VBT gives quantitative interpretation of magnetic data right? In boards we use to write electronic configuration, find number of unpaired electrons, magnetic moment etc.
For one gas CV,Co were (in kJ/mol) 21,30. For another it was 22,29. What can you conclude about the other degrees of freedom known that both are diatomic
@EshaManideep C_v=fR/2 , so one with low C_v must have low degree of freedom meaning that B have lower degree of freedom , all option(except C) have more or equal degree of freedom as that to A....This is my reasoning Disclaimer :"this can be BS also"
@Dante It's right just see solomons (aldehyde , Acetal formation part) The carbonyl carbon is most Electrophilic , and hence CN- attack there and then simple reduction of CN
@AdvilSell Bro... You cannot quench by H2/Ni... Think of it physically.. The compound is adsorbed on the Ni surface,and H2 gas is passed so that H atoms attach to the pi bond.. There is no scope of ion formation here without solvent,and your quenching requires the homolytic cleavage of H2... Which is very unlikely
H2/Ni can only atach atomically to pi bonds in a pericyclic fashion.. No ions can be formed.. And i saw reso's soln.. What i say is,DMSO may be prepared in a slightly aqueous form as well.. Like,0.01% water but major DMSO.. So that could help in quenching
@Dante More than electrophilicity.. To actually see this reaction... CN- is a hard nucleophile,while carbonyl carbon hard electrophilic centre... HSAB..boom
But v.v. hard to see in exam...Mostly people will do SN2 here... And they are also prolly justified.. Cuz HSAB is not at all for mains
@PolarBear Well... I just wrote Cv for each gas as (5+x)R/2 and Cp as (7+x)R/2,equated them to their values and divided the equations.... For A i got a consistent solution of x just greater than 1..while for B i got a negative value of x... So C
@YUSUFHASAN Are you sure CN- is a hard nucleophile , Because This doesn't say so , If it isn't a hard nucleophile then will the reaction be affected like will it go with simple SN2 and do it with I ?
Question
Rank the following radicals in order of decreasing stability
Aromaticity makes a cyclic compund more stable. Here, 1 and 3 are aromatic since they follow Huckels rule(Or am I wrong here?). So, I thought maybe 3 is most stable followed by 1, then followed by 2 and 4(I dont kno...
Question
Rank the following radicals in order of decreasing stability
Aromaticity makes a cyclic compund more stable. Here, 1 and 3 are aromatic since they follow Huckels rule(Or am I wrong here?). So, I thought maybe 3 is most stable followed by 1, then followed by 2 and 4(I dont kno...
