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6:00 PM
For the theorem on existence and uniqueness of solutions of differential equations, see Picard's existence theorem. In complex analysis, Picard's great theorem and Picard's little theorem are related theorems about the range of an analytic function. They are named after Émile Picard. == The theorems == Little Picard Theorem: If a function f : C → C is entire and non-constant, then the set of values that f(z) assumes is either the whole complex plane or the plane minus a single point. Sketch of Proof: Picard's original proof was based on properties of the modular lambda function, usually denoted...
 
"Theorem: $\ldots$ lots and lots of stuff $\ldots$"
 
@BalarkaSen
 
Which is true. That's easier to see if you don't use commas, I think: $\epsilon_{ijk}\partial_i A_j$.
 
@Simply I know the theorem. That's why I quoted it.
 
The professor stated without proof the Casorati-Weierstrass theorem in class, which is the baby version of Picard apparently
 
6:00 PM
@Daminark I like that parsing :D
 
@BalarkaSen :P
 
Yeah, C-W says the image of the punctured ball is dense in C
I think
 
Ah, I'm used to seeing it as $\epsilon_{ijk} A_j \partial_k$
 
Similarly, for the other term you have $(\epsilon_{ijk}\partial_i B_k)A_j$.
 
But sure, relabeling gives the same result
 
6:01 PM
@Alessandro Is it the baby version of Little Picard?
Or is it little Picard itself?
 
baby version of baby picard
 
guys i need help
 
If you then swap the labels of $j,k$ (which you can---dummy indices) you get $(\epsilon_{ikj}\partial_i B_j)A_k=-(\epsilon_{ijk}\partial_i B_j)A_k$ where I've used the antisymmetry of $\epsilon_{ijk}$.
 
Where we can swap i with any index
 
any1 with knowlgde in complex analysis?
 
6:02 PM
this is the strong picard tho
 
@BalarkaSen yup
 
Which is just $-(\nabla\times \mathbf{B})\cdot\mathbf{A}$.
 
Yes of course
 
That work for you?
 
Totally
 
6:04 PM
mmkay.
This is one of the nice cases, as you might've noticed.
 
I'm actually doing an exercise I think you would recognize
 
There's a few product rules in vector calculus which have 4 terms rather than 2 and are basically a huge pain.
 
@Daminark My favorite statement of Stokes' theorem is that if you draw a loop there's a lot of swirly in it
 
Yeah, gradient of dot product comes to mind
 
SMBC?
 
6:05 PM
0
Q: Prove that exist $f_1$ and $f_2$ such that $f=f_1+f_2$

Manolis LyviakisSuppose $f$ is analytic on the ring $D(0,1;2)$ Through the Laurent series of $f$ prove that there exist $f_1$ analytic on $D(0;2)$ and $f_2$ analytic on the ring $D(0;1,+\infty)$ such that $f=f_1+f_2$ on the initial ring $D(0,1;2)$ . I dont know even how to start .I know that having the lauren...

 
Yep.
 
@BalarkaSen The circulation of a magnetic field around a closed loop is directly proportional to the current enclosed by the loop.
 
can you help me?
 
I'm going to make a wild guess and say you're doing either angular momentum or magnetic fields. @Lozansky
(Probably magnetic fields with $\mathbf{A}=\frac{1}{2}\mathbf{B}\times \mathbf{z}\implies \mathbf{B}=\nabla \times \mathbf{A}$ or whatever it is.)
 
@Semiclassica Right, that's the Gauss's lemma.
I like to say "sum of local swirly = global swirly"
 
6:07 PM
heh.
I just like having a physical context to it.
 
local swirly being curl at a point, and global swirly being the integral of the field along the loop
 
@Semiclassical No, showing that the energy density $\mathcal{E}$ satisfies the continuity equation $\partial_t \mathcal{E}+ div \mathbf{P} =0$ where $\mathbf{P} = \dfrac{1}{\mu_0}\mathbf{E} \times \mathbf{B}$
 
I think "Currents generate magnetic circulation" is a nice slogan.
 
Lol wait theres no capital epsilon?
 
yeah that's not bad
 
6:08 PM
Do $\mathcal{E}$ (\mathcal{E})
Ah, yes, continuity equation for conservation of energy.
 
Yeah
 
Not going to lie, conservation of energy in E&M is a pain.
 
It was trivial using that vector identity
 
Though angular momentum is worse.
 
Well this was for a region free of charges and flows
 
6:10 PM
yeah, that makes life easier
 
Oh no, got an exercise in curvilinear coordinates now
 
Have fun :/
 
Hope this one isn't too bad :|
 
Try to work using vector calc identities alone as much as you can
That has the advantage of being coordinate independent
 
Because they are invariant?
 
6:12 PM
Well, yes. But also because it helps avoid actually writing out the coordinate forms
 
Well, I don't have much choice now
 
Perhaps not. It'll depend on the problem.
 
Need to compute scale factors and the divergence in this coordinate system
 
Ahh, yeah.
Which coordinate system?
 
I think I should recognize it
$\cases{x = e^{u+v} \sin(u-v) \\ y=e^{u+v} \cos(u-v) \\ z = w}$
 
6:14 PM
Yeah, I've seen that.
Hmm
 
Don't remember where I've seen it though
Something elliptical maybe
 
Yeah. Looks reminiscent of bipolar coordinates or elliptic coordinates
 
Bipolar coordinates is an unfortunate name
 
It really is.
 
Good lord
 
6:17 PM
It might be a rotation of one of those two? But yeah.
aaanyway.
out for a bit.
 
Cya later!
 
0
Q: Prove that exist $f_1$ and $f_2$ such that $f=f_1+f_2$

Manolis LyviakisSuppose $f$ is analytic on the ring $D(0,1;2)$ Through the Laurent series of $f$ prove that there exist $f_1$ analytic on $D(0;2)$ and $f_2$ analytic on the ring $D(0;1,+\infty)$ such that $f=f_1+f_2$ on the initial ring $D(0,1;2)$ . I dont know even how to start .I know that having the lauren...

can you help me?
 
6:37 PM
$A=\{1,2,3,4,5\dots ,48,49,50\}$. $K$ is a subset of K that have 5 elements. Let $f(X)$ is the function that gives the sum of the elements of $X$. How many integers $f(X)$'s range have?
 
Open question: does anyone know of any mathematica scripts that compute integrals using Feynman parametrization other than this one? I'm almost certain that they must exist, but I can't for the life of me find them anywhere on the internet...
 
forget about last question
 
@Hippalectryon i don't understand what you do ?
 
Anonymous
@BalarkaSen Are Ted's lectures available at 720p ? I can't read what he is writing on the blackboard!
 
6:55 PM
@Lozansky Playing around a bit, I think the lines of constant $u$ and constant $v$ are archimedian spirals (in polar coordinates, $r(\theta)=a+b\theta$) of opposite rotation. But my Google-fu hasn't found a coordinate system with those features yet.
Weeeird
 
@Semiclassical Huh okay. Maybe plotting in matlab/mathematica might help recognizing it?
 
Well, that's how I figured out that they were spirals :)
 
Ahh, I see :P
Well the scale factors are $h_u=h_v = \sqrt{2}e^{u+v}$ and of course $h_w =1$
I've completely forgot in what kind of situation the arise though. Pretty sure I've seen them before
 
@blue Really? I could totally see what he was writing when I watched it.
Which video are you having trouble with?
 
Anonymous
 
Anonymous
7:00 PM
This is how it appears on my PC
 
Anonymous
The first lecture
 
It's supposed to zoom in soon enough.
I have never actually seen the 1st lecture, let me see
Ah, stuff doesn't zoom in that one.
 
Anonymous
Oh, so from which lecture does it start zooming in? I don't think the first lecture is very important though
 
starts happening from #2
check it out
 
Anonymous
v
 
Anonymous
Oh yes
 
Anonymous
Thanks!
 
No probs
 
@Vrouvrou Cauchy schwarz on $f$ and $sgn(f)$
 
@Hippa @Vrouvrou Vous parlez tous les deux français
 
7:09 PM
Ah j'avais oublié >.>
 
How's the hbar tender project going? @Hippalectryon :-)
 
@user314159 Nowhere for now :( I still haven't got any request for special commands
 
Ok, np.
 
Suppose I want to write a vector $v$ as a sum of a perpendicular component $v^\perp$ and a parallel component. What's the TeX code for the symbol I should use to denote the parallel component?
 
@MikeMiller Doesn't \parallel $\parallel$ work ?
 
7:19 PM
Great, thanks.
 
$v^\parallel$
 
Hey guys! apparently I can bound this $\frac{x^2+xy+y^2+(xy)^2}{(1+x^2)(1+y^2)}$ by 4 but I'm stuck. Can you help me?
I reach $1+\frac{1-xy}{(1+x^{2})(1+y^{2})}$ and then I thought about using AM-GM for the xy but I don't reach anything that helps me
(sign correction) what I reach is: 1+\frac{xy-1}{(1+x^{2})(1+y^{2})}*
 
@John11 Have you tried looking at the gradient for a maximum ?
 
No It's supposed to be much simpler, a stupid algebraic manipulation. This is something from before we covered gradients in class
 
@John11 I mean, without even looking at gradients, how does the second term behave when $x,y$ increase ?
 
7:31 PM
@Hippalectryon hello
 
@TheGreatDuck o/
 
@Hippalectryon you mean the second term in what I reached?
 
@John11 yeah
 
long time no see
that post pretty much summarizes the entire breadth of what I continued with aside from minor intuitions and getting a feel for how to solve those things.
 
7:32 PM
@Hippalectryon Greetings
 
@Waiting o/ How are you ?
@TheGreatDuck Alright I'll look into it :-)
@John11 Oh nvm I didn't see the sign correction
 
@Hippalectryon Pretty fine these days. How about you :-)
 
@Waiting Great :-)
 
@Hippalectryon I rarely see you around. Still busy with your stuff?
 
@Hippalectryon trying to see if I can create one that has the same algebraic properties but with periodic instead of piecewise constant. However, I'm pretty busy at the moment so playing with made up differential operators and their algebraic applications is not a priority.
 
7:34 PM
@Waiting I had a fairly busy last week
 
@Hippalectryon I see.
 
@TheGreatDuck Btw do you still update the google doc ?
 
@Hippalectryon nah. Too old. Too obsolete. Too random.
the second is false
:p
 
The second is false ?
 
i was trying too hard to force it into being like a massive document when in reality that one conjecture summarizes it all and it would probably fit better as a minor chapter in a differential equations textbook, not a whole book in and of itself.
plus... I just got sick of writing it
:p
 
7:37 PM
ok :-)
 
@Hippalectryon we can apply Cauchy Schwartz on f and 1
 
@Vrouvrou We can, but it won't give us the result we want
 
Salut @Hippa
 
@TedShifrin o/
 
\o @TedShifrin
 
7:49 PM
How to find $$\sum_{k=0}^n 3^k$$
 
@AbdullahUYU: Look up the formula for a geometric series.
 
@John11 still there ?
 
yes
I think I managed to bound by 3 but it's really ugly lol
 
@John11 Alright I have a simple proof. Let's show that $\frac{xy-1}{(1+x^2)(1+y^2)}\le1$
 
ok I'm following
 
7:53 PM
$\frac{xy-1}{(1+x^2)(1+y^2)}\le1 \Leftarrow xy-1\le 1+x^2+y^2+(xy)^2 \Leftarrow (xy)^2+x^2+y^2-xy+1\ge0 \Leftarrow (xy)^2+x^2+y^2-2|xy|+1\ge0 \Leftarrow (xy-1)^2+x^2+y^2\ge0$ which is true
@TheGreatDuck What do you call a weak solution ? (there's no common definition according to wiki)
 
Never seen I, never felt, a use of brackets so creative.
 
@Hippalectryon Awesome! Thank you! sorry for my slowness I was checking your penultimate implication
 
I love you :)
 
Howdy, a Balarka.
 
8:05 PM
Hi, a Ted.
 
@John11 No problem :-)
 
A Balarka, this looks like it's down your alley.
 
hi chat
 
I don't think I know what amenability means.
 
Heya, Eric.
 
8:15 PM
I like the line "I don't think you should get paid to think about math" :P
 
@Balarka: Did you look at Wiki? Look at the examples section at the bottom.
 
@Hippalectryon Why $\int_0^1 |f(t)|dt \leq (\int_0^1 |f(t)|^2 dt)^{1/2} (\int_0^1 dt)^{1/2}= 1. ||f||_2$
 
I am looking. That's a huge class of groups.
 
@Vrouvrou Oh, you mean using $|f|$, not $f$. That works, it's pretty much equivalent to my solution (since $f*sgn(-f)=|f|$)
 
@Hippalectryon idk. I was told to ask that.
 
8:17 PM
@Ted I was working on a geometry problem from Neves and doing one of your exercises saved me so much trouble so thank you for that lol
 
LOL. Oh? @EricSilva. Tell me more.
 
@Hippalectryon merci
 
@Vrouvrou pas de problème :-)
 
So the problem was basically asking to find some infinite collection of manifolds of distinct diffeomorphism type which don't admit einstein metrics
 
Oh ...
 
8:19 PM
So gotta look at 3 manifolds
 
I was going to guess general Grassmannians.
But for 3-manifolds, Ric completely determines the curvature, right?
 
huh, I figured that dim 3 Ricci controls sectional curvature, so finding something that isn't a space form is enough
 
If that's my exercise you're referring to, it's just uninteresting multilinear algebra.
 
the exercise isn't enlightening, but the result is pretty cool
 
You got my hopes up for nothing :P
 
8:22 PM
lol
most of these exercises on this final pset are basically estimates
 
That's a good skill to work on.
You should read about Bochner-type vanishing theorems based on harmonic forms sometime.
 
@Ted What're the flat Riemannian manifolds with nontrivial tangent bundle?
 
I like doing it, unfortunately I worked these estimates out because they're basically things he skipped over in class during comparison theorem proofs, so I worked them out immediately after lecture :/
 
Eric can probably answer that better than I right now.
So bundles come from representations of $\pi_1(M)$, @Balarka.
 
@TheGreatDuck Why would diff equations change at all with implied operators ? $I(f,x,g)$ is only different from $f'$ in a countable number of points
 
8:26 PM
Flat bundles do come from the linear representations, and are completely classified by them. Flat bundles are equivalently (I think) the ones which admit flat connections.
 
@Hippalectryon hmm? Not sure what you mean?
 
Equivalently the ones which admit a foliation transverse to the fibers...
 
But a bundle can be flat and nontrivial ...
 
@Hippalectryon solve y' = c in both. Notice the difference...
you might find floor useful there
or piecewise constants
 
the tangent bundle of the mobius strip isn't trivial
and it admits a flat metric
 
8:27 PM
Ok, @Eric, give me an orientable ex.
 
hmm
 
I think Siefert fibered spaces are flat.
 
@Hippalectryon solve y'' + 2floor(x)y' + floor(x)^2y = 0 in the other system. Notice how much easier it is to solve.
 
@TheGreatDuck Wait, something isn't clear. By "solving I(f,g)(x)=h(x)", do you mean finding an $f$ which is solution given $g,h$, or finding $f,g$ given $h$ ?
 
Hint: auxilliary equations
@Hippalectryon g is just an arbitrary parameter. My original definition was set based. Only worry about f. pretty sure the g used has no relevance.
I would say that g is more used to decide which operator to use rather than actually being an unknown factor in the equation.
 
8:31 PM
Oh, it seemed to me that the whole point of the question was about $g$... if that isn't the case, I fail to see the difference between the implied diff operator and the usual diff operator, as long as the diff equation is solved on appropriate intervals
 
...
@Hippalectryon solve y'' + 2floor(x)y' + floor(x)^2y = 0 in the other system. Notice how much easier it is to solve.
 
"the other system" ? Do you mean by the usual method ?
 
what're we talking about?
XD
 
@Astyx bonsoir
 
Basically my question is: what's the difference, when considering appropriate intervals, between the implied differential operator and the normal differential operator ? @TheGreatDuck
 
8:33 PM
@Hippalectryon the implied operator treats piecewise constants as constants. We've already discussed this at length a long while ago...
 
@Eric Are all compact, oriented flat 3-manifolds covered by R^3 due to the curvature classification or something?
 
@TheGreatDuck Oh, I was specifically referring to your question on MSE, where that's not (imo) as clearly defined. Hence my confusion.
I see what you mean now
 
it's the same object. I'm just leaving it to those who answer it to develop and or extract as needed.
 
There's a theorem that states that any complete Riemannian $n$-dim manifold with everywhere vanishing sectional curvature is covered by $\mathbb{R}^{n}$ @Balarka
 
I haven't proven any identities regarding it, so claiming such things would be without justification.
 
8:35 PM
Ok, great.
 
It follows from Cartan-Hadamard (which deals with $K\le 0$). The exponential map at any point of a complete $K\le 0$ manifold is a covering map. @Balarka
 
hi chat
 
hi @Semiclassic
 
@TheGreatDuck Just to be sure (it's been a while), the implied differential operator on $f$ is the normal differential operator on $f_1$ where $f_1$ is just like $f$ except we've "removed" all the jumps by negating them (as in subtracting the jump series) ?
 
So $TM$ is going to be a quotient of $T\Bbb R^n$ by $\pi_1(M)$ (extending to tangent spaces). Not sure how that helps, though. Just throwing everything I can.
@TedShifrin Ah yeah that's the name. Thanks for the full statement.
 
8:38 PM
@Hippalectryon please have you an idea for this math.stackexchange.com/questions/2300558/a-not-continuous-map
 
The right book to look at (which I no longer own) is Joe Wolf's book on Spaces of Constant Curvature.
Lots of beautiful stuff in that book.
 
Space forms are cooool
 
Vocab question that I'm forgetting.
 
I should have learnt more Riemannian geometry.
 
the isoperimetric problems in space forms are super rad problems
 
8:40 PM
Suppose I have a curvilinear coordinates $(u,v,w)$ for, say, R^3. (e.g. spherical, cylindrical, or something more obscure)
What are lines of constant $u,v,$ or $w$ called?
 
@Hippalectryon I think it's a bit more complicated than that at this point. Consider the absolute value function as a decent example.
 
Oh, a @Balarka, BTW ... remember that question about characterizing affine subspaces (open line segment from point in the set to point outside the set not crossing the set)? I had a clunky proof you improved slightly? A guy gave a totally straightforward verification that it's an affine subspace (using my first paragraph) just checking that if you translate to the origin you get a linear subspace.
 
@Vrouvrou Where does the question come from ? It is continuous
 
@EricSilva: I'm still sticking to complex geometry and projective differential geometry :P
 
@Hippalectryon in fact, that function is specifically the one that shows that the implied differential operator cannot give a unique value. The sharp corner's implied derivative could be +-1.
 
8:41 PM
I guess they'd be the curvilinear axes? but that seems wrong.
 
coordinate curves, @Semiclassic, in general for any parametrization
 
Can $F_2$ appear as fundamental group of a flat manifold? That boils down to asking whether $F_2$ can act freely and linearly on $\Bbb R^n$.
 
Isoperimetric problems came up a loooot in Willmore stuff @Ted so I've been influenced by Neves lol
 
hmm, okay.
 
Well, it only stands to reason, Eric.
 
8:42 PM
(someone gave curvilinear coordinates for R^2 such that the coordinate curves are archimedean spirals, and I wanted to figure out if there's already a name for it.)
 
That probably can't happen?
 
@TedShifrin Sure enough, but since it's only on one point it shouldn't change the diff equation's solution, except on that one point, and by continuity it wouldn't change it at all
 
@Hippalectryon I think the whole jump series thing relates more of the concept of antiderivatives and discontinuous functions. It has little bearing on derivative taking.
 
That's a representation theory question, @Balarka. Page tern.
 
All the Federer stuff terrifies me though
 
8:43 PM
GMT is hard and technical stuff, Eric.
 
I am pretty sure this can be proved by geometric group theory. Discrete groups of isometries of R^n should never be Gromov-hyperbolic.
 
yeah, I need to try to learn some of it this summer cause of summer school, hopefully I'm not too lost @Ted
 
@TheGreatDuck Anyhow, you should define clearly "weak solution" or I can't really say anything
 
Eric: You can't do everything. Bryant is already a big project :P
 
Hi @all
 
8:44 PM
Salut, JeSuis.
 
ik ik, but attending the summer school is helping me pay my rent
 
@TedShifrin comment vas-tu ?
 
otherwise I'd be sticking to my self study only
 
Oh, that's a summer school project, Eric. I thought it was another one of just yours.
Ça va, merci, @JeSuis, et toi?
 
8:45 PM
yeah
 
@TedShifrin ça va mise à part la chaleur :p
@Hippalectryon ça va?!
 
J'ai regardé un peu le temps, @JeSuis. Quand j'arriverai à Paris il fera plutôt normalement chaud, pas trop.
 
@TheGreatDuck If by "weak solution" you mean "continuous solution", then it seems clear to me that continuous solution for usual operator $\Rightarrow$ continuous solution for implied operator
@JeSuis Très bien et toi ?
 
@TedShifrin Ah tant mieux, c'est plus agréable pour visiter.
 
@Hippalectryon I think it is something one can google tbh. I asked a question on what our undergrad differential equations classes meant as "solutions" as sometimes they are not differentiable.That was the answer,so I altered the conjecture so that it applied to our level's concept of solution.If you think it is intriguing, feel free to ask a question on what they are. Plus,I was mostly just sharing the implied differential's rigorous definition with you(only took way too long to occur to me).
 
8:48 PM
@Hippa: Why do you keep pinging me by mistake!??!
 
@Hippalectryon ça va! Tu seras toujours sur paris le 10juin ?
 
@TedShifrin My bad
@JeSuis oui
 
@Hippalectryon J'ai donné mon numéro à Astyx, pour organiser le repas avec Ted.
 
@Hippalectryon all differential equation solutions are continuous. Weak solution is some weird foobar way of making solutions always exist except when divergent.
 
This should be Paul Plummer-type questions I am coming up with right now but that man has not been here in a while.
 
8:49 PM
it's just technically y' = abs(x) has no solution
 
$18x=\pi$. Evaluate $$\frac{4\tan 7x}{\cot x -\tan x}$$
 
whereas our classes and such would claim it has a solution
shrugs
 
I'm gonna go think about galois theory
bye chat
 
Bye Eric.
 
byes
 
8:49 PM
Good Bye
 
@TheGreatDuck The issue is that Wiki says that there are many definitions for weak solution :(
 
um what...
 
@JeSuis Ok parfait
 
@AbdullahUYU There's a cheap way to solve this. Namely, look up the tangent angle addition identity.
 
8:50 PM
@Hippalectryon you mean weak solution? Implied solution is my made up term. XD
hmm
:/
 
ok. wait a minute
 
Tu as son numéro ?@Hippalectryon
 
go in my recently asked questions and read up on it if you want
feel free to ask for clarification
 
@JeSuis Non pas encore
 
oh, wait. I'm oversimplifying.
 
8:51 PM
I don't see it yet, @Semiclassic.
 
Yeah, I'm being silly. Disregard my angle addition nonsense @AbdullahUYU
 
@TheGreatDuck The one I have in mind is that there's a weak solution on I iff there's solutions on each element of a disjoint cover of I
@JeSuis pris, tu peux l'effacer
 
But I'm not seeing why you can't plug in $x=\pi/18$ directly, since the denominator is nonzero there.
 
I as in an interval?
 
@Hippalectryon ;-)
 
8:52 PM
@TheGreatDuck Or a reunion of intervals, yes
 
ok
I wasn't expecting you to solve it btw.
 
(though I also don't see how that'll simplify)
 
non-zero but not directly computable
 
Plug in as in a calculator, @Semiclassic? This is meant to be done sans calculator.
 
@Hippalectryon Sinon comment se passe ton année ?
 
8:53 PM
I was just sharing it with ya cause you were curious way back when.
 
@TheGreatDuck It doesn't seem too hard though
 
Et des news de GrandDODOM (je ne sais plus très bien le pseudo)
 
well if it isn't that hard and you solve it then applause.
 
I guess it's not obvious to me that there will be a nice non-numerical answer.
 
8:53 PM
X1,...,X100 are independent random variables with the same density function f(x)=4x(1-x^2) for 0<x<1 . Find P(50 < sum of all Xi < 60)
Could someone help me with that?
 
I may be giving up too soon, though.
 
you just verified something I've been using without justification for over a year and a half.
 
Here's a hint @AbdullahUYU and @Semiclassic: That expression equals $4\tan 7x\tan 2x$.
 
oh, lol
 
@JeSuis (message de test envoyé) ça va, mais j'attend la 2A avec impatience
 
8:54 PM
I'm not entirely sure we are equipped to resolve it at our level.
 
@Hippalectryon pourquoi?
 
this falls into the ugh part of trig functions for me, though.
 
LOL
 
@TheGreatDuck Well anyhow, if there's any development or if you make any final document about the whole theory, don't forget to send me a copy :-)
 
Not that far into it, to be fair. But a bit ugh.
 
8:55 PM
except for 4, it should be 8 i think
 
@TheGreatDuck As for this specific question, as always you should formalize it more. I may be able to solve it, but I need to be sure that we're talking about the same thing (especially about those weak solutions)
@JeSuis Pour pouvoir choisir mes cours
 
Do you see what the answer is @AbdullahUYU?
 
@Hippalectryon ah ok. Tu vas choisir quoi ?
 
@Hippalectryon I think I exxagerated its scale back then. It's just a method of solving diff. eq. like auxilliary equations. If it proves useful and correct then people might use it one day. Otherwise, there's nothing important within it for the sake of itself.
 
@JeSuis Ah et sinon je suis choisi pour participer à l'IPT 2018 avec l'X :D iptnet.info
@JeSuis Physique, méca, un peu de chimie et de maths
 
8:56 PM
@Hippalectryon I'd have to ask a question on how to formalize that. I don't even understand the wikipedia article.
XD
 
Not yet
 
Did you figure out my hint?
 
@TheGreatDuck But it's quite interesting and lots of fun, don't you think ?
 
yeah
 
So what does $\tan 7x\tan 2x$ suggest you look at?
 
8:57 PM
$9x=\pi/2$ i got it
 
@Hippalectryon Des félicitations s'imposent!
 
@JeSuis merci :-)
 
OK, @AbdullahUYU.
 
@Hippalectryon I think that it's fun to solve weird differential equations but the actual proof of the main conjecture seems... superfluous and best left to those who eventually learn distribution theory. If I ever do, it will be years from now. So, for the moment I am more interested in geometry and tangible things related to my programming projects.
 
Il faut que je félicite @Hippa? Zut, alors.
 
8:58 PM
also, I have 3 months to help a high schooler make a video game for extra credit so... that tends to occupy my free time.
 
@TedShifrin Lol
 
Can nobody help me?:c
 
@TedShifrin have you ever proven stuff about weak differential equation solutions before? Me and @Hippalectryon aren't sure how to interpret them. We're just trying to understand their rigorous definition in the sense of how must undergrad classes treat them as the actual solutions to differential equations. Bad practice, I know, but he's curious.
 
@TedShifrin :P you don't have to
 

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