import time

test = 123456789123456789
temp = 0
N = 100000
pre_store = 10000

def rev1(n):
	r = 0
	while n:
		r = r*10 + n%10
		n //= 10
	return r

digit_reversal = [rev1(x) for x in range(pre_store)]

def rev2(n):
	r = 0
	while n >= pre_store:
		r = r*pre_store + digit_reversal[n%pre_store]
		n //= pre_store
	p = 1
	while p < n:
		p *= 10
	r = r*p + digit_reversal[n]
	return r

start = time.time()
for _ in range(N):temp = rev1(test)
end = time.time()
print(end - start)

start = time.time()
for _ in range(N):temp = rev2(test)

0.5310304164886475
0.2240128517150879
0.08000445365905762

def clear
  print "\e[2J\e[0;0H"
end

def get_cursor_pos
  print "\e[6n"
  line = ""
  char = '\0'

  while char != 'R'
    char = STDIN.raw &.read_char
    if !char.nil? && char != '\e'
      line += char
    end
  end

  line = line[1..-2].split(";").reverse.map(&.to_i)
  return line
end

clear
puts get_cursor_pos

#include <stdio.h>
#include <sys/time.h>
unsigned long rev(unsigned long n){
	unsigned long long res = 0;
	while(n){
		res = res * 10 + n%10;
		n /= 10;
	}
	return res;
}

int main(int a){
	struct timeval stop, start;
	gettimeofday(&start, NULL);
	unsigned long N = 4294967295L;
	unsigned long long normal = 0;
	unsigned long long reversed = 0;
	for(unsigned long n = 1; n < N; n++){
		normal += n;
		reversed += rev(n);
		if(normal == reversed){
			printf("%d\n",n);
		}
	}
	printf("%lld\n",normal);

1
2
3
4
5
6
7
8
9
12
86
89
9223372030412324865
6860253883396092805
took 226613 ms