As much as it's impossible to truly translate from one language to another by only translating word-for-word, it's even more impossible to "translate" by changing the letters from one alphabet to another. :P
@feersum Right, I see that now. You can come up with more extreme examples easily. But anyway, do you need the center of the circumcircle to be inside? Hmm, I guess you do. Is there a test case that has the circumcenter outside of the polygon?
I've found a trick to make a function that has a zero at the correct radius value whether or not the circle center is in the polygon, but it keeps converging to the wrong zeroes...
@cat It was deleted as part of the effort to remove [underhanded] from the site. Some of the closed challenges are getting deleted, some of the well received ones are getting locked.
@Doorknob clearly Z -> negative, ZZ...Z... rational where Z separates numerator and denominator in some order and ZZZ...Z... negative rational... (and it's always terminated by Z)
Cheddar:T_REPL> set A scope
Cheddar:T_REPL> enter A
Cheddar:T_REPL> set B 123
Cheddar:T_REPL> get B
123
Cheddar:T_REPL> exit
Cheddar:T_REPL> get B
Symbol(KEY_NOT_FOUND)
Let's say we are given a set of positive reals, and we're told that these are the edges of a convex cyclic $n$-gon, and we must compute it's area.
For $n = 3$ there is the famous Heron's formula:
$$A = {1\over 4}\sqrt{4a^2b^2 - (a^2 + b^2 - c^2)^2}$$
For $n = 4$ there is Brahmagupta's formula...
Let's say we are given a set of positive reals, and we're told that these are the edges of a convex cyclic $n$-gon, and we must compute it's area.
For $n = 3$ there is the famous Heron's formula:
$$A = {1\over 4}\sqrt{4a^2b^2 - (a^2 + b^2 - c^2)^2}$$
For $n = 4$ there is Brahmagupta's formula...
OCaml, 17 bytes
while 1<2do()done
1 byte removed thanks to @Mauris.
Another one bytes the dust thanks to @feersum.
