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Ethan
Ethan
7:09 AM
@Sanchez What did you do with your life after you finished high school?
 
Sanchez
Sanchez
@Ethan, I go to college, lol
 
Ethan
Ethan
@Sanchez How did you know which collages to send applications to?
 
Sanchez
Sanchez
there weren't many choices.
Are you applying for colleges?
 
Ethan
Ethan
I will be soon
 
Sanchez
Sanchez
Are you a senior now/
 
Ethan
Ethan
7:11 AM
No, im a jr
 
Sanchez
Sanchez
Ah I see.
Did you go to ucla math circle eventually?
 
Ethan
Ethan
How would that help?
Im not sure if there teaching anything I might be interested in
 
Sanchez
Sanchez
Going there gives you a chance to see some professors.
 
Ethan
Ethan
Couldn't I just unoffically audit any class at ucla?
 
Sanchez
Sanchez
Also, if you want to 1. talk to prof 2. audit class at ucla etc., it's a good opportunity to ask at math circle once you know some people there.
Also you can meet some other young people who are interested in math
 
Ethan
Ethan
7:14 AM
Oh, do you think they would be offended if I was to just show up with out going through there whole registry process, it looks very complicatet
 
robjohn
robjohn
@Ethan are you at UCLA?
 
Sanchez
Sanchez
@Ethan, show up once and see what happens.
 
Ethan
Ethan
I was talking to an undegrad there and he suggested waiting in on one of his classes
I don't wana embarrass myself though
 
Sanchez
Sanchez
@Ethan, don't worry so much. Many professors are delighted that you go talk to them.
@robjohn, I think he's in that area.
 
Ethan
Ethan
@Sanchez What should I ask them?
 
robjohn
robjohn
7:17 AM
@Sanchez It seemed so from the conversation :-)
@Sanchez I am often on campus (since I work there)
 
Ethan
Ethan
@robjohn You work at ucla?
 
robjohn
robjohn
@Ethan yes
 
Ethan
Ethan
@robjohn I wana meet you in person :d
lol
 
Sanchez
Sanchez
@Ethan, well, I think you need some kind of guidance at this point. You can say that you are interested in number theory, read a few basic books on the subject, played around some formulas and get some results (that you wrote up I suppose), then you can ask where I can go next, what I should read, whether these results are interesting etc. Just say things politely and you would be fine.
 
Ethan
Ethan
@Sanchez Thanks for the advice
 
robjohn
robjohn
7:20 AM
@Ethan I taught math there for a couple of years about 25 years ago. Then I went to work for Apple for 8 years, then I came back to write software for the Philosophy dept.
 
Sanchez
Sanchez
Oh, philosophy! I thought you are associated to math dept :P
 
Ethan
Ethan
@robjohn I go to ucla every other sunday for some Ap readiness thing for my chemistry class
 
robjohn
robjohn
@Ethan In Young Hall (Chemistry)?
 
Ethan
Ethan
@robjohn I think thats where it was the first time
Franz hall the second time
@Sanchez How did you decide which collages to apply to? I have representatives and stuff coming from collages to my school, and I don't know what to attend to, and what not to.
 
robjohn
robjohn
@Ethan Ah, I taught Calc to a class of 200 in a classroom in Franz
 
Sanchez
Sanchez
7:24 AM
College @Ethan
and it's been too long, I'm not the right person to ask on this.
 
robjohn
robjohn
@Ethan teaching big classes is less personal. Small classes are better for the student.
 
Ethan
Ethan
@robjohn If you don't mind me asking, how old are you?
 
robjohn
robjohn
@Ethan one usually gets out of grad school around 25 (assumig 4 undergrad and 4 grad)+ 25 years and a few...
 
Ethan
Ethan
Oh
If your economically disadvantaged can you get aid in paying for college?
 
robjohn
robjohn
@Ethan There are lots of sources for financial aid. If you are in high school, one of the counselors should be able to look something up.
 
Ethan
Ethan
7:33 AM
Thanks
 
skullpatrol
skullpatrol
I am his son!
 
Ethan
Ethan
lol
 
skullpatrol
skullpatrol
(removed)
 
Ethan
Ethan
To personal
I take it back
I gues
 
skullpatrol
skullpatrol
;-)
 
robjohn
robjohn
7:35 AM
@skullpatrol you need to color it...
$\color{#A0A0A0}{\mathsf{(removed)}}$
 
Ethan
Ethan
lol
 
skullpatrol
skullpatrol
$\color{#C0C0C0}{\mathsf{Too late ;-)}}$
 
robjohn
robjohn
that's close
 
Sanchez
Sanchez
$\color{#A0A0A0}{\mathsf{(removed)}}$
$\color{#A0A0A0}{(removed)}$
$\color{#A0A0A0}{\text{(removed)}}$
 
robjohn
robjohn
@Sanchez without MathJax installed, that looks ridiculous
 
Sanchez
Sanchez
7:39 AM
haha
 
Ethan
Ethan
lol
 
Sanchez
Sanchez
$\color{#A0A0A0}{\mathbf{(removed)}}$
 
robjohn
robjohn
$\color{#A0A0A0}{\mathsf{(removed)}}$ is what those who don't have MathJax installed see
 
skullpatrol
skullpatrol
$\Huge\text{icic}$
 
robjohn
robjohn
$\color{#8080FF}{\Huge\text{icicle}}$
 
Novice
Novice
8:18 AM
Should my comment her be an answer?
2
Q: Find $a, b, c, d \in \mathbb{Z}$ such that $2^a=3^b5^c+7^d$

D3r0X4Solve $2^a=3^b5^c+7^d$ over the positive integer I know $a$ is odd because: $(-1)^a \equiv2^a = 3^b5^c+7^d \equiv1 \ (mod\ 3)$

number-theory diophantine-equations
Or are they asking for a general solution?
 
Jonas Teuwen
Jonas Teuwen
8:34 AM
@BenW. The odor seems to suggest different things 8-).
 
skullpatrol
skullpatrol
8:52 AM
Yo @Novice wazzup?
 
Novice
Novice
@skullpatrol Hey man.
 
skullpatrol
skullpatrol
@N3buchadnezzar Hey wazzup?
 
N3buchadnezzar
N3buchadnezzar
nuttin
 
Novice
Novice
9:51 AM
Guys, fast: is it possible to have a three-digit number such that the number is exactly 11 times the sum of its digits.
I say that it's not, and I have an algebraic solution, but I'm not sure.
 
skullpatrol
skullpatrol
Let's see your solution.
 
Novice
Novice
10:06 AM
198 is the only one.
 
user19161
11:01 AM
I am now dodgerblue.
 
chihiroasleaf
chihiroasleaf
hi...
 
robjohn
robjohn
11:27 AM
@user58512 Too late :-)
 
Jonas Teuwen
Jonas Teuwen
11:47 AM
Thirsty.
 
Novice
Novice
@JacobBlack The black looked pretty sexy.
 
Jay Satish Teli
Jay Satish Teli
Given Data :

Normal Distribution function

P(x≤−1)=P(y≥2)

x : mean= 1 variance= 4

y : mean= -1 variance= to be found..?.

Ans: 9

How to solve..?
got the solution... thanks any way
 
user19161
12:23 PM
@Novice Haha, well, there are no sexy colours, only sexy people.
 
user19161
So "latex" gets 1 star and "NUTS" gets 2 stars! Another free star day!
 
user19161
@JonasTeuwen Drink water.
 
user58512
user58512
@robjohn, great!!
someone wrote good things to my question but its not what I wanted at all, should I accept it and re-ask my question? stressing that I want as basic a proof as possible
 
Old John
Old John
1:09 PM
@user58512 Since we are talking about one of the toughest known problems in maths, maybe there is no elementary proof possible?
 
user58512
user58512
@OldJohn, it's beginner level analytic number theory
@OldJohn, I'm only asking about the critial strip, not the critical line
 
Old John
Old John
The Riemann Hypothesis is certainly not begiiner level anything
@user58512 if you know it is beginner level stuff, then why can't you find a solution in a beginner level ANT book?
 
user58512
user58512
@OldJohn, I think you misread my question: I have got the zeta function defined as sum 1/n^s for real s > 1 and the Euler product shows this has no zeros. Then analytically continued to re s > 0 by partial summation, and then did the functional equation using fourier analysis, so that proves that the only nontrivial zeros are in 0 < re s <= 1
@OldJohn, all I want is to show there are infinitely many zeros
 
Old John
Old John
@user58512 And you are certain that this is a begiiner-level ANT problem how exactly?
 
user58512
user58512
there are some vague things like "if it has finitely many zeros then it would have polynomial growth" which could prove it
its a just trivial thing, the reason I don't see it because I don't know complex analysis beyond very novice level
 
BenjaLim
BenjaLim
1:15 PM
@OldJohn hello
 
Old John
Old John
Hi @BenjaLim
how's it hanging?
 
BenjaLim
BenjaLim
@OldJohn hi.
@OldJohn not bad. Today we just had a chinese new year dinner. I will put them on facebook!
 
Old John
Old John
@BenjaLim Great! - They are celebrating that in Manchester Chinatown, but I can't really spare the time to go
 
user58512
user58512
@OldJohn, let me explain it this way
@OldJohn, you know there are infinitely many non-trivial zeros of zeta?
 
Old John
Old John
yes, of course
 
user58512
user58512
1:17 PM
so I'm just asking why
I mean everyone knows this, it's a basic fact
 
Novice
Novice
I, along with two of my friends, have made potentially an excellent discovery; I just need someone to write a program and help me out check if it is true.
 
Orange Harvester
Orange Harvester
@Novice Will I get to share the resulting Nobel prize (or Field Medal or Turing Award or anything)?
 
Old John
Old John
@user58512 I think there is a proof in Bateman and Diamond "ANT"
 
Novice
Novice
@OrangeHarvester I don't know... it's not so great.
 
Orange Harvester
Orange Harvester
@Novice :P I was joking.
 
BenjaLim
BenjaLim
1:19 PM
@JacobBlack Did you have your chinese new year dinner?
@OldJohn Go and have a look at the festivities
 
user58512
user58512
@OldJohn, thanks, but my library doesn't have this one
 
user19161
Just answered several lhf...
 
BenjaLim
BenjaLim
@JacobBlack lhf?
 
Old John
Old John
@BenjaLim Might get a chance tomorrow - but there is snow forecast, so I might not make it this year :(
 
user19161
@BenjaLim Low hanging fruit!
 
BenjaLim
BenjaLim
1:21 PM
@OldJohn You have been in the past?
@JacobBlack Did you have a reunion dinner?
 
Novice
Novice
But here's our hypothesis: There is only one three-digit number $N$ in base $b$ such that the sum of its digits is $\frac{N}{b + 1}$.
 
Old John
Old John
@BenjaLim yep - several years ago
 
user19161
@BenjaLim Just a normal dinner. I am in no mood to celebrate, and I only live with my mum.
 
BenjaLim
BenjaLim
@JacobBlack No hotpot?
 
user19161
@BenjaLim Nope.
 
BenjaLim
BenjaLim
1:21 PM
@JacobBlack WTF you're not of chinese descent
 
user19161
@BenjaLim Well, I am not of this world.
 
Novice
Novice
@Orange we could make it wider.
2
But I must confirm if it is true, to start with.
 
user19161
@benja It's OK, no need to remove all these harmless things. Just calm down.
 
Novice
Novice
And you know how "good" I am at programming. :-P
2
 
BenjaLim
BenjaLim
@JacobBlack IJK.
 
user58512
user58512
1:23 PM
@OldJohn, your comment doesn't make sense. You have the same misunderstanding as this Jp Mcarthy guy
the question isn't about RH
 
Old John
Old John
@user58512 looks like you are going to have to learn some complex analysis - the proof I have just seen uses Hadamard's theorem from Comp.Anal.
 
user19161
Three circles?
 
Old John
Old John
@user58512 My comment makes perfect sense if you read it properly
 
Orange Harvester
Orange Harvester
@Novice Learn up something. Programming is a nice skill to have and learning it in starting can be much like playing video games. :P Look up MIT's course on programming with python 6.00. All material is available only including video lectures, so cool.
 
user58512
user58512
I was just hoping a mod will delete Jps terrible comment
 
Orange Harvester
Orange Harvester
1:25 PM
Its not so terrible. Its not like he named you after a particular celestial body.
 
user19161
Can anyone tell me why people are so crazy about MIT OCW?
 
skullpatrol
skullpatrol
@JacobBlack Come on celebrate the year of the snake.
 
Orange Harvester
Orange Harvester
I only celebrate the year of the horse!
 
BenjaLim
BenjaLim
@JacobBlack Why the non-existence of hotpot?
 
user19161
@BenjaLim Well, I don't follow traditions. I am not of this world.
 
BenjaLim
BenjaLim
1:27 PM
@JacobBlack And you scold me for being ashamed of my race?
 
user19161
@BenjaLim There is a difference.
 
BenjaLim
BenjaLim
@JacobBlack Nggak ada bedanya.
 
skullpatrol
skullpatrol
But you are in this world.
 
user19161
I am in this world, but not of it.
 
Old John
Old John
Time for food - back later
 
Orange Harvester
Orange Harvester
1:28 PM
@BenjaLim He is not ashamed. He just does not celebrate. However proud I am to be an Indian, if I started celebrating all the festivals here, I would be literally dead.
 
user19161
There is a difference.
 
Orange Harvester
Orange Harvester
@JacobBlack Celebrating might make things better no?
 
user58512
user58512
@JacobBlack, is there no proof easier than 3 circles. That gives a stronger result than I need
 
BenjaLim
BenjaLim
@JacobBlack Kenapa kau marah saya?
 
user19161
@OrangeHarvester I rather celebrate other things, like my love for ABC.
 
user19161
1:29 PM
@user58512 I don't know, I am only a banana.
 
BenjaLim
BenjaLim
@JacobBlack Diharapkan bahwa kau mejawab soalan saya.
 
user19161
Why did someone flag my above line?
 
BenjaLim
BenjaLim
@JacobBlack Veuillez vous répondre à ma question.
 
user19161
@user Did you flag me just now?
 
skullpatrol
skullpatrol
BenjaLim probably did it since he has done it to me.
Not that I care.
 
Orange Harvester
Orange Harvester
1:33 PM
They flagged banana? Really guys?
 
user19161
Now someone flagged my "I am not of this world".
 
user58512
user58512
@JacobBlack, I consider that rude
 
skullpatrol
skullpatrol
@BenjaLim Excuse me?
 
BenjaLim
BenjaLim
@skullpatrol Where's the proof that I allegedly flagged your posts?
 
user19161
@user58512 So you flagged my two lines?
 
Orange Harvester
Orange Harvester
1:34 PM
@user58512 Wait, banana is rude? or not of this world is rude? How the hell is that rude?
 
skullpatrol
skullpatrol
You did it... see removing posts proves you are feeling guilty.
 
user19161
So today someone flagged my "I am only a banana" and "I am not of this world". Wow.
 
user19161
Really, wow.
 
Orange Harvester
Orange Harvester
$\huge{\text{WOW}}$
 
BenjaLim
BenjaLim
@anon Hey.
 
skullpatrol
skullpatrol
1:37 PM
So... I was suspended for "skullpatol against the world"
 
user19161
@user58512 I will never talk to you again.
 
user19161
I treat you as a friend but you do this to me.
 
Orange Harvester
Orange Harvester
Me neither.
 
skullpatrol
skullpatrol
Me too
 
BenjaLim
BenjaLim
@anon Hmmm not sure if Alex Youcis' answer on main answers my queries...
 
user19161
1:37 PM
My whole life, I try to be kind to people, but people keep abusing me.
 
Orange Harvester
Orange Harvester
@skullpatrol I guess user might have flagged it too, considering how it flagged "not of this world".
 
skullpatrol
skullpatrol
Shhh...
the cops are here
 
user19161
I am very sick and tired of this world.
 
skullpatrol
skullpatrol
relax
 
Orange Harvester
Orange Harvester
@JacobBlack Hold on dude. Hold on.
 
BenjaLim
BenjaLim
1:38 PM
@anon See here
 
robjohn
robjohn
@user58512 re-askng the question will be met with downvotes and negative comments. Thanking the person answering your question is good, but if you are looking for something else, apologize for changing the question, but append your question with a clarification as to what you are looking for. Some people get bent out of shape and say that you have wasted their time, but it is my opinion that they have the wrong idea of the purpose of this site.
 
user58512
user58512
@robjohn, I already re-asked.. i felt i couldn't tell him that was wrong after he typed out so much..
 
BenjaLim
BenjaLim
@anon Hmm I don't think what I ask is true. I think we need $I$ to be non-principal @Sanchez
 
robjohn
robjohn
@user58512 sorry I took so long to reply. I hope you don't suffer too many downvotes and negative comments.
 
user58512
user58512
@robjohn, such good continued fraction work, I wish I had got that
@r
@robjohn, I don't think anyone understands my question - and since RH attracts cranks a lot they are in a bad mode even before reading it
 
skullpatrol
skullpatrol
1:43 PM
@BenjaLim I apologise for accusing you. I really should not have jumped to that conclusion.
 
user58512
user58512
@OldJohn, I do't think you can get a Hadamard factorization without an upper bound on the number of zeros. The upper bound uses strange complex analysis technique I can't understand - that motivates my question.
 
robjohn
robjohn
@user58512: have you looked at this? I wrote it a while ago, and it only deals with simple continued fractions, but it does prove that the continued fractions all quadratic algebraics repeat (not easy).
 
user58512
user58512
@robjohn, I just proved that yesterday math.stackexchange.com/questions/298040/…
oh wait, you have the converse result
that's more difficult I think
 
skullpatrol
skullpatrol
@robjohn In your opinion Sir, what is the purpose of this site.
 
robjohn
robjohn
@user58512 Yes, that repeating continued fractions are quadratics is quite a bit easier.
@skullpatrol to teach and learn.
 
user58512
user58512
1:56 PM
I doubt anyone will answer my question on zeros of zeta, it's too hard for anyone who doesn't study this stuff specifically to answer and it's too easy for anyone who does to bother answering
 
BenjaLim
BenjaLim
@skull apology accepted.
2
 
skullpatrol
skullpatrol
:-D
5
Q: flags in chat yesterday

Will JagyThere was some sort of excitement yesterday or last night which I found mysterious. It turns out that in Chat, and there is just the one main chat which has been going forever, one may either star a comment as good or flag it as bad in some way. Asking about it within chat seemed to get a lot of ...

discussion flagging chat
 
user58512
user58512
2:22 PM
Can comments like this not be removed ? math.stackexchange.com/questions/298722/…
it's just rude and noise
 
Theorem
Theorem
What is total divisor in Modules ?
 
awllower
awllower
2:54 PM
@user58512 You mean the comment of Hagen VonEitzen? I caanot see why it is rude however...
 
user58512
user58512
oh well
ill ignore it
 
awllower
awllower
I mean: he seems to try to provide some intuitions to your problem(I am not so familiar with ANT though).
 
user58512
user58512
I don't think so
he's just making a really lame joke
 
awllower
awllower
And what makes you think so?
 
user58512
user58512
because it's not mathematical
 
Orange Harvester
Orange Harvester
2:58 PM
take a look at the starboard on the right and let me know how many mathematically insightful statements you find.
3
 
awllower
awllower
In my view, it appears to provide a criterion that some number can occur as the number of zeros of the function. But no number satisfies this criterion, hence the number must in fact be infinite?
 
user58512
user58512
no
 
awllower
awllower
@OrangeHarvester My I beg your pardon?
May
 
Orange Harvester
Orange Harvester
@awllower my comment was directed towards user...., we allow occasional lame jokes on this site.
 
awllower
awllower
Oh...
Just that that user seems not like such a user to me.
 
user58512
user58512
3:01 PM
what do you mean??
 
Orange Harvester
Orange Harvester
@user58512 were you previously known as jdoe?
 
awllower
awllower
I mean: judgeing from his other comments, he rarely made some jukes like this one.
 
user58512
user58512
oh
I think it's because he doesn't like my question
because I didn't accept his answer before
 
Orange Harvester
Orange Harvester
Hehe. Peopel are not so touchy. :P
 
user58512
user58512
but his "answer" before was just repeating something that I linked
 
awllower
awllower
3:03 PM
Well, I do not suppose that this(accepting answers) is personal.
But of course I know not what others think though.
 
Orange Harvester
Orange Harvester
@JpMcCarthy I suppose it might serve the purpose of showing some of our readers that RH is harder than they imagine, and that they would be wasting their time trying to settle it themselves - or it might encourage some readers to learn some of the harder parts of complex analysis. — Old John 2 hours ago
 
awllower
awllower
In any case, my poor knowledge of ANT only includes prime number theorem, Dirichlet theorem, Chebotarev theorem, and some others related to zêta, which I prefer to classify as Amgebraic number theory.
Well, since it is late already, I think my bad is summoning me now. Good night everyone, or per chance good day?
 
Orange Harvester
Orange Harvester
Most of the times intuition is a personal matter. What is intuitively clear to me might not be intuitively clear to you. Sometimes, you need TO BE ABLE to work out the details to get to the intuition.
@awllower Naah, it is late evening here. Good night.
 
pourjour
pourjour
3:19 PM
$5^{\cos(x)}+5^{\cos(\pi-x)}\le2*5^{1/2}$
how can solve this
?
 
Mark S.
Mark S.
What is $\cos(\pi-x)$ in terms of $\cos(x)$?
 
pourjour
pourjour
@MarkS. -cos(x)
 
Mark S.
Mark S.
What is the range of cosine?
 
pourjour
pourjour
do u mean -1<= cos(x) <= 1
 
Mark S.
Mark S.
Combining those two facts, your problem becomes "$5^y+5^{-y}\le 2*5^{1/2}$ for $-1\le y\le 1$".
Now that the trig stuff is gone, see what you can do with that.
 
pourjour
pourjour
3:27 PM
@MarkS. thanks
 
user58512
user58512
hello
 
Mark S.
Mark S.
Are you the 58512th in the prestigious "user" family?
 
pourjour
pourjour
@user58512 hi
 
user58512
user58512
@MarkS., lol
is it really possible to get the hadamard factorization of the Riemann xi function without an upper bound on the number of zeros?
 
Nimza
Nimza
4:15 PM
Hi!
@OrangeHarvester hello, thank you for your yesterday's answer :)
 
Khromonkey
Khromonkey
Hi guys
 
Orange Harvester
Orange Harvester
@Nimza Hi. Actually, Jonas said something more about it. He said you can always do it, because the derivative operator is closed and commutes with bochner integral, I don't knwo what bochner integral is though, so I do not understand what he said. .
 
user58512
user58512
hello
 
Nimza
Nimza
@OrangeHarvester Hehe))
@user58512 hi
 
user58512
user58512
hey
 
Orange Harvester
Orange Harvester
4:18 PM
@Nimza :P Here is what he said:
yesterday, by Jonas Teuwen
@OrangeHarvester Can always do so, derivative is a closed operator, and that commutes with Bochner integrals.
 
Nimza
Nimza
@OrangeHarvester :)
 
Orange Harvester
Orange Harvester
:)
:)
 
Nimza
Nimza
Hm, $\int\limits_{\mathbb{R}^n_{+}} x_1^{z_1} \ldots x_n^{z_n} \left(1 - \sqrt[n]{x_1 \ldots x_n} \right)_{+} dx$ diverges for any $z$ if I'm not mistaken... right?
 
user58512
user58512
4:40 PM
@anon, thank you very much
 
anon
anon
np
 
user58512
user58512
do you recommend any nice book or notes for this stuff? I have davenport which is nice but I like to read multiple books
 
anon
anon
not really
 
user58512
user58512
 
BenjaLim
BenjaLim
@anon Happy CNY
 
user58512
user58512
4:46 PM
but stops short
 
anon
anon
@BenjaLim I seem to recall a curious scuffle between you and black on that?
 
BenjaLim
BenjaLim
@anon dunno if you can call it a scuffle
 
anon
anon
@user58512 I get 'object not found' for some reason.
 
user58512
user58512
oops, corrected
I ytyped wrong url
 
robjohn
robjohn
We had snow on the mountain just about 8 miles north of here. I could see it from the park while walking Lilly.
2
 
BenjaLim
BenjaLim
4:48 PM
@anon I have a quick question
 
anon
anon
you're aware you can copy and paste urls?
 
BenjaLim
BenjaLim
@anon Suppose that $m \equiv n \equiv k \equiv 1 \mod{4}$
$m,n$ are squarefree integers and $k = mn/(m,n)^2$
 
anon
anon
... is that html squared inside of latex?
 
BenjaLim
BenjaLim
I get the integers in $\Bbb{Q}(\sqrt{m},\sqrt{n})$ are of the form $\frac{a + b\sqrt{m} + c\sqrt{n} + d\sqrt{k}}{4}$
$a,b,c,d$ are integers
And by taking the norm down to $\Bbb{Q}\sqrt{m}$
I get that $a,b$ must be even.
 
anon
anon
can't help
 
BenjaLim
BenjaLim
4:51 PM
@anon Ok. No worries.
 
user58512
user58512
does anyone have a pdf about weierstrass factorization?
 
robjohn
robjohn
5:27 PM
Read only mode??
 
Orange Harvester
Orange Harvester
yes.
 
CBenni
CBenni
those are the wierdest proof-end symbols I have ever seen in a paper, @user58512...
someone had WAY too much fun with the ntheorem package there
I should be using bananas, you know, for scale
 
user58512
user58512
read only :(
 
anorton
anorton
What is up with the site? Read only?
 
CBenni
CBenni
read.
It says maintainance
 
anorton
anorton
5:35 PM
Oh. :( I wonder what type of maintenance...
 
CBenni
CBenni
ask the SE admins ^.^
theres a meta + meta chat for that
but I guess theyll get annoyed really quick
 
anorton
anorton
I guess so... I could also just rant about it on this chat. :)
 
CBenni
CBenni
so better dont
 
Old John
Old John
If they are making any changes to the underlying database, it makes sense to prevent people stuffing more stuff into the db while they are doing it :)
 
user58512
user58512
i got myself a book on complex analysis
 
Ben W.
Ben W.
5:40 PM
what book?
 
Orange Harvester
Orange Harvester
@CBenni TWK uses fancy qed's too in his companion to analysis.
 
CBenni
CBenni
any reason for that except being a clown? :D
 
user58512
user58512
Ahlfors
 
Orange Harvester
Orange Harvester
:P It might be more common that you think is all I am saying. I personally prefer $\blacksquare$
@user58512 Ahlfors is good.
 
Ben W.
Ben W.
I like Ahlfors too, even if some claim it's bad.
 
CBenni
CBenni
5:43 PM
I usually use the normal $\square$
but I guess thats a personal thing
 
user58512
user58512
$\square^\square$
 
CBenni
CBenni
?
That is easily proven, but kinda suprising for a newcomer @user58512.
 
user58512
user58512
it's immediately obvious to me
 
Ben W.
Ben W.
I guess what is immediate and what isn't is dependent on who's asking.
 
CBenni
CBenni
yes, because you are a 1.2k rep user
 
user58512
user58512
5:52 PM
it was a surprse to me that n | phi(a^n + b^n)
 
Orange Harvester
Orange Harvester
@user58512 Well, he discovered one result and he got another one for free, a more strict version.
 
user58512
user58512
for a > b > 1 I think
 
CBenni
CBenni
to someone who is new to number theory, it might not. The only thing I absolutely cannot stand are the thousands of users who ask "why is 0/0 not equal to <insert random symbol here>"
@user58512 and phi is? Theres a bunch of functions called phi
like every second function is called phi
the rest is called gamma
 
Orange Harvester
Orange Harvester
every $1.618\dots^{\text{th}}$ function is called phi.
 
CBenni
CBenni
@OrangeHarvester I THINK I understood that reference
 
Orange Harvester
Orange Harvester
5:55 PM
@CBenni good :-)
 
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