« first day (1761 days earlier)      last day (3185 days later) » 

7:00 PM
@ACuriousMind ok, so we have to show $|a_n-a|$ is finite, right?
 
@0celo7 Uh...what?
You are not allowed to add or subtract infinite quantities in this setting
So it's either finite or it doesn't make sense to write it.
 
@ACuriousMind well if $a_n$ is unbounded, then $|a-a_n|$ is also unbounded
 
@0celo7 ...but that doesn't mean it's "infinite"
 
what
does bounded not mean finite
 
No.
Not in my world, at least
 
7:02 PM
bounded means finite only in physics books
 
jesus christ
I give up
I just can't do this
 
@FenderLesPaul ::shakes fist at physicists::
 
is it at least true that there must be some $b$ such that $|a_n-a|\le b\forall n$
 
@ACuriousMind offers ice cream as compensation for poor physics terminology
 
@0celo7 Yes, if $a_n$ is bounded, then so is $\lvert a_n - a \rvert$.
 
7:05 PM
@ACuriousMind ...literally what I said above
 
@FenderLesPaul ::devours icecream::
@0celo7 I didn't disagree with that statement, I disagreed with your use of "finite"
 
can you find me an unbounded set that does not have members that are nonfininte?
 
@0celo7 $\mathbb{R}$.
 
@ACuriousMind is infinity not a real number or something
because if it isn't just forget this
 
@0celo7 No, infinity is not a real number!
 
7:08 PM
fuck me
ok, to continue the proof
It looks to me like you can do the proof in Jost without using triangle
pick an $\epsilon$ and find the corresponding $N_\epsilon:\forall n\ge N_\epsilon\quad |a_n-a|<\epsilon$
then pick the bound $b=\sup\{|a_n-a|,\epsilon\} (n<N_\epsilon)$
@ACuriousMind ?
 
@0celo7 I'm not sure the supremum of what set you want to take here, I'm not certain what your notation is supposed to mean.
 
supremum of $|a_1-a|,\cdots,|a_{N_\epsilon-1}-a|,\epsilon$
 
@0celo7 Okay, why is this supremum finite (or rather, why does it exist)?
 
no clue
in the definition of convergent sequence, does $\epsilon$ have to be a real number?
or is that what we're trying to prove
 
@0celo7 Yes, the $\epsilon$ is a real number. What else could it be?
 
7:20 PM
@ACuriousMind $\infty$
 
@0celo7 Basically, unless it is explicitly stated, nothing in analysis is ever allowed to "be $\infty$".
 
Well then how is this not trivial????
If the god damn definition says it's bounded, why is this a fucking exercise
 
@0celo7 wat
Note that the bound in the definition of convergence does only hold above the $N_\epsilon$, so it doesn't mean the whole sequence is bounded
For this to be true, you must tell me why the supremum $b$ you defined there exists.
 
why would it not exist? each absolute value must be less than some $\epsilon$, which you told me are all finite
it they're all finite, just take the largest one!!!
 
@0celo7 Aha!
 
7:24 PM
what does that mean
 
The supremum exists because the set $\{\lvert a_1 - a \rvert,\lvert \dots,a_N - a \rvert, \epsilon\}$ has only finitely many elements, so we may just pick the largest element
 
of course
why would that not be the case
 
You couldn't simply say this if you were taking an infinite set
 
uh-huh
ok
 
(Methinks all the advanced math you know has somewhat spoiled you for the nitpicking that occurs in these "elementary" proofs)
 
7:27 PM
this is infuriating
 
@0celo7 I'm not trying to get on your nerves, but "why does this supremum exist" is a question I've been asked so often (whether it was actually trivial or not) that you should get used to stating things like "This supremum exists (as a real number) because the set is finite".
 
in that case, I guess I appreciate it
but this should not be so hard
and I'm not sure how I've been spoiled, I don't actually know much "advanced" math
nothing that requires as much thought as this, certainly
 
Okay, then it's the sloppy way physicists do proofs :P
 
probably
@ACuriousMind oh god there's a second part to 6.
@ACuriousMind you just use 5. for the second inequality and you have to redo 5. to find the first one?
 
@0celo7 Yep
 
7:39 PM
I'll do that in linear algebra
I want to do 7. and then I have to start homework
@ACuriousMind Ok. Since $b-a>0$, we may apply Lemma 1.2 to get a positive integer $q$ s.t. $q(b-a)>\sqrt{2}$. But if $qa,qb$ differ by more than $\sqrt{2}$, there must be some integer ($p$) multiple of $\sqrt{2}$ with $qa<p\sqrt{2}<qb$. The result follows upon division by $q$.
The fact that $\sqrt{2}$ is not rational is easy to prove.
 
@0celo7 Looks alright to me :)
 
@ACuriousMind Well that hint really gives it away.
lol 8.
FML
@ACuriousMind What's the general proof strategy here?
Doesn't this require me to know there are infinitely many primes?
 
@0celo7 No
@0celo7 I'd do a proof by contradicition - assume there are only finitely many rationals $r_1,\dots,r_n$ between $a,b$, then find a rational between $a,b$ that's none of the $r_i$.
 
7:56 PM
oo how do you do that without constructing each $r_i$
@ACuriousMind Oh. There is always a rational number between any two numbers.
Then $a<r_1<\cdots <r_n<b$ cannot be all of them because there is an $r'$ s.t. $r_n<r'<b$.
 
@0celo7 Exactly
 
Same for irrational numbers: there is always a third.
@ACuriousMind So reading the preface, it seems this is not meant to be a first course in analysis.
The book says a full year of analysis at the undergraduate level is expected.
@ChrisWhite Do you disagree? I know you recommended me this.
 
@0celo7 "In many respects it is a perfectly ordinary first course in analysis" and "I assume that the reader has had at least one semester of advanced calculus or real analysis at the undergraduate level."
One semester is not a full year, I don't know what exactly "advanced calculus" is.
 
Whoops, misread
@ACuriousMind proof writing
 
But yes, it does not seem to be an elementary introduction (seeing as how it tells you to "recall" the definition of a convergent sequence)
 
8:06 PM
Sigh
I might as well just wait until I take analysis next year
ok, working on 9.
 
Looking through the table of contents, it does indeed teach rather advanced concepts.
 
Damn. 9. seems so obvious (at least the first part).
I want to say use 4. and use the "fact" that a sequence of integers cannot converge to a noninteger.
But I have no basis for this "fact".
 
@0celo7 It's not hard to prove, though. (In fact, a sequence of integers converges only if it becomes eventually constant)
 
@ACuriousMind Oh!
Pick $\epsilon <1$!
 
8:13 PM
Maybe!? yay
Cool, first part done?
 
@0celo7 I'm not sure what you've shown. You've shown that every sequence of integers cannot converge to a non-integer. How does this show bounded sets of integers have an integer least upper bound?
 
@ACuriousMind Use 4.!
The sequence that converges to $\sup A$ has to converge to an integer!
 
@0celo7 Why?
 
@ACuriousMind Because integer sequences cannot converge to nonintegers.
 
4. is the statement: "A bounded set of real numbers contains a sequence convergent to its supremum"
 
8:17 PM
Ok, but a set of integers can only contain sequences of integers.
And sequences of integers only converge to integers.
 
Ah, now I see. Yes, that's correct
 
What did you have in mind?
 
@0celo7 Take a bound for the bounded set of integers. If it's in the set, it's obviously a least upper bound. If it's not in the set, subtract 1. Repeat until you've arrived in the set, that's the least upper bound.
 
Well duh.
That's too obvious.
Now for rational numbers...
That's what the intro course uses at UT.
@ACuriousMind Do you have access to that? If yes, I'd prefer switching to that.
 
@0celo7 Praise be upon Shibboleth, I have.
 
8:25 PM
@ACuriousMind Ok, I need to take this slow. This is just upsetting me.
And I want to see what the book is about.
@ACuriousMind Any tips on how to prove 9. for $\mathbb{Q}$?
 
@0celo7 I thought we switched books?
 
Well I have to complete the exercise!
 
lol
Alright
 
And I'm about to switch books to my English text :D
 
Do you have an idea why it fails for Q?
Just heuristically
 
8:30 PM
Using 4.: I'm assuming there are sequences of rational numbers that do not converge to rational numbers.
 
@0celo7 That is correct.
 
Like there's power series for pi, which is not rational.
That kind of thing.
So should I construct such a sequence explicitly or is there some general proof?
 
@0celo7 What do you mean by "general proof"?
A counterexample is all you need to prove "property X does not hold". It's as general as such proofs get.
 
Ok...
So can something like $\sqrt{2}$ be written as the limit of a sequence of rational numbers? (I know it can, but I'm trying to see how.)
@ACuriousMind Power series.
 
@0celo7 That's one way to do it, yes.
 
8:36 PM
@ACuriousMind Find the power series for $\sqrt{2}$ up to term $n$.
@ACuriousMind What are some other ways?
 
@0celo7 I'd have opted for the sequence of $a_n$ where $a_n$ is just the first $n$ digits of $\sqrt{2}$.
 
...
am I overthinking this?
 
Perhaps. Then again, I have a few years of training in coming up with such silly examples.
 
Yes but you said you did this as a Freshman.
 
Yeah, but I did not breeze through it as I do now, the exercises took me (and everyone else) some hours :D
 
8:43 PM
@ACuriousMind what does one do in Prison Architect
 
@0celo7 Exactly what it says on the tin ;)
 
ok, now I feel better
3 pages in, this English book is more confusing than any math
 
user54412
@0celo7 It probably assumes some familiarity with limit-based calculus and sequences. The sort of thing you'd see in a course that pauses to show you what Dedekind cuts are, but doesn't really expect you to use them.
 
user54412
That said, I've never taken such a course, and I didn't feel lost with Carothers.
 
@ChrisWhite Well I do.
What the heck is a Dedekind cut?
 
8:59 PM
@0celo7 A real number. (look it up)
 
@ChrisWhite So you were able to do all of these exercises as a...what? Freshman?
@ACuriousMind I did look it up...I'm just saying I've never been exposed to that.
 
Speaking of homology physics.stackexchange.com/questions/203614/… @ACuriousMind
 
user54412
@0celo7 junior I think
 
Freudian slip?
("cosomology")
 
@NeuroFuzzy lol, fixed
 
user54412
9:00 PM
my math curriculum had a very different order from yours
 
user54412
for comparison, I went to a nearby college to do lin. alg. and multivariable calc in HS, then freshman year I distracted myself with differential equations and statistics and generally applied things, sophomore year was all algebra, and junior year was analysis (and even more algebra)
 
@0celo7 BTW, dedekind cuts give you a definition of the reals that settles all "0.999...=1", "what exactly are the reals" questions.
 
user54412
I still never had a rigorous calculus class, or anything that would prepare me directly for Carothers
 
> nearby college to do lin. alg. and multivariable calc in HS
I should have done this.
They made a big stink about skipping calc 2 though...it was ridiculous.
And they refused to let me test out!
I'm considering doing summer school to knock out my philosophy elective and then take the undergrad algebra sequence next year.
+intro analysis and topology
 
user54412
You're probably just trying to finish a requirement, but I had great fun studying philosophy one-on-one with a prof over the summer.
 
user54412
9:08 PM
Actually, he turned out to be one of my letter writers applying to grad school.
 
0B3
@0celo7 Didn't you do that by yourself though?
 
@NeuroFuzzy I prefer the Cauchy construction over the Dedekind cuts, actually, :P (because it readily generalizes to the notion of completion of a metric space.
 
Oh, I think philosophy will be fun, but I can take more math by doing it over the summer.
@0B3 That doesn't mean I get credits for it.
 
user54412
Philosophy and math are two subjects where it really pays off to have a light course load and be free to just dwell on them.
 
user54412
@0celo7 Even having official courses is no guarantee you'll get credits. I was fortunate to be given the chance to pass out of those classes, but I never got credit toward graduation from them.
 
0B3
9:11 PM
@0celo7 You don't know real analysis of single variable but you do know multivariable analysis right?
There is a lot of overlap with differential geometry I think.
 
@0B3 In practice, "analysis" isn't always "analysis" :p
If I'm not repeating something you already know*. I have a book called "vector analysis" and there is not one proof in there that a pure mathematician would accept completely!
"multivariable analysis" could mean, "take the gradient of this function". Or it could mean, "prove the inverse function theorem". The latter is much harder and belongs to pure math, and the former is really easy and belongs to a second or third calculus course
 
@ACuriousMind the point is that dedekind cuts require only set theory, while cauchy sequences also topology...the first construction is therefore easier to generalize to nonstandard models
 
@NeuroFuzzy Second?
Jesus where do you people go to school...
 
More like Anal ISIS
 
uh
@Slereah go home, you're drunk
 
9:15 PM
for example you can construct a quantum set theory, where the "real numbers" are the self-adjoint operators affiliated with the theory
 
0B3
@0celo7 Is that too early or late?
 
@ChrisWhite At a state school (at least mine) you get credit for everything.
 
@yuggib Before you said "quantum set theory", I though I knew what you were saying :D
@0celo7 ?
 
@ACuriousMind i see nothing
@0B3 that's calc 3
 
@0celo7 lol
 
9:17 PM
where do people get multivar calc in calc 2
 
@0celo7 I did say "second or third" :3
 
0B3
@0celo7 Here at my university you can take analysis II after analysis I in freshman year.
 
I can't even follow this discussion because the concept of "calculus" as a subject in itself doesn't really exist in German.
 
@0B3 well you all are smarter than me
 
0B3
How?
 
9:18 PM
id get how @DanielSank thinks I'm a genius
I could not take analysis as a Freshman
I just can't
I'm not prepared for it
 
0B3
I find that impossible.
 
And what's scary is that I got by far the highest grades in high school math
what about everyone else?
and to then think that everyone in Germany and your school takes analysis as a Freshman...no wonder we're behind as a nation
 
0B3
That's because uoft has a really nice math department with the fields institute.
 
@0celo7 Well.. everyone who studies math, and some physicists
 
Is quantum set theory related to quantum logic
 
9:21 PM
I'm going because I have homework
 
Is it like ZFC with quantum logic or whatevs
 
user54412
When you go to grad school and meet people who did undergrad in other countries, you'll find that Americans are much more broadly educated than just about everyone else. This necessarily comes at the expense of depth in one's field, for better or for worse.
 
@yuggib Got any recommended reference for that, by the way?
 
0B3
What is the point of intuition in physics?
 
@0B3 To confuse people.
(mostly joking)
 
0B3
9:32 PM
If a mathematician decides to become a mathematical physicist after completing his phd, what is he missing that other physicists will have in regards to physics?
 
a souuul
Physical intuition and the will to totally disregard proper math procedure, also
Plus a veritable smorgasbord of various theorems that are always useful to know
As well as dirty tricks and things to keep in mind
Basically you have to know what is PHYSICALLY REASONABLE
There's a lot of things that are unsaid mathematically in a lot of physics work
Oh and I guess you have to know when you can ignore something
can't solve a lot if you don't simplify
 
9:57 PM
@ACuriousMind I considered studying math...high school would have not prepared me for that
 
10:21 PM
@0celo7 Analysis was the hardest course I took in college.
@ChrisWhite Yet we tend to know fewer languages ;-)
 
I don't think I'm very broadly educated at all
I took every non-language AP and I don't know shit.
 
Well then again you are 17
 
Yes but I'm almost done with my gen ed requirements
Only English and Philosophy left
AP'd and German'd out of everything else
 
10:54 PM
@0celo7 "German'd out"?
 
11:05 PM
@ACuriousMind I took a test that evaluated my German and got placed out of the language requirement.
I'm taking like 8 more math classes than I would normally because of all this.
 
Ah, I see
 
@DanielSank You have to see this from my perspective. Sure I know some GR and QM and I can do the "math", but so what? I can't program, I haven't done any interesting projects, I haven't interned at national labs. It seems like all of my classmates have done this!
 
11:18 PM
@ChrisWhite Joke's on you because I did a US-style undergrad degree :P
(...and worked my ass off to cover the normal physics course load)
 
11:46 PM
Errors of intuitive thought are difficult to prevent
@ACuriousMind Even my psychology text knows physics math is bullshit D:
 

« first day (1761 days earlier)      last day (3185 days later) »