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10:06
How do we compare the "intensity of colors of coordination compounds"? If for example we consider octahedral complexes, does a higher $\Delta_o$ mean more intense color or less intense color?
10:49
Does anyone know where the tests for amino acids (like ninhydrin test) are there in ncert? I looked through the lab manual but couldn't find it.
@AshishAhuja I think higher $\Delta_o$ would mean that compound would absorb light of lower wavelength (higher energy) , so light consisting more higher wavelengths (lower energy) would be reflected meaning brighter colors
Answer of it should've been 3 according to me but answer is given as 6
@YashAgrawal wait I'll share the exact question:
I don't understand what the question means by "intensity of colors"...
@YashAgrawal yes, even I think it should be 3...
@AshishAhuja what's the answer given ?
chlorine one would have lowest $\Delta_o$ , it seems contradicting ;/
11:01
You mean $\Delta_t$?
I think it mean higher intensity meaning higher frequency meaning lower wavelength
@AshishAhuja oh right , I just meant energy gap between t2g and eg in both tetrahedral and octahedral complexes
so by that logic (3) seems correct
hmm yes I think what you say makes sense.. higher intensity means higher overall energy, which means more amount of non-absorbed light in lower wavelength region hence (3).
But judging energy gap between H2O and CN ones seems difficult , as tetrahedral and octahedral comparison and strength of ligand goes in opposite direction
11:09
isn't [Ni(CN)4]2- square planar?
oh yes right , it's clear now
$\Delta_t < \Delta_o < \Delta_{sp}$ so we get option (3). Thanks, I got it now.
@AshishAhuja yes :)
also, the only way I can come up with for 6 moles of HI to be used in that question above is if all the -OH in 1,2,3-trihydroxybenzene get protonated.. although I still think the answer should be 3.
@AshishAhuja nothing could happen after that though , better would be 3
11:16
yeah
 
6 hours later…
17:07
Isn't this true?
 
4 hours later…
20:56
@Wolgwang it shouldn't be ig, the enol one will be less stable and thus have higher energy since the solvent is water it will make hydrogen bond with the carbonyl thus resulting in less intramolecular hydrogen bonding

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