« first day (99 days earlier)      last day (2430 days later) » 

00:54
0
Q: n-factor of FeO in the reaction of ferric oxide with vanadium (II) oxide

K. Chopra In the following reaction, what is the n-factor of $\ce{FeO}$? $$\ce{2VO + 3Fe_2O_3 -> 6FeO + V_2O_5}$$ I believe it should be 1, according to the standard "change in oxidation number" formula, but the answer is given as $\frac{3}{2}$. Which one is correct and why?

@Abcd @AvnishKabaj @IceInkberry @Jasmine I am getting n-factor = 1 in this question...Is anyone else getting 3/2?
Oh hi @K.Chopra, didn't realize I posted the same question you did :P
 
5 hours later…
05:52
@GaurangTandon I got 1 too
did anyone of you clear jee adv ?
 
2 hours later…
07:57
that cinversion
see
drastic oxidation of salicylic acid
then sort of a skeleton we get
then we just have to convert one side to alkene
by protecting on carbonyl group
got it only last day.:d
 
2 hours later…
Anonymous
10:30
@GaurangTandon I am getting $3/2$
Anonymous
n factor in oxidation/reduction of same compound is $\dfrac {a×b}{c}$
Anonymous
Where $a$= Change in oxidation number $b$= Initial number of moles of the compound and $c$= Final number of moles of the compound (Had to write in A B C form due to mathjax)
Anonymous
Here, it will be $\dfrac {(12-9)×3}{6}$
10:49
interesting
@IceInkberry How did you get a= Change in oxidation number
?
initial oxidation number is 3, final is 2
so the diff should be 1
Anonymous
Sorry T_T
Anonymous
This is so embarrassing that I do mistakes every single time
Anonymous
No, I am wrong
Anonymous
Totally wrong
Anonymous
Sorry
Anonymous
10:59
So, I get $1/2$
Anonymous
11:17
@GaurangTandon Umm, wait, n-factor is change in oxidation number per mole of substance. So, I am right?
11:37
so where'd you get the 12 and 9 from, I still don't understand :/
 
4 hours later…
15:24
Turns out our chem syllabus was going slow because our sir taught us a lot of reactions beforehand from cooh and nh2
We finished ald&ket & cooh
Today
And amines by Saturday
Maths toh Integration will be left before the phase tes
Physics sir says he'll finish magnitism in 4 classes
I doubt that tho
Anonymous
16:00
@GaurangTandon Okay, I am probably really wrong. I am not commenting on this question, I take my words back. I don't like this chapter ._.
Anonymous
@AvnishKabaj Like while teaching something comes up and while discussing some questions something comes up and he teaches that?
@AvnishKabaj were you taught sets and relations
Anonymous
If that is the case, our teacher is the same lol. We are way too back, I hope our class gears up.
Our teacher took 3 class and indefinite integration gone
I dont know why so much in speed
Anonymous
Is that there in your phase test?
16:08
@IceInkberry can you tell me how fo you decide position of attacking
I always attack at wrong place
I really dont get sometimes why negative charge attac each other
Anonymous
@Jasmine Attack where, whenever someone says attack I remember chess but I know you mean organic chemistry. Do you? If yes, I am not the right person to ask.
@IceInkberry lol its a lolipop question though
Anonymous
Because I haven't even started with real organic chemistry yet.
Anonymous
Dangling with alkyl halides
Whike consider a molecule containing an electrophilic C and H where will attack happen
Some factors in mind- 1. Which is a better elecrophile
Anonymous
16:13
Like if it will abstract H or attack C?
After attack which is a better leaving group
@IceInkberry yeah if you say in a more accurately
And what will form a more stable product
Anonymous
If it is a nuclephile like CN- it will attack the Electrophilic carbon. The property of a base is to abstract acidic hydrogen(If present). So if you have OH- and a Electrophilic carbon as well as acidic hydrogen, the OH- will abstract the Hydrogen whereas CN- will attack the Electrophilic carbon.
Anonymous
I have been taught that in basics.
Anonymous
1) Identify if the attacking thing is base or nucleophile
Anonymous
2) Check if better leaving groups are present
Anonymous
16:17
3) Check the solvent because some groups like OH become better leaving groups in acidic environment
Anonymous
I don't know if that is even relevant to your question
@IceInkberry very much relevent thanks
@IceInkberry ya
@Jasmine nope
I always wanted to be taught from base
Never never mind
@AvnishKabaj will that come in phase test or only in school exams
Anonymous
@Jasmine By the way, it is in JEE mains syllabus only
16:21
@Jasmine one or two questions always come from useless chapters like those
Anonymous
Not in JEE advanced
@IceInkberry oh i forgot
@AvnishKabaj biomolecules questions will be there in phase test
Oh too much to do good night
@Jasmine ya
@AvnishKabaj ok
17:23
@Jasmine How are you handling biomolecules' carbohydrate part. Its so irritating.
@AvnishKabaj no he will finish it. Its very short chapter.
@Abcd o.O
It's the biggest package
@AvnishKabaj it has much variety. He will finish his syllabus but you wont get time for practice.
@AvnishKabaj Your centre will set the paper. FIITJEE delhi is the ruler right? Why dont you request them to shift the dates
@AvnishKabaj Everyone is struggling with maths syllabus and physics practice, why doesnt fiitjee delhi understand that
@Abcd cbt was pre booked
@AvnishKabaj what is CBT
@Abcd that's sad
@Abcd computer based test
17:32
@AvnishKabaj :( ....But they do this nonsense every year sir told us.
Last 2-3 years they did this nonsense and then shifted the dates
¯\_(ツ)_/¯
Only sankalps syllabus is complete
Anonymous
After reading the above messages, I want to wish all FIITJEE students all the best
17:55
@AvnishKabaj Read the part "source books"
@AvnishKabaj This is a reply to "Jan diasgrees" comment of yours.
@IceInkberry Thanks a lot :)
@Abcd don't remember
@AvnishKabaj Let me link you to it.
5
Q: Reaction of tert-butyl bromide with silver nitrite

samjoeWe know that reaction of $\ce{AgNO2}$ with alkyl halides is SN1 type reaction and follows HSAB principle. So in the reaction of $\ce{(CH3)3C Br}$ we would expect $\ce{AgBr}$ to form and also a carbocation $\ce{(CH3)3C+}$. According to HSAB, since the electrophile is hard, we expect the hard nuc...

Jan disagrees I’m up to answering this as it is a very interesting phenomenon. I probably won’t be able to until in a few days time. In any case let me drop the hint that any argument involving HSAB is wrong. Avnish Kabaj May 12 at 9:13
18:11
@Abcd meh the dude's written sources and you don't know what's been cited
 
2 hours later…
19:55
@abcd not yet started bimolecules but it looks it has lots of memorising stuff

« first day (99 days earlier)      last day (2430 days later) »