwood and Earnshaw, with additions noted. Oxidation state 0, which occurs for all elements, is implied by the column with the symbol of the element. The format of the table, which was devised by Mendeleev in 1889, shows the periodicity of the oxidation states of the elements. == List == A figure with a similar format (shown below) was used by Irving Langmuir in 1919 in one of the early papers about the octet rule. The periodicity...
 
hmmmm alright
@DHMO the project I've been working on is to 'build a better battery... equation generating machine' in software
 
@roscoe_casita I fail to see how the two link together
 
so far it now builds balanced, whole equations.
Given a set of compounds, generate ALL of the reactions
the next step is to filter the reactions to only redox reactions
so given a complete whole reaction (no ions or charges), determine if the reaction is a redox reaction given usage of oxidation state numbers
changing*
 
ok
 
thus, knowing the exact discrete oxidation states that each compound can take on becomes critical, because H 2*+1, and O 2*-2 becomes unbalanced and breaks the machine ^
 
5:02 PM
maybe the machine gets oxidized
 
I try to avoid lookup tables, as they tend to be incomplete...
 
knowledge is incomplete ...
 
given these tables...
H_2O_2 can take on {H:2*+1 and O:2*-1} or {H:2*-1 and O:2*+1} ?
 
@roscoe_casita if I say yes, many people would fight me
but I still say yes.
 
@roscoe_casita next thing to learn is electronegativity
 
5:06 PM
well, yeah, those tables don't tell you anything
 
@roscoe_casita the oxidation states of the same elements can be different
 
it could be 0 and 0 for all you know
 
electronegativity is what decides the oxidation states
 
for example, in Na2S2O3:
Na1 = +1
Na2 = +1
S1 = 0
S2 = +4
O1 = -2
O2 = -2
O3 = -2
notice that S1=0 and S2=+4
 
5:06 PM
the element who is more strongly electronegative gets to be in the more preferred
state?
 
@roscoe_casita no, the more electronegative element gets to be in the more negative state
 
@DHMO this is bad news for my program... that is combinatoric
in nature
@DHMO k, so if I was partitioning a compound into a set of oxidation states
then start with the more electronegative elements, and assign them the 'more' negative state
 
oxidation state is kind of my (and everyone here's) second nature...
I don't really know how I derive the oxidation states
 
@DHMO hrmm, understand.
yeah, I'm reading up on the fractional oxidation states... what exactly is oxidation state?
 
> "Oxidation state" is defined as the charge an atom might be imagined to have when electrons are counted according to an agreed-upon set of rules:

1. the oxidation state of a free element (uncombined element) is zero
2. for a simple (monatomic) ion, the oxidation state is equal to the net charge on the ion
3. hydrogen has an oxidation state of +1 and oxygen has an oxidation state of −2 when they are present in most compounds. Exceptions to this are that hydrogen has an oxidation state of −1 in hydrides of active metals, e.g. LiH, and oxygen has an oxidation state of −1 in peroxides, e.g.
 
5:12 PM
well... there isn't a lot of combinations
easy enough to enumerate all possible combinations of all atoms in a compound, and find the set that works correctly
 
@roscoe_casita see how that works with OF2
 
yeah, F is -1, O +2
 
nice
HOCl?
 
Cl -1, H -1, O +2 ?
 
@roscoe_casita nope
 
5:14 PM
hmmm, I don't like that because O is more electronegative
Cl : +1, H +1, O -2
 
brilliant
KMnO4
@orthocresol is it better now?
1
A: What is Bimolybdenum's hybridisation?

DHMOYou probably meant dimolybdenum. Its electronic configuration is given in Dimolybdenum: nature of the sextuple bond, Bruce E. Bursten, F. Albert Cotton, Michael B. Hall, J. Am. Chem. Soc., 1980, 102 (20), pp 6348–6349: $$\ldots\mathrm{ 9\sigma_g^{1.88} 5\pi_u^{3.78} 2\delta_g^{3.42} 10\sigma...

 
O: -2, K: +1, mn, +7
 
@roscoe_casita nice
CH2Cl2
 
@Hippalectryon te plains pas tu n'es pas dans la plus mauvaise école.. vous faites de la chimie à l'X ? Non vraiment ? :P
 
Cl: -1, H+1, C: 0
 
5:16 PM
@Loong thank you
 
nice
 
damn
yeah, enumeration is going to be the quick way
 
what is enumeration?
 
[Na(2,2,2-crypt)]Na ?
 
so say you wanted to 'calc' what the oxidation states where of CH2CL2
 
5:17 PM
What about Na :P
 
you have a list of oxidation states for C, H, Cl
so you try assigning C to one of them H to another, Cl to another
check if it balances to 0
then try changing one state, check again
so its {elemental oxidation states}*{elements}*{number of elements in compound}
exponential in nature
 
@roscoe_casita maybe I tell you how I derive
 
aye, that would be a good heuristic
 
I derive by mentally picturing the structure (which I don't know how your program can do)
because enumeration would fail for large compounds like CH3CH=CHCOOH
 
I think you're correct
go on
 
5:21 PM
@roscoe_casita i finished my speech
 
@roscoe_casita you can also check with the electronegativity of each atoms
For example with NaH chi(Na) < chi (H) then Na+ with H-
 
hmmm actually its pretty small
CH3CH=CHCOOH ~= (4*9)*(4*3)*(2*5)
~4320 combinations of oxidation states,
one is right, pick that one,
 
how do you know which one is right?
 
check them all.
100,000 reactions/ 1 second currently,
 
check them all for what?
what is the criteria?
 
5:25 PM
that the oxidation states internal to a compound sum to zero
 
only that ?
 
aye, but now you have an assignment of oxidation states to atoms
you can do that for all compounds ones, then store the results
then in a given reaction, look up the assignment of oxidation states, and determine if the reaction is a redox
this is great, thank you all =)
 
What about carbone monoxide ?
 
5 possible zero assignments ;)
 
Does your prgm give the good answer?
 
5:27 PM
@roscoe_casita and what would be the best then?
 
that is a question i don't know how to answer
so of the possible 5 assignments what would be the correct one?
 
Then one who respect at least the quantum chemistry
:P
 
lol, aye, but I'm not at that level yet
this is to eliminate computing things that don't need to be computed ;)
So there are 5 assignments to the pair of (C,O) in CO: [ (0,0), (-1,+1), (-2,+2), (+1,-1), (+2,-2)] which would be the 'correct' assignment of oxidation states?
I assume O would default to -2, and C to +2
but why?
 
Remove +2 for the oxygen lol
 
and can we just use the list of electronegativities to assign from this set of possible states?
 
5:31 PM
Because we tell them to.
 
@9-BBN quoi?
 
why @9-BBN ?
 
oxygene est +2 en OF2
 
If you have CO
 
there are some 60k + compounds in the database
think in general, the assignment is possible just not logical
but the electronegative rules would determine that
alright
 
5:33 PM
You can also do something else
 
such as?
 
Check with the electronegativity and make a list from the most probable (which one respect the electronegativity) to the less at first time
 
alright @9-BBN I'll keep thinking on this (this is a years long project by the way... here is some picture of the current state)
 
But if you have CO I guess you'll have troubles without quantum chemistry
 
@9-BBN classically it is explained by 2 double bonds plus 1 dative bond
 
5:36 PM
with electronegativity as the assignment prioritizer, it is possible to extract a single 'correct' value from the list of possible assignments.
 
or if you prefer to use formal charges, -C=O+
 
alright, keep it easy all.
thanks you for the help!
 
@roscoe_casita what the hell are those (non-)compounds?
 
@DHMO i do not like your representation
 
@roscoe_casita Are you supposed to untie this knot or something?
I'm not gonna help with that.
 
5:37 PM
@9-BBN I didn't advocate for that representation; I'm just saying how it would be represented classically
 
@9-BBN I do not like your lack of capitalization
 
And there is a triple bonds between C and O
@Rubisco capitalization ?
 
@9-BBN Yes, I meant -C#O+
 
@9-BBN 'i' -> 'I'
 
@DHMO they came from this database: materialsproject.org
 
5:39 PM
In France we right no capital letters in sentences expect at the begining
 
@Rubisco this is a small view of the hypergraph / reaction network of all possible reactions for the given set of compounds
 
@roscoe_casita I have never seen anything resembling H24O12
 
I think they represented H2O that way,
I don't know why
 
@roscoe_casita you can also check octet rules for elements before Neon
 
alright
 
5:41 PM
And duet for hydrogen and helium
 
thanks again, back later ;)
 
@9-BBN duplet, because English
 
duplet
 
I like duet better
 
French is better sure
 
5:43 PM
German is betterer
I'm definitely not saying that to get more votes.
Definitely.
 
Anataha Rubisco san desuka? :P
Japanese quite good too
 
Anata wa.
I mean, I know you write/type it with ha
 
We pronounce "wa" but we write "ha"
When you say "watashiha" the "ha" is pronounce "wa"
 
I know.
But when you are writing it out in romaji it should be wa.
 
Oh OK ^^
 
5:49 PM
I've always seen it that way, at least.
 
I never have written in romaji
 
@9-BBN No swearing in this chat
Oh God. Somebody save me from Japanese geeks.
They're even worse than Japanese geeks.
 
@Rubisco do not refer to religion in this chat thank you
Yeah I've ever been modo :P
 
Flags itself as abusive
 
LOL
I forgot to say please
@roscoe_casita The oxidation number of a free element is always 0.
The oxidation number of a monatomic ion equals the charge of the ion.
Fluorine in compounds is always assigned an oxidation number of -1.
The alkali metals (group I) always have an oxidation number of +1.
The alkaline earth metals (group II) are always assigned an oxidation number of +2.
Oxygen almost always has an oxidation number of -2, except in H2O2 (when it is -1) and in OF2 (when it is +2).
Hydrogen has an oxidation number of +1 when combined with non-metals, but it has an oxidation number of -1 when combined with metals.
I don't know if all the statements are true everytime
IfChemDraw do it, hack it :P
 
5:54 PM
Wrong statements:
The alkali metals (group I) always have an oxidation number
The alkaline earth metals (group II) are always assigned an oxidation number of +2.
Oxygen almost always has an oxidation number of -2, except in H2O2 (when it is -1) and in OF2 (when it is +2).
Hydrogen has an oxidation number of +1 when combined with non-metals, but it has an oxidation number of -1 when combined with metals.
 
@DHMO And these are wrong, why?
 
Then @DHMO will give you exhaustively all cases in which this is false
 
1. alkalides
2. https://en.wikipedia.org/wiki/Low_valent_magnesium_compounds
3. − 1⁄2 (superoxides), − 1⁄3 (ozonides), 0 (elemental, hypofluorous acid), + 1⁄2 (dioxygenyl), +1 (dioxygen difluoride), and +2 (oxygen difluoride).
4. NaBH4
@9-BBN why am I so predictable
 
@9-BBN That's boring.
Exhaustively boring.
@DHMO Good luck ever finding alkalides.
 
@Rubisco It has been produced
 
5:57 PM
With informatic everything is fast but if some of these statements are true it will be faster sure
 
@DHMO Have you?
 
@9-BBN superoxides are not uncommon
@Rubisco Have I what?
 
DHMO, the point is, it's fun showing off inaccuracies, but what you, I, and everyone else is studying is an approximation of reality, so after a certain degree, it becomes meaningless.
@DHMO Seen, or produced alkalides.
 
@Rubisco superoxides are not uncommon
 
Aug 23 '15 at 21:18, by inɒzɘmɒЯ.A.M
I'm writing an epic answer about oxidation states. The curious may see my progress here.
 
5:59 PM
@Loong IKR . . . Kids these days
 
Aug 23 '15 at 21:19, by inɒzɘmɒЯ.A.M
Holy moly indeed; I've written 149 paragraphs?!
 
in g-block elements, Sep 28 '15 at 11:25, by Loong
Don't fret! I'm trying to write (a) canonical answer(s) to this question, will hopefully get it done tomorrow. — inɒzɘmɒЯ.A.M Aug 21 at 20:28
 
@Loong what is the question?
@Rubisco No, I have not.
 
@DHMO "What is Oxidation Number?"
 
@Loong deleted
 
6:01 PM
yes, deleted by Community♦
 
@Loong I waited desperately for this answer ...
 
@Loong I think I still have that answer somewhere, but I saw there wasn't a hype at the time to write canonical posts, and MS word kept messing with SE's editor. I'm ready to finish it whenever we start writing some canonical posts in an organized manner.
 
@pH13-YetanotherPhilipp I still do. ;-)
 
@Loong whatever "zu Recht" would translate to ...
 
@Loong HEY
@pH13-YetanotherPhilipp Justifiably
But that doesn't make sense.
Or maybe it doesn't make sense at this time of the day
 
6:06 PM
maybe with great justice
@DHMO are those orbital pictures in your answer for free use?
 
@pH13-YetanotherPhilipp no idea
 
then I’d say you better find out
 
@pH13-YetanotherPhilipp if not, should I just use the original link instead?
 
you should find some 4d orbitals with an appropriate license if not
 
@pH13-YetanotherPhilipp the thing is, they're hard to find
 
6:29 PM
@Rubisco I guess what I did a couple of weeks back was kind of a trial.
These things seem to be well-received and two of them also received alternative answers
Which is a good thing
 
@orthocresol What did you do?
Everyone, what did he do?
ಠ_ಠ
 
I suspended your account.
 
Oh my God. Then I'm a ghost.
I can prolly pass through . . . ouch.
 
Or, to be precise, that is the first thing I will do at 9 p.m. on Tuesday.
 
Phew.
I have a few days before becoming hollow.
Until then, I can keep catalyzing things happily.
 
6:34 PM
hmm
 
@Loong NO!1! VOTE FOR ME! THIS IS LIFE AND DEATH NOW
 
6:47 PM
youtube.com/watch?v=qO8yfBLNVjU the second movement is known and so good to here after the first one sure !
 
What
 
Listen and shut up :P
Beethoven wants respect
 
@pH13-YetanotherPhilipp Nom nom
 
@DHMO If I was not doing something wrong, this should be 4d orbitals.
 
6:51 PM
I have something to confess
 
of hydrogen ... of course
 
@9-BBN That you didn't vote for me? Gets ready to kickmute
 
I began to watch Breaking Bad yesterday
 
Yep, I should kick him.
 
Is there a limit to the size of a pseudo?
 
6:54 PM
P-what?
 
@9-BBN I think, it's 30.
 
Well when I worked at GIVAUDAN when I had to make samples for an order, it was possible from the software to create the software to ask at the maxium 5000 samples. We cannot use any engin to help us. So 5000 samples doesn't make sense for that. So here I'm asking for the num of a pseudo. If I put 5000 caraters if you "@" me it will flood the chat lol
I'm evil
to create the order*
 
Hi Josh, and welcome to Chemistry Stack Exchange! On homework questions, we usually prefer to give a hint rather than a direct solution… — F'x Oct 25 '12 at 7:27
 
@orthocresol I saw that.
 
Times have changed..
 
7:06 PM
flaggedthis comment belongs on math.stackexchange
 
7:50 PM
@Loong If I were a mod, I would've migrated it without second thought.
Vote for me.
 
 
1 hour later…
9:10 PM
!!TEA
 
Yay, we have tea again :D
 
02:00 - 16:0016:00 - 22:00

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