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00:27
Who would submit an AI-generated edit suggestion to code golf stack exchange as an anonymous account
Like if they were doing it for the rep why are they anonymous
and why that one specific answer?
then again stranger things have happened
like that one time some bingus posted a spam answer to "tips for golfing in Vyxal 3"
and used the readme in the answer
> Literate mode is designed to allow you to write papa's freezeria vyxal 3 programs in complete ascii while maintaining a SBCS score.
classic :p
 
3 hours later…
03:11
What's the strategy for connect-3(like connect-4, 3 in a row enough, gravity applies on both dimensions)?
03:36
@lyxal lmao I need the link
@lyxal I'm afraid I just blue myself
@emanresuA I think you forgot to remove the [1] earlier in the text - but also, shouldn't the whole thing be re-written, since it's just admitting to using AI which isn't allowed?
04:00
10k+ only link obviously
@noodleperson only unattributed ai content is explicitly banned on cgcc
Because of the inherited rule from the greater SE network
It's up to the site to ban or not ban attributed ai stuff
Attributed ai answers are explicitly not banned, questions, well that didn't get an explicit response but I imagine it'd be the same
8
Q: Should AI generated questions and or answers be banned?

lyxalRelevant discussion that inspired this question Questions and answers (content) generated by AIs like LLMs (e.g ChatGPT, Google Bard, character.ai) are not prohibited on the StackExchange network by default: With due consideration, we've decided no network-wide, general policy regarding banning ...

@lyxal Aha. Well, @emanresuA just removed the attribution :)
I'll roll it back, I guess.
I added it back because it wasn't completely useless :p
(as in I rolled it back myself before I saw you were going to lol)
04:09
Side note, why is it easier for <2+k rep to do a roll back on mobile from the edit page than it is for 2k+ rep?
To roll back with edit rights means to have to go to answer history and find the right revision
Without edit privileges, all accessible from the edit page
I'd like to also thank SwiftKey for autocorrecting well to we'll, despite the fact I changed it back
If I didn't have unlimited edits that'd be ever worse lol
@lyxal Aww ok
04:13
You don't have sufficient rep?
I'll screenshot for you then
Thanks
I am in awe
No you're user
I stand corrected
04:16
You stand as user
Not corrected
...
😎
04:41
@lyxal ... I really don't think providing a citation in that form is remotely useful, or something we want to encourage
05:08
@emanresuA Sure, but without it, it's plagiarism
(Arguably, plagiarism either way, but whatever)
... I guess :p
@emanresuA even though it's a questionable practice, it's necessary to allow the challenge to not be deleted
 
2 hours later…
07:09
CMC Output a sequence that sums to 1 and can be unordered paired that each pair sum to 0
07:39
@DLosc yes!
CMC I have a sorted list of positive integers I want to print. If there are three or more that are consecutive I want to show the interval as start-end. So 2,6,8,9,10,12 becomes 2,6,8-10,12. How golfed can you do this in python?
08:24
@mousetail yes, that's why it's either just trivial or it feels like 2 cchallenges in a trenchcoat
att
att
08:37
@l4m2 both dimensions?
@att aka they fall both down and left
att
att
depends on the size of the grid i think
@Simd not extremely golfed but better thhan anything i can come up with stackoverflow.com/a/52302366/7611125
0
A: Sandbox for Proposed Challenges

Mukundan314Count collisions in a python dictionary hashing python code-golf Task Given a list of integers as input, simulate Python's dictionary insertion process and count the total number of collisions that would occur. The process works as follows: Start with a hash table of size 8 For each number in th...

att
att
08:53
actually i might have a p1 wins strategy for ~4x4 up?
att
att
09:10
nvm
att
att
09:40
@Simd thought i had 69 but i read more closely and this is 76
@att is the {*a} conversion to a dictionary?
att
att
set
cool
att
att
there's a special ** for splatting dicts
69b also combines just two consecutive elements
10:39
for i in sys.stdin:print(i.rstrip(),'->',f(eval(i))) avoids the EOF error
for i in open(0): can be used to avoid the sys import
att
att
11:01
habit
 
2 hours later…
12:35
I believe cryptographic hash functions may be key to solving the P=NP problem.
I believe the time complexity for solving inverse Blake2b is O(256^n), where n is the number of bytes.
But the blake2b hash is definitely polynomial time
But if P=NP then this would imply all hash functions could be cracked in polynomial time
(And there goes your security)
 
1 hour later…
13:49
nice
all of that just so i'd give you an upvote
well actually see that for once wasn't the intention
14:13
@lyxal Very cool
 
1 hour later…
 
1 hour later…
17:04
0
A: Sandbox for Proposed Challenges

EzlandingRecently, in an Analysis class, I was tasked with proving that the dyadic rationals are dense in R (which can be proven by the archimedean property). The dyadic rationals are defined as: $$\left\{ \dfrac{m}{2^n} \; | \; m \in \mathbb{Z},\; n \in \mathbb{N} \right\}$$ Your Goal: for two real numbe...

 
1 hour later…
18:24
@att maybe I should make it a challenge
@Themoonisacheese pandas is cheating!
att
att
18:39
21
Q: Determine ranges from a list of values

Corey OgburnGiven an unsorted list of unique, positive integers, output the shortest list of the longest possible ranges of sequential integers. INPUT An unsorted list of unique, positive integers e.g. 9 13 3 11 8 4 10 15 Input can be taken from any one of the following: stdin command-line arguments ...

though that's 2+ and could use modernizing
19:20
@lyxal this is hilarious
@TheEmptyStringPhotographer this is exponential time tho, not polynomial
and cracking one function, even in constant time, may not necessarily mean that P=NP. see also: MD5, SHA-1
@att I fear having my challenge closed though. I am not brave enough
att
att
20:02
yeah i do think it'd be close enough to warrant closing
 
2 hours later…
22:06
Lucky I am a coward
22:46
@Seggan I know it is, I wasn’t trying to prove P=NP, but in fact the opposite

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