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00:55
@Relativisticcucumber jigglypuff~
@Relativisticcucumber oh nose! kitty was also really sick, but not due to covid
 
7 hours later…
08:25
Trying to get an overall vibe of the popular perception of relativity through time
It is a bit tough
Having to wade through random newspapers and books
Basically nothing before 1919 when Einstein got his big break with the eclipse result
a lot of the sources offered b y google ngram are just not available at all
Although the results can be delightful
"His new equations are based on the assumption that gravitation an electricity are the same thing."
 
2 hours later…
10:52
A lot of people were rejecting relativity in the early days, so Tesla's reaction was probably just normal for the time
11:50
Gotta figure out if I can legally use some of those pictures by figuring out when the guys died
 
2 hours later…
13:59
If a particle is moving with a relativistic velocity, but I know it's momentum, would it be correct to calculate the velocity as v=p/m ?
14:15
By "velocity" do you mean the measured velocity ie distance travelled per time, or do you mean the 4-velocity
And ditto with momentum, is it a vector or a 4-vector
the momentum is the 3D momentum
then no, the relation has the Lorentz gamma factor in it
So my situation is the following, I am having a Z boson from which 2 \tau leptons emergy. Now, the momentum of the leptons have some value a. I am given as info that in the rest frame of the lepton it has a mean liftime \tau. So I did the following. I considered the rest frame of Z and that of the lepton, and I came across
$\Delta t=\gamma \Delta '$, where
$\Delta t$ is the mean lifetime of the lepton as seen from the reference frame of the boson
14:30
@imbAF IMHO, it's a bit confusing because you have a tau lepton with a mean lifetime of tau, since tau is also commonly used for proper time. And of course, the mean lifetime in the rest frame of the particle is a proper time. ;)
@imbAF As Slereah said, you need the relativistic equation for momentum, which is $p=mv\gamma$. There are nice trigonometric relationships between $v, \gamma, v\gamma$.
@PM2Ring yes the meanlifetime is in the leptons frame. But I want to find it as seen from the Z boson
The only problem I am facing with is, calculating \gamma
Let $\beta=v/c$. Then $\beta^2+1/\gamma^2=1$. So if you write $\beta=\sin\theta$ then $\gamma=\sec\theta$ and $\beta\gamma=\tan\theta$
I see
But in the solution it has $\gamma=\frac{E_\tau}{m_\tau c^2}$ which I don't see how it's derived
from
the general
$\gamma=\frac{1}{\sqrt{1- \frac {v^2}{c^2}}}$
But it is more common to use hyperbolic functions. $\beta=\tanh\phi$, where $\phi$ is called the rapidity. Then $\gamma=\cosh\phi$ and $\beta\gamma=\sinh\phi$.
Are you familiar with this equation for kinetic energy, $E_K = (\gamma-1)mc^2$?
14:45
no
But I believe I need to describe my problem a little bit better
Give me a moment
A resting Z boson of mass MZ = 91.1887 GeV/c^2
decay into a τ+τ− pair, where the mass of the τ -lepton is given by mτ± = 1.7771 GeV/c^2.
Firstly I needed to find the energies and momenta of the leptons, which I did, which are E= 45.5944 GeV and momenta p_\tau= 45.5597 GeV/c.
The mean lifetime of resting τ -leptons is 2.956 · 10−13s. How far do the τ -leptons get on average?
So I am operating from the POV of the bozon
as such I find $c\Delta t==\gammac\Delta t'$
So, the only problem I am having is finding \gamma for which I know, in general :
$\gamma=\frac{1}{\sqrt{1- \frac {v^2}{c^2}}}$
And I am thinking of using the fact that
v=p/m, plug it in and find what I need
But I am not sure
@imbAF No, v=p/m won't work.
Yes it won't
just to make sure tho
for my understanding
Give me a minute. I'm a bit slow typing Latex on my phone...
ah
Do you know the total energy equation, $E^2=(pc)^2 + (mc^2)^2$ ?
14:52
Yes
I used that
to find the energies of the leptons
since they have same mass and same momenta (absloute value)
therefore their energy is half of the energy that the boson represents
Great. Back in a minute.
More than the answer I'd like to derive it myself with your help
15:04
$E^2=(pc)^2+(mc^2)^2$
Substitute $p=mv\gamma$
$E^2=(mvc\gamma)^2+(mc^2)^2$
Divide by $(mc^2)^2$
$\left(\frac{E}{mc^2}\right)^2=(\beta\gamma)^2+1$
But $(\beta\gamma)^2+1=\gamma^2$
Thus $\frac{E}{mc^2}=\gamma$
Well I have a few questions
why is p=mv\gamma
because you are using relativistic mass?
@PM2Ring
m is the rest mass, $m\gamma$ is the relativistic mass. But we prefer to avoid that these days. ;) It's better to think in terms of the total energy, which we just showed is $E=mc^2\gamma$
isn't mass though
$E=\sqrt{(pc)^2 + (mc^2)^2}$ ?
What? $m$ in that equation is the mass.
the rest mass?
or the relativistic mass?
15:10
Rest mass
So , one can go from $E=\sqrt{(pc)^2 + (mc^2)^2}$ to $E=mc^2\gamma$?
where in the first you have the rest mass
and in the 2nd the relativistic mass?
As I said, $m$ is the rest mass. $m\gamma$ is the relativistic mass. But we prefer to avoid relativistic mass these days because it tends to create confusion.
Ok
But how does one derive that?
I had no idea of this expression
so there must be a way to derive it, from the energy momentum relation, I would assume?
If we subtract the rest energy $mc^2$ from the total energy, we get the equation for kinetic energy that I gave in chat.stackexchange.com/transcript/message/64281752#64281752
@imbAF Derive what?
I am a bit confused
This is the kinetic energy $E=mc^2\gamma$?
15:25
@imbAF No, that's the total energy= kinetic energy + rest energy. Kinetic energy is $E=mc^2(\gamma-1)$
ok
0
Q: Causal structure of mutually transversely intersecting surfaces in $\mathbf L^3$

John ZimmermanConsider a finite family $\Psi_\alpha$ with $\alpha=1,2,3,4$ of mutually transversely intersecting mixed type surfaces of $\mathbf L^3$ inscribed in $[-1,1]^3.$ Let the $\Psi_\alpha$ have the same first fundamental form, Gaussian curvature $+1$, and be surfaces of revolution. This is a particular...

can you see the tachyons?
If you're wondering where $p=mv\gamma$ comes from, it can be derived using the Lorentz transform. See en.wikipedia.org/wiki/Four-momentum
I am a little concerned about my model given that it seems a bit too symmetrical
@PM2Ring In what you linked it is using the lagrangian
15:51
What are the exact boundary conditions on the Poisson's equation to get the retarded scalar potential?
[I guess it is obtainable cz it is obtainable for Lorenz gauge (via use of retarded Green's functions to wave equation satisfied by the 4-potential) and all gauge choices are equivalent]
16:05
I think I got the answer from Brill and Goodman (1967)...
No...sorry I didn't get it...what they did was consider the Coulomb potential and calculated the electric field and showed it to be causal (and equivalent to that calculated with the Lorenz gauge).
I am looking for getting the retarded scalar potential itself...and now I am wondering what will I get if get retarded scalar potential and also retarded vector potential (with transverse source) if the solution with the ordinary Coulomb potential and retarded vector potential gave the retarded solution itself!
123
123
16:35
Hello Everyone..
17:24
what book would yall recommend learning stat mech out of
18:02
@SillyGoose from which level of understanding to which level of understanding?
hm i suppose introductory undergraduate, but more precise and rigorous than the level of schroeder
And maybe a book that is undergrad/grad level for looking into specific topics in more detail
Have you understood why we care about entropy up to the level of Feynman Lectures?
If you do, then I would suggest Ian Ford
Schroeder is just so unreadable
I do not (i haven’t done any stat mech)
Then you should read Feynman lectures on the energy and heat parts
all in vol 1
then Ian Ford
After you do Ian Ford, you should read Callen, and Kittel & Kroemer
Okie i shall try these out
in vol 1 are you suggesting 39-45?
also, do treatments of statt mech that assume (undergrad level) knoweldge of probability theory and quantum mechanics exists/are better than usual treatments of thet subject?
18:22
@SillyGoose yes. Also read the front bits on energy
@SillyGoose I think so? if you dont know some prob and stats, and quantum, stat therm will be unreadable
for introductory, the text will have to contrast classical thinking with quantum, so not knowing the full quantum business will be part of the journey
hm but is a classical discussion not a waste of time if the audience is expected to know quantum>
?
18:38
For grad level stuff, that will be the case.
But this is introductory, and we kinda want to contrast what classical expectations v.s. quantum statistics say things should be, and thereby show that a classical description of our universe is kinda impossible to defend
fqq
fqq
19:13
There once was a classical theory,
Of which quantum disciples were leery.
They said, “Why spend so long
On a theory that’s wrong?”
Well, it works for your everyday query!
When an equation is said to be lorentz covariant, does it mean it doesn't change as we change reference frame?
 
2 hours later…
21:05
@naturallyInconsistent makes me wanna kms
21:58
@Relativisticcucumber YONK
That's a yo honk FYI

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