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7:03 PM
Got a pirated copy. Only your books don't have pirated copies @TedShifrin.
 
Hi @Ted. How's things?
 
I didn't hear any of that, @Balarka.
According to some, my books do have pirated copies, and I've found one of 'em myself.
@DanielF !! You still exist?
 
Can guess what happened to the pirator, @TedShifrin...
 
@Balarka got smacked? @Ted
 
7:04 PM
Anyhow, I would expect Jim's book to be quite informative, @Balarka.
 
@TedShifrin On and off. I won't exist tomorrow and most part of Friday, visiting family.
 
Well, happiest of Weinachten to you, @DanielF.
 
@TedShifrin I'm downloading it right now.
 
@TedShifrin Thanks.
 
Are you three done with mod training school?
 
7:06 PM
@TedShifrin No, it will take a bit longer until we will roam freely. Still learning this and that.
 
I'll try to misbehave to give you practice :)
 
Hyperbolic geometry over $\Bbb H$ involves quite a lot of analysis.
 
uh huh ... complex analysis
 
@TedShifrin Check whether you can find Rene, that might cause a little commotion.
 
I have not run into him, whether advertently or inadvertently.
 
7:08 PM
@DanielFischer haha
 
Jim took something like 8 quarter courses from me, @Balarka, as an undergraduate.
 
@TedShifrin you must know him quite well then
 
Haven't seen him in years, though ...
 
@TedShifrin Trying to teach arithmetic, or is "eight quarter courses" something different from "two courses"?
 
Quarter as opposed to semester, so three quarters to the academic year :P Don't ask me about fractions @DanielF
 
7:11 PM
Ah, that makes sense.
 
Three quarters = 1 year, that makes perfect sense
 
Officially, semesters are trimesters (summer) and there really are 4 quarters because of summers.
I beat you to it, @Studentmath.
 
Ah, he PhD'd from Stony Brook, it seems.
 
Wait, there is Spring, Winter and Summer - ain't that 3?
 
Yes, @Balarka, with a very famous Kleinian groups guy.
Fall, Winter, Spring ... + Summer @Studentmath
 
7:13 PM
Oh. It's very different from ours then
 
Semesters, @Studentmath, we have Fall, Spring ... and then summer.
 
Wait I think I heard of Bernard Maskit from prof.
 
Not surprising, @Balarka.
 
Ah. I'm confused.
 
@Balarka must be inhaling that book.
 
7:20 PM
skimming through it
looks nice
 
More to learn ...
 
Hrm, if I look at $R^I$, why won't the strictly monotonic functions set be open?
 
prof would surely pummel me for reading hyperbolic geometry instead of algebraic topology
 
What topology on $\Bbb R^I$, @Studentmath?
 
Product
 
7:22 PM
I seriously doubt he'll pummel you, @Balarka.
 
I.e. finite number of open sets, the rest being $R$
Oh and $R$ with the standard topology. Should probably mark $\Bbb R$
 
So what does that topology mean, @Studentmath? In particular, if $f_n\to f$ in that topology, what can you say?
 
@TedShifrin He smacks me quite often.
 
I thought I was the only smacker, @Balarka.
 
Product topology in infinite products is hopeless. If I were you, I'd not think about it @Studentmath
 
7:23 PM
@Balarka: There you go again.
 
smacks @Balarka
 
wags finger menacingly
 
Product topology in finite products is simple - it's the box topology.
 
True, @Studentmath.
That's boring.
 
Box topology is the coolest topology.
It's very smooth -- anything you want to be true is true there.
 
7:25 PM
I'm sure there are interesting questions/subjects/things, but the idea of open sets there is rather simple to grasp.
 
By the way, @Studentmath, even in the uniform topology, monotonic functions won't form an open set.
False @Balarka unless you just have the finite case.
 
What's the uniform topology?
 
Don't worry about it, @Studentmath. Answer my question about $f_n\to f$.
 
@TedShifrin Box is finer than product topology in infinite spaces too, I think.
 
Take a basic element and tell me what it tells you, @Studentmath.
Right, so if $f_n\colon X\to Y_n$ are all continuous, when is $\prod f_n\colon X\to\prod Y_n$ continuous, @Balarka?
 
7:28 PM
In what topology?
 
That's my question.
 
Oh.
 
Hint: This is why the product topology is so important.
 
Hmm.
Actually it needn't hold in the box topology.
 
@Ted I think I get it. If I take some open set in the basis, I can take it to be equivalent to open basis set in the homeomorphic $\Bbb R^I$ where I order the products so that the ones with open sets not being $\Bbb R$ are at the start, followed by the infinite number of ones that are $\Bbb R$. I can enforce the strict monotonocity only for $x$ in the finite number of products, in the rest it can be constant.
I hope I didn't say too many silly things.
 
7:30 PM
Hrm. I think it holds iff $\{Y_n\}$ is finite, in the box topology.
 
$\{Y_n\}$? @Balarka
Well, @Studentmath, remember that you have a factor for each $x\in I$. Take a basis element that's an open interval for one particular $x$ and everything everywhere else.
Yes, @Balarka. One reason box topology is not very practical.
 
I'm skeptic.
 
Go back to my hint.
 
You can see the open sets in the box topology.
 
Yeah, and they get way too small, @Balarka.
 
7:33 PM
I just sent my dear Lee an email @TedShifrin, lol. Just to ask about his book and wish him happy new year too.
 
@Balarka you are fond of categories, aren't you? I've heard product topology has to do with it being natural when it comes to them.
 
I am not fond of categories.
Abstract nonsense is BS.
 
@Studentmath: Still, so when does $f_n\to f$? In the sense of analysis ...
 
Unless, of course, you can do something with them.
 
Well, all of algebraic topology is about functors, so you have to care a little bit, @Balarka.
 
7:34 PM
@Balarka You can, though. That's pretty much the whole point.
 
$f_n$ being a sequence of functions, right?
 
Yes, @Studentmath ... In the product topology, what sort of convergence is this?
 
@MikeMiller Eh. I see nonsensical generalization of homotopy theory in categories. What's the point of all that?
 
To do math.
 
For $0 < x< \infty$, let $\phi (x)$ be positive and continuously twice differentiable satisfying:

(a) $\phi (x+1) = \phi (x)$

(b) $\phi(\frac{x}{2}) \phi(\frac{x+1}{2}) = d\phi(x),$ where $d$ is a constant.

Prove that $\phi$ is a constant.

I'm given the hint let $g(x) = \frac{d^2}{dx^2} \log \phi (x)$
 
7:36 PM
Well, a lot of stuff is inventing abstraction for inventing's sake, as far as I'm concerned, @Mike. :P
 
You need some Grothendieck-type idea it apply it in practical cases. Grothendieck never generalized much more than he needed, AFAIK.
 
One classical problem that's solved using partly of higher-categorical homotopy thwory is the exotic sphere problem: determining what dimensions have exotic spheres.
 
But MacLane, say, ... sheesh.
 
If you want to see some applications look at my highest-voted MO question.
 
@MikeMiller what is le exotic sphere?
 
7:37 PM
Wouldn't it be uniform convergence?
Or, no.
 
tries to recall definition of an exotic sphere from past life
 
@MikeMiller @BalarkaSen Do you know how I could go about doing this. I've tried doing what the hint says, but I'm just not getting anywhere.
 
@BalarkaSen You believe in rebirth too now? Seems I have got everyone believing in it.
 
Is $\log \phi$ going to end up being convex or concave, @user112495?
 
I would need it for a finite number of $x's$ in $I$ to have that for some $n$, $d(f_n(x),f(x)<\epsilon$ for every $\epsilon>0$
 
7:38 PM
@JasperLoy who else is believing in it?
 
@BalarkaSen Mike seems to have said something similar to what you said.
 
Your quantifiers are out of order, I think, @Studentmath. So, if for every $x$ and $\epsilon>0$, there is $N$ so that $d(f_n(x),f(x))<\epsilon$ for all $n>N$ ...
 
@TedShifrin Wouldn't it be both as we need to show $\phi$ is a constant?
 
Well, yes, but I'm suggesting you think about conditions (1) and (2) in that light.
 
@Ted I think much of it is. But much also isn't.
 
7:41 PM
I have no idea, @user112495. That second condition is weird.
 
Nobody likes my posts today. It's tragic!
 
Get used to not being liked, @Mike.
 
I was unsuccessful persuading @Mike to give me rough ideas.
bah.
 
You'll learn about them later.
 
@TedShifrin If it helps, this is supposed to be the first step in a proof of Euler's reflection formula. So what you said about convexity seems like it's on the right lines.
 
7:42 PM
Merry Christmas all you. I am now looking forward to the new year.
 
I'm scared of the new year, too, @Jasper :)
I guess I'm starting a new life in it just as you are.
 
@TedShifrin Well, it will be your last semester. Maybe consider postponing your retirement? Lots of students need you.
 
No, not postponing.
 
@TedShifrin when are you going to retire?
 
@TedShifrin Right
 
7:43 PM
If I truly miss it, I can get some sort of temp job in San Diego.
 
@TedShifrin Have you planned what to do for the rest of your life?
 
So what sort of convergence, @Studentmath?
Hell no, @Jasper.
 
@JasperLoy Of course, hang out in the chat 24/7.
 
@TedShifrin I see. Well, I have!
 
I know, @Jasper :)
 
7:44 PM
Uniform, that's the precise definition @Ted
 
smacks @Studentmath
 
So, I just watched A Walk to Remember again, what a lovely movie.
 
I don't know that movie, @Jasper.
 
@TedShifrin It's about two high school kids falling in love. The girl eventually dies of cancer, but that happens after they get married.
 
Oh, that reminds me of the sappy Love Story ...
 
7:46 PM
I like it's a wonderful life
's a good Christmas movis
 
My favourite animation movie is The Polar Express. I should really watch it now that it's Christmas, because it is about Christmas.
 
@Ted D: I'm not sure what we are aiming for here
 
@JasperLoy That was a very nice movie.
 
A correct definition/answer? :D
 
Oh, it's unformly.
 
7:48 PM
NOOO ... you keep saying that.
 
No, I mean yes - I just mispelled it before, but that's besides the point
 
You have to watch where you put your quantifiers in analysis. It's not sloppy like discrete math :P
 
@TedShifrin angry
Discrete math is not sloppy.
 
Quantifiers can be :P
 
@Ted alright, let me shut up and think
 
7:49 PM
Are you missing the days of yore yet, @Ted?
 
Yes, @Mike. Missing some of the days of Gore, too.
 
I don't think he had any days, @Ted. Bush won, unfortunately.
 
Someone upvoted me on the Gal(\bar Q/Q) answer. Now I've got 3 upvotes.
 
I haven't forgotten.
 
I'll go cancel his out, @Balarka.
 
7:52 PM
Well, you'll have to explain why you did that @Mike, if you do.
 
I am wondering if people will come to chat on Christmas day itself. Does that mean they have no life?
Anyway, it's already 25 here.
 
No I won't. That's not how votes work.
 
I'm going to friends' an hour away to help cook dinner tomorrow, @Jasper, but that's not until around this time of day.
 
@Jasper: where else are they supposed to be? playing in snow (or sand for southerners)?
 
BTW, Happy Christmas, @Jasper. May next year be everything you wish.
 
7:54 PM
@DonLarynx They are like supposed to be spending time with family and friends, not in this chat, lol.
 
@Ted Jeez, point-wise convergence sigh
 
@TedShifrin Thank you. I really hope so.
 
I'm not a southerner, but I don't have any snow...
 
It's 25 here too.
 
Merry Christmas, @Balarka!
 
7:55 PM
Merry Christmas.
 
Yippee @Studentmath. Now you should understand the answer to your original question.
 
By the way, lots of Indians here are vegetarians, @BalarkaSen, even though they are not Buddhist.
 
I'm going to be in my own head, as always, @Jasper.
regardless who is around me
 
@DonLarynx I will be with myself and with my mum.
 
Go ask a good question, @Ted. I can't find any.
 
7:56 PM
I'm not here to ask good questions.
 
Well, who else am I gonna ask?
 
OH, you never answered my Lawson question from earlier.
 
I can ask a question @Mike
 
By the way, if you buy a book from amazon, always look and see if every page is printed. Once I got a book with a missing page, and you have to do this within X days.
 
A good one, that's hard enough that I won't just say "go do it yourself", @Balarka?
What quesrion was that, @Ted?
 
7:57 PM
One of my students last summer got a copy of Rudin that was missing 20 pages, @Jasper.
Without any algebraic topology crap, @Mike, prove that a compact hypersurface $X$ in a simply connected manifold is orientable.
 
$X \stackrel{p}{\to} Y \stackrel{q}{\to} Z$ be covering maps such that $X, Y, Z$ are path connected, locally path connected and semilocally path connected.
 
@TedShifrin Yet it is so expensive. I confess that I spent over a thousand dollars on my 12 holy books.
 
Prove that $r = q \circ p$ is a covering map @Mike
Is that good enough?
 
Hmm, composition of coverings isn't usually a covering ...
 
Sure, @Ted. But I have assumed a hell lot of stuff.
 
7:59 PM
No, that's not good enough. There's a counterexample in one of Hatcher's problems.
You assumed jack.
 
@TedShifrin The most expensive book I have gotten so far is Cohn's Classic Algebra, over 200 dollars...
 
Yeah, I don't think you've assumed enough.
 
That's not semilocally simply connected @Mike
 
I think I get it now, @Ted! many thanks once again
 
Well, @Jasper, you and I are at opposite ends ... I've collected math books my whole life and now I'm starting to give them away. In some ways it's sad. In other ways it's very freeing.
Of course, @Studentmath.
 
7:59 PM
A hawaiian earring isn't even locally simply connected.
 
Then maybe that should have been in your assumptions.
 
I did not get Apostol's Calculus 1 and 2, but each is also about 200 dollars.
 
oh i said semilocally path connected instead of semilocally simply connected
my bad
 
I actually have two copies of Apostol I, II. I bought one set and got the other as a desk copy, but I don't remember how.
 
And no, the example I have in mind is even locally simply connected.
 
8:00 PM
Of course, I can get the paperbacks at one tenth the price, but I do prefer the hardbacks.
 
(locally SC is harder than semilocally.)
 
You're talking about a hawaiian earring covered by hawaiian earring joined with a bunch of lines and that covered by a totally messed up space
 
But I think Springer should do something about its binding. Supposedly many of the hardbacks don't last very long.
 
aren't you?
 
No, I'm not.
 
8:01 PM
@MikeMiller oh right
@MikeMiller ok, then i am interested in your example.
 
Generally when I say "I'm not doing X", what I mean is "I'm not doing X".
Ok, @Balarka. Then you can find it in Hatcher.
 
One reason I gave up on publishing, @Jasper ... My linear algebra and multivariable books fall apart. When I went to Wiley for the multivariable, I made a scene about how bindings were crummy and falling apart. My editor said, "Oh that won't happen with us." Well, they've had to replace over 20 books for my students because new books fell apart. I'm fed up.
 
Ugh that book Mike.
It'll take me ages to find it.
It's so huge.
 
It's somewhere in the section 1.3 problems.
 
I think Lee is not checking his email on Christmas Eve. I don't think he would ignore me, lol, considering I am such a big fan.
 
8:03 PM
Which is the section on covering spaces, which is why you should look there.
 
He deserves a vacation, @Jasper.
 
@TedShifrin I think you can spend your next few years writing even more books, like Lang.
 
No, @Jasper, not going to happen. I may LaTeX up my graduate diff geo courses, but I probably won't, because hardly anyone would care.
 
One good thing Lang did before he died is that he got all his books to be done by Springer. That makes sure they stay in print.
 
Lang's book are... eh.
 
8:05 PM
Next time, I will publish my books with either Springer or the AMS.
 
Wiley's books always fall apart @Ted
 
Wiley books are very very expensive.
 
@Ted Interesting question. Orientability of a hypersurface is the same as having trivial normal bundle. So look at the associated sphere bundle of the normal bundle. If it wasn't trivial there'd be a loop on $M$ (the hypersurface) that lifted to something nontrivial in the sphere bundle. I'm not sure how to finish yet.
 
You'll feel sorry for my copy of Dummit-Foote.
 
That question was Lawson's gift to me when I first got to know him, @Mike.
 
8:06 PM
@BalarkaSen Is that also Wiley?
 
I gotta go, so I'll finish it before next we meet.
 
@PedroTamaroff Congratulations. You're a mod now.
 
Happy holidays to your family, @Mike.
oh, @Pedro is here? Merry Christmas, mod-in-training.
 
@BalarkaSen I once got a copy of Dummit and Foote but I sold it to someone else because I did not like it.
 
Dummit-Foote is not quite that bad.
The theories are crummy, but exercises are good.
 
8:08 PM
@BalarkaSen Well, I have a weird habit here. I only like reading algebra books where rings are defined with 1, lol.
 
Well that's nothing compared to me not pretending even existence of noncommutative rings.
 
@TedShifrin Hello!
 
Merry Christmas @Pedro the mod.
 
@BalarkaSen You're one observant feller, eh? =)
 
@BalarkaSen Well, even matrix rings are noncommutative. You definitely need them.
 
8:10 PM
Ah, @Pedro and @DanielF finally all in blue.
 
Yes, two more mods join the chat.
 
@Pedro, you still gonna talk with us li'l people?
 
He's going to forget us.
 
That might be well-advised.
 
Does anyone know since when the "Related" section on meta has disappeared? It's a stupid change IMO.
 
8:13 PM
Gah I want more exercises for alg top. Munkres's exercise sections are puny.
 
That's what Hatcher is for, @Balarka. Or you can look at Massey's book.
 
@BalarkaSen You got the latest edition for Munkres's Topology?
 
2nd edition, sure.
 
If you get Massey, make sure it's the latest edition too. He wrote 2 books and then combined them into 1.
 
@TedShifrin Hatcher is too huge and presumably, from what I see, is too advanced for me.
 
8:14 PM
@BalarkaSen How can it be? You are a genius?
 
I am not a genius, I keep saying that.
 
Our grad students say the same thing, @Balarka.
 
I am a slow guy. Can't grasp that much stuff so quickly.
 
@TedShifrin Well, of course.
 
Bredon does more things with manifolds than Hatcher does.
 
8:16 PM
But now I'll be a Ted busier with flags and stuff.
 
But neither does classification of curves and surfaces, which is done in Lee.
 
Don't forget to keep learning math, @Pedro. This is what worried me.
@PedroTamaroff a Ted busier, huh
 
haha interesting pun
 
I don't like puns. I only like stupid jokes that nobody else likes, lol.
 
@TedShifrin I am reading math right now,
Unworry!
 
8:17 PM
LOL
 
@TedShifrin Well I am not a grad student plus Algebraic topology is way too advanced.
 
Then go back and do more basic mathematics, @Balarka. Duh.
 
I have done algebra...
 
@TedShifrin Lang wrote a book called Basic Mathematics, lol.
 
the problem is that i just can't handwave in algebraic topology
 
8:18 PM
OK, I'm outta here ...
 
@PedroTamaroff Congratulations. Glad to see one more mod in the chat. :-)
 
@TedShifrin Bohoo.
 
8:35 PM
@Pedro! You're blue!
 
@Studentmath Yes. Modding makes you sad.
 
Being sad makes me sad.
Okay, I REALLY should not try to type when I'm extremely sleep-deprived....
 
Go to bed
 
@Alizter But it's 3:00 in the afternoon...
 
@teadawg1337 drink
 
8:43 PM
@DonLarynx But I'm not 21 yet....
 
@teadawg1337 Sleep who cares?
 
@Pedro Sigh.
 
@teadawg1337 oh ok, have fun with that
 
8:49 PM
I created a relatively simple sequence today
3, 15, 13, 9, 12, 10, 18, 7, 14, 19
 
What is the pattern?
 
no
don't say it
 
Why would I share that?
 
please
thx you
 
Well, I am not really into patterns.
 
8:50 PM
smacks jaspee
@Jasper why are you here?
 
@DonLarynx I am here to celebrate Christmas.
 
@Lord_Farin It didn't disappear, it just takes some time to populate. After five minutes or so, it should be there.
 
Oh. Merry Christmas @Jasper, and may a bunch of Ho Ho Hos be in your favor!
 
Anyone who can figure out the pattern to that sequence gets a cookie, and anyone who can find the 1257th term of it gets a free hug
 
@DonLarynx So, are you going to apply for grad school?
 
8:52 PM
@DanielFischer Oh, I see now. Thanks :).
 
Do you get a hug, @teadawg?
 
@Lord_Farin De nada.
 
Someone just sent me a very encouraging email. It means a lot to me.
 
@Jasper: No, I want to program
 
@DonLarynx I see. Going to become a programmer then?
 
8:53 PM
JL, @Jasper
 
@TedShifrin No, lol. JL is not exactly a friend for now, lol.
 
@TedShifrin Of course, I don't post this sort of thing unsolved. I came up with that sequence myself and can name the 432607th term
 
you just said "someone."
 
@teadawg1337 You sure it is correct? Don't waste our time if it is wrong.
 
@JasperLoy I am sure
 
8:55 PM
Anyway, I had KFC for dinner just now.
 
I'm always bugged by these IQ test sequence questions, @teadawg ...
 
@Jasper: No
@Jasper: I am becoming a programmer.
 
@DonLarynx I see. Then you should not be in this room, lol.
 
@Jasper: I am completing Project Euler, and I am taking 5 math classes next semester.
 
More than 2-3 math classes at one time is usually a mistake.
 
8:58 PM
@DonLarynx, are you computer science major?
 
@Ted: If you recall, last year I took 5 math classes.
 

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