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10:00 AM
have a look at dummit-foote, @Committing. it has a small chapter on lattices. recommend you read it.
 
(although, like many things in mathematics there are other types of lattices, that is just the kind Balarka was referencing)
 
i was talking about lattice of subgroups, @DiscipleofBarney.
 
Yah, I guess I didn't make that clear, I was wanting to saying you were talking about the structure lattices
like the one I described
 
yes, sure, there are more general notion of lattices.
 
Sorry I got a coffee
Yes I have a pdf of D&F I will check it out for sure
 
10:06 AM
a quick look at lattices tells you a lot of things, along with the first isomorphism theorem.
 
I'll be taking a 4th year advanced algebra and a third year algebraic methods of physics next semester, so I have to work hard on algebra for the next 20 weeks
@DiscipleofBarney Essentially I try to get rid of the garbage on the site, noise that is worthless
 
for example, in the lattice of $Q_8$, you'll see a copy of the lattice of klein-4 group hiding inside it once you relabel $\langle -1 \rangle$ by $1$ and remove stuff below it.
that tells you that $Q_8/\langle -1 \rangle \cong V_4$
 
What's the idea of a 'presentation'?
 
@Committingtoachallenge Totally, the past couple days I have been using all my votes on old, bad, questions so Community will delete them.
 
It looks like a way of lying down cycles?
@DiscipleofBarney What's your method of finding these?
 
10:11 AM
@Committingtoachallenge well it's a way to write down a group conveniently
 
@BalarkaSen I have a doubt
 
if you have a huge group, then you can't just write the cayley table -- it'll take you years
 
@BalarkaSen Writing it out in a way that requires no more information? Like putting cycles down to save space
 
rather, you can write down a few elements and a few relation between the elements that "generates" all the other elements and relations.
@Committingtoachallenge kind of
 
@BalarkaSen Okay, I thought that was it, and I suppose that fits well with the name
 
10:13 AM
If the number of elements in a set A is 15 and the number of elements in set B is 25 what is the range of elements in the symmetric difference of A and B @BalarkaSen
 
I see you have already asked that question above, @Sayan. Didn't you get an answer already?
 
@Committingtoachallenge I havn't found t a great way, I have been using the search "answers:0 isanswered:no hasaccepted:no closed:no score:0" plus maybe some tag I want to look through anyways to see if there are any quesitons I would also like to answer. One could also try to get closed questions deleted so removed the closed:no, and maybe even the isanswered:no.
 
@Dis
http://data.stackexchange.com/math/query/272758/find-posts-with-0-votes-and-0-answers
 
@DiscipleofBarney he was not sure so I thought I would ask you
 
well, i'd say the question is not well-stated
what is "range of elements"?
 
10:16 AM
That's what I don't know
 
@SayanChattopadhyay That question doesn't make any sense, I would just get your prof to make it more clear.
 
I am really confused
 
so it's not a sensible question
ask your professor or whoever gave it to you what he means by "range of elements"
 
I called him and he said I have to find what the range of elements mean
 
figuring out definitions is not mathematics
 
10:19 AM
You... 'called'... him?
That is the weirdest thing I have heard
You can call your professors in your country??
 
@Committingtoachallenge Does that have any advantage over normal searching?
 
@DiscipleofBarney It lets you open a tab and ctrl click a list and sort through which ones are garbage and not very easily
@DiscipleofBarney I do around 10 votes there a day(very rarely an upvote here, but often I skip them if they have high view counts and aren't garbage)
@DiscipleofBarney and the other 30 are across the new ones
 
@Committingtoachallenge Since you know a bit about cosets, here is a somewhat interesting exercise for you : $\Bbb R$ be the additive group of real numbers and $\Bbb Z \leq \Bbb R$ the subgroup of integers. Can you figure out how the quotient group $\Bbb R/\Bbb Z$ looks like?
 
@Committingtoachallenge About the only reason why I want more rep is so I can vote to close. It does seem like a quicker interface, although adding a couple of restrictions so that a couple more relevant things are sorted out, to make the votes count as much as they can.
 
More precisely, show that $\Bbb R/\Bbb Z$ is isomorphic to the subgroup of the multiplicative group of nonzero complex numbers consisting of elements with absolute value 1.
This example is not only very interesting algebraically, but there is also a topological significance. The map $\Bbb R \to S^1$ that produces this isomorphism is an example of a covering space of topological groups. But you don't need that stuff to do it.
 
10:32 AM
Hi @Committingtoachallenge
 
@Committingtoachallenge I am scared I won't get my miracle.
 
Greetings
 
@Chris'ssis Hi!
 
@JasperLoy Hello!
 
10:37 AM
@JasperLoy That is expected(feeling scared)
 
Today I discovered something totally strange, I found an integral that produces the prime numbers in a perfect order. I mean the answer contains a string with the prime numbers in their increasing order.
 
indefinitely?
 
@infinitesimalsimplicio It seems so. I think the integral generates the whole prime numbers in the perfect increasing order.
 
I think you all know me enough to believe the mathematical things I say here. This is very strange to me too.
 
10:41 AM
have you told rob?
 
@infinitesimalsimplicio Rob seems away for 1 hour.
 
@Chris'ssis Wut
 
this could be big
 
@Committingtoachallenge Exactly.
 
@Chris'ssis Surely it stops after numerous iterations
 
10:43 AM
@Committingtoachallenge I cannot confirm this. I still check large values.
 
how large have you gone?
 
@Chris'ssis Is there some no disclosure thing I can sign to see this?
 
@Chris'ssis Interesting. But probably not impossible.
 
$2, 3, 5, 7, 11, 13, 17, 19$
 
I would say thought that I've never seen an explicit formula for the Copeland-Erdos constant. Can you post your integral?
 
10:46 AM
@Committingtoachallenge @Committingtoachallenge @BalarkaSen first I need to check that for larger values. This is done with some difficulty by Mathematica.
 
Yeah I don't think posting here is a good idea, probably by email instead(if she is willing)
 
@Committingtoachallenge It's no problem to show it, but first I need to check that and see if I need to communicate the result. Then I show you the integral, no pb.
I show it to you all.
 
(as I usually did with many of my results)
 
Ping me when you have decided to post it.
 
10:48 AM
@BalarkaSen Sure.
Mathematica has a hard time for larger values of $n$.
 
@Committingtoachallenge Why do you think so? There are numerous formulas for generating primes.
 
The integral is \int dp_n, LOL
 
dp_n is nonsense, as p_n is not even a continuous function.
 
Hi @JasperLoy, LOL
How are you feeling today @JasperLoy
 
@ᴇʏᴇs I am scared I won't get my miracle. I have made some plans for them to happen, but there are many obstacles.
@Chris'ssis Perhaps with your integral you are on your way to fame and fortune.
 
10:56 AM
Update
 
Has Did been banned before?
 
$$2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47$$
 
Looks like you have found it.
 
How did you find it? Intentionally or not?
 
A fields medal is on its way.
 
10:57 AM
If not deceived by the strong law of small numbers... but I'd say it's likely you have found a formula. It's not impossible.
 
It might also be $2^n=2(\text{mod} n)$
 
Very cool, although does it produce 57
2
 
Show the integral so I can play around with it on my mathematica :)
 
I'm eager to see it.
 
I look at it with the eyes of a kid (full of excitement).
@JasperLoy lol, I don't even know what that means, but first I need to make sure it works.
 
11:00 AM
I am dying @Chris'ssis plz
 
@Committingtoachallenge Don't die yet. Wait till you see me.
 
I want to get back to my assignment haha, but I have to see and play with this first
 
The prime numbers are represented like that $n1*\log(p_1)+n2*\log(p_2)+\cdots$
I mean they appear inside the logarithm in an increasing order. The numbers in front of logarithms are very ugly, large numbers.
 
What are these $n_1,n_2,\dots$?
 
That's even more interesting.
You should OEIS the $n_i$s too, just in case there is a sequence.
 
11:04 AM
Wait, another set is done. Let me put them on paper and post another update.
$$2,3,5,7,11,13,17,19,23,29,31,37,41,43,47,53,59,61,67,71,73,79,83,89,97,101$$
 
aww, 57 is missing.
 
What is special about 57???
 
@BalarkaSen Is 57 a prime number? $5+7=12$ :-)
 
i was only joking :P
 
11:07 AM
@BalarkaSen ;)
 
it's a grothendieck prime, nonetheless
 
57 is not prime!!!
A fields medal is still on the way.
 
It's a joke, read barney's link :P
 
@Chris'ssis Don't forget me when you win the prize! =)))
 
@JasperLoy I doubt a non-mathematician would ever win such a prize. ;)
 
11:09 AM
@Chris'ssis Miracles happen to those who least expect it.
 
@JasperLoy :D
 
$$\large\color{blue}{\text{:D}}$$
 
There can be miracles when you believe.
 
@Chris'ssis You might make Mathematics Chat room a major math journal
 
$$\large\color{red}{\text{:D}}$$
 
11:11 AM
I have made this chat my psychotherpy room.
 
$$\large\color{green}{\text{:D}}$$
 
@DiscipleofBarney hehe, I think @robjohn altready did that. :-)
 
now, now, let's not make this into a colorful smiley room.
 
Yes, I am procrastinating, where shall I learn complex analysis hmm
 
yes, your highness
 
11:13 AM
I'm preparing for a new update!
 
drum roooll...
 
@Committingtoachallenge I thought you were planning on doing algebra?
 
@BalarkaSen I love algebra so far, and am taking heaps of algebra next semester, but I am doing my semester now, and one of my courses is complex analysis(non optional course[but would have taken it anyway])
I am also doing functional analysis, and also cryptography+Coding theory
 
ah, i see.
 
11:16 AM
(it would be funny if Chris'ssis was just making this up and just posting sequences of primes)
 
@DiscipleofBarney I considered that
And started studying as a result
 
She should have waited a week for April 1
 
$2,3,5,7,11,13,17,19,23,29,31,37,41,43,47,53,59,61,67,71,73,79,83,89,97,101,103,‌​$ $107,109,113,127,131,137,139,149,151,157,163,167,173,179,181,191,193,197,199$
 
Give us the integrallllllllllll
 
I don't think you need math mode for just a sequence of numbers
 
11:21 AM
True, I guess it is habit
 
I do that too
out of habbit
 
@Committingtoachallenge :-)
I'm concerned about 341 ... (not sure if this appears - I hope it won't appear)
 
Why does it worry you?
 
Is there a reason to believe 341 will show up
 
Because $2^{341}=2(\text{mod} 341)$, and it's not a prime number.
 
11:25 AM
Ah, woried it might be showing you that sequence
 
Ready for a new update
 
We aren't getting the integral are we?
 
Or A216883 Primes p such that x^31 = 2 has a solution mod p.
 
enjoy the moment
this is Chris'ssis' moment
 
11:36 AM
$2,3,5,7,11,13,17,19,23,29,31,37,41,43,47,53,59,61,67,71,73,79,83,89,97,101,103,‌​$ $107,109,113,127,131,137,139,149,151,157,163,167,173,179,181,191,193,197,199$, $211,223,227,229,233,239,241,251,257,263,269,271,277,281,283,293$
OEIS doesn't recognize the primes numbers when add this input. They are all primes numbers in the perfect order.
One more update and then ... I wanna say something
$307, 311,313, 317, 331,337, 347,349,353,359,367,373,379,383,389,397,401$
Guys, I think it's about prime numbers!!!
 
I never ever met such an integral before.
 
You are solving for primes in fast linear time I imagine
 
@Committingtoachallenge You'll see the integral, for sure, but I need to do some steps before diong that.
 
11:45 AM
@infinitesimalsimplicio thanks! This is a moment hard to manage, really!
One of the questions is: how important such a result is?
 
I don't study complexity theory, but I am pretty sure I heard prime counting isn't linear time, and that would make this godlike if it is, but I don't know if you are in linear time either
 
1 hour ago, by infinitesimal simplicio
this could be big
 
As I mentioned, they appear in this form $$n1*\log(p_1)+n2*\log(p_2)+n3*\log(p_3)+\cdots$$
@Committingtoachallenge hmmm, I see.
 
But more importantly, it would give us hints on how primes are distributed
Less interesting for me for some really odd reason :P
 
12:00 PM
It works perfectly for the first 100 prime numbers (I just checked that):
 
So are you just going to be teasing us?
 
@DiscipleofBarney This is just real. As regards math, I never say words for the sake of saying words.
 
When do you plan to show the integral?
 
Maybe it's better to write $$Q1*\log(p_1)+Q2*\log(p_2)+Q3*\log(p_3)+\cdots$$
since they are rational numbers (the numbers in front of log).
 
there is a famous series, involving alternating between two different calculations for the next term, that always seems to converge to the same repeating set of three numbers, but it's never been proven that it does
can anyone tell me it's name, because this has been bugging me all day
 
@DiscipleofBarney THANK YOU
 
What do the Q's look like (aside from being rational)?
 
@DiscipleofBarney I cannot tell you how many times I've tried and failed to google that
 
@detly No problem
 
@Semiclassical Very large as we consider larger values in the generating integral. It's under investigations.
 
12:09 PM
Hmm
 
@Semiclassical It works for the first $100$ primes numbers.
(I didn't check more yet)
 
Sure.
It sounds like the chebyshev prime-counting function, though with coefficients
 
But those take prime inputs right?
I was under the impression perhaps falsely that Chris'ssis didn't take prime input
 
The chebyshev function? No
 
@Committingtoachallenge I only use natural numbers in the generating integral.
 
12:15 PM
All it does is sum up the logs of all primes smaller than $n$
But I think I was wrong to call it a prime-counting function
 
Well I am guessing it will either be stared or not posted by the time I wake up. @Chris'ssis Good luck, it would be really cool, and I am sure exhilarating, for it to be proven to generate the primes. (Depending on how it works maybe some alt and independent proofs of infinitude of primes or prime number theorem)
 
@DiscipleofBarney Thanks.
 
12:33 PM
$W \in (X_a \delta X_b)$ - Where does it state that delta can mean that W is either in $X_a$ Or in $X_b$ but not in both?
I can't find it anywhere
 
However, it might not be such a a clever thing as thought.
(more investigation is needed)
BBL
One more thing, it's not weird that we have primes numbers, since we take log of a natural number, say, and decompose it into such forms, but the fact that the log primes follow an increasing pattern, skip no prime number.
BBL
 
1:06 PM
How do I find angles between to linear functions?
$4x + 18 = 2x - 7$
 
1:17 PM
Whos there
 
@BenBeri: Do you mean the angle between the two lines $$y=4x+18 \quad\text{and}\quad y=2x-7?$$
 
yes
 
What tools are you using? Trigonometry? Vectors?
 
trigo
1 question, is the angle between -2x = 2x 90 degrees?
 
First, stop writing equality of the different linear functions. That's not correct.
No, it's not. The angle between $y=2x$ and $y=-x/2$ is $90º$.
Are you doing this with pencil and paper or using a calculator? Your first line makes an angle $\alpha$ with the $x$-axis where $\tan\alpha = 4$. What about your second line?
 
1:27 PM
I don't understand, im new to this
 
@BenBeri: For your second question, look for symmetric difference $A\Delta B$ (not little $\delta$).
 
ah
 
Well, I have no clue what you know and what you don't know. You need to know basic trigonometry to answer the question. You don't know that slope of a line gives the tangent of the angle? Draw a picture and think about it!!
 
Hi @TedShifrin
 
hi mr eyeglasses
 
1:34 PM
You know you should be sleeping when @Ted logs on
 
I should be sleeping, @Committing?
 
No I should be, because you logged on
 
Well, go to sleep! :)
 
It's almost midnight, but I needed to workout(just finished) because I failed to workout for 10 days and I am getting fat :'(
 
I'm sure your notion of "fat" is still 30 pounds lighter than mine. :)
 
1:35 PM
+I really needed to do some complex analysis
 
You guys need to stop hating analysis. If this turns into a room of utter algebraists, I shall never return.
 
@TedShifrin I was once literally anorexic(~56kg at 6ft) and then I reached 76kg pretty muscular, and now I am 84kg and much weaker
@TedShifrin Where did I hate on analysis here?
 
You didn't this time ... but you and various other people have been talking about hating analysis. :P
 
@TedShifrin Complex looks like it might be good, and I am not sucking at real analysis so much now, and we all know that doing good = having fun, doing bad = hating
 
Well, at 6', I don't call 84 kg fat. Maybe not trim, and maybe not built ... muscles aren't just weight-dependent :P
 
1:38 PM
I was benching 110kg and deadlifting 160kg and now I bench 90kg and deadlift ~120kg
 
Guys how can I prove that linear function inverse creates 90 degrees?
 
I don't think your table of equivalencies there is universal, @Committing. I have done well in things I didn't necessarily enjoy, and vice versa.
That is false, @BenBeri.
 
Probably lost 2-4kg muscle mass while increasing in weight by 8kg, so 10-12kg fat gain
 
@TedShifrin What do u mean?
 
@TedShifrin But were they solely learning related or other?
 
1:39 PM
You can start computing d(muscle)/d(weight), @Committing :)
 
@TedShifrin xD
 
@TedShifrin I was taught that if you inverse like x = -x/1 it always creates 90 degrees
 
Is that division by 1?
Oh lol
 
@BenBeri: That is not inverse. And you MUST stop writing ax = bx when you're talking about $y=ax$ and $y=bx$.
 
How is that called?
 
1:41 PM
What you should have been taught is that perpendicular lines have SLOPES that are NEGATIVE RECIPROCALS.
 
This is for programming @Ben?
 
@Committingtoachallenge Nope
 
@BenBeri What is this for?
 
yields the floor to @Committing
 
@Committingtoachallenge Just a mate saying that changing the slope from plus to minus or vice versa creates 90 degrees
 
1:43 PM
@TedShifrin But...but... I should be sleeping :P
@BenBeri Have you drawn any examples?
 
Which he looked at the scale for obviously
Did my sarcastic comment solve the problem?
 
maybe
 
What? Why maybe?
 
because I am not sure what did you say lol
 
1:46 PM
Does that answer your question then?
 
Well he says that WA graph is not accurate
 
He is either trolling or you are.
Sorry I am probably just tired my bad[he is still wrong though]
That 'inaccurate' graph weirdly had 2 different angles both of angle 90 degrees, pretty crazy
Did I do well minus the unnecessarily bad attitude[sorry Ben] @Ted
 
I'm not criticizing you or your attitude, @Committing. :)
 
1:54 PM
I need to formulate something in a mathematical way ...
 
@Chris'ssis Don't we all :)
@Ben Are you there, sorry for being rude, is it alright now?
 
A very nice question I created yesterday
 
I am ok, but I dont understand why the graph wolframalpha.com/input/?i=%7By+%3D+x%2C+y+%3D+-1%2F2x%7D doesnt show 90 degrees
or I am just being blind
 
@Chris'ssis How fast is your prime counting method? Did you do each by hand, or computationally
 
Find $f_n(x)$ such that $$\int_0^1 \frac{1}{\log(x)}+\frac{1}{\log^2(x)}+\cdots+\frac{1}{\log^n(x)}+f_n(x) \ dx$$ converges.
@Committingtoachallenge Computationally.
 
1:57 PM
Is that the prime one?
 
@Committingtoachallenge No.
 
@BenBeri Why do you think it should be 90 degrees?
 
Hi @Chris'ssis how is the integral?
 
opps sorry for that one lol
 
@JasperLoy Hi
 
1:58 PM
Good night, @Committing :P
 
@Committingtoachallenge Sorry, but that one wolframalpha.com/input/?i=%7By+%3D+2x%2C+y+%3D+-1%2F2x%7D
 
@TedShifrin Why are you goodnighting me lol
 
Because you said it was past your bedtime?
 
@BenBeri Why do you think that is 90 degrees?
 
@JasperLoy Related to the one with primes, it's still interesting for the fact it covers all primes in an increasing order following the patterns described above.
 
1:58 PM
@TedShifrin It is haha
 
Because of negative reciprocals or something?
 
Do you know vectors?
 
@Chris'ssis Have you shown them the integral?
 
@JasperLoy No.
 
@JasperLoy No, I have waited for hours lol
 
1:59 PM
no
 
@Committingtoachallenge I have waited for years to get well.
 
Well yes
 
@BenBeri Well yes? Can you write those directions(of the lines) as vectors
 
hi @Jasper ... I said something earlier I was waiting for you to star :P
 
@TedShifrin Let me see...
 
2:01 PM
oh vectors don't have reciprocals
 
$(1,2)$ and $(1,-\frac12)$ right?
 
well yea
 
$(1,2)\cdot(1,-\frac12)=$
Not bad, $0$ hence orthogonal(90 degrees)
 
@JasperLoy How should I specify mathematically that $f_n(x)$ cannot contains the terms with the negative signs above? I'd like my question be clear enough.
 
But it doesn't look like it, weird. Ohhhh the scale changes on WA because WA is annoying and QED
Good now?
 
2:03 PM
@Chris'ssis Which question?
 
Otherwise one might say, for example $$f_n(x)=-\left(\frac{1}{\log(x)}+\frac{1}{\log^2(x)}+\cdots+\frac{1}{\log^n(x)}‌​\right)+1$$
 
@Ben hellloo
I'm getting loopy as David would say lmao
 
@JasperLoy the integral I posted above ...
 
@Committingtoachallenge So the answer is that WA drawing in inaccurate?
 
@BenBeri No
@BenBeri It is accurate, butttttt the scale isn't 1:1
If the scale was 1:1 it would look like you think it should
 
2:05 PM
I mean the integrand must be consisted of $$\frac{1}{\log(x)}+\frac{1}{\log^2(x)}+\cdots+\frac{1}{\log^n(x)}$$ and thus $f_n(x)$ cannot cancel any of them.
 
If the scale was 1:100000000000000000000000 it would still be write(other than display error) but it would just be a straight like on the axis
 
Ahh i see
 
Whatever axis that is, too tired to work that out right now
 
write = right, hence goodnight @Committing :P
 
I know roflmao
Nice rhyme though I will sleep because it was too good
 
2:06 PM
I no you know.
 
Thanks @Ted I can rest piecefooly naow
 
@Chris'ssis Hmm, I don't know, cannot think now.
 
Cya guys, hope that helped @Ben
 
@Committingtoachallenge you're da boss
 
@JasperLoy OK. If you have any idea, let me know. No hurry with that.
 
Yay scales are 1:1 :)
 
@Chris'ssis I just got back from dinner with a friend. Pork with curry!
 
@JasperLoy :-) You're not a muslim, that's sure! :-)))
 
People are queuing up for ten hours to pay respects to my dead first prime minister.
Many people fainted and had to be carried away.
Even my mum went.
I did not go.
The only person I would pay respects to is my mum.
4
@Chris'ssis I am sort of Buddhist. One day you may want to study Buddhism.
 
2:13 PM
@JasperLoy I might reach this way the Nirvana of integrals. :-)
 
@Chris'ssis In a way, Buddhism explains science and other religions to me.
 
@JasperLoy I realize every day that the complexity of life becomes deeper and deeper to me, it's like a black hole from which no one escapes. I lost much of my courage to find a meaning in all things that happen around.
Life is too complex to me to ever understand anything.
 
@Chris'ssis I have lost most of my will to live on. I have struggled for too long with mental illness.
@Chris'ssis Like you said, sometimes there is nothing to understand. Things just are.
 
@JasperLoy Still, life is beautiful, and if many things happen without a meaning, that's not a reason to give in, but we can give noble purposes to our lives. Trust me, it is worth living your life and never give up.
 
@Chris'ssis I hope so. Maybe the meaning of my life is to meet you one day, LOL.
 
2:19 PM
@JasperLoy :-)))))
 
@Chris'ssis I am wondering why those people don't want to give you the job.
 
@JasperLoy Asking too much for them? That's the reason (well, they think it's too much, but no, it's less).
 
Guys is slope is just the tangles of the angle?
 
@BenBeri Yes.
@Chris'ssis Maybe ask less?
 
@JasperLoy So how can I turn a slope into an angle?
 
2:22 PM
Take inverse tangent function? Or use magic.
 
thanks
 
@JasperLoy This is a possibility I don't embrace that much.
 
@Chris'ssis Do you use Windows?
 
2:40 PM
hello - off topic. for a power series are "convergence" and "uniform convergence" equivalent?
 
@JasperLoy Why do you ask?
 
@Chris'ssis I am using Linux.
 
@JasperLoy Ah. I'm using Windows.
 
@Chris'ssis When I am rich, I will buy Windows in future.
 
@JasperLoy Maybe you simply like Linux more. :-)
 
2:47 PM
@Chris'ssis Windows is actually much more convenient in many ways. Also Microsoft Office is much much better than LibreOffice.
 
@JasperLoy Agree.
 

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