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06:00 - 13:0013:00 - 23:00

06:35
How was the paper @AvnishKabaj @PolarBear @AdvilSell @YUSUFHASAN @Jasmine ?? All answers correct or not?
 
2 hours later…
08:32
@Abcd the dunno about correct
But was easy
@AvnishKabaj Are you giving AITS Mains on 23rd
@Abcd nope
@AvnishKabaj Y?
@Abcd Haven't touched jee stuff since a month and a half
Saw your paper.
It's easy$^\infty$ !
literally 0 tricky questions.
you all r so lucky!
08:42
Yeah it's the statements and the time limit which take your marks
@Abcd I mean you could have joined a cbse school
No one gave proper advice at the beginning of 11th! And by the time I realised it was too late.
Now I am going to warn all my juniors against opting for this foolish board.
These school teachers pretend to care and love you and even they dont give the right advice. When I attended school in the beginning of 11th and we told our Chem teacher about students who had joined CBSE/ dummy, he was like "Biggest Mistake of their Life".
08:58
@Abcd really easy
09:16
@Abcd Yeah.. I have solved all of them.. But a few lapses may have occured in the calculation part of the matrix question.. (But anyway,it is step marking).. Otherwise questions were definitely easy
@YUSUFHASAN Which matrix question?
The one of system of eq^ns ?
Yeah.. The values looked very dicey to me.. And I was short on time as well.. But explained the entire procedure.. So probably will lose 1 mark for final answer if it's wrong
dude
for that you should have put your answer in the given equation's LHS
to check if you are getting the right RHS
@Abcd Yeah Ik.. My final answer is of course right... But in b/w.. The value of the determinant and adjoint and stuff... They may have gone a little south.. That's why I say 1 mark
That's to say... If the examiner reads each and every line XD
not possible. If final answer is crkt it means steps are correct in that question.
Slightest mistake in adjoint gives wrong answer
@YUSUFHASAN You have one more exam left?
09:22
@Abcd Arre I solved the 3 equations separately... Then I have put that as the values of x,y and z... But it wasn't coming out exactly the same via matrix method... So got sthg slightly wrong somewhere(a factor was extra IIRC)
@Abcd Yeah... Informatics practices.. 2nd April
@YUSUFHASAN :O
Dictatorship XD
@Abcd Your choice.. You anyway won't be able to "dictate" much if I decided to spam this group with trash messages.. XD
@YUSUFHASAN Whats your plan for next 10 days ? Only IP or JEE + IP
JEE (90-95%).. IP(5%).. Cuz its really easy.. We only have a single book.. Which I have memorized atleast 2-3 times before.. U should really have opted for CBSE! XD
09:56
@Abcd Different regions have different paperssss
@PolarBear i guess I checked the all india paper only
It was lengthy for me.
@Abcd It's different in that too.
Any hard question for you?
Not hard exactly. But, I solved some questions with different methods and I got some weird answers even though I checked.
It was lengthy for me. Took 4 supplements. 42 + 4(8) pages. I was writing and writing xD
Students in my school couldn't complete papers except for the high scorers.
@YUSUFHASAN Niceee
We have two sections in CS. One section common for all languages and one language section.
I don't know the common one xD Need to study T_T Two big boooks
Hey, for the first time they asked proving formula
In my set it was to prove $\int_{a}^{b}{f(x)} = \int_{a}^{b}{f(a+b-x)}$
@PolarBear dafq !! 4 supplements !!, I barely completed the answerbook
@PolarBear mine too
10:02
Different sets had different but every set had one
@AdvilSell I was in vroom vroom mode since start, I am happy I could atleast complete xD
@PolarBear did you suspect any answer
??
I checked while/after writing, so expecting they I didn't do mistake in checking.
@AdvilSell Means?
I did. Some were weird. But I checked it. Sometimes I did wrong, so I cut it and wrote again. Sighhh.
@PolarBear anything you didn't know , or any part you didn't solved ??
@AdvilSell No, solved and knew everything. Was stuck on transformation proving det at last but finally got it in last minute.
@PolarBear nice , I didn't remembered the bayes theorm and hence did the question wrong first time , then derived it , it took a lot of time !!
10:08
Sad :P
@PolarBear :D , I am happy that boards are over !!
almost
For that integral from 0 to a proof.. I don't suppose we can use a previously proved identity?
@YUSUFHASAN Like?
Oh you had similar proof but instead of a to b you had 0 to a right?
You can't use the a to b one
Some news pages say paper was easy some say it was as tough as physics .-.
@AdvilSell Yeah finally.
Yeah.. I don't think we can... Lol,I almost did a wowzie there... I first said that we know that this is the identity for (a+b-x).. Now set b=0.... Tada!!(Although I corrected it later there with the actual proof)
Now I have to go to school because my CS teacher thinks I know no CS. I missed last CS pre board xD
10:20
@YUSUFHASAN lol
@YUSUFHASAN Lol, 2 marks.
No, more marks
Idk
@PolarBear Yeah.. It was 4 marks.. So 2 for proof and 2 for using it in a question next to it.. The second one I of course did properly
But it had been sooo long since I had proved that identity.. And who even asks that... It isn't needed as such in problem solving
@YUSUFHASAN my problem was directly asked on the property given to proof
Yeah same.. I also had to use it in a problem.. That I'm comfortable with.. But I know almost zero proofs in maths.. If I forget sthg.. I'm done for in the JEE! XD
@YUSUFHASAN Many formulae are derivable on spot
10:25
@YUSUFHASAN sometime proofs are needed in the question of JEE advanced , not much tho
@PolarBear almost all
Whoooosh, I have to now study CS. Sigh. CS tips CS tips
@PolarBear True.. But those I can derive by sthg I know from prior knowledge.. Like in conics and stuff.. I remember basic formulae and work fro there.. From scratch I almost know nthg to derive
I am bored of board
3
@PolarBear Dude.. U have more than a week from now.. Why rushing now?
@PolarBear same :D
10:29
@YUSUFHASAN Otherwise my teacher will ask me to come to school everyday
She's more worried. She even called.
I should be happy right
@PolarBear Which teacher is so caring in this country? My IP teacher talked to me last time in the month of January.. XD
Hmm, I should be grateful to my teacher. I will thank her nicely.
Goodbye everyone enjoy the holidays
@PolarBear heh
"holidays"
@PolarBear Yeah.. You should.. And these are not holidays.. This is a chance for redemption for the JEE.. XD
@AvnishKabaj Me when I hear non JEE people say "I am going to party today."
And me also when they ask me what my plans are. Solving physics. You know. Solving physics.
@YUSUFHASAN Absolutely.
10:36
@PolarBear ER gawd I should get started
Have to do all of DC pandey level 1
Some are even going to their Native for Holi. Even JEE people.
I don't even know when Holi is.
This makes me feel I am on right track.
Ok kewl
@AvnishKabaj Whoooo. You have DCP?
Oh wait, which DCP?
@PolarBear yeah
@PolarBear DC pandey
Problems one or theory one?
10:38
@Abcd missed a 2 mark probability question but the paper was nice
Which one is the problem one?
@AvnishKabaj Just a single book
@PolarBear Is it like super good?
Now time for advanced
3
@AvnishKabaj Umm, not really. Moderate. Good for first time solve.
Helps build concepts.
10:40
@PolarBear ok thanks
Okay good
I also have the 500 problem one. It's good.
Very nice.
@PolarBear the new pattern one ??
@AdvilSell No, the first one is new pattern one.
Idk the 500 one isn't famous I bought it just for fun but it's good
It has only subjectives
10:43
@PolarBear Ohh...okay :D
But the questions aren't calculative.
What are you all doing today
@Jasmine Partying
Partying by doing what :D
@Jasmine Nice question. I like solving maths to party.
10:44
@PolarBear oh 62
@PolarBear Probably Praying
@PolarBear I knew it
I will join your party soon in sometime
@AdvilSell I don't pray. I know my fate is my own fate nothing's going to happen xD
@Jasmine lol join in sis
@PolarBear XD , I was just kidding ( Even I don't pray )
I xD too much
10:46
Ok XD
तुम सब नरक जाओगे
11:13
वोके, थेँक्यू
31 mins ago, by PolarBear
@AdvilSell I don't pray. I know my fate is my own fate nothing's going to happen xD
11:39
ई सेड वोके
ई कन्नौ मय बाड़ फेट
HCl is a stronger acid than HF. Then why does HCl behave as a weak base in HF?
OP tandon physical chemistry page 691
Board exams are done
12:20
1 message moved to ­Trash
@Jasmine missed means you didnt see it?
@Dante HF aint able to polarise HCl because HF itself has Hydrogen bonding.
.
in ­Trash, 48 secs ago, by PolarBear
in ­Trash, 3 hours ago, by YUSUF HASAN
Anyway.. Wasn't aiming for full(unlike toppers such as @Abcd) XD
Yes @ice. Why dont they have separate English and Hindi papers.
Quite irritating to see them together.
Also you must be having situations like "Duh, I started reading the hindi one!"
Yeah, many people have that problem. I just cut the hindi part and questions I am not going to solve. Crooosss crossss
@Abcd I didn't get Dante's question.. What are you justifying by H-bonding?
@Abcd Happens happens
12:24
@YUSUFHASAN He is saying HCl is not strong acid in HF.
And I am saying strength of acid is solvent dependent.
HF is not able to polarise HCl like water. Because HF is self-involved/ preoccupied.
@Dante First, I don't know if this matters but we normally talk of acid when it's aqueous
@Abcd He said it behaves as base?
@PolarBear base is a typo. He meant acid.
I mean.. What I get from his question... Is that why HCl is not as strong as it usually is in standalone aqueous form rather than when it is mixed with HF.. So here of course dissociation of HCl will go down due to (whatever small) dissociation of HF occurs... Common ion effect..
@Abcd He said that HCl is stronger than HF
12:27
@PolarBear No.. I think we meant that HCl becomes weaker in HF
Doubt @PolarBear @YUSUFHASAN
@YUSUFHASAN Oh, now I get it
@YUSUFHASAN I dont think Common ion effect is right explanation.
@Abcd I never understood this questions properly, though being a adv 2017 ques it had many solutions online. It was after looking at this ques I lost confidence in thermodynamics X
$\ce{H2O(l) (1 bar, \pu{373 K}) -> H2O(g)(1 bar, 373 K)}$
12:29
@Abcd I mean.. Common ion effect weakens the dissociation of both acids simultaneously,right? Simulataneous equilibrium and all that..?
Write $\text{signum}(\Delta G), \text{signum}(\Delta S)$ for this reaction:
1 min ago, by Abcd
$\ce{H2O(l) (1 bar, \pu{373 K}) -> H2O(g)(1 bar, 373 K)}$
@YUSUFHASAN @PolarBear @Dante This easier one as well pls^
@Dante Well, rest of the thermodynamics archive is very easy. Dont get disheartened by 1 or 2 questions.
@Abcd (Okay I don't know that answer but just trying on my getting answer by hook crook method is it (A)?)
H-bonding is there in HF... But it is quite weak in solution phase.. So i would say that common ion effect is good enough here
I see
@PolarBear Crkt
12:32
OP says HCl + HF <-> H2Cl+ + F-
(Whoo, lemme think then btw I found out the answer by dimensional analysis)
So it's not a typo
@PolarBear All answers are in bar!! How did you use Dimensional
@Abcd Calculation for that question is very easy, it's direct XD
@Abcd Not exactly.
12:33
It's just difficult to understand
Answer 2nd question you all.
@Abcd Where is the 2nd question?
@YUSUFHASAN See signum
@PolarBear I tried using : $\Delta G^o = -RT\ln(K_p)$
(deleted because you shouldn't do questions that way lol)
@Dante Proves my point.. Common ion effect is surely randomising stuff here.. Thats why that equilibrium exists
12:35
lol$^\infty$
@YUSUFHASAN I still think its because of low polarity of HF
@YUSUFHASAN Who is stronger Acetic or HF
Maybe you both could google for a confirmation?
I did but wasn;t satisfied
11
Q: Acidity of hydrochloric acid in acetic acid

NanoputianA question asked to find the $\mathrm pK_\mathrm a$ of $\ce{HCl}$ in acetic acid. The equation of $\ce{HCl}$ disassociating in water is: $$\ce{HCl + CH3COOH \leftrightharpoons CH3COOH2+ + Cl-}$$ I predicted that the $\mathrm pK_\mathrm a$ should be higher as acetic acid is a weaker base than wat...

Thats in acetic
So I opened my book and I have started abcd's question
I don't even remember solving thermo
Because of low polarity.
@PolarBear 2nd question first please!!
Thats 1 second question.
7 mins ago, by Abcd
Write $\text{signum}(\Delta G), \text{signum}(\Delta S)$ for this reaction:
7 mins ago, by Abcd
1 min ago, by Abcd
$\ce{H2O(l) (1 bar, \pu{373 K}) -> H2O(g)(1 bar, 373 K)}$
@AdvilSell Are you online
I meant starred* when I was little in class 11
Starred* not started*
(See that's what I did)
(Not really)
@Abcd delta S is Delta H/T
12:42
@PolarBear tell answers first
@PolarBear this is so hard!!
You didn't give delta H
@Abcd Not hard
I did it in seconds xD
@PolarBear question didnt give
dG is VdP that's the only info reqd
Is internal energy of solids dependent only on temp just like ideal gases?
@PolarBear But we have to derive it too right? Or did you learn this formula?
12:45
guess not...
Wait a minute.. Is some info missing?
@YUSUFHASAN Which ques?
@Abcd latent heat 40.8 we know
@Abcd U can derieve it via thermodyanmic sqaure.. dG=VdP-SdT
Guys signum just means give the signs.
12:46
I think that's what we will use
@Abcd The second one.. R u giving us the enthalpy?
@Abcd Oooh didn't know didn't notice either
@YUSUFHASAN C my latest message.
So you are talking about system or surrounding or whole?
Also sign(0) = 0
@PolarBear Question didnt say anything.
12:47
Oh.. So entropy change sign is.. Positive? For system?
Let's assume it to be system
@YUSUFHASAN Right And $\Delta G$?
@Abcd positive
@PolarBear wrong
Someone had linked a question on SE somewhere or I had just read it
@YUSUFHASAN wrong
12:49
It's reversible
Guys nothing is given in the question.
its IIT 2007 ques
17 lol
No 2007
no 17
@PolarBear 373 K is 100 C not room temp
12:51
@Abcd Is there anyway I can bookmark this conversation?
I would like to go through it after I finish thermo from NA
@Dante See my instructions to bookmark conversation in PSS to nobodyrecog.
We should have bookmarked the conversation on how to bookmark a conversation that would have made bookmarking easier
right
oh Ice has also given d instr.
Jun 27 '18 at 3:07, by Anonymous
@Abcd Go to this chat transcript, there is bookmark on right side of the desktop page. Click on it, then click on your 'start message' and then click on your 'end message'. The whole conversation from the start message to the end message will be bookmarked.
@YUSUFHASAN @PolarBear Why is $\Delta G = 0$ ???
It's zero. I said it.
Oh yes. I didn't see the temperature... And sincd they have given only the forward reaction.. So it will definitely be spontaneous at 100 degree celsius(facepalm, I am stupid)
12:53
@YUSUFHASAN For spon. $\Delta G = -ve$
It's zero. Zero. Yay. I'm right. I'm right.
It's equilibrium.
I am acting dumb today.
Ice give reason
16 secs ago, by PolarBear
It's equilibrium.
@PolarBear They have only given forward reaction in the question.. So u can't assume backward reaction here as far as I think
It seems like I have done all thermo questions.
@YUSUFHASAN No. You can.
That's what you have to think.
12:55
@Abcd Where's chat transcript?
It's an equilibrium we know that.
$\ce{P_(white, solid) -> P_(red, solid)}$
what is chat transcript?
@Dante Actually
click Room on LHS
Above your gravatar
@Abcd What to do?
12:56
@PolarBear Well.. Then delta G is zero.. So?
@PolarBear Is it phase transition or not?
@Abcd I am saying that since it is not given.. I don't know that whether they want us to consider the back reaction and take it as a phase change
@YUSUFHASAN ya exactly
@YUSUFHASAN Question 3 or 2?
@Abcd sign of delta G one
@YUSUFHASAN OK I agree with u on that
$\ce{P_{(white, solid)} -> P_{(red, solid)}}$
State if the above reaction is a Phase Transition or Not. @YUSUFHASAN
12:59
@Abcd Allotropes aren't phase transitions but we consider them sometimes
@PolarBear Say definite answer. yes or no.
Traditionally, no. But yes. I remember my teacher saying that.
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