While I was reading from the book of Brussaard on shell-model applications in nuclear spectroscopy, he mentioned that isospin of a neutron-neutron pair couple to $T=1$. On the other hand, if it was neutron-proton pair, the isospin couples to either $T=0$ or $T=1$. Now, my question is I can't see ...
Why can't we somehow power the human body using electricity? Like, replace all the organs with mechanical alternatives and boom. Like, we can remove eating, drinking, peeing and pooping all together.
Unfortunately, other cells will still need food, water, oxygen... Why don't we remove the body altogether, learn to keep the brain alive, and attach it to mechanical parts?
The thing is, the brain cells will need food, water, oxygen... ahh...
The major obstacle I feel is that it takes a lot of prerequisites (like general relativity, quantum field theory, string theory) to even understand the research problems in this field: Without these prerequisites, it's extremely hard to understand the research papers in this field. And these prerequisites are generally taught in the beginning of a typical graduate program.
@Slereah Can we hook up a mechanical arm for example to the motor cortex of the brain (give it action wire and feedback wire) and see if the brain can adapt and learn to control it?
I'm applying for a graduate school which asks the PhD candidates to submit a statement of interest that address the following questions in particular: (1) your area of interest ? (2) specific problems you would like to work on? (3) can you suggest some methods to deal with such problems? [This note is written beside it: The write-up should reflect original ideas. Don't write a general essay describing the area]
OneNote is trash. kept crashing and then it said "some files have been corrupted, reset to restore to the previous save," did that and now it can't open anything. that is all my work for four texts. WHAT IS HAPPENING. and their so-called cloud storage has failed miserably as well. I need a drink.
@Slereah Hmm. I feel I don't have the necessary prerequisites to even understand most research problems. And now I'm being asked to pick problems that I would like to work on... Most probably it just reflects my poor preparation during my undergraduate study.
@Slereah I'll just plug the inputs wires somewhere in my arm-controlling motor cortrex part and the feedback wires into the arm-feedback somatosensory cortex and boom.
Just having people volunteer is not overall a great sign of ethical happenings, because people may not understand the risks properly or have other incentives to try even for high risks
@Slereah Morality is a simple mechanism that evolution has embedded in our brains so we can preserve life (and most importantly, continue it). Everything you consider immoral is something that decreases the chances of someone reproducing. It's quite simple and honestly, doing some experiments on volunteers can help with overpopulation. Humanity has a long history of not obeying evolution anymore.
@Slereah Of course, I totally agree with that, but in our overpopulated world, it's not unacceptable, considering the fact that it's a contribution to technological progress.
Right, so he begins by claiming the proof is similar to the method he uses to show two permutations of $n$ things are isomorphic
An 'invariant' subgroup is a normal subgroup, i.e. a subgroup $H$ of $G$ such that $g H = H g$ which basically means you can split the group up into equivalence classes using $H$ as the class of elements equivalent to the identity
So basically, the idea is a group could have multiple different maximal normal subgroups, and each of them can have further maximal subgroups, and the number of them and the way the quotients will look will be the same up to ordering
That's a really shocking result no? For something as complicated as a group, the whole $12$ divides into $6, 2, 1$ or $4, 2, 1$ or $6, 3, 1$ stuff, it's like a prime factorization of a group or something
Consider $C_{12} = \{e^{\frac{2 \pi i k}{12}} , \ k = 0, \ldots , 11 \}$. We note $C_6 = \{e^{\frac{2 \pi i 2k}{12}} , k = 0, \ldots , 5 \}$ is a subgroup of $C_{12}$ and $C_{12} \backslash C_6 = C_2$. We also note that $C_{4} = \{e^{\frac{2 \pi i 3k}{12}} , k = 0, \ldots , 3 \}$ is a subgroup of $C_{12}$ and $C_{12} \backslash C_4 = C_3$. The intersection of $C_6$ and $C_{4}$ is $C_6 \cap C_4 = \{0, e^{\frac{2 \pi i 6}{12}} \} = C_2$.
We note $C_4 \backslash (C_6 \cap C_4) = C_4 \backslash C_2 = C_2 \simeq C_{12} \backslash C_6$. The first step of the proof seems to be showing this is a general result.
@bolbteppa Hip-hop doesn’t touch the heart you know. I need something calming, if you have time please listen to book of my life by sting, or some poems from great poets like Wordsworth, Keats, Blake etc.
What's the point of making it a privilege to see separate up and down vote count when someone willing to do so can easily check it with timeline? (Even the users who aren't logged in)
The "view vote count" privileges is less about restricting access to the specific vote counts and more about limiting load on the servers.
From Jeff's answer on Show Total Votes (or Up/Down Votes)
The total vote count (score) is denormalized, but the individual up/down vote counts are not.
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@Knight Here's a silly but clever song by Annie Ross: Twisted, (Wardell Gray wrote the tune). Joni Mitchell did a good version of it back in the mid 1970s.
@Knight Pink Floyd & King Crimson were contemporaries. A lot of people liked both bands, but there was also some strong rivalry. I suppose King Crimson were a bit more intellectual and "arty", but Pink Floyd had more commercial appeal and success.
@JohnRennie Of course. :) I do like In the Wake of Poseidon, apart from the penultimate track, which drags on for too long (IMHO), and it's a blatant rip-off of Gustav Holst's Mars, the Bringer of War.
In the Wake of Poseidon is so similar to the first album. It's good, but it feels like they used all their best ideas in the first album and ITWOP was the leftovers.
@JohnRennie Here's an Aussie prog rock track that had commercial success. The recorder was played by a guest, Bon Scott, from the band Fraternity. Bon went on to become the 1st singer of AC/DC.
@Knight Yes, I used to listen to the radio when I was younger. I still do, from time to time, but mostly small community stations, not commercial ones, and I usually listen to them via the internet.
In the mid 1970s, the Australian government broadcaster (the ABC) launched an alternative AM rock station 2JJ, which became an FM station JJJ a few years later. They played all sorts of stuff you'd never hear on commercial stations. But I stopped listening to them in the late 1990s because they played too much rap for my tastes.
@PM2Ring correct me if I am wrong. I have observed that many (high rep) users here are quite active on stack overflow. It might be because they are in the field of scientific programming or something related. Is there any specific reason for this?
@JohnRennie You also had the "pirate" stations, though... if you were in the right location to receive them. Some of the best presenters / programmers on 2JJ had been on those pirate stations before coming to Oz.
@JohanLiebert I'm not sure, but there are quite a few scientist types on Stack Overflow who aren't employed as programmers, but who do write code for their science work.
@JohanLiebert Beat Saber is really fun. I own a pretty low-end VR setup and Beat Saber. The biggest hassle is having a small apartment and having to move stuff when I want to play standing games like that.
@JohanLiebert I made it across the Hong Kong border two days before they started doing two weeks of required quarantine. >150million Chinese citizens now under lockdown. Crazy.
@Semiclassical I've definitely been emotionally engaged by it before. I haven't listened deeply to it in awhile; but when I used to listen to it more there were quite a few songs with an emotional impact on me.
@JohanLiebert Indeed, really interesting time to be over there. Vast majority of the shops, restaurants, roads, and public transportation was empty by the time I was leaving. Felt like a ghost town. In good health though, cheers
Read these expressions from right to left. Your expression $\langle\phi|Q|\psi\rangle$ can be read as "the amplitude of finding the $|\psi\rangle$ state in the $|\phi\rangle$ state after measuring the observable $Q$." Mapping this onto your spin example, $\langle S_z;+|S_x|S_z;+\rangle$ is the am...
Is this correct?
@dsm I think I am thrown off by your wording a little bit
@AaronStevens Sorry, it's 4am over here and I'm sleep deprived. Didn't want to get into normalization because the question was aimed at interpretation, but I see that wasn't a good approach. Deleted the post because I didn't want to go down the path of editing when I should be asleep. I appreciate the comment
Well, -1 and 3 are the same mod 4, and by convention we choose to represent numbers mod 4 with 0,1,2,3, so both -1 and 3 are "correct" as being the same as -29, but 3 is the conventional choice.
The way I do it is: what integer you can multiply 4 by so to end up as close as possible to -29. Now take the difference between -29 and that 'as close as possible' number
@NovaliumCompany Then there you've made a conventional choice to represent 3 mod 4 as -1 mod 4 (note that this procedure also gives -1 for 3, since 4 is the closest 4-multiple to 3 and 3-4 = -1).
So to end up at a positive result, the number I'm subtracting from -29 must be greater than -29. So if I choose -30, I can't multiply 4 by a solid integer, but I can do so with -32.