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15:52
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A: Simple question pertaining to LCM

lab bhattacharjeeLet the numbers be $2x,3x\implies $ GCD $=x$ As you have rightly identified , the LCM is $\frac{\text{ Product}}{\text{ GCD }}=6x\implies 6x=48\implies x=8$

Can you please forget the formula for the moment, go the analyzing way?
@Mr.Anubis, lcm $(2x,3x)=x\cdot$lcm$(2,3)=6x,$ right?
How did you take $x$ in (2x,3x)=x⋅lcm(2,3) simply out I am wondering . I am looking for concept which I am missing
@Mr.Anubis, consider real example with different combinations when $2,3$ divide $x$ and when they don't divide.
Proof (vii) of Article $9.1.12$ in bookos.org/book/1500438
Can you tell where my analysis which I posted in my answer is wrong?
I am about to cry really
15:53
" since LCM contains 31 , it must come from either number" is false
why is that?
it must come from at least one of the numbers
what you said is true for GCD
aah
but I am still confused , how to tackle the problem using just analysis
what is the problem using LCM * GCD = product?
I don't get close to question and concept
15:56
example lcm (2*12,3*12)= 12*6
lcm(2*7,3*7)= 7*6
@labbhattacharjee what is this proof?
I'm adding to the answer
Thanks a lot, I really appreciate the help
please fidn the edited answer
 
2 hours later…
18:01
" since LCM contains 31 , it must come from either number" should be from at least one of the numbers
Also "it's obvious 2^4 comes from other number which is 2x" not fully correct as $3x$ may contain $2^m$ where $0<=m<=4$

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