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YODA
5:01 PM
@MartinSleziak hello martin
I have a question of trigonometry. Can you help me ?
How do I resolve sinh (2ln5)?
Martin Sleziak
5:22 PM
@YODA Simply using sinh(x)=(exp(x)-exp(-x))/2$.
So you need to calculate exp(2*ln5).
I guess the question was resolved in another room, anyway.
in TheSimpliFire's Chatroom,
17 mins ago
, by
YODA
How do I resolve sinh (2ln5)?
6 hours later…
Aritro Pathak
10:56 PM
Is Prof Joel Bellaiche of Brandeis University in good health now?
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