For $0 < x< \infty$, let $\phi (x)$ be positive and continuously twice differentiable satisfying:
(a) $\phi (x+1) = \phi (x)$
(b) $\phi(\frac{x}{2}) \phi(\frac{x+1}{2}) = d\phi(x),$ where $d$ is a constant.
Prove that $\phi$ is a constant.
I'm given the hint let $g(x) = \frac{d^2}{dx^2} \log \phi (x)$