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20:00
@MikeMiller So you're only defining $d+d^*$ on the even-dimensional forms?
I wrote everything incorrectly, but see where I originally said "I prefer to think of signature as..."
1) That's Euler characteristic. 2) Odd and even should be swapped.
Yeah, there you wrote on even forms, right
odd
Wait,
So you wanted to write $\bigoplus_{n\text{ even}}\Lambda^nT^*M\to \bigoplus_{n\text{ odd}}\Lambda^nT^*M$
And you're only defining it on even forms because...?
because it actually gives the euler characteristic that way, as you just showed half of
20:04
But the thing I did did not distinguish odd/even at all---what's up with that?
Did I mess something up?
no.
the kernel of the map, on even forms, is the even-dim harmonic forms. so you add those dimensions up.
the cokernel of the map is the odd-dim harmonic forms. in the index, you subtract off the cokernel.
Yeah, and then the kernel of the adjoint is odd
But the adjoint is... just the same thing again??
Okay, so I'm not crazy
the cokernel is (equivalently) the kernel of the adjoint
20:05
I've become too insecure lol
@MikeMiller Right, that's what I thought (I wasn't sure... the place I "learned" that was string theory...)
I hate writing still.
the cokernel is the codomain mod the image, equivalently (when the image is closed) the orthogonal complement of the image, equivalently the kernel of the adjoint
I still love it---just wish I had some interesting subject matter!
@PVAL-inactive me too
@MikeMiller Ah, I see
20:06
@Danu there's different flavors of writing
expository writing tends to be more fun i think
Yeah, for sure
I love expository writing, and that's all I've done of course.
Even my bachelor's thesis was hardly any research stuff.
I can parallel translate now
What's that?
Oh.
transport
Moving a vector on a manifold w/ an affine connection "parallely" along a path
20:08
For expository writing you can just reference the research for anything you don't want to deal with.
And you don't have to deal with making up notations.
^an important task!!
@PVAL-inactive My advisor once had me read the thesis of a student of a particularly famous Floer homologist. He told me that he quit math because he was inable to write any of ideas down even though he had plenty of good ideas. I think only 70% of the reason he told me about this is because the thesis would be useful for my work.
@MikeMiller ah, yes, that was the word IIRC. Ted says "translate".
@MikeMiller 30% intimidation and asserting dominance, clearly ;)
30% was telling me to fucking write
20:11
I was joking
How did he write the thesis then?
Doesn't that show the ability to write
?
It was like 40 pages or something, about three different papers at once, and was basically only written with support over five years I think.
Like it's not that he was a bad writer but that he had a lot of trouble putting pen to paper which is the problem I have too.
But I'm glad you got his message
(just disconnected for a minute or so, sorry for delayed messages)
I sort of wish I was around before TeX existed so I didn't have to do all the formatting myself.
When is it going to be out?
20:16
I think it would've been harder rather than easier back then
"Christmas" is what I am going with.
The journals did the formatting./
You just sent them a manuscript./
Probably about 10-15 pages.
My proofs right now are unbelievably terse. I think because I thought about them so much, that its hard to go back to beginning to understand them.
@MikeMiller Really?
Was there a fee? :P
maybe a depressed grad student will kill Don Knuth someday
20:18
@BalarkaSen That's not funny.
It also wouldn't help
@Danu Universities pay for journals. They used to actually do something of value to justify the cost.
There is also still a fee
at many major journals
Oh well. Guess we're all screwed.
It's kind of frightening when you are learning so much from someone who couldn't keep doing math.
I've felt that way at least.
20:21
MF?
Schoenberger
I don't know who MF is
who is that?
Freedman.
I have no idea who Schoenberger is.
Oh, he could keep doing, but he did other things.
Think Freedman is by choice, and I'm pretty sure his position is as good as any academic one.
He also had at least one redic. successful student (more successful than him).
Fair enough.
Schoenberger was a student of JE like 15 or so years ago.
20:23
Got it.
I've learned quite a bit from his thesis.
@MikeMiller: I suppose it's not, yeah. I realize it's a pain to keep typesetting the margin or something for the whole day even when you've got a whole theorem you want to write down.
I mean when your student wins a 5 million dollar prize and you won a Fields medal, I think you've already had a pretty full academic career.
G'night, @MikeM, particularly @Balarka.
Hi @PVAL
20:28
Hi @Ted.
@PVAL-inactive I didn't realize he'd left academics!
Hi @TedShifrin
Hi @Danu
@BalarkaSen Sometimes whole theorems are 50 pages long. And you have to spend time writing the background section.
@TedShifrin I got some more topic suggestions from my supervisor! :) If you're interested, I linked them around here.
I also talked to him about the "isolated" position I've been experiencing---and he had some nice news to deal with that, too: He might start holding (bi?)weekly meetings for his students (he calls it "research tutorials")
20:32
I like the sounds of those topics, @Danu. And getting to know and talk with more students is always a good thing.
@Balarka: Did you look at any of my favorite exercises yet?
@TedShifrin I did a couple of problems, but only the helicoid&catenoid problem intersects with your list.
I am moving ahead to connections for a bit
@TedShifrin There's a famous theorem that if you have two connections on a $G$-bundle such that the holonomies around every loop are conjugate, the connections are gauge equivalent. I'm working out how to do this again, which will probably take me a couple hours (to do that and the enhancement I want). Do you know a reference I can look at where this is proved?
Oh, well, I guess I'll stop recommending problems.
Nope @MikeM
Just don't blame me for it.
I think I am falling into the pattern of writing down theorem/lemma/prop-> proof-> completely meaningless remark to fill space before next theorem/lemma/prop/ and repeat.
20:36
@TedShifrin I did do (and liked!) the ones you recommended before :) I didn't find that particular chapter very exciting, except the (statement of) Theorema Egregium and Hilbert's theorem.
Thanks. I'll just do the work.
I'll look at it again though.
@TedShifrin Are you up for talking about the Albanese map a little bit?
I think understanding that constant principal curvature happens only for tubes is cool (albeit intuitively plausible). Two constant principal curvatures?
What can you say if you have lines on a surface making constant angle at each point? What about the corresponding question for geodesics (next section)?
Maybe soon Balarka can answer my question.
20:40
These questions sound more interesting, @TedShifrin. I'll bookmark them instead.
@Balarka: Three of these were in my list you so rudely ignored.
What's there to say other than integrating, @Danu?
@TedShifrin ...welllll
@Balarka: What's more ... these are questions that — at least as far as I know — do not appear in other texts.
Hello all! I've got a really quick, dumb question that I guess is fairly perennial about standard terminology -- if, in some well behaved vector space, a function maps numbers to numbers, operators map functions to functions, and functionals map functions to numbers, what is the name given to an object that maps operators to operators?
20:42
I take back what I said. I don't know how I missed these.
So I understand the definition of the Albanese torus.
@TedShifrin Looks like I can just black box it.
Probably still an operator ... @Landak. Are you talking about a linear map or a general map?
I'll ask my advisor tomorrow.
@TedShifrin -- Let's say in general
20:43
I'd have to see context, but I'd probably just use the generic word map(ping) ...
Fair enough
OK, @Danu, so what's the definition?
I just thought there might be something I was aware of but had forgotten!
@TedShifrin So you mean, $k_1 = 0$ and $k_2\neq 0$ is constant?
There might be, @Landak, but then I've forgotten too :)
20:44
Then you want me to prove it's a tube, yes?
oh, no, by tube you don't mean cylinder
No, one nonzero constant, the other variable.
So if I have a closed path $\gamma$ in $X$ then $[\alpha]\mapsto \int_\gamma\alpha$ is an element of $H^0(X,\Omega_X)^*$.
If both are constant, what can happen? @Balarka
So we get a map $H_1(X,\Bbb Z)\to H^0(X,\Omega_X)^*$
Pretty sure either sphere or plane or cylinder.
20:46
OK, @Danu. Is that map injective?
Prove it, @Balarka.
Working on it.
@TedShifrin Yes, it forms a lattice right
This becomes a much more interesting question in higher dimensions, btw. Studied by Elie Cartan. @Balarka
We're back to our question of rank of that lattice, @Danu?
Eh yes I guess?
@TedShifrin Ah, alright
20:48
We're assuming compact Kähler, so you can answer it, @Danu.
Yeah, same idea as before right
Let me recall what I said there
Oct 8 at 17:15, by Danu
@TedShifrin Eh... $H^1(X,\mathcal O)=H^{0,1}(X)$ which is half dimension of $H^1(X,\Bbb C)$, as is $H^1(X,\Bbb Z)\otimes_{\Bbb Z}\Bbb R$ as a real vector space, since $H^1(X,\Bbb C)=\text{that}\otimes_{\Bbb R} \Bbb C$?
Boy, you search quickly.
"rank" is not such a common word ;)
I guess this means we don't do much linear algebra in chat.
20:51
Bad for me! More linear algebra is what I need
Salut, @JeSuis.
Anyhow, so you're getting a (compact) torus when you mod out.
Certainly I need lemma 3.3. here and I'm terrified because I take it as a blackbox and mostly don't understand it
@TedShifrin Yeah, I guess the argument is essentially identical.
So we have this torus and that's okay. Now I need to understand the next lemma about properties of the Albanese map.
@Balarka: I don't understand that attitude. It's the result of a bunch of formulas. If you want more intuitive understanding, you'll see it with moving frames/forms.
So $\operatorname{alb}:x\mapsto(\alpha\mapsto \int_{x_0}^x\alpha)$ for fixed $x_0$
20:53
Right, and well-defined because you've modded out by periods.
and it's independent of base point because we mod out loops, which are changes of base point
right
So now there are the following properties
No, it depends on basepoint.
Sorry, you're right
I messed that phrasing up
If you take two different basepoints, what's the relation?
@TedShifrin If I have a linear vector field of dimension $2$, a periodic orbit means that there exist T>0 such that $\phi_T(x)=x$ (where $\phi$) is the flow, right?
20:56
For some particular $x$'s, yes.
Why linear vector field? Any vector field.
yeah sorry, what does it means that all orbit are periodic that $\phi_T(x)=x$ for all $x$ ?
@TedShifrin Well, idk how to say anything more sensible than saying that the difference is $\int_{x_0}^x\alpha-\int_{x_0'}^x\alpha$
@TedShifrin Okay. I have almost never done symbol-pushing without understanding the intuition before (and inevitably get tripped up in such calculations), and I want to get this chapter done before the moving frames section in the next one.
Oh, no, @JeSuis, if it's for all $x$, then you need $\phi_{T(x)}x = x$ for some $T(x)$, right?
Ah, but since we're modding out loops I guess we can say it's then $\int_{x_0}^{x_0'}\alpha$ or maybe minus that
20:58
I'll get over it I hope
@Balarka: I think it's intuitive that (at least with a reasonable parametrization) Codazzi exactly tells you about rates of change of the principal curvature along the lines of curvature.
@Danu: I guess I was wanting you to say well-defined mod a translation of the torus.
True enough.

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