@EᴀsᴛᴇʀʟʏIʀᴋ I tried to look up the reason on the internet but could not find it, and so made a hypothesis based on periodic trends, electron configuration and crystal field theory.. lol
Is it simply because the atomic radius increases, the d-orbitals are closer to the ligands in a complex and thus there is a greater electron repulsion in the octahedral electrostatic field, meaning that the electrons in the d-orbitals will be displaced by a greater amount resulting the crystal field splitting energy to be greater?
I am not sure if this is the right place to ask, but people in the h-bar chat didn't reply. Just a question regarding crystal field theory: why does the crystal field splitting energy increase as we go down a group with the same oxidation state?
Since the atomic radius increases down a group, doesn't that mean that the d orbitals are going to be farther away from the center, does that cause a greater electronic repulsion with respect to the ligands in the complex, and is that what causes an increase in the crystal field splitting energy???
Hello, I have a question regarding crystal field theory, why does the crystal field splitting energy increase down a group with the same oxidation state in a complex?