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ronak jain
ronak jain
04:30
Hi everyone
Why in case of free radical addition of HBr on alkene , firstly Br attacks ? If it would be electrophilic addition than we could say that Br will attack. But both are radicals so attack of Hydrogen should also be equally probable.
 
2 hours later…
Priya
Priya
07:00
user image
Here, does anyone know why is option 4 not correct? It seems to also satisfy the definition of standard enthalpy wherein one mole of product is formed from components in their stable states.
Aniruddha Deb
Aniruddha Deb
07:36
@Priya because C is in gaseous state. for standard enthalpy of formation, C would have been in solid state.
Priya
Priya
Ah.. Fine. Thank you!
 
2 hours later…
rash
rash
09:16
user image
Please help with the question
If they ask just isomer, is it both geometrical and optical isomerism or only either of them?
Safdar
Safdar
@rash (b) 2 ?? since there is no optical isomers..
rash
rash
@Safdar the answer is (d) 4
Safdar
Safdar
@rash Also, can you delete that question you've posted? Same reasons as I gave in comments..
rash
rash
ok
Safdar
Safdar
@rash All unless specified..
rash
rash
09:23
if it is all then wouldn't there be more than 4 isomers...
Safdar
Safdar
@rash how?
rash
rash
there are many places where different groups can be shifted(geometrical isomerism)
Safdar
Safdar
there is only one possible chiral centre (not sure about this). and two double bonds..
rash
rash
for geometrical isomerism i am talking
Safdar
Safdar
The double bond attached to ring is also a doubtful chiral centre.. the other one shows isomerism.
@rash nope.. there is only 2. Try drawing a 3D version as I shared in the other answer.
rash
rash
09:29
@Safdar you are saying double attached is chiral considering it like allenes?
Oh ok @safdar
I see why only 2 geo isomers
Safdar
Safdar
@rash I'm not sure if it can show.. since you can't shift the bond on the left..
Saniya
Saniya
10:12
@rash the double bond one will show gi (one cis and other trans) whereas the other at the ring shows stereoisomerism due to chiral center which gives answer 4
Safdar
Safdar
@Saniya Can you explain why you think the ring has a chiral center?
Saniya
Saniya
Cause there is no plane of symmetry
And by the way how to post picture I have a doubt but cant see any option for a picture
@Safdar
Safdar
Safdar
upload
Saniya
Saniya
@Safdar how
Safdar
Safdar
@Saniya what about a plane passing through H and CH3?
@Saniya there is a button saying upload.. Are you on mobile?
Saniya
Saniya
10:18
@Safdar nope a tab
Safdar
Safdar
@Saniya both are same in this context.. Are you on chrome?
Saniya
Saniya
Yup
Safdar
Safdar
There should be a 3 dots, way you take settings.. Press that and click load desktop page.
 
3 hours later…
Saniya
Saniya
13:02
Leave it which of the following shows gi
The options are a.Pt(Nh3)2cl2 b.Zn(nh3)2cl2 a is correct but b is not.
I think both are ma2b2 type so both should exhibit it isnt it?
Safdar
Safdar
@Saniya Zn is tetrahedral complex. Tetrahedral doesn't show GI.
so Pt.
 
2 hours later…
Saniya
Saniya
15:11
@Safdar and how do we know which on is tetra which octra .sorry for being silly
Safdar
Safdar
@Saniya A very rudimentary way in our scope would be to check hybridisation of the complex (Oversimplified). Zn would have sp3 whereas Pt would have dsp2.
sai-kartik
sai-kartik
16:01
also for octahedral, you would need six ligands(as long as lone pairs don't mess things up)
Aniruddha Deb
Aniruddha Deb
16:50
@Saniya do you mean tetrahedral and square planar? Tetrahedral and octahedral you just need to look at number of ligands. Tetrahedral and square planar would depend on electron config. and CFSE (hybridisation is an easy, although at times incorrect way of looking at it, as said by @Safdar)
Safdar
Safdar
@AniruddhaDeb you just gave me a heart-attack, my notifications were on when you pinged me..
Aniruddha Deb
Aniruddha Deb
@Safdar The structure of the cyclohexane ring and two substituents is somewhat similar to allene, so you have 2 isomers there. 2 more about the double bond to give 4 total isomers
@Safdar baymax voice my hands are equipped with defibrilators :)
4
Safdar
Safdar
@AniruddhaDeb that was what I was confused about.. I wasn't sure on how to count are there..
Aniruddha Deb
Aniruddha Deb
AFAIR the question is from MS chouhan...
Safdar
Safdar
@AniruddhaDeb I know.. Couldn't find my solutions manual tho ;D

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