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00:18
@TedShifrin quick question about part iii). I know already that it is symmetric through $y=x$, I also have derived the reflection map, based on all of our previous work and redoing it here as exercise. To verify, is it enough to just use the coordinates given by my reflection and put them into the original equation to see that it works?

That is if $R(x,y) = (y,x)$ is the reflection map $R(t_{1}, t_{2}) = (t_{2}, t_{1})$ and then $t_{2}^{3} + t_{1}^{3} = 3t_{2}t_{1}$. Where $t_{1}, t_{2}$ is the parameterization of the expression. I'm just not writing them out explicitly but I did get them.
00:36
@TedShifrin I'd say logicians aren't far from many topics in functional analysis
@dc3rd Yes, it's just the observation that the equation is invariant under switching $x$ and $y$.
Well now I can casually say that in "advanced speak" because I understood it as my explanation above........

When do I get to use "And clearly as one can see...." when I'm writing exams? :p
"And we leave it to the reader(grader) to verify the final result...."
never. it is waving a red flag in front of a bull. never do it.
i guess i don't know. who knows. i would hesitate.
one time in my real analysis class i wrote something. i was under time pressure. my prof acted like she had no idea what i was talking about. i knew exactly what i was talking about. but i'd said it in those mathematiciany words. as one can see. if i had just left that out i would have gotten credit.
can we scale images in answers or questions? sometimes the images of the OP's are enormous so I have to scroll 5 minutes to see the actual question. is there a command for example like in tikz [width=2cm] and then the image get's smaller?
"captious" is a very good English word. it summarized my real analysis experience.
00:46
(forgot to say: sometimes they're supposed to be big but I'm talking about images where it's really possible to scale it down.)
Edit and replace with a smaller copy of the graphic ?
How can i get a smaller copy? Do you mean by editing, edititing the post or the image in an extern program (sorry if that's a stupid question I only have about 1,2months mse experience)
Yeah, I meant to save a copy of the graphic to your computer and use your own (free) software to shrink it.
ms paint allows rescaling.
i do this when i want to bother people about images that my daughter created. resize to 25% of the original.
Ms paint may screw up serious graphics.
00:55
you can't scale too small, this is true.
Okay thank you very much. Do you think it would be a good idea to add a fast scaling command in mse? (scaling the image immediatly in mse) In my opinion it would be a very practical tool.
it's hard. the platform has to deal with whatever people submit to it.
I din't know how their platform imports graohics. @robjohn probably understands all this.
Well you can just use imgur and then resize it in a pinch.
i don't know what i would do if i had people submitting images to me with no external scale information. sometimes every pixel matters. sometimes it does not.
01:00
e.g. take your picture i.imgur.com/Eg2KWNa.jpg and before the .jpg, add s, b, t, m, l, or h.
I think t is tiny, m is medium, l is large, and h is huge
that's a cute dog. i'm tempted to submit photos of my cat to imgur. i think i could get some upvotes. but it is hard to automatically generate that information
s and b, not sure.
small and big, but I think it crops to a square.
i think it's hard to tell software to choose the right scale. images that humans find interesting have all sorts of scale factors. from very small to extremely large.
@TedShifrin If you're talking about MS paint, then I have no idea.
I was never.
I meant the sizing of graphics uploaded to MSE
01:08
i've spent most of the day looking at images of mammalian cells. the scale was chosen by journal authors. it seems right but i don't know how to tell a program to do that level of focus and not 4x or 1/4x. it is hard.
i think factors of two are difficult to automatically determine. i'd love to be proved wrong.
01:25
In the first part
I calculated the average value to be
40.8
However I am getting stuck up with the correct answer..
I got the value to be 5...But the answer reads 7..this is where I am running into contradiction..
I am speaking specifically about problem 3..
I told you to quit this, @RajorshiKoyal.
Evening
Hi Edward
Hey Ted
@RajorshiKoyal The better thing to do would be to post a question on the site along with your attempts to solve the problem :P
01:46
He's already been told that.
several times
Next time I kick him.
@robjohn is a softie. If he agrees with me, enough is past enough.
@robjohn Do you think it would be a good idea to add a fast scaling command in mse? (scaling the image immediatly in mse) In my opinion it would be a very practical tool.
01:53
@vitamind making it bigger or smaller, do you think?
@robjohn Sometimes images are huge and it would be nice if one could scale them down easily. So that for example a single triangle is not covering my whole screen anymore.
@vitamind If a picture is taking up too much screen real estate, a mod can edit it to be a link
of course, any image is going to scroll off the screen pretty soon in this room.
It's a solution. I prefer to stay at the question and not to jump between image and text. But programming such a scaling command isn't easy I believe so I guess I have no other choice to become a moderator myself. See you in ten years :).
@robjohn I thought vitamin meant posts in main.
@TedShifrin Ah... yes, I am not sure how that would go over with the devs, but definitely something could be suggested in meta.
02:09
@TedShifrin what do you mean/ is the definition of "entirely contained on a surface"?.....that the point/line/object satisfies the equation of the surface?
If $A$ is an integral domain and F is its field of fraction and $M$ be an A module, then $1\oplus x=0$ implies x=0? (tensor product is $F\otimes_AM$)
@dc3rd are we talking a ruling class here?
the standard examples cover this
@robjohn I'm not sure what that is.....so I'll take my 50% guess and say ....yes?...lol
02:14
sounds like a ruled surface to me
oh...that notion of ruled surface.....well I haven't arrived officially at that idea....for now it is just a surface to me......
let me ask revise my question
@dc3rd This kind of ruled surface
~ implies x is a torsion element
02:16
just reading over the wiki right now.
doubly ruled
the hyper link worked the first time
@dc3rd is that surprising?
no....I was just wondering why you turned it into a linked text instead
under the same conditions
02:18
@dc3rd to take less screen space.
had a feeling.
So the idea I had was the right one, I was going to parameterize my line in the form $f(t) = \mathbf{x_{0}} + \mathbf{u}$, but I'm still not sure what being contained on the surface means......
so my line has to also lie on this surface.
@dc3rd it means that the line is a subset of the surface
@everyone I formulated my question on Meta. Of course I will add a few important things but this is going to be the main part. My english is not that good and I hope you can help me to phrase some things better and fix grammatical errors:
In my opinion, the MSE community could benefit a lot from being able to scale down images in answers and questions. Often images get unintentionally big, which prevents users from seeing as much information as possible at once. It is also tiring to scroll up and down to get to text that is above and text that is below the image. Currently images aren't working well-enough together.
ah, interesting, I think it's true then
since F is flat over A
crud...I meant $f(t) = \mathbf{x_{0}} +t \mathbf{u}$
02:23
why F is flat over A?
*Currently images and words aren't working well-enough together.
tensoring with F is localizing at (0) and localization is an exact functor, this is standard
you can prove it by hand fairly directly
Maybe because it was so "elementary" @robjohn, but essentially I just have to make sure using the $\mathbf{u}$ vector:

$f(t) = (a,b,ab) + t(1,0,b) = (a+t,b, ab+tb)$. So then using the first two coordinates: $f(a+t, b) = ab + tb$ which establishes what I "want".
@RajorshiKoyal I'd check that again, then I'd note that the numbers are the number of rupees in a dollar.
kind of hard to tell from the question.
02:50
my daughter is flipping out because she wants me to read 'the snowy day' a second time.
it's a good book. i remember my mother reading it to me.
I did so @robjohn but 7 is above average and not below I feel
@RajorshiKoyal the rupee is doing below average when the number is high.
that is the confusing part
Oh yes you are right.
Thanks a lot.
03:13
@Thorgott Ah, $F\otimes_AM\simeq (A-\{0\})^{-1}M$ and the image of $1\otimes x$ under the isomorphism is $x/1$ so $x$ is a torsion element right?
@leslietownes do it
we did the snowy day a total of three times. my daughter has no idea of what snow is.
show her pictures and get an ice cube from the freezer :-)
@love_sodam yup
ask her inquiry based questions
03:17
my wife and i were so miserable in iowa city. and ann arbor. and saline. and cambridge.
it's better for her just to wander around palm trees and sand.
she's going to learn how to surf.
can she swim?
she's begun to get the hang of it.
coolio
03:19
@leslietownes so you live near the beach?
yes. we live near a very long beach.
did you originally live there? so you missed it? or do you just not like the city-type places you mentioned so it's nice in comparison, independent from where you originally were from?
my wife grew up nearby. my daughter will be tropical.
i grew up in a more wintry environment.
mmm i see
i like fog and rain and sleet and all of that. i've removed myself from that.
my stepsister just bought a house near my childhood home. i'm annoyed with that. i should have bought that house.
03:25
you must love your wife more than the fog and sleet and rain. maybe you can use the money to pay for surfing lessons for your daughter
we'll all be surfing eventually.
03:40
hums Beach Boys for @leslie
(removed)
Would studying cohomology theory in (homological) algebra help the study of cohomology theory in algebraic topology?
I found it helped in homology theory
::I'm picking up good vibrations:: la, la, la
 
1 hour later…
05:03
Is there any transcendental element in $\Bbb C$
?
Hi. I've been looking here: https://learn.lboro.ac.uk/archive/olmp/olmp_resources/pages/workbooks_1_50_jan2008/Workbook30/30_4_mtrx_norms.pdf

It says on the second page that |AB| <= |A| |B|. Is this true for all matrices and all types of norms? (or at least the L2 norm?)
05:23
@love_sodam of course ā€” most numbers!
05:56
@TedShifrin Oh the term 'transcendental number' and 'transcendental element' are different.
so my question is vague
06:21
transcendental over what field?
over $\Bbb Q$ it's the usual transcendental numbers
06:36
@love_sodam a number is an element which is a member of a set
everything is a member of some set.
including the lack of anything
07:15
@TedShifrin I mean over $Q$ which you meant. (so the question is silly)
07:57
@copper.hat would I want to be a member of a set that would have me as a member?
08:20
@MinaMichael That is what it says there. Those are properties common to all norms.
08:35
is the set $S = { (x,y); |x| <1 , |y|>1 }$ open? I know the definition of an open set, and I think it's open, but in my book, it's given that this set is not closed and not open. I can see why it's not closed, need help with not open.
@Shobhit It is written exactly like that?
$(x,y)\in\mathbb{R}^2$?
yes, professor teaching online, he said this.
yes, (x,y) in R^2
I'd like your professor to show a point in $S$ that does not have an open disk around it. By $\mathbb{R}^2$, I mean the standard topology.
so it is open, right?
I'd say so. Unless your prof is using a non-standard topology.
08:51
one more question, how can i draw the graph of $(sin x , 1 )$?
@Shobhit is this a curve in $\mathbb{R}^3$?
in R^2
this is closed, he said. I cant draw.
Then what do you mean by $(\sin(x),1)$? That is a point in $\mathbb{R}^2$ and if it is a function of a variable in $\mathbb{R}$, the graph would live in $\mathbb{R}^3$.
$ S = \text{{} \text{}}$
$S = \{ (sin x , 1) ; x \in R \}$
as a subset of R^2
@robjohn
09:06
Hello.
I made stairs.
$$ n^{n^{n^{n^{n^{n^{n^{n^{n^{n^{n^{n^{n^{n^{n^{n^{n^{n^{n^{n^{n^{n^{n^{n^{n^{n^{n^{n^{n^{n^{n^{n^{n^{n^{n^{n^{n^{n^{n^{n^{n^{n^{n^{n^{n}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}} $$
@Shobhit You mean $[-1,1]\times\{1\}$?
@Shobhit I guess $(\sin z, 1)$ means $\{(x,y); \vert x\vert \leqslant 1 \wedge y=1\}$
sigh, I'm slow at MathJax...
Now the proper exponentiation.
$ 1^{2} $
@MarkGiraffe Stairway to Heave$n^{n^{n^{n^{n^n}}}}$?
I guess...
09:20
@MarkGiraffe Nah... that's just $1$
Ahh, I forgot the logic on that.
You know that I make custom SE headers, right?
I made a Teams for it...
09:47
@MarkGiraffe what headers have you made?
10:07
@robjohn if my question changes to $ S = \{ (x,y) : |x|<1 , x \in Q , |y| >1 , y \in Q^{c} \}$, is this set open? again, i see it is not closed.
and yes, i meant $[-1,1] X \{1 \}$
2
Q: $uu_x+xu_y = 1$ has infinitely many solutions

love_sodam PDE $uu_x+xu_y = 1$ with initial condition $(\frac{1}{2}s^2+1,\frac{1}{6}s^3+s,s)$ has infinitely many solution. All notations follow Pinchover-Rubinstein introduction to partial differential equation. I used Lagrange's method to solve this. From the equation, I get $udu = dx$. Solving ODE, $x=...

Is there anyone can explain the comment?
the comment of mattos
 
2 hours later…
12:23
Hi all
https://math.stackexchange.com/questions/4073970/for-absrez-frac13-sign-refabi-sign-rea

any ideas ?
13:18
How to prove that if $bar{A}\cap \bar{B}=\emptyset$ then $int(A\cup B)\subset int(A)\cup int(B)$
13:34
@Shobhit in $\mathbb{R}^2$, that is neither open nor closed.
@Shobhit $[-1,1]\times\{1\}$ is closed in $\mathbb{R}^2$
\o @BalarkaSen
14:23
hi
15:03
I don't see how it's not open. can you provide the point where a disk is not contained in the set. @robjohn
@Shobhit remember that $\mathbb{Q}$ and $\mathbb{Q}^C$ are dense
Can a set be open if its complement is dense?
other than the one vacuous example
16:09
@robjohn Great!
@Shobhit take literally any point
I clicked a button that said automatically move the discussion to a chat room. Does the chat stay there forever? Can it be deleted or edited like I seem to have seen the comments? Or is it like the discussion here, set in stone forever?
@MatthewChristopherBartsh a chat room may become frozen after inactivity, but a moderator can unfreeze it if necessary.
It can also be deleted, but I don't think that happens automatically
Is it true that this chat here gets published as a sort of book every month?
@robjohn
where would it even get published
16:20
No idea, someone told me that here about two weeks ago.
@robjohn Sir I tried the second problem also..
I had asked what the dotted lines that cross the screen were, and the person said maybe they are page breaks for when it gets published.
The highest value of rupee is te lowest in the graph..
yeah man, can't wait to order the newest print copy of MSE chat logs from the AMS
that is 39.02 but I am unable to arrive at the correct answer same with the next problem please help me out..
16:24
lol I don't think he said anything about printing. Maybe he meant a PDF book or something.
@MatthewChristopherBartsh Those lines are often there to tell you where you had read to the last time you looked at that page (if you were reading other pages and stuff was said here).
Often, you say. Is there anything else they might be for?
That seems to be right, I just refreshed another SE page, and I got a new dotted line.
Is this the kind of line you are thinking of?
I went away and came back so that the line would be there.
I think you have to be gone for a certain period of time for it to be drawn when you return. It shows you what you probably haven't read yet.
16:40
Anybody wwho can answer me what is means by,"highest value of money"
is certainly wwelcome..
welcome..
Once I feel it is supposed to be the lowest and in the next moment I feel it to be the highest.
Please answer this to me in detail..
16:59
@robjohn Yes. On my screen it is in a different place.
17:11
How can I compute that sum((2*n+1)^5/(1+e^(pi*(2*n+1))),n,0,infinity)=31/504?
@RajorshiKoyal The values given in the chart are how many rupees equals 1 dollar. So the rupee is worth more when that value is lower.
It is not clear whether the text is taking the reciprocal of the average of the INR/USD or the average of the USD/INR
The first is $41.2888$ the latter is $41.3425$
this might be clearer in the context of the expository part of the book
You are very correct but how do you answer 4 and 5
Well, @robjohn, I guess you didn't mean what you said yesterday.
We're stuck forever with this.
@TedShifrin well, looking at the question, it is rather convoluted, so I thought I would offer some assistance.
thanks a lot...
17:18
Then we're stuck.
@RajorshiKoyal You should look at the expository part of the text to see how they are using the data. We cannot tell much more here.
@TedShifrin I hope not. There was a bit of effort shown last night, and I hope this is over for now.
Nope, you've sunk us.
It's like the one time I helped with one elementary physics question; we were then bombarded by several kids asking virtually identical questions for days.
@robjohn@TedShifrin Just wanted to inform you that I posted my question on Meta.
oh, cool, @vitamin. I think that was a good issue to bring up.
@TedShifrin I don't like the chat being covered with the same large image repeatedly.
17:27
Well, or repeated spamming of links to the same question on main. So what do we do other than tell them not to behave this way?
I mean ... there's lots of off-topic discussions/behavior here from our regulars; I'm sure it annoys plenty of people, too.
@RajorshiKoyal Please create a separate chat room to ask for detailed information about a complicated question.
or ask your question on main.
This is not the proper venue for such a long, drawn out discussion.
My complaint is not one discussion, but the feeling of entitlement to come here time and time again, posting these exam questions and ā€” in tone ā€” giving us orders, despite being told not to act that way.
But if you're going to engage with him, I cannot in good conscience try to enforce anything.
17:49
@love_sodam one way to get a handle on the issue here: if you pick generic (x,y), must there exist u such that x=u^2/2+1 and y=u^3/6+u simultaneously?
 
1 hour later…
19:05
hello, someone have an idea about how to prove that if $bar{A}\cap \bar{B}=\emptyset$ then $int(A\cup B)\subset int(A)\cup int(B)$
@TedShifrin Hi
19:26
@TedShifrin, I wonder if the reason these situations arise all the time with regard to people coming and demanding answers. Here and in the physical has to do with the lack of appreciation in understanding the need to display a thought out approach and that is what needs correcting
. But since the external pressures of everything being so "results driven" and needing to find quick answers people students are blinded at what the true end game should be.....I don't know just a conjecture from my experiences
eh. i feel like it comes down to an assumption of us being here to answer questions, when what we really want is for people to be able to answer their own questions
but answering my own questions takes effort and uncomfortable strain on the mind............................. :P
So I just happened to be over in the Stats- Chat room and Ted's new favorite student was spamming the same question over there.....
oh jeeze
definitely looks like a throw everything against the wall and something will stick somewhere......
20:00
hello. What do you guys do to take off your thoughts from everything
maths
i play with my cat or my daughter. math too. it helps that math is no longer my career.
20:21
@EdwardEvans finally a healthy and practical answer here
@leslietownes meowtivation
20:41
Hi all, Iā€™m new to SE and I have posted my first question here: math.stackexchange.com/questions/4072802 It has attracted a number of views, but few up votes. Do you have suggestions on how I can improve my question?
what if math feels too tiresome
and I don't drink
nor do I have a daughter or a pet
meditate?.......practice muay thai?......or you can use the Snoop Dogg approach........
Bingewatch Fresh Prince of Bel Air. That's what my girlfriend does
that's a good suggestion ^^^^
bingewatching something... yeah
21:16
have a hobby
21:37
@EdwardEvans classic UK
22:05
@AlessandroCodenotti celebrating his cultural heritage
simple, yet effective
if math is tiresome it may help to read about the history of math. how some idea you think you know now developed. sometimes it helps you understand the subject better. other times it makes you feel better by making clear how very clever people often spent a lot of time looking at things in the 'wrong' way or attacking problems without success.
4
22:58
@robjohn If you want to know, I have a room where I show them off.

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