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12:00 AM
@Mew, o/
 
 
3 hours later…
3:16 AM
Howdy
...Anyone here?
@obe Ya really leaving?
 
3:36 AM
Hiii , good morning
 
user116211
3
A: What is the most efficient way to destroy the universe?

BarsMonsterFind antiuniverse somewhere and annihilate it with what we have here. Black holes does not work as they evaporate when growing.

 
user116211
Why did this 5 years old post come to Late Answers review queue?
 
4:10 AM
eye is gleeming Bubble of nothing?
 
4:26 AM
@Secret You around?
 
yup
 
Do you know Linear Algebra?
 
I have done a course on it 3 years ago. Just ask and I will see if I can help
 
in Mathematics, 1 min ago, by Bernard Meurer
A set being a vector subspace of $\mathbb R^4$ with dim=2 the same as it being a generator of $\mathbb R^2$?
 
well, it is true that since the vector subspace is 2 dimensional (it has a basis of two elements, say the unit vectors along x and y (or more generally any 2 linearly independent unit vectors in $\mathbb{R}^4$, say u and v)), then it is going to span all possible values of $u$ and $v$. I suspect then it should be isomorphic to $\mathbb{R}^2$ but let's see if I can construct the isomorphism to show that
 
4:40 AM
@Secret Does it being isomorphic to $\mathbb R^2$ imply it spanning $\mathbb R^2$?
 
yes, as an isomorphism is bijective. Thus it is surjective. That means the inverse map should be able to take any point in $\mathbb{R}^2$ back to the 2 dim subspace. If the map only take the 2 dim subspace to a small set of $\mathbb{R}^2$ then the inverse map cannot recover the whole 2 dim subspace.
 
@Secret Sweet, got it
 
@Secret Why can't the universe have a happy ending? :(
Goddammit second law of thermodynamics and vacuum decay
You two ruin everything (literally)
 
2 days ago, by Bernard Meurer
Let's be honest here guys, life's a bottomless pit of pain and suffering
@SirCumference ^
 
@BernardMeurer Damn, so pessimistic :(
 
user218912
5:04 AM
huh they're not deleting my account. -.-
 
@obe Who?
 
user218912
the mods
 
@BernardMeurer Hey, traitor!
You're math-cheating!
 
@DanielSank You were taking too long :P
 
user218912
I requested deletion 27 hours ago but still no e-mail or deletion.
 
5:06 AM
@obe Why?
 
@BernardMeurer Let $a,b\in \mathbb{R}$ fixed constants, Let $k,l\in\mathbb{R}$ and let a basis of $\mathbb{R}^4$ be $\{\mathbf{s,t,u,v}\}$ and a basis of $\mathbb{R}^2$ be $\{\mathbf{c,d}\}$. Suppose the subspace is $S=\{<\mathbf{s,t}>+a\mathbf{u}+b\mathbf{v}\}$. Then define a homomorphism $f: S\rightarrow \mathbb{R}^2$ as follows:

$$f(k\mathbf{s})=k*f(\mathbf{s})=k*\mathbf{c}$$
$$f(l\mathbf{t})=l*f(\mathbf{t})=k*\mathbf{d}$$
$$f(a\mathbf{u})=a*f(\mathbf{u})=a*\mathbf{0}_{\mathbb{R}^2}=\mathbf{0}_{\mathbb{R}^2}$$
 
user218912
@BernardMeurer I feel like it's time to move on, and I don't think people like me here :p
 
@obe I'd say you're being stupid, but you literally never listen, so do your thing man. Thanks for all the help you gave me back when applying to Waterloo, I truly appreciate it. Let me know if you ever need anything.
 
Typo: I timeout in the edit, thus there are couple of bolding I cannot fix, hopefully they are clear enough that you can work out what they should be
 
@Secret I like you
You wrote a thesis for my dumb question, lol
 
user116211
5:15 AM
@DanielSank o/
 
user116211
Hey @obe.
 
@SirCumference There's one ending of the universe which might be a happier ending if it is true: A cyclic universe, one which expand and contract forever
 
@Secret Yeah but that violates the second law of thermodynamics
If entropy must always increase, then it would increase between cycles
We'd find a dead universe eventually
That fact has led many astronomers to abandon the oscillating universe hypothesis
@Secret This paper says
> ...one principal obstacle is the second law of thermodynamics which dictates that the entropy increases from cycle to cycle. If the cycles thereby become longer, extrapolation into the past will lead back to an initial singularity again, thus removing the motivation to consider an oscillatory universe in the first place.
The only hope is that future revelations in what we know about dark energy may help us evade the entropy problem
 
Agreed
 
user116211
@SirC, do you know obe's name at Skype?
 
5:26 AM
@MAFIA36790 'Fraid not
But he still hasn't deleted his account
He said he would do so over a day ago
 
user116211
@SirCumference He already requested.
 
@MAFIA36790 It's been 24.5 hours since he said he requested
 
user116211
@SirCumference yes.
 
@MAFIA36790 Do you know what country he's from?
 
@MAFIA36790 \o
 
user116211
5:28 AM
no; maybe @Bernard knows.
 
@SirCumference Canada
@MAFIA36790 Hey mate
 
user116211
@BernardMeurer hey .
 
@BernardMeurer Nope, didn't find anything in skype search
 
user116211
@SirCumference yes, I didn't find anything either.
 
But perhaps mods can see deleted messages
@ACuriousMind to the rescue?
 
user116211
5:30 AM
@SirCumference What deleted message?
 
@SirCumference Who are we talking about?
 
user116211
@BernardMeurer obe.
 
@MAFIA36790 Obe gave his skype name yesterday, but he deleted it a few seconds later
 
He's Canadian
I've skyped with him
 
He didn't want it staying here
 
5:30 AM
He's very much canadian
 
@BernardMeurer So help Mafia out
 
What's going on?
 
user116211
@SirCumference I missed that :( Poor connectivity is always a problem of mine.
 
5 mins ago, by MAFIA36790
@SirC, do you know obe's name at Skype?
 
I'll sell that information for 5 dollars
 
5:31 AM
@MAFIA36790 lol, repeated that
@BernardMeurer ...
 
Okay
I'll put it real quick and then delete ir
Are you looking @MAFIA36790?
 
@BernardMeurer K
Wait
Make it a riddle
It'll be more interesting that way
 
No, I'm busy
 
user228700
I...have a fantastic memory, u guys.
 
5:35 AM
@BernardMeurer So?
 
@SirCumference Waiting for @MAFIA36790 to say he;s looking
 
user116211
@BernardMeurer wait; leave a comment in any of my post; I'll then reply; you'd delete it then; my connectivity is poor; so I may not catch the comment here before you delete it.
 
Oh boy
 
@MAFIA36790 LOOK QUICK
 
@MAFIA36790 LOOK QUICK!!!
BEFORE IT'S TOO LATE
 
user116211
5:36 AM
\o/
 
user116211
gotcha.
 
high five
 
You owe me a coffee or something
You better have good coffee in india
 
user116211
@BernardMeurer :)
 
5:36 AM
@BernardMeurer No such person exists in skype's contact search...
 
@SirCumference O.o
 
I copied and pasted
 
He's here for me
Me too
 
user116211
wait, let me check.
 
oh nvm
It's because I only looked for people in canada
 
6:14 AM
1. I can float myself to the skies by kicking as if I am swimming
2. Space based on familar locations are usually at least twice as big
4. I usually have the power to rewind time or a dream scene

Despite all of this (except 3, which seemed to carry a very powerful emotion or some other reason that will almost always destablise the dream) my dreams have learnt how to handle them to the point that it is mostly in control even when I have powers.
That is, it is possible for me to be aware I am dreaming without becoming lucid
My dream and I are like two different people, and we together fabricate the dream world that we experienced. We sometimes compete for dominance, other times we worked together
 
6:26 AM
I don't like his attitude. However...
I don't know enough of quantum mechanics to say anything about this
 
Anonymous
@Secret That was a troll :-P
 
Anonymous
I think it will be closed soon
 
Digging his profile: If something is off topic in philoSE, then it is very very bad
2
 
@ACuriousMind Accurate though :-)
 
6:50 AM
@SirCumference I know that feel. This is one reason why we cannot have an endothermic fire (a fire that lowers the temperature of things), because $T\Delta S$ will eventually drop to a point that the reaction will stop
 
Anonymous
@JohnRennie I have a regarding about one of your answers physics.stackexchange.com/a/152695/135977. I recently read that increasing or decreasing magnetic fields through a certain area produce clockwise or anticlockwise electric fields in circular pattern by Faraday's law. But how is "charge" involved here in the generation of the electric fields (having a circular pattern) ?
 
@S007 you'd have to provide a reference. As far as I know a changing magnetic field doesn't produce an electric field. But electrodynamics isn't my favourite subject, so it's entirely possible I'm wrong about this.
 
Anonymous
@JohnRennie Okay, one minute please
 
If we want to make an explosively self sustaining endothermic reaction, then given

$$\Delta G = \Delta H - T\Delta S$$

for each second of the reaction the increase in $\Delta S$ has to outpace the reduction in the temperature $T$ in order to make $T\Delta S$ to grow without bound. however it is not very clear on how this can be achieved, or whether any reaction can acheive that

One possibility is that entropy can be increased by an expansion in volume, and the expansion accelerates as the temperature lowers
Suppose we can achieve this (even for a sufficiently long finite amount of time), then these endothermic explosives might be potentially more powerful than their exothermic counterparts without much change in heat
This is because their volume has to be expanded in an accelerated fashion in order to be able to sustain itself for long enough
 
Anonymous
 
Anonymous
@JohnRennie Could you check these out ^
 
OK I'll have a look at the video, though that won't be until a bit later today.
 
Anonymous
@JohnRennie No problem. Take your time :). It is not very long though.
 
7:15 AM
@JohnRennie Suppose I want to follow a combustion reaction (e.g. burning coal). While the Gibbs free energy will tell me that at constant pressure and a given temperature $T$ the reaction is spontaneous, as the reaction continues with time the temperature will increase.
It is correct to to say that the rate of change of the Gibbs free energy is just differentiating the $\Delta G$ equation by time, or something more complicated need to be done to incoporate the change in temperature (assuming pressure is relatively constant and stay at ambient pessure)
 
I'm ashamed to admit that only a few days ago I realized that electrons get their name from electric.
 
Anonymous
@SirCumference I think you said this same thing a couple of days back :)
 
@S007 Yeah, but now I realized the same thing about photons
Photo = light
 
Mew
here's a new one for you, neutron is a neutral particle
 
Anonymous
Well that thing about photons happened with me as well
 
7:18 AM
@Mew That I realized a while ago
@S007 Hence, photograph, photosynthesis, etc.
 
Mew
and tachy means fast , tachyon = fast particle
 
@Mew Whoa, that I didn't know
 
Anonymous
@SirCumference Well, most particle names in physics have some reference to their behaviour
 
Anonymous
Or are named after scientists
 
@S007 Like bosons
Fermions too
 
Anonymous
7:20 AM
Yep
 
Bohrons?
 
Mew
and gluons, "glue" quarks together
 
Boron
@Mew Yeah, realized that too
Quarkons
 
Anonymous
Neutrino :-P
 
Jeez, every neutral particle creatively has "neutral" in it. Neutron, neutrino, neutralino...
 
Anonymous
7:23 AM
 
Anonymous
I don't have any justification for charm and strange though :-P
 
@S007 Why'd ya post the table of elementary particles?
 
Anonymous
@SirCumference What does "charm" and "strange" mean?
 
Anonymous
Charming particles ? :-D
 
Anonymous
Strange particles ? :-D
 
Anonymous
7:25 AM
LOL XD
 
@S007 Well the concept of strangeness predates strange quarks
 
Anonymous
Good to know
 
Anonymous
and charm ?
 
@S007 No clue
 
Anonymous
:-P
 
7:26 AM
@S007 But I can say that topness is often called "truth", and bottomness is often called "beauty"
So we got truth, beauty, charm and strangeness
 
Anonymous
Ok. So physicists become romantic sometimes. Like poets :-P
3
 
7:47 AM
How to make profile like this?
 
Anonymous
@Ramanujan What ?
 
Anonymous
Which part of the profile are you talking about?
 
Keeping a low profile
 
Anonymous
You can't. That user hasn't made any posts that is why they are displaying a custom message
 
Anonymous
You have already made so many posts
 
Anonymous
7:49 AM
@Ramanujan
 
OK,sorry
 
Anonymous
no probs
 
user228700
8:01 AM
Morning :-) (Erm, afternoon here :-P)
 
@Kaumudi good afternoon
 
Anonymous
@Kaumudi Good 1:32 pm IST :)
 
user228700
Lol :-P
 
Anonymous
@Ramanujan @Kaumudi you guys use quora ?
 
user228700
I don't ask questions, no.
 
Anonymous
8:15 AM
Even i don't ask questions there, but I found it recently and feel it is a great website and better than stack exchange in some aspects :-)
 
Anonymous
Especially the technology and science section is too good :)
 
user228700
Hmm, you discovered the website now?!
 
Anonymous
Well, a couple of months back
 
user228700
(Also, Quora addiction is a genuine thing, I'm not even kidding. Many of my friends suffer from this :-P)
 
Anonymous
I would love to get addicted to it (especially to the science and tech section) :-P
 
user228700
8:20 AM
But the academia sections contain some great questions and answers, yes. Although, I dunno if I would go so far as to say that it's better than SE in some aspects.
 
Anonymous
BTW I think i am addicted to stack exchange also :-P
 
@S007 all sites have their strengths and weaknesses. The strong point of the SE sites is they quickly identify which members know what they're talking about and which are the nutcases.
2
 
1 hour ago, by Secret
@JohnRennie Suppose I want to follow a combustion reaction (e.g. burning coal). While the Gibbs free energy will tell me that at constant pressure and a given temperature $T$ the reaction is spontaneous, as the reaction continues with time the temperature will increase.
It is correct to to say that the rate of change of the Gibbs free energy is just differentiating the $\Delta G$ equation by time, or something more complicated need to be done to incoporate the change in temperature (assuming pressure is relatively constant and stay at ambient pessure)
 
Anonymous
@JohnRennie I know. SE is great when you have some technical queries. But i feel Quora is a great place to learn new facts (even about topics on which you have no mastery) :) I agree with the fact that every site has its strengths and weaknesses. Like quora doesn't have good moderation :-P
 
user228700
8:46 AM
@JohnRennie:
 
Morning ...
 
user228700
> "William Willet, the grandfather of the great grandgather of the frontman of Coldplay, is credited as the pioneer of daylight saving."
 
user228700
:-D Just a piece of trivia I thought u may be interested to learn.
 
Things I never knew about Coldplay :-)
 
Anonymous
@Kaumudi "grandfather of the great grandfather" XD...by that logic I am related to every person that ever existed on the planet :-P
 
9:01 AM
@Kaumudi I'm feeling a little guilty that I might have dissed Coldplay, but i didn't mean to. We all have bands that are special to us - in my case Hawkwind, in your case Coldplay. Trying to explain these attachments logically is a futile endeavour :-)
 
@JohnRennie You're clearly an unidentified nutcase :P
(plz don't ban me)
 
9:18 AM
Has anyone here come across the zero-component lemma in vector analysis?
 
user228700
@JohnRennie Oh, that's OK sir :-) Indeed. It certainly proved to be futile when I attempted to explain it to my mother whilst watching the program last night.
 
user228700
Hawkwind? Will look it up, sometime...
 
9:47 AM
Does anyone know anything about the Lorentz force
 
Anonymous
@John Yep
 
@S007 Ok so I was told that current cannot be induced unless there is a change in flux. But this does not account for why a single wire, looped outside of the field, when moved through a uniform magnetic field will have an emf induced across it - as there is no area for which flux can flow.
@S007 So am I correct in thinking that it is not a flux change which induces an emf in this scenario?
 
Anonymous
@John In case of a moving wire, the wire "cuts" through the magnetic flux and hence by faraday's law emf is produced
 
Anonymous
Suppose speed of wire is v and length of wire is l
 
Anonymous
Then in time dt it cuts through magnetic flux region having area Blvdt
 
9:55 AM
@S007 but we only talk about flux for an area - a single wire has no 'area'
 
Anonymous
@John We are talking about the area the wire has traversed here
 
Anonymous
in time dt
 
Anonymous
$d\phi=Bvldt$ and emf=$\frac{d\phi}{dt}=Bvl$
 
Anonymous
where B is supposed to be the magnetic field perpendicular to velocity direction
 
Anonymous
I know that you area feeling confused because a wire cannot contain any area
 
Anonymous
9:58 AM
But think of the area in this case as the area traversed by a wire
 
@S007 I'm not talking about a wire on two metal rails which moves through the field - there is an area in this case due to the complete circuit being inside the magnetic field, and this area changes. So a change in area results in a change in flux, hence emf is produced.
 
Anonymous
@John We do not need two metal rails. Even if the wire moves in a magnetic field flux will be cut by the wire. You just need to know the area traversed by the wire
 
Anonymous
See the whole video if you still have a doubt
 
Other answers on stack exchange have said one cannot talk about area, hence flux, for a single wire - it's the Lorentz force acting on the changed particles
 
Anonymous
10:01 AM
@John We can explain the phenomenon in both ways. By lorentz force method or by faraday's law
 
Anonymous
Anyway see the video. Your doubts will be cleared
 
Ok, I'll go watch the video and get back to you
 
Anonymous
@John If you are in a hurry then start from 4:52 of the video
 
Caption: Ok finished analysis. It seems it is theoretically possible to have an extreme cooling reaction if you can get the entropy change to accelerate as the temperature drop in the reaction, until maximum entropy.

It in unsure how this can be done, other than somehow, you need to generate microstates at a rate faster than the loss of numbr of accessible microstates due to the reduction in temperature
The issue is, however, not only entropy increases until maximise in a closed system, it also slows down in that increase over time due to the natural log dependence
Therefore, this explains why neither exothermic and endothermic reactions can go on forever, as these physical scenarios means the gibbs free energy cannot decrease forever
 
10:18 AM
@Kaumudi You wouldn't like Hawkwind. Trust me on this one :-)
How dare you? That's not true - I'm not an unidentified nutcase!!
I'm an identified nutcase :-)
 
@S007 ok so emf is induced when flux changes or when it is cut
 
Anonymous
@John Exactly :-)..any other doubts ?
 
@S007 so what about if we have a rectangular coil of wire and pass it through a uniform magnetic field. There is no change of flux, but the flux is still cut, yet no emf is induced
 
Anonymous
Yes, emf will be generated but you need to keep in mind the direction of emf generated also. In one side of the rectangle the emf may be in one direction and in the opposite side the emf may be in the opposite direction..hence making the net emf zero
 
Anonymous
@John
 
10:27 AM
@S007 ah ok that's what I was thinking
 
Anonymous
You need to calculate net emf in such cases
 
Anonymous
i hope it is clear now @John
 
@S007 so, back to the single wire, we can talk about this as motional emf (Lorentz force) or induced emf(Faradays' law)
 
Anonymous
yes..both are correct!
 
Anonymous
@John
 
10:29 AM
@S007 ahh ok. Well thanks, you've been a massive help!
 
Anonymous
Welcome and feel free to ask any physics related doubts on hbar :) @John
 
@S007 I'll probably
@soo
@S007 this keyboard, I'll probably be on here again soon:)
 
Anonymous
bye :)
 
10:47 AM
@S007 is this from physics galaxy
 
user228700
11:10 AM
@JohnRennie Yeaah, I listened to The silver machine and didn't enjoy the experience very much :-P
 
Anonymous
11:22 AM
@koolman yes
 
Caption: Everything is easier with arrays
 
user228700
Hmm, a song that has the word Quarks in the title. I too know a brilliant song that shares this property:
 
user228700
11:56 AM
@JohnRennie I liked that! :-)
 
@Kaumudi The only Hawkwind track non-fans know is Silver Machine because it was their only chart hit, but it isn't really typical. However I still don't think you'd like them. QS&C is one of their poppier songs.
 
If you pass a current through a wire which is in a magnetic field, this will extert a force on the wire. Does this force then induce another emf across the wire in the opposite direction?
 
[Division by zero] Got a new result, to be written into a theorem later:
The amount of control the zero terms have on the + structure depends on the range of the 0 row and/or column of the * cayley table
Therefore, if you found multiplying by 0 to all other elements is equivalent to a permutation of the elements, then you are in deep trouble
 
user228700
@JohnRennie Ah, I see.
 
user228700
Yeah, no, as Kyle Kanos puts it, I'd listen to them if they were to come on the radio, but I wouldn't go out of my way to look for their music.
 
user228700
12:05 PM
Say, Camden is in London, correct? Is that very far from where u live?
 
Camden is in London, and London is a bit over 200 miles from me - about a four hour drive.
 
1:05 PM
hey
 
@S007 do you that teacher on
Physics galaxy teaches us
 
1:17 PM
*do you know
 
1:38 PM
hello
 
user228700
@JohnRennie Ohh, okay :-)
 
user228700
@heather: Allo!
 
@obe, please don't leave us...
@Kaumudi, o/
how was coldplay?
 
user228700
They were <3 <3 <3
 
=D
 
user228700
1:41 PM
How was calculus? :-P
 
user228700
@koolman Oh, that's awesome!
 
it was <3 <3 \o/ <3 <3 =( =)
the frowny face: where I made multiple stupid mistakes in a row
=P
 
user228700
Ah, I see. At least the "<3"s outnumber the frowny face :-P
 
\o/ was where I finally got something right
 
user228700
:-)
 
1:43 PM
yep
it was a good day
 
user228700
Great :-)
 
Yeah @Kaumudi
 
Mew
Hi Kaumudi
sup heather
yo koolman
anyone good at biology here?
 
7th grade life science: sure
anything beyond that: nope =P
 
user228700
@Mew: Ello :-) Again, why are u learning Bio at midnight, sir? :-P
 
user228700
1:54 PM
Also, try The Periodic Table. There is a person named Aaron Abraham who frequents the room. It appears that he knows a lot of Biology.
 
Mew
nvm i answered my own question
I have a new question
can the laws of physics be derived from reason alone or do they require observation?
If they require observation, does this mean that the laws of the universe are arbitrary?
 
well, there are a few points I might make here; this is more relevant to mathematics, but it is worth looking at anyway, because physics is described in the language of math.
1. people tried doing this with math; see the Principia Mathematica, a multiple volume work that attempted to create a consistent system for the laws of mathematics. Took until the second volume to prove that 1+1=2; at which point they stated something like "This result is occasionally useful" =P
2. then Godel came along, with his incompleteness theorems, and others came along, and generally proved that it is impossible to create a self-consistent system for all of mathematics.
 
Mew
point 2 you mention just seems weird to me
would point 2 apply to physics or just maths?
 
@heather do you have that book?I am not getting it's PDF online
 
@Mew, points 1 and 2 apply to math, but one moment, I'm coming back to physics
@Ramanujan, nope, don't have a copy. I'll look around for it though.
3. going back to physics, the basics of it is observation, but all of physics is really described by math (even if we haven't completely pinned down the math). In fact, even the more abstract areas of math have been brought into physics (in most cases).
 
2:04 PM
@Mew Science requires observation by definition. Otherwise you're just doing math (not that there's anything wrong with that)
 
4. considering whether the laws of physics can be derived from reason alone, isn't that kind of what Aristotle tried to do? and he failed miserably.
 
Mew
@ACuriousMind if science requires observation, then would you agree the laws of physics didn't have to be the way they are?
because if the laws could only be the way they are, then one should be able to work out this one solution without observation
 
That is, even if one could derive all laws of physics logically from a simple axiomatic starting point, we would still require observation to check that those axioms actually hold in reality.
 
Mew
only if there are multiple possible solutions would observation be required
 
@Mew, but there you are getting into philosophy, surely. If you believe in a God, then it isn't arbitrary, true? Because God created it. If you believe it is all random chance, or maybe that there are multiple universes, then yeah, it is arbitrary.
 
Mew
2:06 PM
@heather, mabye Aristotle tried and failed, but that doesn't mean a super genius alien couldn't succeed?
 
@Mew I think that is a meaningless question - the set of universes/laws of physics I have observed has cardinality 1. I don't know what "could have been different" is supposed to mean.
 
Mew
@heather if there is a God, then God may have "free will" and thus could choose which arbitrary laws to create
 
@Mew, now this is starting to sound like determinism, which quantum mechanics tossed to the wayside, don't you think.
 
Mew
IF there isn't a god, one would expect the universe could only be what it is?
 
@Mew, and as for God, He has free will, surely, but then He also has infinite intelligence, therefore allowing him to pick what is perhaps the best possible option?
 
Mew
2:08 PM
@heather, do you think quantum mechanics really tossed away determinism though? many world's interpretation doesn't require determinism to be tossed
Determinism only needs to be tossed away under the copehan hagen interpretation which isn't that popular
 
@Mew, as far as I know, most scientists believe in the Copenhagen interpretation. But either way, I don't think the many worlds interpretation is quite right (and neither do I think the copenhagen interpretation is quite right). But at that point, we are discussing interpretation. Your super-alien now must have access to multiple universes. Does that even make sense?
 
@Mew I think the notion of "could only be the way they are" is ill-defined. What is the ensemble of alternatives here? We know of no universe but ours, no laws of physics but the ones we discover. "Could have been different" implies that there is a repeatable event of "starting a universe" and you're asking whether it is deterministic or not. But it's not clear that that event exists at all, let alone is repeatable.
 
Mew
@ACuriousMind do you agree with heather that QM means there is no determinsm?
 
@Mew, and doesn't that answer basically agree with me?
 
Mew
@heather the point is there is an interpretation of QM where determinism holds. Also QM doesn't mean the actual "laws" of physics are random, but only the outcome of particular events.
@heather the second answer states that QM doesn't disprove determinism
"Quantum Physics doesn't disprove determinism."
 
2:14 PM
@Mew, it doesn't explain how it doesn't. It says "it significantly complicates it" but gives no example of how you can squeak by.
 
Mew
Note I'm not concerned with whether the actual events of the universe can only happen in a particular way, but rather whether the "laws" of th euniverse had to be the way they are
 
@Mew No. Once one adopts a collapse-free viewpoint modelling both system and apparatus quantumly determinism is restored. But this is tangential to the question of the laws you originally raised, imo.
 
Mew
@ACuriousMind I agree, but heather was of the view that QM was inconsistent with determinism so I thought I'd get your input
 
@Mew, now remember, in this conversation you have to keep in mind that I haven't studied physics nearly as much as either of you.
but I would still have to say that QM is inconsistent with determinism.
 
Mew
@heather yes that's why I wanted to convince you that QM is compatible with determinsm
 
2:18 PM
but see the problem with questions like these, is it all comes down to the interpretation. I mean, it's just that, an interpretation.
 
Mew
But surely the statement "the laws of physics can be derived without observation" is either true or false
not dependent on interpretation
I agree though that whether the results of the universe are deterministic or not probably does depend on interpretation of QM
ok gtg to sleep now
laterz
 
have a good night
 
Anonymous
2:45 PM
@koolman You must be from Allen Jaipur I guess ?
 
Anonymous
You are lucky to have him as your teacher :)
 
3:19 PM
[Division by zero] On 5 element division by zero divisor algera: If $a\neq b$ and $ab=0$, $ac=1$ then the algebra is NOT associative

Proof: I have no idea, other than I literally tried every consistent cases and found the nonassociative entries of the cayley table are actually locked up (i.e. has only one possible choice, which is the nonassociative choice)
 
3:56 PM
@Mew sorry not in biology
@S007 absolutely right
 
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