To be honest, i think i probably spend three hours of my life dealing with imaginary numbers. In all of my schooling i have never encountered complex numbers.
It got marked down because the answer was "You can not do that" (by which they meant "you can not do that with the stuff we tought you, and if you read some other books and know more then we just mark the question as bad".
The Apollo command module had a diameter of about 12.8 ft (which I assume is pretty close to the diameter of its heat shield). However, the heat shield for the new Orion spacecraft is a little bigger, at 16.5 ft (again, the diameter of the vehicle itself).
@UndotheSnowman here's one fantastic chapter from FAA on Returning from Space: Re-entry (PDF) it should have you covered if you take the time to read it ;)
@TildalWave I wanted to thank you for being the big part of the site you are. It's been an awesome journey watching the site grow up, and working together on the issues that arise ;)
@UndotheSnowman C'mon you're making me blush now :) I'd be here anyway as a mod or not, I love it here. I wish I had all the time to research everything, there's not a single boring question here.
@TildalWave Yup, same guy. A beaver chewed on the cable going into his area or something and completely wiped him off the face of the planet as far as the internet is concerned.
He says that pages take 3-4 minutes to load.
Which means he can't run his classes. Which means he can't tell me how to format my paper. Which means I can format it in a decent way!
@TildalWave I was in his class when the beaver wiped him off the planet. Unless he's really good at faking a rapidly failing broadband connection, he's telling the truth.
It was amazing - halfway through the class, he started sounding like he was inside a barrel going down a waterfall.
At the end of the class I'll expose his name... I don't want to now, he searches the internet for bad things said about him.
Currently I have an app on iOS that I am looking to port to Android. This app uses the Objective-C GCMathParser framework/class.
I am looking for a replacement on Android (or a way to make GCMathParser work on Android) that would be able to calculate stuff like:
2*2
(2+3)+2
((2+3)+2)/5
(-2 ...
Try saying self.tableView.userInteractionEnabled = YES; after you implement the clock view.
If this doesn't work, try [self.view bringSubviewToFront:self.tableView];
I remember being soo excited to be able to vote ;)
This month's undergraduate research post features pulsars as a probe of our galaxy's magnetic field, and the possibility of asymmetries in supernovae associated with gamma-ray bursts.
An Open Letter to President @BarackObama from Bill Nye of The Planetary Society @ExplorepPlanets http://www.planetary.org/blogs/bill-nye/20131205-an-open-letter-to-the-president.html#.UqK3dmQRr3c.twitter
In word processing and digital typesetting, a non-breaking space, also known as a no-break space or non-breakable space (NBSP), is a variant of the space character that prevents an automatic line break (line wrap) at its position. In certain formats (such as HTML), it also prevents the “collapsing” of multiple consecutive whitespace characters into a single space. The non-breaking space is also known as a hard space or fixed space. In Unicode, it is encoded as .
Non-breaking behavior
Text-processing software typically assumes that an automatic line break may be inserted anywhere a space ...
In this case I have to launch a satellite into an circular polar orbit at height 800 km.
My question is:
I need to find the latitude and the longitude of the satellite as reference of time (t) and I have to plot it in a map using matlab :)
Thinks I know:
h= 800Km,
i(inclination)=90 Deg due to ...
Is this homework? It seems too narrow by specifying input parameters and software used to plot ground track with to be of any future use to the site, would you please edit your question to clarify what is the purpose of your calculations (you start by saying "I have to launch a satellite into an circular polar" but somehow I doubt that is actually the case) and if possible frame it a bit wider? Thanks! — TildalWave17 secs ago
Wikipedia states that Voyager 1 is currently farthest from Earth; it gives the distance as of Dec 3 2013 as 126.95 AU ($1.899 \cdot 10^{10}\text{ km}$) from Earth. At that distance, the speed of light delay is approximately 17 hours 36 minutes. By Dec 7 2013 it was listed as at a distance of 127....
@Everyone Well I argue in one of my answers that that wouldn't make much sense (like pulling yourself up by your own hair), but if you have your light beam source somewhere else then yes you'd get useful push. Problem with onboard laser is that while you'd get some push it would also be negated by the push in the opposite direction at the point of your light source
and using laser alone without the sail isn't efficient
Hehe that movie is still hilarious even tho I watched in now prolly 5 times or more. The funniest thing about it is that most of it actually happened not much differently than how it's shown there, it really was that naïve era of spaceflight :)
I don't understand in what sense you mean that? Support by what? I see no reason why our moon couldn't be even bigger than the Earth as far as orbits go. Of course, that'd change a few things around here.