The h Bar - 2017-09-15 (page 2 of 3)

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1:01 PM

@Kaumudi.H i love thinking about little bits of reality that can be explained through half assed mathematics

pretentious, perhaps, but fun

@ACuriousMind maybe we should use this to our advantage

The dot disappears for an hour after your last review (or the last time you clicked the button). If no one else has reviewed in that time, the indicator would reappear. This too may need to be adjusted for sites with, for example, reviewers who check in very occasionally. — Shog9 ♦ 20 hours ago

user228700

@BalarkaSen Oh, absolutely, I agree.

@WDNWBM In principle yes, if it is related to the site and its moderation.

make sure the thresholds for the closevote review blinkers are set so that it minimizes false positives and it does actually carry information about when that queue can really use some love

I have slim hopes that that feature will become useful, but you never know

user308168

@ACuriousMind It is about moderation but not about this site.

1:12 PM

@Kaumudi Oh, there's a cute application of Euler's $\chi$ I should have mentioned when we were talking, by the way. Have you seen the K3,3 graph by any chance?

@BalarkaSen Is one supposed to have?

user228700

@BalarkaSen Nope.

user228700

::Googles::

Take three houses and three factories, supplying electricity, water and some other shit respectively. The problem is to connect the houses to the factories.

On a plane, so that the connections (wires/pipelines/whatever the hell) do not intersect and mess up.

@0ßelö7 i dunno it's a pop math phenomenon

user228700

@BalarkaSen Ah...

user228700

1:15 PM

Hmm, how does one do it?

@BalarkaSen I think it was a counterexample to my curve in a coordinate chart doubt

It's called the utility graph, if you do it with intersections then you get a picture like this: upload.wikimedia.org/wikipedia/commons/thumb/f/f3/…

@Kaumudi.H The theorem is that you can't.

Not without possible intersections. Aka, "the graph is not planar" in buzzwords (TM)

user228700

@BalarkaSen Yes, right, I understand. Wow, I see.

There's a proof using Euler characteristic. Remember how $\chi = 1$ for any planar graph whatsoever?

user228700

Yep.

user228700

1:17 PM

I see where you're going.

So our dude right there has 6 vertices, 9 edges and uh, $f$ number of faces

Well, after assuming we can draw it on the plane

user228700

Right, $f=4$, under this assumption, which is weird.

It should be, yup

But we're going to contradict that

user228700

We are?

Is the number of faces a homotopy invariant?

1:20 PM

@0ßelö7 not just triangulate

it's a combinatorial thing

@Kaumudi.H Yeah, as follows. Notice that this graph is special in the sense it's "bipartitie"; what this means is that you can color the vertices in red and blue so that each edge connects a red vertex to a blue vertex

and there's no connection between red vertices/between blue vertices

Namely, just color the houses red and the factories blue

user228700

Hmm, what if you color them randomly? I don't get it.

Oh, I mean there exists such a coloring

user228700

Ah, right.

you can do it

user228700

Right, right.

1:23 PM

@Kaumudi.H An easy example of something which is not bipartitie: take a triangle with three vertices

Can you see why it can't ever be colored in the way I mentioned?

user228700

Yep, I understand.

What are the buzzwords in modern combinatorics?

The algebra people deliberately do not advertise their seminars here, so I never go

Right, just to spell it out, if you color it red and blue you're going to end up with at least two of the vertices to be of the same color

but there's an edge joining any two vertices of a triangle!

#getrekt

@0ßelö7 I have no clue

user228700

@BalarkaSen Lol, yes, I understand.

schubert cycles something something

user228700

1:26 PM

How does this fact contradict $f=4$, exactly?

@Kaumudi.H Alright, cool. So our utility graph is bipartite. Notice that this means if I draw it planarly on the plane (planarly on the plane? really?), there cannot be any triangular face.

We're slowly getting to that. The contradiction is not far

user228700

x'D What is the definition of a utility graph?

Oh I mean the thing we're dealing with here; 3 houses, 3 factories and edges going between them

That's called the "utility graph"

Or K3,3 if you prefer junk notation

user228700

Ah, wow, quite the fancy name for a rather specific definition :-P

user228700

@BalarkaSen Anyway, yes, right.

1:29 PM

@Kaumudi.H Do you see why?

user228700

Yes, you spelled it out for me! I do, I understand.

Ok, cool.

So any face of the utility graph is at least a quadrilateral because that's the next polygon on the list after a triangle

Of course, it can be pentagonal or hexagonal or whatever, but never less than a quadrilateral

user228700

At least, yes.

Now, count. Every face has $4$ edges or more, and a specific edge is counted by exactly two faces adjacent to it. So $2e \geq 4f$.

This might take more than a second's thought to convince yourself.

user228700

Uhh, hmm...

1:35 PM

Basically, if you take a quadrilateral and count the edges, for each count of the edge you're counting the face once.

So $4 = 1 + 1 + 1 + 1$

(the left hand side counts edges, right hand side counts the same face of the quadrilateral 4 times)

Agree?

user228700

Yes.

Now, say you have $f$ quadrilateral faces

user228700

OK...

Then $e = f \cdot (1 + 1 + 1 + 1)$ by generalizing the previous formula (for each count of the edges you're counting the face associated to it once)... except, not. Because each edge has two faces on either of it's sides.

So actually you're counting each edge twice.

$2e = f\cdot (1 + 1 + 1 + 1)$

Aka, $2e = 4f$

Is that a bit easier?

user228700

Hmm, yes, but what's with the four?

1:40 PM

$4f$ means you're counting all the faces, but each face is counted four times.

That's because for each count of the face you're counting an edge on it's boundary

Anonymous

Seems some cool geometry stuff going on here :)

So four counts of the face completes the count of edges on it's boundary (because everything's a quadrilateral)

@Blue graph theory shit yolo

user228700

> because everything's a quadrilateral

user228700

Right.

user228700

AHH.

1:42 PM

You see?

user228700

I see :-)

The final formula is actually not $2e = 4f$ because faces might be polygons for poly > 4 (much terminology).

So it's $2e \geq 4f$

Because the number of edges increases if any face is more than a quadrilateral

@ACuriousMind Are you interested in the new noncompact G2 paper or do you only like compact ones?

user228700

Right, right, I see.

So let's use this shitz

What's $e$ for our utility graph?

user228700

1:45 PM

9, no?

Yup

@0ßelö7 Non-compact is non-interesting

@ACuriousMind :(

But we know from $\chi$ that $f = 4$ if we can draw it on the plane

That'd mean $2e \geq 16$

Aka $e \geq 8$

Uh, something's off.

user228700

Erm...

1:47 PM

Oh, I see what's wrong

We should really count face including the exterior face, not just the interior faces, when we use the formula $2e \geq 4f$.

@Kaumudi.H Example, take a plain simple square on the plane with 4 vertices and 4 edges.

user228700

I, erm, I see(?)

If you think $e = 4$ and $f = 1$, that formula fails

8 is not greater or equal to 4 last time we checked

user228700

There is an exterior face here?

@Kaumudi.H Indeed! $f = 2$, actually, because the square has an outer face, the vast nothingness outside the interior.

This is very important actually

user228700

The, erm, right, uh, OK...

1:50 PM

The reason our logic failed because we said "$2e$" appears because each edge is adjacent to two faces

But that's not true in the square case unless we assume the exterior is a face

user228700

@BalarkaSen Is it OK to resume this discussion after one week? My exams start next Monday and I've got lots of Calc. to do, some of which I don't understand :-(

Check out my new gaming rig guys

user image

@Kaumudi For sure. We're more or less done, actually, because you now get $f = 4 + 1$(counting the exterior face)

And then $2e \geq 4f = 20$

But $2\cdot 9 = 18$ is not greater or equal to $20$

user228700

And that is a contradiction. Hmm.

That contradicts planarity.

user228700

1:53 PM

Whenever I find the time, I will look through this discussion once more and I will ping you when I fail to understand any specific part, OK? When :-P

@Slereah lol what the hell is that

sure, it's a cool theorem

the combinatorial logics are sometimes confusing to me

Prathyush Poduval

@Slereah How did you find one?

ebay

Prathyush Poduval

was it cheaper or costlier than original price?

user228700

@BalarkaSen Wokay, thank you! :-)

Prathyush Poduval

1:55 PM

@Slereah It should be in a gaming-zoo

Every program takes 4 minutes to load

It's a bit of a wait

also if the cassette is a bit shitty you can hear squeaks when it loads

u playing atari pong on that trash

user228700

Does anybody have the time to explain a bit of multivariable calculus to me?

shoot

user228700

Hang on, I'll upload two pictures (but this might take awhile):

2:07 PM

please, this is a modern computer

It's from like 84

It can play MODERN games

yeah like atari pong

Pong is more of a 70's game

80's was all about side scrollers and platformers

what's a famous 80's game

M A R I O

lol

2:10 PM

Super Mario Brothers Super Show - Plumber Rap

yo have you ever played catmario

that shit's lit

I have not

look it up

it's a rage game based on mario where it trolls you every few seconds

user228700

Is that image available?

nope

user228700

2:13 PM

ARGH.

user228700

user image

user228700

YES. YES YES YES!

user228700

user image

user228700

RIGHT.

Ok, so, what's the question

user228700

2:18 PM

I have next to no idea exactly what they're trying to say here.

user228700

OH, my God.

user228700

I typed that sentence about 3 minutes ago!! ARGH.

In Example 9?

Do I smell Analysis

user228700

@BalarkaSen Yep.

2:20 PM

Can you be more precise? Which bit is troubling?

user228700

I'm sorry, I've been trying to send sentences.

It's ok

user228700

I don't understand the bit about "It is not evident from Formula (3)..."

user228700

Is it possible for you to tell me what the point is?

Ah, yes.

The thing is the manipulations in (4) and (5) they did is valid only for $(x, y) \neq (0, 0)$

Because $f$ is not defined by that formula they manipulated from at the point $(x, y) = (0, 0)$.

user228700

2:22 PM

Right.

So, you have to explicitly compute $f_x$ and $f_y$ at $(0, 0)$ from the first principles.

user228700

Ah...

user228700

And how did those two come out to be 0, exactly?

They did the computation below.

user228700

They did, but how does that work? As $\delta x$ tends to 0, $0/{\delta x}=0$?

2:25 PM

Yes, $\lim_{h \to 0} 0/h = 0$. Because $0/h$, for nonzero $h$, is equal to $0$.

And limit of the zero function is uh, well, zero.

Remember that a limit has nothing to do with the function at the point you're interested in

You have to remember that you don't plug in $h = 0$ when you're taking the limit; you make $h$ smaller and smaller, but still nonzero, and see what the function does.

Just behavior around it

user228700

Ah (Y) Thanks so much!

user228700

Ah, hmm, although, along the same lines, the other limit doesn't exist?

2:27 PM

Other limit, as in?

@EmilioPisanty Can't. Busy.

(Y)?

$f_y(0, 0)$ is still $0$.

@DanielSank no worries

user228700

@BalarkaSen No, not that one.

2:28 PM

@0ßelö7 fb slang

@Kaumudi Oh, the continuity thing?

user228700

The one next to Solution (b)

user228700

@0ßelö7 ::Thumbs up::

That does not look like a thumb

Like, not even close.

user228700

@BalarkaSen Yeah ::Sheepish smile::

2:29 PM

Well, no, I don't understand what you mean by "same logic". But I explain why it does not exist.

What does it mean to say $\lim_{(x, y) \to (0, 0)} f(x, y)$?

user228700

No, not same logic, I meant, OK, anyway.

user228700

@0ßelö7 Apparently, it converts to a thumbs up in Fb chat. Dunno, I picked it up from friends who use it.

user228700

@BalarkaSen You approach the point (0,0) in that function from...I dunno from which side.

Right, that's the point. You approach from every possible direction.

user228700

Right..?

2:31 PM

$\lim_{(x, y) \to (0, 0)} f(x, y)$ exists and is equal to some $c$ if and only if the limit exists "when approaching from all possible directions to the origin".

user228700

Right.

@Kaumudi.H What if you approach, for this particular function, the origin along the line $x = y$?

i.e., what is $\lim_{(x, x) \to (0, 0)} f(x, x)$?

user228700

@BalarkaSen Yeah, this is confusing, as it has been always. Approaching along that line would lead to x being very very very close to y at all those points and so the limit of the function being -1/2

"Approaching along that line would lead to x being very very very close to y at all those points" Well, no, x is literally equal to y along that line

Because the line is by definition $x = y$ :P

But yes, the limit of the function is $-1/2$ along that line

user228700

:-P OK, sorry, this is confusing, OK?

user228700

2:35 PM

I geddit, somewhat.

if you explain why it's confusing i could explain more

user228700

Limits have always been somewhat confusing to me.

user228700

...in ways I dunno how to explain :-/

Do you want to learn the definition?

user228700

I already do know the definition, that's the trouble.

2:38 PM

multivariable limits are especially confuzzling because there's a lot of informations to keep track of

Usually I think of limits in terms of sequences

@Kaumudi.H with epsilon and delta?

@BalarkaSen yes, by far the best approach for calculus

$\lim_{x \to a} f(x) = c$ if for all sequences $\{x_n\}$ converging to $a$, $\{f(x_n)\}$ converges to $c$

I was going to give a sequential definition

@0ßelö7 agreed. unfortunately nobody likes that definition for whatever reason

epsilon-delta is the most rigorous but the least useful lol

@BalarkaSen most rigorous? They're completely equivalent!

2:41 PM

If you spell out what convergence means

When Cassini's final moments begin, I was at lunch with no computer, thus I missed the live. Is there actually images from the camera showing the descend into Saturn?

Does smoothie not know what convergence means? I'm assuming that, of course.

it's easy to explain what convergence means without spelling out the definition

@BalarkaSen my analysis class started with sequences and didn't get to functional limits until halfway through. I think that's a great approach

but once you know it it's also easy to come up with the definition lol

@0ßelö7 yep

2:42 PM

Get sequences and topology out of the way and then talk about functions

user228700

@0ßelö7 I do, I just learned that.

I also firml believe that one should learn single variable really well before going to many (or infinitely many) variables

@Kaumudi.H Here's the thing then. For the function you have there, $\{f(1/n, 1/n)\}$ converges to $-1/2$ whereas $\{f(1/n, 0)\}$ converges to $0$.

But both of those sequences $\{(1/n, 1/n\})$ and $\{(1/n, 0)\}$ approach/converges to $(0, 0)$

So $f$ is not continuous; $\lim_{(x, y) \to (0, 0)} f(x, y)$ is nonexistent

Anonymous

@Secret I didn't spot many. Mostly simulations were being shown on the news channels.

This is equivalent to arguing $\lim_{(x, x) \to (0, 0)} f(x, x) = -1/2$ and $\lim_{(x, 0) \to (0, 0)} f(x, 0) = 0$, on the other hand.

Anonymous

2:46 PM

There might be one or two floating around on the net.

I see, I guess they come later

user228700

@Balarka: Yeah, no, I see.

user228700

I think.

user228700

This is excellent, really. She taught all this crap in the last two days and expects us to sit the exam on Monday.

user228700

I've no idea what I'm going to do, actually.

user228700

2:49 PM

I'll figure something out. Thanks @0ßelö7, @Balarka :-) Thanks so much.

you gotta commend this guy

0

Q: How can elementary particles spin if they are points?

My understanding, albeit limited, of quantum mechanics is that there is a property of elementary particles called spin. This seems to be a misnomer, though, because if elementary particles truly are point particles, they can't rotate. So, what is it I am misunderstanding?

it's not every day that you get duplicates of question #1

just roughly once every two months =P

@Kaumudi.H my professor stuck limits like these on homework in my analysis class and they were harder than the actual analysis lol. The trick is to look at a graph

Wolfram alpha

user228700

@0ßelö7 Ah, but are you given access to it during exams?

@Secret No. The last image sent home by Cassini is this which is taken yesterday at a distance of 634,000 kilometers from Saturn. It was the last piece of recorded data on its memory. (images are too large to be sent as they're taken and are recorded and sent over time)

After that, as Cassini got closer to Saturn, its data link was set to send the precious atmospheric measurement data back in real-time (at around 3 kBps) and couldn't send back any images anymore.

@Kaumudi.H I've never had to do a limit on an exam. But looking at graphs and getting a feeling for these things (saddles, branch cut looking things) is good

user228700

2:59 PM

Oh, wow, right, hmm.

@Kaumudi Exercise you can do if you want: Consider $f$ defined by $f(x, y) = xy^2/(x^2 + y^4)$ for $(x, y) \neq (0, 0)$ and $f(0, 0) = 0$. Is $f$ continuous at $(0, 0)$?

user228700

@Balarka: Thank you :-) Really, but I gotta hit the sack. I've got a bit of a crazy sleep schedule going on, lol.

for sure

user228700

I'll come back in...6.5 hours and look at it :-)

@lılostafa Ah I see

3:02 PM

@Kaumudi.H I did them in calculus in high school and in analysis 1, but beyond that no one cares. I also didn't take calc 3

I hope you actually get the search to work before you put it in the spotlight like that. — GiantCowFilms 19 hours ago

ooooof, buuuuurrrrrrnnnnnnn

3:25 PM

@JohnRennie amazon.com/Education-Important-Physics-Importanter-Shirt/dp/…

@lılostafa :-)

3:40 PM

hey all you brilliant ~~physicists~~ mathematicians, heres a tough/ deeply challenging problem working on, its the endpoint of years of work/ analysis, relates to dynamical systems theory. anyone wanna dig into it? (so far dead silence...) :o o_O

0

Q: stochastic recurrence relation "convergence"

Consider a recurrence relation $x_n = f(x_{n-1})$. Suppose $f(x_n)<0$ for some "large enough" $n$. Now consider a "stochastic variant" $x_n = f(x_{n-1})+y_n$ where $y_n$ is a sequence of random variables. Under what conditions will there again exist a "large enough" $n$ such that $x_n < 0$ ? E.g....

limits-and-convergence stochastic-diff-equations recurrences

...

ah @#%& that stuffs too hard. whos that going on about ravioli in here? lets get that guy matched up with EmilyRataj, perfect couple o_O thedailybeast.com/…

you wouldn't want filthy frank to be matched up with her in any sense

trust me

Anonymous

4:17 PM

@BernardoMeurer I'm planning to buy a Arduino board to learn and practice the basics at home. Not sure which model which be suitable for me (beginner). Suggestions?

4:28 PM

Disbelief as container ship heads straight to shore (full version) Hong Kong April 6, 2014

lolz

4:40 PM

@BalarkaSen cmon man theyre the perfect couple. is filthy frank viral? shes viral too. o_O :P

I am not exactly sure if I understand the answer. would anyone be kind enough to explain it to me?

0

Q: Angular momentum conservation under Galileo translation

I was trying to see when angular momentum is independent of choice of origin, but then it seems angular momentum no longer conserved under Galileo translation to me : Given a point mass is doing circular orbital motion in an inertial frame: $$\vec L = \vec r \times \vec p $$ In a new relatively...

classical-mechanics

shoot

I mean galileo transformation

@vzn he's not a virus, he's literally the throbbing sack of tumors of the youtube world

for example

Prathyush Poduval

@Blue Most of the projects i come across online use the uno, followed by mega

@BalarkaSen sounds dank, maybe even worse than pewdiepie o_O ... so youre a fan eh? :P

Anonymous

@PrathyushPoduval Hmm, I'm thinking of getting this one: amazon.in/Quad-Store-TM-Starter-Beginners/dp/B01KNR581U/…

4:52 PM

worse than pewdiepie? what are you even comparing with

whether i'm a fan or not is irrelevant, filthy frank is a legend

@BalarkaSen pewdiepie is (must be?) pretty bad. he got fired by disney. o_O

@BalarkaSen lol if hes a legend, its because fans

i mean the comparison doesn't make sense. pdp is an edgelord who got rekt by media

filthy frank is openly massively offensive and absurdist prankster

beyond the reach of any mainstream community

@BalarkaSen whats an edgelord?

@BalarkaSen pewdiepie not a prankster? cmon man

acts edgy but is just doing it for the lulz

frank is a legit warrior

leave him alone

Prathyush Poduval

4:55 PM

@Blue Looks awesome and has lots of things for a beginner, but what is the remote for?

@BalarkaSen lol speaking of absurdist, he seems to get ravioli orgasms. "to each his own"...

@BalarkaSen you talking to me?

@vzn no he's just a dumb gamer

his pranks suck

@0ßelö7 yeah that was a frank reference lol

Anonymous

@PrathyushPoduval Probably each key of the remote can be programmed. Say '1' to light up the Red LED, '2' for the Blue one, and so on...

@BalarkaSen I can't stand him so I don't know

Prathyush Poduval

4:57 PM

Ah okay

edups is about as edgy as I get, and it's pretty damn cringey at times

@BalarkaSen am pretty sure youre the only person in the world who is fans of both Tarkovsky and Filthy Frank o_O

yeah i know i am pretty unique

Prathyush Poduval

@blue Try asking around if any of you're classmates have an arduino and try using it first before buying

why would anyone actually have an arduino

what is it with people in this chat taking schoolwork home

4:58 PM

i wouldn't really call myself a fan of filthyfrank though; he's too much for me

i support him but that's it

Anonymous

@PrathyushPoduval I don't think anyone in my class has one.

Prathyush Poduval

batch?

Uni?

Anonymous

@PrathyushPoduval Maybe. But I'm new there. Don't know many people.

@BalarkaSen uh, nothing personal but filling your pockets with ravioli seems kind of dumb to me too o_O

Anonymous

Anyway, I'll need one in the long run

Prathyush Poduval

4:59 PM

@Blue Yeah you would, especially if youre doing any diy projects

@Blue need one? I used one for a class, but I must have completely missed the point

what are they supposoed to be useful for

Prathyush Poduval

@0ßelö7 hobby

@vzn it's just a prank bro

@BalarkaSen some pranks are better than others. can agree with that (trying to find way to agree lol). which reminds me of a prank have you guys seen this one? making the rounds... (bordering on ~~evil~~ unethical psychology experiment...)

Anonymous

@0ßelö7 I will need it for my physics research project.

Anonymous

5:01 PM

@0ßelö7 Lots of stuff

LG Ultra HD TV Prank - End Of The World Job Interview [Meteor Explodes]

yeah i saw that one

@Avantgarde & whatdja think? like the tech angle myself... have long mused (since their intro) that HD tvs seem like "looking out of windows" :)

wow en.wikipedia.org/wiki/Filthy_Frank

> Additionally, Miller's video titled Do the Harlem Shake (Original), which originated as a clip on the video "Filthy Compilation #6 – Smell My Fingers",[5][6] has been viewed 58.1 million times (as of July 2017) and led to the creation of the Harlem Shake meme,[7][8] which was directly responsible for the debut of the song "Harlem Shake" (by producer Baauer) at number one on the Billboard Hot 100.

yeah he discovered the harlem shake

@vzn I didn't think much about it besides that it was a nice prank

I have been out of touch with TV/TV shows for long, and that's how it's going to be

5:15 PM

@Avantgarde BaS seems to be an aficionado/ connoisseur of pranks, maybe will have to go with his superior judgement on this one

Every once in a while people spam GoT posts, and that's when I know a new season just came up

@vzn BaS?

@Avantgarde non edgy initials of Balarka

@vzn ahahaha

@vzn nah i'm a memelord

2

the meme culture is very different from the prank culture

although they do overlap

Yeah he knows it all

Ask him for recs

5:17 PM

interesting. seems like AFT is the memelord around here. anyway can have some appreciation for both memes/ pranks... who doesnt... humorless ppl? o_O

AFT hasn't been here in a while

maybe he's stuck in a -+++ dimension

Anonymous

Sep 3 at 22:38, by ACuriousMind

@Blue Probably gone into hiding to craft better +--- memes.

Memes are good. But I got bored of them lately. Or probably I just came across the same old ones, or ones based on a similar concept

@BalarkaSen lol yeah either that or +---

@Avantgarde lol at anyone who is "tired of memes" o_O

speaking of pranks did anyone ever see that old ashton kutcher mtv show? didnt watch it a lot but do recall one where somebodys car seemingly blew up in parking garage... some pretty edgy stuff on there... & hey marrying a 15yr older woman, thats pretty edgy too o_O

5:22 PM

@vzn meh memes meh

@Avantgarde you just need to look at the good meme, or, as they say is, the god maymays

It's a French word after all

@Avantgarde r/Bikinibottomtwitter

@BalarkaSen huh? god memes? how about this ultimate one? o_O en.wikipedia.org/wiki/Flying_Spaghetti_Monster ... come to think of it maybe filthy frank/ ratajowski are actually also pastafarians o_O

@Blue what are you gonna do with your arduino? defn good for robotics... which reminds me need to look up upcoming conference :)

Anonymous

@vzn My project is related to making optimizations for non-inductive wireless chargers. Currently learning to control hardware using Arduino.

Anonymous

Also, found a really good book on wireless power transfer

Anonymous

5:34 PM

this

never use 'this' when you can 'dis'

Anonymous

@Avantgarde 'tis' s btr

@Blue cool. reminds me, heather said shes working on a bell experiment, wonder if shes gonna use a controller or just computer... would like to see worlds lowest cost bell experiment, maybe using low cost controller like arduino. used this myself yrs ago, Stamp, bought it at radio shack! measured photons o_O parallax.com/sites/default/files/downloads/…

@Avantgarde don't add to negative stereotypes whenever possible

Huh?

5:38 PM

r/indianpeoplefacebook

lol

@BalarkaSen do you know it?

yea

@Avantgarde just look

I think one should strive for spelling perfection

It's just a joke, chill

5:43 PM

@Avantgarde did you look?

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