Finckelstein reaction: $\ce{RX + X' <=> RX' + X-}$ For Fluoride preparation: treatment of alkyl halides with: 1) Anhydrous HF (for allylic and benzylic only) 2) $\ce{AgF}$ 3) $\ce{KF}$ 4) $\ce{HgF2}$ 5) $\ce{Et_3N.2HF}$ -> Equilbrium shifted to right because of $\ce{F}$'s poor leaving tendency
@Hema
Anonymous
@J_B892 I think that since water is the solvent, it will probably kind of 'solvate' the NO3 ions preventing them to attack and meanwhile since water is in excess it will attack.
@J_B892 Please mention the source of the question.
@J_B892 First of all, I have checked the reference book. The nucleophilicity of $\ce{H2O}$ is given to be 0.0 and that of $\ce{NO3-}$ is given to be $1.00$ calculated from some Swain-Scott equation.
SO obviously $\ce{NO3-}$ is a better nucleophile than water.
@J_B892 Since difference in nucleophility is small so both reactions will run in paralllel (attack by nitrate and water) unless water is taken in excess.
but another problem is developement of Finckelstein reaction like situation because nitrate ions are even being free after Ag bonds with Cl to form AgCl precipitate. . Yes @Jasmine?
@Abcd So if we had KNO3 then NO3- would have been the attacker?
@Abcd Well, my preps are more towards Olympiad. We have just entered phase 2 in FIITJEE so I'm doing this parallely so that I cover most of organic before NSEC
Side chain oxidation of aryl alkanes takes place if there is at least one alpha hydrogen present by all accounts I presumed that there would be no reaction. However the answer given was trimethyl acetic acid. Is the answer key wrong?
Side chain oxidation of aryl alkanes takes place if there is at least one alpha hydrogen present by all accounts I presumed that there would be no reaction. However the answer given was trimethyl acetic acid. Is the answer key wrong?
