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03:27
Morning
 
3 hours later…
06:07
@ACuriousMind I thought about your comments to my recent question that the term is only called "pressure" ... Doesnt that $P$ obey Naiver Stokes equations? It has to be pressure we all think about
 
5 hours later…
11:08
@MoreAnonymous No, the Navier-Stokes equations are the non-relativistic equations for a viscous Newtonian fluid. But "pressure" is more general than that - we also call the spatial $T^{ii}$ components of the stress-energy tensor pressure, but this doesn't need to describe such a situation at all (in particular it's usually relativistic and the generic continuity equation is just $\nabla_\mu T^{\mu\nu} = 0$).
pressure is just "force per area"
how you compute that depends on your specific situation, your question is like complaining that "the force" is computed differently for a spring than for a charged particle in an EM field
12:03
Your right I should have said the Euler equations ... So this is where Im stuck. To summarize:

1. We take a bunch stress energy tensors of discrete particles and we know they since we do not include any interaction term they cannot behave like pressure (force per unit area)
2. However when I take the divergence of the corresponding stress energy tensor and then the non-relativistic limit I get Euler's perfect fluid equation. The P in that equation is definitely the pressure we all know.
Also is it me or do physicists play a horrible misleading semantics game somtimes :/
@MoreAnonymous what you mean is that it doesn't behave like a fluid. Again, the components $T^{ii}$ are normal stress/pressure regardless of the physical situation. As an example, the dust solutions of general relativity have vanishing pressure because the "dust" particles only interact gravitationally . they don't act like you'd expect "real" particles to act, but that doesn't mean the term pressure doesn't apply.
the problem seems to be that you conflate the notion of a real-world fluid with hydrodynamic pressure with the abstract notion of pressure as momentum flux/force across surfaces
@ACuriousMind But it has to behave like a fluid right if it obeys eulers equations of a perfect fluid?
the dust solutions are called "perfect fluids", I don't think that's the term you want to use there
@ACuriousMind Ummm ... Ideal fluid?
probably
but I'm not sure what the question is
Euler's equations are equations for the motion of fluids
you use them if you want to describe a fluid
so it's a tautology to say that things that obey the Euler equations "behave like a fluid" - we designed these equations to models the stuff we call "fluid"!
12:16
Yes ... And they have a P term which is ubiquitously means the newtonian pressure right?
your semantic problem is that you seem to think that pressure and fluids are intrinsically linked
@ACuriousMind But when you derive Euler equation thats what P means
@MoreAnonymous no, again, $p$ is just momentum flux across (imaginary) surfaces
just because pressure in the context of fluids is the most common use of the term "pressure" doesn't mean you can't use it outside of that context
I can shove my fist against the wall and then I'm exerting pressure on the wall (total force divided by contact area)
there's no fluids involved there, but still the term pressure applies
Sure ...
Okay how about this
If I put the stress energy tensor from Caroll's book in the Penrose box. Will all the walls after sometime feel uniform pressure?
I don't know what it means to put a stress-energy tensor in a box
the stress-energy tensor is a description of a particular physical situation - if you change the physical situation, you get a different stress-energy tensor
12:22
I mean put the system with a stress energy tensor mentioned in Caroll's book
depends on what the system is
@ACuriousMind Why don't you have the equations of motion? To see how the fluid will evolve?
the stress-energy tensor doesn't tell you whether the components of its system can bounce off the walls or not
and whether they can do that or not is the crucial question for what happens when you put it into a box
@ACuriousMind True you can add that as a boundary condition
it doesn't even tell you whether the components of its system can bounce off each other, which is the other thing that's relevant for the Penrose box
the stress-energy tensor is not the systsem
it's like asking "What happens if I put 100 MeV into this room?"
it's a nonsensical question - are these 100 MeV heat, particles, something else?
12:26
The one Caroll derives in his book assumes discrete particles which can go through each other. Are you saying I can have a collisional fluid and get the same stress energy tensor? I concede I am assuming there is some uniqueness theorem
the Carroll example is a perfect fluid, so sure, if you put that into a box, it will behave exactly like light
@ACuriousMind So it will touch all the walls?
look
perfect fluids don't exist
there are no real-world particles that interact purely gravitationally
photons don't bounce of each other either, but they are also massless so they don't really interact gravitationally
Yes and for photons we know they wont touch all the walls ... But photons dont obey Eulers equations. Right? (In fact I dont think there is a non relativistic limit of a photon)
if we imagine some particles that do not bounce off each other and only off the walls, then they are for the purposes of the Penrose box the same as light and won't reach everywhere, but what's the point of this exercise?
Euler equations or any other hydrodynamic equations are completely irrelevant here - they don't model the interaction with the walls of something the fluid flows through. Why would you use hydrodynamics to figure out what happens to the particles in a box when for photons it also sufficed to think about where the individual particles will bounce?
you didn't go and do relativistic dynamics for a photon gas there, either
12:56
So if you are so concerned about the wall interaction. I can construct a universe where the boundary behaves like a mobius strip and any molecule that touch the wall reappears on the other side with the parity changed only (kinda similar to pacman reappearing) ...

In this case one would conclude it is impossible for the momentum flux (pressure) to be distributed (such that it is non-zero everywhere). However, I would be very surprised if simulations of an ideal fluid (obeying eulers equation) did not reach all spots.
hello
13:15
@Slereah yo!
 
1 hour later…
14:42
Hi everyone
I have a question about the Principle of Least Action
Light takes the path of least time (or action)
That's why it goes in a straight line in air, refracts in water, and reflects in equal angles.
Now, I was researching the Brachistochrone problem, which asks "What is the shortest-time path between two points in a gravitational field?"
The answer, discovered by Johann Bernoulli, is a cycloid, which he found by ingeniously exploiting the fact that light will naturally take the least-time path.
Using Conservation of Energy, we have $v=\sqrt{2gh}$
Since $\frac{\sin{\theta}}{v_1} = c$, a constant
We have $\frac{\sin{\theta}}{\sqrt{y_1}}$, which is the differential equation for a Cycloid
Now, my question is, what if we're in an arbitrary force field?
In other words, what if instead of $n\propto \frac{1}{\sqrt{y}}$, we had $n\propto \frac{1}{f(y)}$, where $f(y)$ is some general function in terms of $y$?
If anyone could suggest any ideas, that would be much appreciated.
Sorry to ping @DanielUnderwood, but any ideas?
@rb3652 please don't ping random people
My apologies
@rb3652 I think the only answer one can give to that is "it comes arbitarily complicated"
14:58
I'm sure an analytical solution is next to impossible, but would a computational/numerical "solution" be possible?
quick googling shows there are plenty of articles that consider various generalizations of the brachistochrone problem, see arxiv.org/abs/math-ph/0612052v2, doi.org/10.1016/S0020-7462%2897%2900026-7, sciencedirect.com/science/article/pii/S0895717711004213
Yes, I've read many of them.
However, they are different generalizations, in which the boundary conditions are varied, and such.
Some add friction, some consider a "terrestrial" brachistochrone problem.
I think Synge talked of weird boring problems like that
Like the ballistic suicide problem
"The usual problem of ballistics is to aim a projectile so that it hits someone else. Here we consider the ballistic suicide problem : the projectile is to hit the projector himself!
However perverse such a problem may be sociologically, it is a neat problem in relativity, because there are only two observations and both are made by the same observer. Moreover it forces us to realize that although the trajectory of a projectile fired straight upward seems sharply curved at the top, from a spacetime standpoint it is as straight as possible (geodesic). "
Just thinking out loud here -- would it be possible to create in a program which numerically solves for the least-time path in any conservative field?
That might involve calculating the change in angle of the light ray at every interface, using Snell's Law (?)
@rb3652 I mean sure, algorithms exist
You could just bruteforce every possibility on the mesh and that would work!
15:02
Brute-force every possibility? Could you clarify?
@rb3652 I'm not sure what the question is, then - for a conservative force you should be able to write down an action functional and derive E-L equations, no?
It's the first dumb idea that comes to mind as an algorithm for least action problems
once you have the E-L equations you can apply whatever numerical method for solving differential equations you want
Just make the program generate all the paths and compute the action for each
Then sort the list
simple enough to program if long
but it shows it can exist at least
@Slereah That's really interesting -- it gives an approximate solution, if not an exact one.
15:03
well that is what you can expect with numerical solutions
@ACuriousMind But will solving EL give me the path itself?
I'm sure there are much more elaborate algorithms for it though
@rb3652 Hm? If you have $(x(t), y(t))$ you can always (locally) get $x(y)$ as "the path"
A useful trick in computer science to check if an algorithm exists is to ask "What about bruteforcing every possible solution"
Well, this is certainly food for thought. Thanks everyone @ACuriousMind @Slereah for the ideas. If it works out, perhaps I'll come back to report my findings.
15:05
It's not usually the best algorithm, but it's good to show existence
sites.millersville.edu/rumble/StudentProjects/Gemmer/… similar to the first link above looks good too
but note also that the difference between "an algorithm exists" and "it is feasible to implement it and it will find a solution before the end of the universe" is often annoyingly large
@ACuriousMind I never worry
Leave the computing to the computer
I can wait $10^{500}$ years
15:24
$10^{500}$ years of computation to work out that the line was the shortest path
15:35
Deep Thought only needed seven and a half million years of calculation.
You can make it arbitrarily long since you can increase the mesh size of your space
More paths to check
just checking that a straight line is the shortest path up to $10^{-30}$ meters
@Slereah 1 for each string theory vacuum, nice
Maybe there's a secret path that we missed
I think "shortest path calculations of a space that has been triangulated" is essentially graph theory
what you want is graph algorithms
Regge calculus something something
16:06
-1
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Xira ArienHrm....where to start....I will likely be banned for something in this post - but nothing I say herein is untrue as I currently understand it and believe. My money is also real :D NVCR from 12$, CCXI from 4$, SAVA from 9$, ANVS from 10$ <3 But first! A somewhat non-specific introduction to we! WA...

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16:59
Only thirty five more black hole mergers detected. Come on guys, stop slacking! :-)
17:27
0
Q: Seeking physicist with access to computational quantum simulator to work on questions about acceleration of spacetime expansion and wormholes. Ill pay

Xira Arien I have a question about physics relating to quantum-entanglement, maximum/minimum energy levels, distance, the accelerating expansion of the universe, and the recent plans for new gravity-wave detectors to be built. These questions will require expensive computer simulations to be run - which I...

is it ethical to take a crazy man's money
can't everyone just flag these questions instead of posting them here?
Because it is more amusing
 
1 hour later…
18:29
I'm a bit confused. I've seen various ways to get the cycloid solution $( r(\theta - sin{\theta}), r(1 - \cos {\theta}))$, but I haven't seen anyone derive it from EL (or at least, not in a way I understood)
For example, one video showed the derivation from $\int{dt}=\int{\frac{ds}{v}}$
Wait a second, I think I got it. Let me try again.
glS
glS
18:49
@Slereah these kinds of posts really make me wonder about the person behind them.
"(tl;dr - I am a high functioning physchopathic buddhist (little b) monk and occultist with multiple degrees from good universities who wants to pay possibly up to hundreds of thousands of dollars (gradually in milestone payments) to someone to run some simulations on angular momentum, the accelerating expansion of spacetime, and quantum entanglement)" lol
Although I suspect that if he sends me money it's gonna be all in NFTs
glS
glS
the guy is talking about how he self-operated on his finger "cutting to the tendon", and how the dark gods later told him it was a good idea. I'm not so sure you want to try to get money from them lol
I mean he doesn't sound any crazier than Elon Musk
glS
glS
eh, different kind of crazy though
at least Musk doesn't go around boasting about car accidents and bad things "happen" to people that were mean to him.
He only goes on about evil AI
19:02
I wrote quite a simple program, hoping it would give me the equations of a cycloid, but instead, there's a bug:
x   = dynamicsymbols('x')
t   = dynamicsymbols('t')
xd  = dynamicsymbols('x', 1)

L = math.sqrt((1+(xd)**2)/t)
f = diff(diff(L, xd), 't') - diff(L, x)
pprint(f)
**TypeError: can't convert expression to float**
19:14
Can someone explain how exactly we go from the Lagrangian to EL to a Cycloid? I think if I better understand this process, I can generalize it to any $f(y)$
19:32
Chapter one of the notes I sent above explains it
19:59
@bolbteppa OK, I'll look into it.
 
2 hours later…
22:29
is the reason why $\int pdq$ is called abbreviated action because it's only part of the action - the whole action is $\int\mathcal{L}pdq=\int (pdq-Hdt)$?
the whole action is $\int\mathcal{L}dt=\int (pdq-Hdt)$

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