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3:01 PM
I wonder if there is a connection between tropical geometry and the monomial stuff I did...? One of the purposes of the monomial stuff is that in some sense you are making parts of the problem linear, so it is easy to calculate. @AlexClark
 
Did any of you see A Beautiful Mind ?
[I haven't seen it yet]
 
@AlexClark Oh and as someone interested in geometric group theory and things related, I feel obligated to mentions this paper "Geometry of the space of phylogenetic trees" By Billera, Holmes, and Vogtmann
 
[The link is SFW contrary to what the link may suggest]
 
user147690
@Clarinetist Yep, great movie
 
user147690
@PaulPlummer Haha I'll check it out now
 
3:03 PM
@AlexClark Yeah, apparently the mathematician featured in that movie died yesterday
 
Hmmm, I don't remember the movie being any good
 
user147690
@Clarinetist Yeah I saw in the star bar
 
user147690
@PaulPlummer What? I guess you don't like dramas?
 
Dramas are fine, I don't remember the movie to well, and I am pretty sure it wasn't any good
 
user147690
@PaulPlummer whhhhhhattttt[you are somewhat right, it isn't very rewatchable]
 
user147690
3:05 PM
@PaulPlummer Did you like good will hunting?
 
That was good
 
Yup that is it
 
user147690
@PaulPlummer It'll probably be good to go through
 
Huh, I have not given the paper a read (for some reason I thought it was 60 pg), I think I will read it.
Well I am going to make breakfast and read a bit of this, probably won't be back for 30 minutes, I suspect you will be sleeping @AlexClark
 
user147690
3:12 PM
@PaulPlummer I hope so
 
user147690
@PaulPlummer So goodnight to goodmorning!
 
Yes goodnight,
 
user147690
@PaulPlummer Before you go, I ruined my chat graph
 
Haha
 
crl
@crl Does someone have a good way to solve this? or to prove the unicity of the solution?
$a_1+(13*a_2/a_3)+a_4+12*a_5-a_6-11+(a_7*a_8/a_9)-10=66$ with $a_i$ elements of $\{1,2,...,9\}$ non-repeated
 
user147690
3:29 PM
@crl Move $10$ and $11$ over to the right, and consider what numbers leave $\frac{a_2}{a_3}$ integer and same with $\frac{a_7a_8}{a_9}$
 
user147690
Three options for the first(including a class of options for 1 on the denom), more for the latter
 
crl
for the first there are: 9/3, 6/3, 8/4, 8/2, 4/2, and i/1 for any i>1
 
user147690
@crl True, apologies I gave it very little thought
 
user147690
It's 1:30am and I am normally asleep
 
crl
hehe no problem
 
3:34 PM
Really basic linear algebra question. If $X \in M_{n \times p}$, I would like to prove that $N(A^{T}) = C(A)^{\perp}$, $N$ being the nullspace, $C$ being the column space. I have the following: we have $$A^{T}x = \begin{pmatrix}
c_{11} & \cdots & c_{1n} \\
\vdots & \ddots & \vdots \\
c_{p1} & \cdots & c_{pn}
\end{pmatrix}\begin{pmatrix}
x_{1} \\
\vdots \\
x_n
\end{pmatrix} = \sum_{i=1}^{p}\sum_{j=1}^{n}c_{ij}x_i = 0$$
where $c_{ij}$ is the value of the $i$th column and $j$th row of $A$.
Now $C(A) = $span of the columns of $A$, so there I'm a bit stuck.
 
crl
I would have called them $a_{ij}$ then ith column and jth row of $A^T$ you mean ^
 
Okay, that makes more sense :P
 
@crl How did you delete a part of your sentence?
 
@crl Wait, I indexed them wrong?
 
crl
@evinda ---I would have called them $a_{ij}$ then---
 
3:42 PM
Is there an easier way to show $N(A^{T}) = C(A)^{\perp}$ rather than play around with matrix components and sums?
 
I tried it but I don't get that what you wrote.. @crl Where else did you use $$ ?
@crl Or did you write exactly this: I would have called them $a_{ij}$ then ?
 
Yes, @Clarinetist. Either understand constraint equations for $Ax=b$ to be consistent, or think about why $N(A) = R(A)^\perp$ and apply this to $A^\top$.
Hint: $Ax=0 \iff x$ is orthogonal to all the rows of $A$.
 
@crl A ok.. Thank you!!! :)
 
I think this question deserves a good answer.
I haven't thought a lot about it, but I always thought that Mayer-Vietoris can actually be derived algebraically from doing homotopy theory on chain complexes.
 
3:56 PM
@BalarkaSen Lol, I was reading the question and was about to say here "ten quatloos that RB posts something about one of his books", then I saw the answer below.
 
haha
 
Although it looks like it could be one of the more relevant posts he has done (I am not familiar enough with the ideas to say if it is or not)
 
hi guys
 
It might or might not be, but I am not gonna look through each of his books to check if it is or not :P
 
Haha, look at the comment on his answer @BalarkaSen
 
3:59 PM
lol at the comment
yeah, I was just looking at it.
 
I think he has only two books (Topology and Groupoids and the free one he mentions)
I actually own topology and groupoids and so far I like it
 
bah.
 
although the behaviour on math.se is sort of annoying
Well the comment was removed... @BalarkaSen
 
His book isn't bad. His spam, and posts on essentially unrelated questions, are.
 
I agree @MikeMiller
 
4:18 PM
@TedShifrin That makes sense, so $A^{\prime}x = 0 \Longleftrightarrow x$ is orthogonal to all of the columns of $A$... is it really that simple?
0
Q: Orthogonal complement of column space is orthogonal to null space of transpose

ClarinetistLet $X \in M_{n \times p}$. $C$ denotes the column space, $N$ denotes the nullspace. I would like to prove $C(X)^{\perp} = N(X^{\prime})$. Let $X = \begin{bmatrix} x_{11} & \cdots & x_{1p} \\ \vdots & \ddots & \vdots \\ x_{n1} & \cdots & x_{np}\end{bmatrix} = \begin{bmatrix} x_1 & x_2 &\cdots &...

 
Yes, @Clarinet.
 
So it just follows immediately. Wow. Thanks @TedShifrin
 
Hi @Balarka
Goodnight @Mike
 
@TedShifrin: Morning. That submersion question is mostly solved now; there remains the question of whether there are submersions $S^{4k-3} \to S^k$ for $k \geq 4$, $k$ even. Qiaochu solved most of the cases; I, uh, solved $S^5 \to S^2$.
 
Qiaochu is impressive.
 
4:27 PM
Now to learn about SVDs, Genearlized Inverses, PPOs... fun stuff
 
hi
 
But, then, @MikeM, all of us MIT/Berkeley folk are. :D
 
Awww ... :)
That was not a serious remark.
 
I know, I'm just kidding.
 
4:30 PM
math.stackexchange.com/questions/1270940/… if my field have 10x 15 units and if I fix a startposition, the starting position is standing up
 
Aha, right. May I ask a small question regarding complex analysis?
 
Hi everyone! I am interested in visualizing the convex cone of symmetric positive-definite $n\times n$ real matrices. Could please help me? I have just asked a question, if you like to take a look. Thanks a lot in advance!
 
Hello everyone, one question: Do you happen to know how to construct the lattice of S5? Is it possible? I try GAP but it says no 1st choice method found for `MaximalSubgroupsLattice'. Has anyone been able to do the lattice of S5
 
Does anyone know if Dummit and Foote plan to release another edition? I noticed the plethora of errata...
 
After all, you came from Berkeley... how good could they be?
 
4:30 PM
can I move my 1x2x4 cuboid to every endposition ?
 
Sorta my point, Mike.
 
Oops
 
ask, @Alp
 
how good are people in Berkeley @TedShifrin ?
 
Varied, @Karim. You mean students?
 
4:32 PM
yeah
 
Right. So, say, p(z) is an even polynomial, all the roots of which are of modulus < R, for some R.
 
Yeah, varied. Some superstars, many duds.
 
I need to try and define a holomorphic function h(z) on the region { |z| >R} such that, h^2 = p.
 
You know what baffles me? A lot of people that I saw on the actuarial forum that I used to go on have been asking the question Should I go to UCLA or UC-Berkeley for a career in actuarial science and I was just like... facepalm
 
4:34 PM
Now, I need to, in a sense, talk about why this exists and is well-defined.
 
why @Clarinetist?
 
I know, I can say, h = e^{ (1/2) log(p(z)).
 
Ok, @Alp. Think about Morera's Theorem, perhaps.
 
I guess its same as if you go to ucla or berkley as long as your good in what you do then its the same
 
I wouldn't go that route.
 
4:35 PM
@KarimMansour IDK, if you manage to get into *any* of those schools, I would imagine you would have other options. Most people pursue actuarial because they feel that have no other options.

Actuarial puts little stock into what you actually do at the institution you go to, and as long as you have a GPA of 3.5+, you have a good chance of getting hired.
 
@Ted Salut, j'ai vu ton message concernant la courbe d'hier. Dommage qu'on puisse pas arriver à caractériser le cercle de cette manière
 
@KarimMansour Of course, that's assuming you pass a decent number of exams
 
Salut, @LeGrand.
 
Hmm, fair. Morera says that if every integral of a continuous function around a closed loop in my domain is 0, then, the function is holomorphic.
 
4:36 PM
I might go to US in my phd
I am still debating
 
But, I'm puzzled by why I need the polynomial needs to be even?
Or, do odd polynomials work just fine, as well?
 
Peut-être symétrie de toutes ordres?
 
@Clarinetist you live in US?
 
@KarimMansour Yes I do
 
No, @Alp, with odd you need a branch cut to infinity.
 
4:38 PM
@TedShifrin would it make a difference if I stay in canada for phd or go to US for it?
I see
 
@KarimMansour I'm interested in knowing the same. My impression is that Canadian standards are on average higher than U.S. standards, but maybe I'm wrong
 
What do you mean, you need a branch cut to infinity?
 
@Clarinetist so after your done your actuarial degree are you planning to do degree in math or just as a hobby ?
 
Actually, the main thing is well-definedness, @Alp.
 
Of the logarithm, yes?
 
4:40 PM
yeah I wanted to know if I go to like university of Toronto or mcgill is it same as going to one of ivy league in US
 
@KarimMansour I quit my actuarial degree after 3.5 semesters, switched to statistics in my last semester and graduated exactly a year ago (concidentally :) ). Worked in actuarial science for the last year, got bored of it, and am now starting a M.S. statistics degree while working in healthcare technology.
 
@Clarinetist
 
It's not a good time to ask question here, I think :P
 
oh I see
 
@KarimMansour IDK. It seems that people only know about those if they try applying for them where I'm from...
 
4:40 PM
Try $\sqrt z$ versus $\sqrt{z(z-1)}$.
 
@Clarinetist Heya!
 
@N3buchadnezzar Hey, got more spreadsheet stuff?
 
I see
 
@Clarinetist You read my mind ;) How can i update A2 when A1 changes? But I want to also change A2 manually
 
@KarimMansour You know, if there's one thing I've learned in the last year, it's that I need to do what I actually enjoy during the day or I'll go insane
 
4:42 PM
Depends on quality of place in US, @Karim, and quality of your adviser and thesis.
 
@N3buchadnezzar Pretty sure you can't do that. Either manual or automatic (lol)
 
like for example comparing berkley to UOFT
 
@Clarinetist After some hectic googling, I came to that conclusion as well :p
 
Hello everyone, one question: Do you happen to know how to construct the lattice of S5? Is it possible? I try GAP but it says no 1st choice method found for `MaximalSubgroupsLattice'. Has anyone been able to do the lattice of S5?
 
You know what's funny @KarimMansour. People ratted me out on the actuarial website I was on because I don't like putting my time into things I don't enjoy. :P
 
4:44 PM
people from your class ?
 
If you write a top-notch thesis at Berkeley, you win. A mediocre one ... Meh. What isUOFT?
 
university of Toronto
 
Confusing, @Karim.
 
@KarimMansour Not necessarily, there's an actuarial forum of a bunch of people who want to remain anonymous. A small minority (myself included) choose not to. It's breeding grounds to be mean to each other
Wait UOFT, how do you get University of Toronto from that?
 
U of T
 
4:46 PM
yea
I don't know we always refer to university here by first letter like mcgill UOFM
 
@KarimMansour Another suggestion
And this one is absurd. Just absurd. I don't know how anyone can play piano like this.
 
I think I'm going to make an omelet
Btw @KarimMansour, this is the original version of the first one I sent you (the Vocalise). It was originally written for Soprano and orchestra.
 
I like the vocal one better
 
Then you'd probably like this, the Zdes' khorosho by Rachmaninoff
 
4:55 PM
@Clarinetist Perhaps a bit more advanced, but... How can I automatically import a CSV file? The problem is at the website, one has to download the file. I have problems using =IMPORT(vinmonopolet.no/api/produkter)
 
@N3buchadnezzar OOH fun. Well, in my experience, I usually have to download it to my computer. You really only have two options: 1) learn how to code in VBA (a pain to do for this sort of task) or 2) import it manually
 
I guess I will ask some of my computer geek friends to give it a go :p
 
@N3buchadnezzar Importing it manually isn't terrible. What are you using? Google Docs?
 
@Clarinetist Yeah, I was able to import it just fine after downloading it ^^
 
:) Good.
 
4:59 PM
Having to filter out what I need from 5000 entries is going to be a bitch though
 
very nice I do @Clarinetist
 
@N3buchadnezzar Imagine working with about 500,000 and filtering that out. During my last few days at my job, I would be waiting for three hours! I mean THREE HOURS! to get a filtering job done
And then a filter on top of that filter....
:P
 
@Clarinetist Say I know that the row i want contains 1039001, how can I get that row in another spreadsheet? I know I can google this, but since it seems this was your horribly? boring job. I might ask you :p
 
Haha @N3buchadnezzar Let's see, what you would do is go into your new spreadsheet, let's say you want to put what is in row 1039001 into row 1 of your new spreadsheet
Assuming the values start at column A, in A1 of your new spreadsheet, type =A1
Then press ENTER
and then you should get the value
Then click on cell A1 again but don't double-click it
You should see some sort of little wedge thing on the bottom right on the cell.
Click and drag it to the right as far as you want and you will get the row values
It's horribly inefficient, but that's Excel for you
OOPS
Actually, it should be =[WorksheetName]!A1
But everything else should be right
WorksheetName is the name of the worksheet you reference
 
@Clarinetist Not working, sigh
 
5:11 PM
@N3buchadnezzar Step by step
So your values are in row 1039001, right?
 
@Clarinetist Oh no, that is its reference number. I am actually looking for the row that contains that value.
 
@N3buchadnezzar Okay now THAT is a different question
Oh I misinterpreted you Sorry @N3buchadnezzar :P
 
Pardon my horrid English. I tried " =SEARCH(1039001,'products!'B3000:B5000) "
 
@N3buchadnezzar So you want the row number for 1039001 and it's somewhere in B3000:B5000?
 
@Clarinetist Yeah, I tried with B2:B first, but I got an error, so I tried narrowing down the range.
Gives me #VALUE , "Error In SEARCH evaluation, cannot find '1039001' within '1301'."
 
5:16 PM
@N3buchadnezzar I'm gonna try this one out... let you know what I find
@N3buchadnezzar This looks like a textbook case for VLOOKUP. What are you using this 1039001 value for?
 
@Clarinetist I need to extract a few column values from that row
 
@N3buchadnezzar Yeah, VLOOKUP is your best friend
I'm going to work inside your Sheet2 @N3buchadnezzar
 
@Clarinetist Yeah no problem =)
 
@N3buchadnezzar See what I did? I extracted the column after the number
 
@Clarinetist AJ4190?
 
5:21 PM
@N3buchadnezzar B1:AJ4190 is the entirety of your table
 
Ah right =)
I think I can manage the rest now, I tried hard doing this using SEARCH but alas to no avail.
 
@N3buchadnezzar So how you should think of this is VLOOKUP(reference_key, table_reference, column_number, FALSE). Always use FALSE at the end for an exact match on the reference_key.
 
VLOOKUP, looks earlly nice. Yeah, I looked up the definition ;)
 
The reference_key should always be unique if possible. @N3buchadnezzar Once you get really good, you can start using INDEXMATCH, but VLOOKUP is a nice start.
 
Yeah, the number I see now is unique.
 
5:25 PM
@N3buchadnezzar What's even more fun sometimes is that it's not unique and you need to do a VLOOKUP. In these cases, I would have to create a concatenated column of some sort so that the key is unique... Man, I do not miss those days
 
@N3buchadnezzar Once you get used to VLOOKUP, you may want to learn INDEXMATCH. See here: randomwok.com/excel/how-to-use-index-match .
INDEXMATCH is just a more efficient VLOOKUP.
 
@Clarinetist Can I do a HLOOKUP as well?
 
@N3buchadnezzar Yes, you can, but I have rarely had to use it. Usually it's good principle to create new values on rows, as in the worksheet you have
 
@Clarinetist Concretely I was thinking of using =VLOOKUP(B3,products!B1:AJ4190,2,FALSE) and wanting to get the price "pris" but say I do not know what column this lies in. How can I figure out that it is the 5th column?
 
5:32 PM
what the hell
physics book derive some equation by resorting to magic
 
@N3buchadnezzar I see what you're trying to do. Could I modify your sheet for you?
 
No problem =) Basically the goal is to get a simplified version of the big spreadsheet, only having the relevant colums.
 
@N3buchadnezzar I had to insert another row
 
@Clarinetist Yea, I saw. clever use of HLOOKUP
 
@N3buchadnezzar There you go, that should be right
 
5:45 PM
@Clarinetist Indeed. I think "=COLUMN(HLOOKUP(C2,products!$A$1:$AJ$2,2,FALSE))-1" Might be a tad shorter for retriving the number though, also no need for letters
 
Yep @N3buchadnezzar Notice also that I changed the reference_key to $B3, so that the column remains fixed
@N3buchadnezzar One thing to be careful with that is you want to change C2 to $C$2
I should probably change those as well
@N3buchadnezzar To test this, I'm going to insert another one
And it looks like dragging works, so the code should be good @N3buchadnezzar
 
@Clarinetist Thanks a bunch =)
 
@N3buchadnezzar Np, anytime
 
A last question. If I update the first sheet, does the second one also update. Or is there a button I must push?
 
Hi @Alessandro
Wie geht es dir? :)
 
5:50 PM
@N3buchadnezzar For your VLOOKUP, as long as you don't put it on manual calculation mode (I don't think Google has that), it should update automatically
 
Anyone wants to compute some group cohomology?
 
@Pedro of what group?
 
$C_p$ acting on $C_{p^2}$.
 
what's the action?
 
Oh look a group theorist @BalarkaSen :D
 
5:54 PM
Actually I want for $A=\Bbb Z[C_p]$ and $M=C_{p^2}$, ${\rm Ext}^2_{A}(Z,M)$.
Suppose that $\xi$ generates $C_p$ and $\sigma$ generates $C_{p^2}$, and assume that $i=1\mod p$. Then $\xi\sigma=\sigma^i$.
 
hallo @evinda jetzt besuche ich einen anderen Deutschkurs und muss deswegen sehr früh morgens aufstehen, apart from that (how do you say that in German?) very good :D und dir?
 
For $M=C_p\times C_p$, I proved there are two nonisomorphic structures up to isomorphis, the trivial one and $\xi(x,y)=(x+y,y)$, the one given by $\begin{pmatrix} 1&1\\0&1\end{pmatrix}$. For $M=C_{p^2}$, there are $p$ nonisomorphic structures up to isomorphism, which are $M_i$ under $\xi \sigma=\sigma^i$ for $i\equiv 1 \mod p$.
 
OK, no idea. All I know about group cohomology is that $n$-th group cohomology of a finite $G$ is the singular cohomology group $H_\bullet(K(G, 1))$.
 
Well, there is a canonical free resolution for $\Bbb Z$ as the trivial $A$-module, given by $$\cdots\stackrel{1-\xi}\longrightarrow A \stackrel{\nu}\longrightarrow A \stackrel{1-\xi}\longrightarrow A \stackrel{\epsilon }\longrightarrow \Bbb Z\longrightarrow 0$$
Where $\nu=1+\xi+\cdots+\xi^{p-1}$.
If you apply $\hom_A(-,M)$ to this complex, you get a cochain complex, and you can calculate the second cohomology group of that, which is ${\rm Ext}^2_A(\Bbb Z,M)$.
 
Aha.. You can say it ansonsten in german. @Alessandro
Am 5 Juni fangen bei mir die Prüfungen an.
 
6:03 PM
And since $\hom_A(A,M)\simeq M$ naturally, it follows that ${\Ext}^2_A(\Bbb Z,M)$ is $\ker(1-\xi)/{\rm im}\,\nu$.
 
@BalarkaSen: That's only true if your coefficients are in $\Bbb Z$ with the trivial action, which I guess is what Pedro is saying right now. You can actually generalize this to other coefficients, but this involves working with what are called local coefficients on your space $K(G,1)$, and this is essentially impossible to compute.
 
But I want to describe that as explicitly as possible.
 
Mr @Pedro!!
Damn, @Pedro's turned into a homological algebra.
 
For example, in the nontrivial case $M=C_p\times C_p$, $\nu$ acts by $0$ and $\xi-1$ acts by sending $(x,y)\to (y,0)$.
 
Hey, Pedro, did you get that job?
 
6:04 PM
@TedShifrin No news so far. =/
That means I haven't been told yes or no.
 
Which job?
 
Doesn't matter.
 
Darn. Well, I'm leaving town Wednesday at 5 AM, so if you need to me to do an email, I should do it soon.
 
Personal things.
 
Guten Abend, @Alessandro.
 
6:06 PM
Hallo @TedShifrin wie geht es dir?
 
Ganz gut, danke, und Dir?
 
@TedShifrin How's the moving going?
 
No one's been to look at the house in 16 days now, so I'm worried. We'll lower the price on Tuesday. ... Going to hunt for an apartment Wednesday AM.
 
mir auch :)
 
Studies almost done for this school year, @Alessandro?
 
6:13 PM
I'm not studying this year, I only attend German courses, I will (hopefully) begin the university in october
 
Oh, I misunderstood what was going on ... When do you find out?
 
I need to pass a german proficiency test
 
Die Mathematik ist schwerere auf deutsch :)
Heya @Fargle
 
@TedShifrin how many languages do you know ?
 
Only a few, @Karim.
 
6:15 PM
4?
 
english, french and german at least
 
Not really ... some knowledge of Russian and Latin, but basically French, German, English.
But I've forgotten too much of all of 'em.
 
You're forgetting math, @Ted :)
That's also a language.
 
I am forgetting most of my math.
I'm going to try to learn some Spanish, though.
 
Why do my sentences always get misinterpreted?
:P
 
6:17 PM
Your sentence was deliciously ambiguous, @Balarka.
 
Italian is much better than Spanish, in my totally unbiased opinion :P
 
I would agree, @Alessandro, but I will have to converse with Mexicans, so Italian won't help :)
 
A bunch of math grads are learning Russian next year, @TedShifrin
 
Learning learning, @MikeM, or reading to pass a math exam?
 
The first. You don't need to do anything to pass the language exam.
 
6:18 PM
i was joking, Spanish is much more useful :)
 
I think Italian is a beautiful language, @Alessandro.
 
I need to learn italian
Swedish and romanian and hungarian
 
My advisor lectured me on how to pronounce Hungarian names a few weeks ago.
 
spanish too
 
"If you want to work in this field, you need to know how to pronounce these."
 
6:20 PM
Good @MikeM
 
my gf is of hungarian origin so she is teaching me the language xD
loool
must be alot of good hungarian mathematician in your field @MikeMiller
 
Yes.
 
I know of only one Hungarian mathematician.
 
Lots of Hungarians in combinatorics and number theory.
 
Why are they going to learn Russian? Just interest? I was originality planning to learn Russian or German as a language requirement, but it seems more important to learn French nowadays @MikeMiller
 
6:22 PM
Interest, yes, @Paul.
 
Okay, wondering if there is a Russian come back :)
 
If your goal is just to read mathematics you don't need much more than a little bit of understanding of the language. I can read French without a dictionary perfectly well because I've had some amount of French training; I can read Spanish with some more effort...
But of course there's a lot to get out of a language than the ability to read math papers.
 
indeed ... I still plan to reread some French literature in my time.
 
I don't know French :(
 
You barely know English, Balarka .o.
 
6:25 PM
glares
 
I love a good glare.
 
when you take the wedge sum of spaces, does it ever matter which points you identify?
 
I still get the best grades on English in my exams, mind you.
yes.
 
I guess if one space is a disjoint union of spaces then it does
what if none of them are
 
It does for very pathological spaces too.
 
6:28 PM
@SamuelYusim: It matters if the spaces look different near some points than others, for one thing, like for $S^1 \vee S^1$. What you really want, for this operation to not matter, is if you're thinking of $X \vee Y$, there to be a homeomorphism on $X$ that takes any one point to any other point.
We say that the homeomorphism group acts transitively in this case. This is true, for instance, for connected manifolds.
If this is true, it doesn't matter what point in $X$ you pick; if it's true for $Y$, it doesn't matter what point in $Y$ you pick.
 
I guess you can whip an example up using infinite earring.
 
Or the cone over it.
 
But, for instance, consider $S^1 \vee S^1$. If I wedged on another circle at the wedge point, it would look different than if I wedged on another circle away from it.
 
true
 
6:29 PM
Oh, yes, I was thinking of spaces upto homotopy equiv.
 
why, then, does the notation seem not to encode this information
 
Abuse of notation.
 
to abuse notation you first need a good notation to abuse
 
you do?
 
in my mind you do
 
6:31 PM
@SamuelYusim: 1) One often does this with manifolds. 2) The operation is most useful for pointed spaces (for obvious reasons); the wedge sum is the coproduct of pointed spaces. So often $X \vee Y$ is written in the case that $X$ and $Y$ are pointed spaces...
 
ah, I didn't know what a pointed space was but I just looked it up
 
they are a useful notion.
 
don't throw a riot about connected sums later, which is only unique if one of your manifolds is non-orientable or if they both are and you demand that the sum be done in an orientation-preserving way... and even then it takes some work to show uniqueness... and we write it $M \# N$ :)
 
I dunno what connected sums are yet but I'll keep it in mind when I eventually see them
 
it's similar to wedge sum, but done in a way so that it actually spits out a manifold
 
6:36 PM
makes sense
 
Chuck a copy of disk from each manifold, and glue the two resulting spaces along the bd of the removed disk
 
neat
probably a more important question: how should I be thinking about open sets in a quotient space?
 
The simplest example of a quotient space is where you just pick a subspace $A$ and identify it to a point. In this case, there is a correspondence between open sets containing $[A]$ and open neighborhoods of $A$ in $X$. This is indicative of the general case.
In general points of the quotient space correspond to sets of points in the original space, and neighborhoods of points in the bottom space correspond to neighborhoods of those sets in the original space.
This is going to be hard to visualize if your equicalence classes aren't nice. $[0,1]^n$ is a quotient of $[0,1]$.
 
6:51 PM
so what happens to a neighbourhood of a strict subset of those points?
to use your first example, if $S \subset A$ and $N$ is a neighbourhood of $S$, what does $N$ correspond to in $X/A$?
I actually have to go, sorry
I'll be back later though
 
It doesn't correspond to anything, unfortunately.
 
@Alessandro Hast du dir gestern eurovision angeguckt?
 
@evinda Was ist das? Ich sehe fast nie fern :(
 
7:09 PM
Es ist ein internationaler Musikwettbewerb. Italien hat den dritten Platz belegt. Schweden hat gewonnen: youtube.com/watch?v=5sGOwFVUU0I
@Alessandro Wie findest du das Lied?
 
hi chat
 
Das Lied gefällt mir gut, und das Bühnenbild auch (can you use Bühnenbild for this kind of show or is it used only for the static elements of the scenery?)
 
Yes, you can use it... :) @Alessandro
 
8:29 PM
Sad news, John Nash died yesterday
 
@Alessandro, this is a really tragic way for someone to die. These are indeed sad news...
 
8:46 PM
@Vrouvrou, unfortunately not, but +1 for letting this be known soon (hopefully)! What about this?
 
8:58 PM
!!!
john nash
 
9:40 PM
RIP
 
 
2 hours later…
11:48 PM
does anyone know how to prove T3 and countable implies T4?
 

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