12:31 AM
@bobble well, that's a bit worrying

1 hour later…
1:53 AM
0

When all is shadowed, dark as night, Just look for me out in the light

3 hours later…
4:31 AM
@bobble I don't feel like I'm being "warned". I'm rather excited for this

It won't be out for at least a week - I take time to grid
(I'm guessing ~2 weeks, actually)

3 hours later…
7:19 AM
0

Let's have the equation \$(DX)^2-Y^2= ± Z^5\$ and \$x,y\$ two positive integers greater than zero. From some facts we can obtain solutions of the above equation by giving integer values at \$x,y\$. Examples: if \$x=11\$ and \$y=2\$ then we have the solution \$11*(641)^2-(2122)^2=7^5\$; if \$x=5\$ and \$y=2\$ ...

^ not sure why this question has got so many downvotes. It's quite a nice puzzle, notwithstanding the OP's insistence on (DX)^2 rather than DX^2.
Very little description given of the connection between all the numbers, but with just a little knowledge of one thing from elementary number theory, it's possible to reconstruct the whole chain of reasoning. I'd almost call it .
(also, hi people! been a while since I've popped in here)

0:

8:04 AM
0

Three prisoners are seated at a table. Each of them has a mobile phone on their lap, and they are not allowed to look at anyone else’s phone (and obviously no other form of communication is allowed). Each phone displays a number from 0 to 10 inclusive. They know no two prisoners have the same num...

6 hours later…
2:16 PM
0

Trying to solve this riddle: When all is shadowed, dark as night, just look for me out in the light. I know it's not a shadow, the sun, or the moon.

1 hour later…
3:30 PM
0

So from a couple other puzzles, you might remember that I'm a professor of Awesomeness at the Ad Hoc University! This time, I've given my students some numbers and their scorez. They need to tell me how I scored them! Here we are: 197 = 26 + 592 = 618 1 = 0 + 1 = 1 1337 = 44 + 8584 = 8628 43770 ...

7 hours later…
10:32 PM