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02:02
@TedShifrin hi
fin
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its meow mix
idk if u remember me lol
Oh, I asked 2 days ago what had become of Meow
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lol whats up
i just came out as trans like last year
Well, good for you. I hope you're doing well!
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02:05
im doing ok
i turn 18 on the 27th
kinda crazy
Times are tough enough with covid.
You're getting old!
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haha its interesting
high school sorta sucked a lot but im excited for college
ill be studying biochem
biochemistry is a tough subject
You decided on biochem ? You may always change your mind. But that's cool stuff.
fin
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im pretty decided on it
02:09
Most of my advisees over 35 years changed their minds even at college.
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who knows what will happen lolol
imma just go with the flow
have you done any AP organic chem?
There you go.
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i know like very small amts of organic chem lol
i know the functional groups
gonna need it
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02:09
but by no means am i anywhere near qualified to talk about it
i liked chemistry a lot. i thought about majoring in it after my first college class, but it would have required changing colleges. which was about two more pieces of paperwork than i wanted to do that year.
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my dream would be to be a musical artist but thats not that feasible and i dont mind just keeping it as a hobby
So I thought this was supposed to be college this year. Waited a year?
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nah
i mean i could have taken college math
but too expensive
I loved physicsl chem ....
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02:12
cuz i took a shitty calc 3 course at my high school my junior year
OK, I lost track.
Ah, which I bitched about loudly.
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im gonna have to take it in college anyways i think
it was really surface level stuff
Taking a break for dinner. Keep in touch! You still have my email, I assume.
fin
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awesome
enjoy ur dinner
ill c u around
Glad to see you!!
02:43
but, biochemistry is about as close to an opposite of math that you can find @leslietownes
at least at the under grad level
03:00
i started as an intended literature major. i didn't say my preferences were consistent.
:)
:-)
have you seen this?
3
no. good luck with that. side note, i didn't realize there was an oxfam america
speaking of diverse interests when i was in law school i was very interested in taxation for about a year. never did anything with it.
tax policy could be a very effective way of achieving a wide variety of goals less expensively or coercively than other ways. in the US, however, very difficult to get a lot of ideas off the ground.
 
1 hour later…
04:20
A is a commutative ring with unity and X = Spec(A). Then denote $V(f) = {P\in X: f\in P}$. In this notation, for $f,g\in A$, if $rad((f)) = rad((g))$ then $V(f) = V(g)$ is obvious? here, rad(f) means radical ideal
yes, because $V(f)=V(\operatorname{rad}(f))$
prove this by hand
Yes I know that
My TA said it's not a obvious stuff so I got zero point in that problem
The problem is that if we denote $X_f = {P\in X: f\notin P}$ (basis of X)
then $X_f = X_g$ if and only if $rad(f) = rad(g)$
From the definition, it suffices to show V(f)=V(g) if and only if rad(f) = rad(g)
So I wrote for <= direction clear noting that $V(f) = V(rad(f))$
=> is also clear because rad(f) is an intersection of all prime ideal containing $f$
So prime ideal containing f and g are same so radicals are same
He accepted => direction
But he said my explanation of <= direction is not sufficient
I wrote V(f) = V(rad(f)) in that problem
Should I accept his claim?
04:36
This is a complete argument as far as I'm concerned. I can't judge your specific situation completely, but I would at the very least ask the TA to elaborate on what they think is insufficient and then maybe you can work from there.
Yes I mailed him. He replied : I should've written because the radical of prime ideal is itself (i.e. rad(P) = P), if a prime ideal P contains $f$, then it contains rad(f) = rad(g) so it contains $g$.
True but I wonder I should've told that
05:29
Where should I post a question asking what is the origin of the term 'b-thousand' that means 2^3? Actually what I really want to know is anything at all about this term, which doesn't yield anything on Google. There's also b-million, b-billion, and so on.
05:48
@robjohn What is a way to ping someone without using the mouse, but rather just keystrokes.
Why are some chat rooms frozen?
What do you get the supporter badge for?
It says it's because of 'first up vote' but I have upvoted things before and been upvoted before, so neither of those seem to explain it.
06:34
@AlessandroCodenotti oi oii
06:53
"The Union flag will be flown daily above all UK Government buildings in an attempt to unite the nation, under new guidelines set out by ministers"

Woo hoo! More senseless nationalism.
@Thorgott I complained and I got full point lol
Does anyone know how ping someone here using only keystrokes?
what do you mean by "keystrokes"?
If I type @u I get a bunch of pop ups including your user name. How can I select your user name without resorting to using the mouse?
By using only keystrokes, i.e. by typing.
07:10
Type the full name?
good question, i think you have to type more letters
$$ 1^{2^{3^{4^{5^{6^{7^{8^{9^{10}}}}}}}}} = 1 = WasteOfTime $$
Yes.
@MatthewChristopherBartsh as you type more letters the number of names will decrease
when you get to a single name just press the space bar
That didn't work for me when I typed @Ed as you can see.
or, as Edward said, type the full name
you need a three character minimum for usernames
there ya go
now all the Edward's will be pinged
What does that mean?
Edw's actually
07:25
I'm confused.
All users with names beginning with "Edw"
But there's only one, right?
Who knows.
looks like you're right
07:27
Is there a sandbox chat room where I can experiment with this?
I don't want to ping a bunch of people as an experiment.
I don't understand your experiment lol, just write @ plus enough letters that exactly one user is identified
Then just use the full name :-)
and then press enter
If there isn't maybe there should be a sandbox chatroom with robot chatters. What do you think?
You want to have a sandbox chatroom filled with bots to help people learn how to ping?
07:30
lol
That's right.
It's not easy.
Unless I am a bit of moron :)
It is very easy. Follow this rule.
21 mins ago, by Edward Evans
Type the full name?
I wouldn't say you're a moron. I might intuit from this conversation that you've rarely used the internet, though.
Well I have used it less than most I suppose.
don't look for short cuts until you run the full race :-)
07:33
When do you switch to the keypad to type a number? I mean how long a number does it have to be to justify that?
@user85795 What does that mean?
It means type the full name.
I mean, why should you not look for short cuts until you run the full race?
And why do you have such a hard to type name?
you rob yourself of a learning opportunity
What am I learning by typing the full name of everyone?
With the greatest respect, this conversation is a complete waste of time. Just type the name, it takes like 2 seconds and there's no need to find a shortcut. Also, do you not have a mouse? Why are you looking for a way to ping people without a mouse? I have no idea what's going on wtf
07:38
It takes me more like thirty seconds.
If it is mostly numerals.
Who said I didn't have a mouse?
I don't want to have to take my hand off the keyboard.
What are you so irritated about?
He's not
So.. why don't you just click on the relevant name? There has to be some additional information about you that means that you can't easily click or something, else this is just a waste of time
I'm not irritated, I'm baffled
You said the conversation is a complete waste of time.
07:41
It is.
Because it is? I just don't understand why you can't lift your hand off the keyboard for a second to click a username lol
We are regulars who use the @ all the time @MatthewChristopherBartsh
Well I don't want to waste your time. Let's agree to stop this conversation here, shall we?
Lol we already gave you an answer, there's not much else you can do if you don't want to type the full name out, except clicking the username
You are the one who used his name to practice pinging @MatthewChristopherBartsh
07:44
I thought you wanted to stop the conversation.
@ + three characters = ping
6 mins ago, by user 85795
https://chat.stackexchange.com/faq#notifications
I did nothing wrong, because I pinged him as part of a conversation we were already having. So why did you say '
You are the one who used his name to practice pinging @MatthewChristopherBartsh'
And why are you still talking to me?
3
Can the newton's method for finding roots of a function be generalized to a function of the form $f:\mathbb R^n \rightarrow \mathbb R^m$?
08:22
@MatthewChristopherBartsh type at least the first 3 characters of the name after the @. See the FAQ.
how's it going? @robjohn
@MatthewChristopherBartsh This is in the FAQ
@user85795 fine. How are you?
fine, thanks @robjohn
hope @OldJohn comes back soon
@user85795 I see that you answered the questions that I just answered. Thanks and sorry.
np, pal :-)
08:29
@robjohn I saw your reaction, even @user85795 did. Thanks! :)
yup, cool stuff @MarkGiraffe

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Mark Giraffe makes Stack Exchange headers and shows it off. Re...
@MarkGiraffe I figured if I pinged you, you would see. Nice work.
Mucho gracias, @robjohn.
Is the newton's method for finding roots of a function only works for scalar functions?
If i want to find the roots of $f:\mathbb R^n \rightarrow \mathbb R^m$ what can be done?
@Eminem There are versions using matrices, but their convergence is much less likely.
08:38
Ive tried looking for them but the function are always scalar functions, i.e $f:\mathbb R^n \rightarrow \mathbb R$
@Eminem yeah, but then you get an $n-1$ dimensional surface or variety as the "root"
Yea i know. This is a long shot, but perhaps we want to find $x\in \mathbb R^n$ that gives $f(x)\in \mathbb R^m$ such that $|f(x)|$ will be closest to zero as possible.
Does that even makes sense?
Rolling through the valleys of the surface?
Im not sure what you mean by that...
Look at Newton's method applied to analytic functions in $\mathbb{C}$, you can see there some of the problems that can arise.
@Eminem Newton's method follows a steepest descent path. In higher dimensions, these paths are convoluted by valleys and dells in the surfaces.
09:18
Ding ding.
Sorry, been vibing to Axel F recently.
Just to be clear, I am a fan of NicoNico since 2012.
Although I never used it, I love the medleys.
This one is from 2009, and has been put to its Original Songs Version (as clearly seen in title).
Yes, you wouldn't understand it, but I'll (if not "you'll) still jam with it.
Moderators, if this ain't good here, please delete.
 
1 hour later…
10:45
@robjohn Thanks for answering my question.
@robjohn Why do people post answers as comments on the question rather than as explicit answers? Does one get more points/rep that way?
@MatthewChristopherBartsh no one gets less points/rep but its also less of a hassle
@Semiclassical I don't understand your comment. Solving two ODE gives that relations.
@user2103480 Why is it less of a hassle?
What does 'no one gets less points/rep' mean?
Oh I see what that means now.
It means you do get less rep.
11:25
in fact, you don't get any for comments
Not even if they are voted up?
11:59
If $R$ is an integral domain and $S\subset R$ is a multiplicaitve set and $M$ is a $R$-module, then I already know $T(S^{-1}M) = S^{-1}T(M)$ where $T(M)$ denote the torsion submodule.
I want to show $M_m$ is torsion free for all maximal ideal $m\subset R$ then $M$ is a torsion free moduel
(T(M))_m = T(M_m) by the property I stated. and by assumption, (T(M))_m = 0 for all maximal ideal $m\subset R$. Now as $N_m = 0$ for all maximal ideal $m$ implies $N =0$ where $N$ is a $R$-module
this shows that T(M) = 0
right?
Q is 3i+4j-5k and 4i+7k-4j . Find angle between the two vectors. I am not getting how to find it
12:20
@SrijanM.T Use dot product.
@Wolgwang Ohk . Got it
12:46
Hi, if $X$ is a set for which there is a filter $\mathcal{F}(x)$ of sets containing $x \in X$ assigned to every point $x \in X$, and these filters are such that for all $U \in \mathcal{F}(x)$ there is some set $V \in \mathcal{F}(x)$ such that for all $y \in V$, $U \in \mathcal{F}(y)$, if we say a set $O$ is open if it is empty or such that for all $o \in O, O \in \mathcal{F}(o)$, does every member of $\mathcal{F}(x)$ contain an open set containing $x$?
it seems like intuitively this has to be true for us to call $\mathcal{F}(x)$ the neighbourhoods of $x$, but I can't see to prove it
hello
i'm unable to get the latex to render, despite adding the UCLA javascript to a bookmark
sadly
13:03
@MatthewChristopherBartsh You can use extensions like 'Text expander'
 
1 hour later…
14:08
I'm being a moron: given G-modules M, N and the set of group homs Hom(M,N) "is made into a G-module" via $(g\varphi)(m) := g\varphi(g^{-1}m)$. But it doesn't look like $(gg^\prime)\varphi = g(g^\prime \varphi)$ to me (which is why I'm being a moron)
oops
14:22
Does the Cauchy Schwarz inequality hold for complex inner product spaces?
Cauchy Schwarz holds for any inner product space
The best I can get is Re(<x,y>) $\leq$ norm(x)norm(y)
Can we say the the volume of a cuboid is 0 when all the sides are coplanar . If I imagine it , it’s like a cuboid on the floor where I can’t store anything inside.
Since there is no height of the cuboid , volume is 0.
@EdwardEvans ((gg')φ)x = (gg')φ((gg')^-1 x)
(g(g'φ))x = g(g'φ)(g^-1 x) = gg'φ(g'^-1 g^-1 x)
14:38
@user Thanks a lot man
@Leaky durr
thanks
15:22
@VVKK77 what browser are you using?
15:39
someone in my topology class found an explicit homeomorphism between klein bottle and P^2#P^2
15:59
@Astyx Cool Brauer spam fact of the day: computing the Brauer group of a number field is "almost" equivalent to proving global Artin reciprocity (which establishes an isomorphism of a quotient of the idèle class group corresponding to a finite abelian extension of your number field with the Galois group of that extension)
16:21
What's an idèle class group ?
Oh hey it's @Lukas !
In abstract algebra, an adelic algebraic group is a semitopological group defined by an algebraic group G over a number field K, and the adele ring A = A(K) of K. It consists of the points of G having values in A; the definition of the appropriate topology is straightforward only in case G is a linear algebraic group. In the case of G being an abelian variety, it presents a technical obstacle, though it is known that the concept is potentially useful in connection with Tamagawa numbers. Adelic algebraic groups are widely used in number theory, particularly for the theory of automorphic repr...
it's I(K)/K*
where I(K) is the ideles of K
The adèle ring of a number field $K$ is the restricted product of $K_v$ over all places of $K$, the idèles are the invertible elements of this guy, and the idèle class group is idèles modulo principal idèles (which are the image of $K^\times$ in the idèles)
This looks closely related to the infamous Brauer sequence we talked about
@EdwardEvans summoned by ideles being mentioned?
16:29
It's @Edw from now on
Hi @Ast and @Ale
aww
16:53
@Astyx it is and I was gonna write why but it took up too much room and then I thought maybe it'd be too spammy
There are two ways I solved this Q. 8N + 4N = 12N . So , classify it in vectors form. So , I did found the resultant of 8i + 4i = 12i and 8i + 4i only. So , for 12i = sqrt of 12^2 = 12N But for the other one it is sqrt of 64+16+8*4cos theta where eta would be 0.(Angle between i and i is 0) . So , I get 112 as answer. Why are both the answers different
but yeah you're right
@robjohn I'm on Chrome
17:22
Hello.
17:54
Hello world.
What's up, Simone?
same as always
you?
I don't know what always is.
evidently you're not on a hard lockdown, or you'd know XD
17:57
You can do a variety of things during lockdown.
I don only one thing during lockdown
ok, two
I am wondering which of sleep, eat, use the toilet you are forgoing during lockdown.
that's a very personal question...
Three bodily functions that everyone does---personal?
indeed
18:16
I want to graph sin(1/n), but just over the integers. What should i write in wolfram alpha? "Graph sin(1/n) over the integers" does not work.
graph sin(1/x) and just ignore the stuff that isnt integers?
@Shobhit discreteplot[sin(1/n),{n,1,100}]
I am sure you can figure out how to edit the bounds from the notation/
Thank you @anakhro
@TedShifrin if I have a sequence of nested simply connected sets $\Omega_n$, each with a biholomorphic $f_n\colon\Omega_n\to D$ with $f_n'(a) > 0$ and $f_n(a) = 0$ (i.e. uniquely determined by the Riemann mapping theorem), then the local behaviour of $f_n'$ at $a$ is always the same, right, even in the limit? I can't have a subsequence converge to $f$ such that $f'(a) = 0$?
I am having troubles wrapping my brain around what could change. If Riemann mapping theorem uniquely determines the $f_n$, and the sets are all nested and simply connected, then shouldn't f'_n(a) = f'_m(a) for all m and n?
@Shobhit no worries. In the future, try a few actual Wolfram language commands and see if they work. They often have implementations in wolframalpha.
I used to work on mathematica, but i have forgotten all of it now. Advice taken.
18:30
Google is how I found it. ;)
Actually I think my question is completely stupid, Ted. Nevermind.
What is really meant by stock here...I cannot really follow the definition..What do I really need to figure out from the given data set..?
 
1 hour later…
19:47
How to prove that the series formed by the sequence $ 3^n sin(x / 4^n) $ converges absolutely and uniformly on $(a , \infty ), where $a>0$. I calculated the pointwise limit, which came out to be zero. Now to prove uniformness, i know, weierstrauss M-test, dirchlet test and abel's test. I am not able to prove its uniformness using any of the three ( i dont see how). How can i apply any of these tests ( if applicable, here)? If not, how to do this?
20:09
absolutely follows from the estimate $|\sin y | \le |y|$.
20:27
Weierstrass, Dirichlet
 
2 hours later…
Rob
Rob
22:00
@amWhy Noticed your profile, great mathematicians are welcome at Operations Research.SE
 
1 hour later…
23:22
good morning murica
funny you say that, it's only morning in Asian timezone
23:45
@RajorshiKoyal Please don't repost images repeatedly to chat. I see that you haven't asked any questions on main; that would be a better venue for some of these questions which tend to turn into long drawn out discussions about problems in a book about which we have no more information than you.
@Shobhit That does converge pointwise to $0$, but not uniformly.
x_n = 4^n pi/2 is no fun at all.
@leslietownes yep
@VVKK77 I know that some other Chrome users have had problems. I don't know if there is a fix that anyone has found, but I don't have a Chrome device, so it is hard for me to debug what's wrong.
i can explain why my latex doesn't render. i like to provide a platform-independent experience

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