Light travels slower in glass than in air, and if the index of air is $1$, then the index of glass should be higher. I got that the index of glass was $1.12$
with the formula $n= \frac{v}{c}$ which was given to us by our teacher.
How do I calculate the speed of light? If the index of glass is eq...
@Ramanujan The gravitational field of the earth extends till infinity but it becomes negligible after sufficiently long distances as it falls over as $\frac{1}{r^2}$. Moreover, the effect of the sun's gravitational field begins to dominate over the earth's gravitational field at distances far away from the earth.
@Ramanujan In Newton's times, people hated the idea of 'action at distance' very much.
People couldn't believe that a force could be felt magically through air.
People were used to pushing and pull but were surprised that gravity can pull things downwards through air/vacuum.
Faraday introduced the concept of field for the first time.
The idea was to assume that the an object creates a field around itself.
Other objects interact with the field and feel a force.
Earth creates a field > object interacts with the field > object feels a force
The optical chirality of the electromagnetic field is a conserved quantity, analogous to the energy density, linear momentum density, and angular momentum density, which describes how chiral the EM field is at each point, and it is given by
$$
C=\frac{\varepsilon_0}{2}\mathbf E\cdot\left(\nabla\t...
@EmilioPisanty Is this possible according to Noether's 1st theorem? I mean, Zilch is obtained using the duality symmetry of Maxwell's equations (From your other question). Can this (finite) set of symmetries give rise to infinitely many conserved quantities?
but I want to be original. Maybe one big, fat dreadlock
user228700
@JohnRennie This might sound boooring but I might attempt to procure my driver's license before heading off to college seeing as there won't be much to do in the summer.
@JohnRennie Ah, OK :-) It might be some trouble getting both in the span of 60 days but hey, I literally came up with that just now and now I'm taking it seriously so thanks!! (:-P)
@Mostafa Zilch does not correspond to the duality symmetry (that's the optical helicity if I remember correctly). Zilch corresponds to a more complicated symmetry transformation.
@YashasSamaga When I first saw that I had a moment of hope that someone was asking about the experimental methods of doing reasonable precise bench-top measurements.
There are some very nice ways of using interferometers to get three to four digits of precision in a very simple measurement. (You are limited by your thickness measurement, because the instrument has dynamic range to spare.)
@Ramanujan You have to fix the rails to something to stop them moving. Since the rails have to pass over all sorts of different types of ground the simple solution is to put a base under the rails. That's what the sleepers are.
@Ramanujan As @JohnRennie says, they balance the train's weight to the ballast below, keep the rails spaced evenly (because of expansion, etc.), and other stuff.
It is easy to construct a home-made cloud chamber. In observation, one finds that the directions of the trajectories are quite random. Does this mean that all the particles detected are secondary cosmic rays?
points out that in a cloud chamber we see only the secondary electrons not the cosmic rays themselves. Why don't the cosmic rays (high energy protons) leave a trail in the cloud chamber?
@Mostafa there's other quantities that share the same meaning
so, for instance, you could take the optical helicity, $\mathrm{Hel} = \frac12 \left( \mathbf A^\perp \cdot \mathbf B - \mathbf C^\perp \cdot \mathbf E \right)$, and it's also "a sort of handedness".
So there's this big hierarchy of related quantities
@dmckee as I recall the droplets in a cloud chamber form around ions created by the charged particle. So that must mean the (low energy?) secondary muons are better at ionising atoms than the high energy protons in the cosmic rays. Why would that be?
In NuSea (Fermilab E866) we put about 3 tons per square meter of shielding in the cavity of the main magnet to remove most of the non-muon junk and it worked just find even though the mean energy of the detritus was higer than a mere GeV like cosmic rays.
@dmckee if you watch a home built cloud chamber you don't see lines spanning the chamber. You see tracks starting at random points in the chamber then travelling a few cm before fading out.
I assume those are electrons created when a muon scatters off an air molecule.
@JohnRennie I would guess so. Muons have pretty low dE/dx, and a only slightly supersaturated detector might not notice them. But delta rays (scattered electrons) have much higher dE/dx.
@dmckee is there an intuitive explanation of that? Assuming the scattering is mainly EM the only difference is the momentum of the particle. Why are high momentum muons bad at ionising atoms in the air while low momentum electrons are good at it?
The Bethe formula describes the mean energy loss per distance travelled of swift charged particles (protons, alpha particles, atomic ions) traversing matter (or alternatively the stopping power of the material). For electrons the energy loss is slightly different due to their small mass (requiring relativistic corrections) and their indistinguishability, and since they suffer much larger losses by Bremsstrahlung, terms must be added to account for this. Fast charged particles moving through matter interact with the electrons of atoms in the material. The interaction excites or ionizes the atoms...
I dont think that there is an intuitive/physically obvious reason. Its just that when you plug in actual numbers, muons have low dE/dx while electrons have high dE/dx.
your question doesnt make much sense though. They commute because when you calculate the commutator, it is zero
thats why
if you want to know the reason for why we expect it to commute to begin with, or why we know that it has to commute, then it is because rotational invariance
@0celo7 In principle I would like to understand how to define a manifold, but in practice I lack enthuisiasm for the amount of work required. I think you should assume I'm a lost cause unless I suddenly discover I have a lot more free time.