My reasoning is simply that the conjugate base formed after abstraction of proton from the tert alcohol, (CH3)3O- will form a better complex with Na+ than K+ , as the lattice will keep becoming weaker when O- forms an ionic compound moving down the group.Therefore, due to less counter-ion hindrance in the KOH case
It should give a better yield
I am guessing you would have heard about solvent separated ion pairs, it would kinda be sthgl like that
Ok cool, yeah I just feel that the yield will depend more on the extent of solvent sheath separation between the reactants than what these guys have said, especially since both of these are pretty strong bases themselves
Any competition in basicity will always be won by NaOH/KOH as far as I feel
@YusufHasan Yes. No issues in understanding that. I meant that solvation of the ions in both (a) and (b) are guided by the same reason. If so how can the reason given in the book can take precedence for (b) and not (a).
@YusufHasan Ah. Fine. You understood my point. That's why your reasoning is better.
It would be nice if you could write your own version of chemistry after your college. The other day (when it was in HNQ list) I read your explanation of dependence of bond angle on electronegativity using the ring-finger example. It was nice.
@GuruVishnu Thanks for the encouragement, I actually feel like teaching chemistry myself, but I get deterred many times due to doubts regarding the reception of these courses
But if I do see enough support sometime,sure...I might start on this venture as well :)
Hello, I hope this is allowed here. My friends and I recently started using discord and thought it would be an amazing platform to discuss doubts (we were comparing it with telegram which, I think, is a very ugly app anyway). So we created a new server:
Anyone interested in joining a bunch of people discussing doubts and discovering the various features of discord is invited here discord.gg/kYsTe5A
