
Consider the Nemuann series of the $D=\frac{d}{dx}$ operator: $T = 1 + D+ D^2+...$
Applying T on $x$ yields $x+1$ (i.e., $Tx=x+1$) for $x \in R$. One can also look at it as a Taylor series.
I would appreciate if someone helps me to resolve the following confusion.
Since the sum above converges, w...