@ACuriousMind "Energy does not have mass, it is can be transformed into mass" and so on and on. Try asking graduates about the history of relativity theory. You will see I am not making this up.
@MatthewChristopherBartsh I mean, if that is your experience then that of course sucks, but I really don't know where you got those interlocutors from. Really anyone with some basic understanding should have been able to explain rest/invariant mass to you.
this really sounds as if you only talked to people who had their knowledge of relativity from pop sci treatment instead of actual physics
of course they perhaps won't know the historical details of the shift in the usage of "relativistic mass", but actual physicists being unable to explain what they mean by the photon being massless sounds just absurd to me and does not match my experience at all
you either vastly overestimated the expertise of these people or they thought you were a crackpot ("The photon can't be massless and relativity is wrong" is a common thing crackpots say) and were just trying to make you go away
@MatthewChristopherBartsh So? Unless their expertise was in a field that required relativity, they might not ever have actually learned relativity at a formal level
The Laki fissure eruption of 1783/4 in Iceland was not particularly large or explosive, but it is infamous for the large quantities of fluorine (or hydrofluoric acid) and SO2 that it produced, and the resulting local mass poisonings and Europe-wide vog (volcanic smog).
How come a number of Icela...
@ACuriousMind I thought he was dumb for thinking that a photon had no mass. I guess in a way he was, but it wasn't his fault. He had been miseducated. I think I've found a way to mitigate the problem, and the benefit to nonrelativists would greatly outweigh the harm if any to relativists. Indeed, all relativists were once nonrelativists so it might even benefit those people on balance.
@ACuriousMind He did use relativity. He used to make software that simulated relativity. I don't know how good it was, but I saw some other software he made and it was impressive.
*not dumb for thinking it had no mass, but dumb for not knowing why.
Does a photon have mass or not? Im confused now... but to be fair I still havent read QED. Yukawa theory which I think is supposed to be a toy model of QED seems to give mass to the "photon"
it is entirely possible that the photon has a vanishingly small mass that just so happens to be so small that none of our experiments so far has detected it
@ACuriousMind Even physics professors at decent universities have misconceptions about physics, and even about simple stuff like the basics of Newtonian mechanics. The focus in physics education is on calculation and lab work. Discussion and debunking of misconceptions and splitting hairs does get much emphasis. Physics puzzles catch out a surprising percentage of physics professors. I heard that even the great Richard Feynman wrongly answered in public a simple puzzle about the level of water
@ACuriousMind in a lake. Academics are not at their best when something new is presented, or something is presented from new perspective.
@ACuriousMind As for my experience sucking, it does in a way, but OTOH all's well that ends well. In the end, as a result of never giving up, and eventually getting lucky, I did find out what was going on, and now am in the enviable position of being one of the few people to know what the true situation is (at least I've got an inkling now). But rather than just enjoy being one of the lucky few I want to make things better for those who are still in the dark.
@MatthewChristopherBartsh This somewhat reminds me of my girlfriend who asks me questions all the time about basically everything, and when I say I dont know, she responds: well, arent you a physicist?
My point is that we are not supposed to know everything in physics, especially if its not in our area of expertise
@SirCumference Right now most physicists, and nearly every nonphysicist, when they use the word "mass" when relativity is relevant they are in danger of making no sense at all, or making an untrue statement, because they don't know that there are two definitions of "mass", and they are very different. Using one definition, photons have mass, and mass increases with speed, using the other, not at all.
@So I'm not just trying to help the public, but also physicists to not make fools of themselves.
@SirCumference I have no hope at all here. I don't expect anyone to listen to me about anything. As you say, it makes it worse that it's a matter of terminology. They'll just say, shut up and calculate.
@SirCumference Does use of "derivative" cause misconceptions, though?
@MatthewChristopherBartsh For sure. Some people use it to refer to differentiation (a linear operation on the set of differentiable functions), others to refer to the derivative of a function (e.g. cosine being the derivative of sine, which isn't linear), and others to refer to the derivative at a point (which again, gives you something linear)
The case of "derivative" being overloaded brought me a lot of confusion since people tend to say "derivatives are linear". That's true in definitions 1 and 3 (e.g. a Jacobian matrix is indeed linear), but not definition 2
> All proofs are separated into two columns. There are statements on the left-side and reasons on the right-side. See the diagram below to see how they look.
I'd argue "proof" means the same at every level, but what's different is the kind and amount of scrutiny something is subjected to before it's accepted as proof :P
@ACuriousMind I don't agree with everything there (I think the history of math ought to be separated from math classes), but it is a shame most of the good stuff in the essay was ignored by educators
@ACuriousMind I mean forcing people to use a stupid column structure is just bad preparation
Especially bizarre that it comes up in geometry classes of all places and then is never used again
Most of the "proofs" there are obvious to anyone with eyes
@SirCumference quoth Lockhart: "Instead of a witty and enjoyable argument written by an actual human being, and conducted in one of the world’s many natural languages, we get this sullen, soulless, bureaucratic formletter of a proof."
@MatthewChristopherBartsh I think math in general is just completely different in uni compared to most high schools
You're expected to understand what's going on at a deep level rather than memorize
It's no wonder so many high schoolers find math confusing when they're offered none of the intuition
People look at e.g. the fundamental theorem of calculus and see some abstract equation they gotta memorize, when it's really just a (brilliant) way of saying "the sum of all changes equals the net change"
All the fun of math is lost when the intuition is discarded
after intro QM (where it is important to not additionally confuse people about what's a number and what's an operator when they're already being confused by QM itself) people simply often stop putting hats on operators because it gets annoying to put hats on everything
hm, that sounds like an interesting quirk - maybe it's because $a$'s eigenvalues are usually written $\alpha$ and $a^\dagger$ has no eigenvalues so there's no risk of confusing the operators with their eigenvalues like for most self-adjoint operators (where $\hat{x}$ is the operator and $x$ an eigenvalue)?
That is actually a good explanation. I can't think of another operator whose eigenvalues are denotes with a different symbol, except of course the hamiltonian
another explanation: $a$ and $a^\dagger$ are not the quantized version of classical observables
if you're using the hat to mean "this is the canonically quantized version of the classical thing below the hat", then it's just correct to not put hats on them
Ya know, considering how much the world tends to disagree on the units for temperature, mass, length and other stuff, I'm just glad there's a universally accepted unit of time
Imagine if Europe used the second and the Americas used some other unit equal to 1.3 seconds
Hmm, I guess I should consider myself kinda lucky they're usually written in my native language. I imagine it'd be much harder for me to learn a programming language that strictly uses e.g. Japanese characters
@SirCumference That reminds me the preface to Griffiths's Introduction to Electrodynamics, where he writes "Neanderthals still speak of pounds and feet". That was savage
The only thing I know is that I haven't worked with numbers for a long time and I have this test where I have to. It takes more time to use the calculator and convert units than solving the problem
Hopefully this will be my last test using numbers :P
Or rather you should be asked the numerical result only there is something to say about it. Why would you make an exercise about Zeeman effect and ask for the numerical value of 10 wavelenghts?
When quantising the Dirac field, do we have the freedom to quantise with the spin directed towards a particular axis? I.e. do we quantise "the particle in the $S_z$ eigenstate"?
The choice of basis in the solution space of the Dirac equation amounts to choosing one of the Pauli spin matrices to diagonalize, which we generally take as $S_z$. I can't think of a point at which this enters during quantization but I am unsure
@Charlie yes you have this "freedom" - but you're just picking a "random" basis to expand the field in, there's nothing particular about the choice of spin axis (you're not somehow only quantizing particles with spin in that direction or something like that)
I would be extremely grateful if someone will entertain my stupid confusions.
So I was thinking about 1-loop matching in EFT, and how it's supposed to capture all correlation functions to some desired accuracy in E/M, where E is the typical energy scale of measurements, and M is the mass of the particle I've integrated out.
There are many cases in which the effective potential has a different vacuum than what you originally expanded around to do perturbation theory. Eg. the classic coleman-weinberg potential.
However, unlike the coleman-weinberg potential, I'm thinking about a Wilsonian effective action, not the quantum effective action. Therefore there's still a path integral to perform when computing observables.
Aren't the following two statements contradictory? 1) the 1-loop effective potential reproduces observables to the desired accuracy 2) The original vacuum is unstable, so that 2-pt functions in particular, do not match?
Perhaps I just need to follow through a computation and see for myself. I feel like I'm missing an essential point.