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06:51
morning
@PM2Ring Hey, there, you gave me a question yesterday, the question is to find the cone of smallest size that can have a unit size Sphere in it, the progress I've made till now, confirms that it must have the length $l=2$, is that correct? Note it's not perpendicular length, it's length of the slope of cone
Morning
@Slereah you live in Egypt or Israel?
Or France...?
07:08
@AbhasKumarSinha Odd question
Hehehe see replies to this tweet (so called handcrafted tweets received great replies) twitter.com/realDonaldTrump/status/1137051097955102720?s=20
 
1 hour later…
08:17
Guys, would someone please help me figure out how to pose me question physics.stackexchange.com/questions/484784/… better? I'm basically interested in what happens if a ball tied to a rope falls down in a pendulum like contraption, but there's some object in the way of the rope.
@AbhasKumarSinha A unit sphere has radius 1, so its diameter is 2. So any cone containing a unit sphere must have a perpendicular height >= 2. And the sloping height of a cone must be greater than its perpendicular height.
Maybe the situation could be better described (thought this problem is a bit different) by a double pendulum? Initial conditions would be the two objects $A,B$, just hanging, where $A$ is vertically above $B$. Restrict the movement of $A$ to only one plane. What happens if we apply a small force to the object $B$ ? If the direction of this force is perpendicular to the plane in which $A$ can move, it should be true that $A$ will simply stay still, and $B$ will start rotating around it.
(By plane I mean perhaps the $xz$ plane). Maybe this problem is difficult - I'd be happy to know that's the case, but I'm afraid I'm missing some simple explanation for what happens. But maybe this is quite complicated - I'm not even sure what happens if I apply a force to the lower object in a hanging-resting double pendulum, for say force $(1,0,0)$. I would expect that would cause the pendulum to simply reduce to a simple pendulum/sphere, but I don't know.
@JohnRennie any opinions please?
08:34
@JohnP if you restrict the motion to one plane then it's an easy problem since all that happens is the length of the string changes when it hits the barrier. So the SHM divides into two parts with different frequencies.
But as I recall your question the barrier was slanted so the string would slide along it i.e. the edge would produce a force out of the plane. That makes the problem considerably more tedious.
Oh right, by plane I meant various planes (like the one generated by $(0,0,1)$ and $(1,1,0)$.
Maybe I should mention that I'm not necessarily interested in some precise/analytic explanation, just a way of how I could numerically simulate it for example (approximating how fast the string will slide is enough for me).
09:12
(also in the explanation above I meant that only the upper object is restricted to a plane, the other isn't). In some sense I would expect that the distance covered by the rope must be efficient in some way if there is no friction. So maybe for example it can't happen that the rope goes from $(0,0,1)$ to $(0,0,0)$, and then from $(0,0,0)$ to $(1,1,0)$, because the rope could also reach the point $(1,1,0)$ by going from $(0,0,1)$ to $(1/2,0,0)$ and then to $(1,1,0)$. Does that make sense?
Either way thanks for the response @JohnRennie , at least I know the problem is probably a bit tedious, I was afraid I'm missing some very simple trick (like maybe the thing I just wrote above, but I doubt it's true ... it might be an ok visual approximation though).
 
4 hours later…
13:40
Hello @JohnRennie
14:01
Hello ....anyone here?...what exactly is thermodynamics...what we deal with in it? We study Clausius calyperons equation...we study contact angle kinda related and gases...and lot more....can anyone just say what exactly we study in thermodynamics....does the name and the topics match
@pss1 Sometimes one says that thermodynamics is the study of statistical systems in equilibrium, but sometimes that's too restrictive. See physics.stackexchange.com/q/476554/50583, where an asker had a similar question about the extent of "thermodynamics".
@skullpetrol "forces"?
14:08
When they say that mass increases with speed in special relativity, is it inertial mass or gravitational mass?
and hi hows you
@PrittBalagopal neither
oh
then what does it mean?
Also, "they" don't really say that anymore, cf. physics.stackexchange.com/a/133395/50583
Modern relativity does not rely on the notion of relativistically increasing mass. It's an anachronism that it still appears in many introductory treatments
That beginning students are stuck with.
14:11
Hii ! Can somebody please tell me what does derivative of a cross product actually mean?
Thank you
@user8718165 What do you mean by "meaning" there? ;P
@ACuriousMind thanks :-)
@ACuriousMind I wanted to say is there some kind of visualization?...because in cross product a and b are constant only the angle $\theta$ between them changes so all we can do is take the derivative of $\sin\theta$...is it possible?
@user8718165 Wait, what are you differentiating this cross product with respect to?
14:16
@user8718165 are the vectors constant in magnitude and direction?
The cross product on its own is just an operation on two fixed vectors, it has no inherent notion of a derivative because there's nothing varying there
A specific vector do not change w.r.t anything tho...is it mentioned that the oneof the two or two vectors Ur taking product of is function of some variable?
@ACuriousMind with respect to time...
@user8718165 So you're taking the time derivative of a function that is the cross product of two other, time-dependent vector functions?
@ACuriousMind I'm trying to find relation between angular momentum and torque...
14:21
In that case the derivative is just a vector that point in the direction in which that cross product is changing, like with the derivative of any other vector-valued function. There's nothing special about the cross product there
@ACuriousMind Thank you so much...got it:-)
15:01
Chairs' account is now deleted!
:O
@ACuriousMind dynamics means "other forms of energy" ;-)
(Even if that were true, I don't see how that's a reason to talk about "forces associated with heat", but)...not really. While the Greek dynamis means "force" or "power", today by "dynamics" we usually mean the opposite of "statics", i.e. an investigation of evolution rather than that of an unchanging state.
you also see the kinematics/dynamics distinction. not entirely sure how to compare that with the statics/dynamics distinction
@Semiclassical There the original meaning is preserved somewhat, in that "kinematics" cares only about the description of motion, while (Newtonian) dynamics cares about the "cause" of motion, i.e. Newtonian forces.
yeah, that sounds right
15:13
"forces"? :P
::runs::
@Semiclassical are you back home yet?
@ACuriousMind how about "other forms of energy associated with heat"?
What do you think "heat" means?
What "forms of energy" are you talking about, and how is/was this supposed to help the user who inquired about what thermodynamics is?
....does the name and the topics match
i mean, thermophoresis is a thing
but i don't think the mechanism there is some kind of other force
(also, 'thermodynamic forces' do show up in the context of Onsager reciprocal relations, but that's hardly elementary)
15:29
thermoplastic is a thing also :P
> Thermodynamics is a physi­cal branch of science that deals with laws governing energy flow from one body to another and energy transformations from one form to another.
@skullpetrol That’s good! Actually
yup, it's a good start :-)
Start?...meaning?
It gets complicated fast.
Oh..
Idk anything about thermodynamics except for the high school part!..XD..
15:44
in high school they leave out all the calculus
physics - calculus = :(
Hmm...so u enjoyed a lot of it ha (idk what ur now)...of course Ido with mine(high school tho!)
physics + calculus = 8-O
@peterh that's a pity
@pss1 learn calculus on your own!
16:17
@ACuriousMind how would you define "heat"? (other than the energy associated with the motion of molecules :)
@skullpetrol That's not heat, as you would know had you bothered to read the very first sentence of the Wikipedia article on heat you yourself linked. Heat is not a form of energy, it's any energy transferred during a thermodynamic process by means other than mechanical work.
The heat/internal-energy distinction is not merely overlooked among students, it is not universally attested in (a) historical sources or (b) source pertaining to other disciplines that care about energy. I'm looking at you, chemistry.
@ACuriousMind I was taught heat is an energy in transit !
But it really (really) helps in clarity and communication to make a strong distinction between the state property (internal energy) and the process property (heat).
16:24
@pss1 Which is the same thing I said, isn't it?
Yeah.
@dmckee To be fair, technical terms whose meaning differs from their colloquial meaning always tend to fair poorly in this way.
Internal energy isn’t a dynamic one(possession) so it’s not heat?and surroundings energy generally in in flow so...heat?
XD
"power", "heat", etc. - it's not that they're difficult concepts, it's that they are also ordinary words with a non-technical meaning that makes for confusing communication outside of explicitly technical texts
@ACuriousMind Sure. Essentially every technical distinction that gets built on common words has this problem for a while.
Though I feel like this one is more common and persistent than some of the others.
16:30
creating new words is not an easy task
such is more problematic for mathematical terminology, e.g. look at how "normal" is overused to the point that there is confusion even within maths disciplines
and then in business sectors, you have people sticking "quantum" to almost anything they can think of
good point
@skullpetrol why did u suggest me to learn calculus on my own.?,,..have fun u say?...I will ...
16:45
If you had normally-distributed data coming in over time, would doing a binary classification based on a confidence interval around a linear regression be different than by doing it with a confidence interval in a histogram? I feel like counts and position should be different things, but I'm having a hard time convincing myself that that's the case.
(ignoring the bit about the histogram's bin size)
@pss1 I said that so you can get the sense of amazement shown here:
58 mins ago, by skullpetrol
physics + calculus = 8-O
that^ is what is missing in high school
I find it bizarre that in some places, senior high school physics is taught without calculus. Ok, at my high school physics calculus was a bit sloppy, but that was ok, since we got a more rigorous version in the maths class.
17:01
The same goes for biochemistry in the biology class compared to it being covered properly in organic chemistry.
We didn't really even have calculus-based physics the first year or so of university, but I think that was due to some students coming in without any calculus knowledge
@danielunderwood We had a two-week math refresher at the start after which everyone was assumed to be able to do Taylor series in their sleep!
Well there was some calculus, but you weren't really expected to work it out entirely yourself. Then a similar thing went on with differential equations in the later years. Like I don't think we really ever had to solve the infinite square well all on our own
I don't think I knew what a Taylor series was as an incoming freshman, even though I was one of the people with more high school math. Quite an education system we have here in the states
did you take AP?
17:13
I think AP calc AB, though it wasn't the best. I think 3 of us actually took the AP exam
@ACuriousMind we also spent roughly half a semester of an EM course teaching vector calculus even though it was a prereq
Wait, vector calculus before single variable calculus?
And it's a bit of a shame that we didn't really go much into the theory side of EM since it's kind of a jumping off point for deeper theoretical stuff
@skullpatrol well by the time of that EM course, we were kind of assumed to know single variable calculus fairly well. That was an upper-level EM course and not the freshman level
I see.
There was "freshman-level" EM that did not require vector calculus?
Every time I think I sort of understand how academic things are on the other side of the pond, I realize I just don't :P
@ACuriousMind You can see walter lewin lectures, that’s without vec cal.
And that is freshman level too.
17:22
Yeah there was a 3 semester sequence of CM -> EM -> QM that didn't really require calculus because people weren't expected to know it entering as a freshman. Then we had upper level courses that expected calculus, but people didn't typically understand vector calculus well enough to not get stuck on EM and for whatever reason we weren't expected to be able to solve any differential equations
As much as I'd love to dwell on my astonishment here, there's a party I need to be getting to.
have fun
thanks, I will
Do you mean QM was linear algebra based? As you said calculus weren’t expected.
So the initial QM course only did stuff with square wells from what I remember. That was done with calculus, but it was more of "here's the answer" which is kind of what continued to be the case in upper levels when there was a differential equation. I don't think we even went much into the algebraic formulation in that course
17:27
sounds like a lot of memorization
I did do a funny thing in one of the upper-level quantum courses when solving the QHO on an exam. I didn't really understand the algebraic way, so I had a gigantic answer that was me doing everything in the position representation. I think my professor was just shocked that I went through so much unnecessary effort
It was some memorization, but it was like the type of thing where you'd remember that for square wells, you'd remember to have some combination of exponentials/modes and work out the actual details for the probably. Though we did have a lot of derivations in class that the only real requirement was to realize the result. It took me far too long to realize that the best way to remember the result was just to work it out from the beginning a couple of times
17:52
↑ unexpectedly nice-looking
(from here)
though now that I put it out of context, it kinda looks like an enormous mouth with an inordinate number of teeth
@JohnRennie well, that's a new one, for sure.
rob
rob
18:27
@EmilioPisanty A quantum lamprey.
with 50 teeth
18:43
@rob ugh =/
anyways
PSA: if you've been seeing a lot of questions (or other buzz) about the HBO show Chernobyl, and you're wondering "is it really that good?", then the answer is yes, it really is that good. Go watch it.
Hey there. So I'm trying to figure out how far away an aircraft or spacecraft's lights are visible, ignoring the effect of the atmosphere.
Now, I know that if a light is far away (so far away that it looks like a point source), then it appears dimmer the farther away it gets.
And I'm a little confused about all the various measurements of brightness. :D
@EmilioPisanty ooooo
(OK, I dunno if I'd reaaally rate it as the absolute best ever, particularly given that The Wire is lurking just under GoT at no. 7. But still. Yes, it really is amazing.)
@TannerSwett those are confusing indeed.
It looks like the "amount of light per unit of solid angle" is the luminous intensity, measured in candelas.
(Or is the plural just "candela"?)
So I might talk of, say, a lamp which emits 5 candelas when viewed from the front.
@TannerSwett I take it you've found your way to the table at the end of this?
In photometry, luminous intensity is a measure of the wavelength-weighted power emitted by a light source in a particular direction per unit solid angle, based on the luminosity function, a standardized model of the sensitivity of the human eye. The SI unit of luminous intensity is the candela (cd), an SI base unit. Photometry deals with the measurement of visible light as perceived by human eyes. The human eye can only see light in the visible spectrum and has different sensitivities to light of different wavelengths within the spectrum. When adapted for bright conditions (photopic vision), the...
18:51
@EmilioPisanty which potential is that with---just a disk with hard walls?
@Semiclassical yeah, nothing fancy. Just a Bessel function times a cosine
MM code in the answer's source if you're that curious
I'm trying to remember where Mathieu functions show up in QM (besides a cosine potential)
I think it's with an elliptic disk rather than a circular one?
@Semiclassical if I ever start a mathematical physicist's list of Things I Won't Work With, then that's one of the top places you'll find Mathieu functions
18:53
lol
@EmilioPisanty Yep, but it's taking me several minutes to think through all the implications of that.
@TannerSwett yeah, it's always a nightmare
What is it you actually know about the lights?
@EmilioPisanty hard to avoid it entirely given that it's the simplest periodic potential (at least in the sense of momentum space)
I know that, from a particular angle, regulations require the lights to be at least 5 candelas.
@Semiclassical eight years or so, thus far, and I've managed just fine
18:55
so you do see it in solid state, albeit mostly only the computations for the lowest bands
though if you think Mathieu is weird, I can do you one better
And then, since the "apparent brightness of a distant lamp" goes down with the square of the distance, I would expect this to be measured in... candelas per square meter?
@TannerSwett then you want the illuminance at the chosen distance over the pupil area, I should think
Mathieu (cosine potential) is $-\psi''+\alpha(e^{i\theta}+e^{-i\theta})\psi=E\psi$
@Semiclassical I really don't understand what a cosine potential gets you that tight-binding doesn't
at a fraction of the complexity
you're probably right in practice, yeah
but one of my first projects with my adviser addressed not only that but also stuff like $-\psi''+\alpha(2e^{i\theta}+e^{-2i\theta})\psi=E\psi$
(it wasn't actual a QM problem, but you could do some shenanigans to map it to that)
18:58
@Semiclassical that's ridiculous
the underlying problem was just classical stat mech, mind. coulomb gas stuff
non-hermitian and all?
18:59
ugh
on the other hand, it does have a nice bicircular feel to it
I'm going to do a Google search for "measurement of brightness of a star" and see what I get. :D Presumably whatever unit that is, that's the unit I'm interested in.
though you'd want to knock the first factor of two out
note that it's a pt-symmetric potential (it's invariant if you do both parity and conjugation, but not either individually)
@Semiclassical you say that like it's helpful
actually, that factor of two is handy. it ensures that the potential is harmonic at the origin
19:00
I feel like you're right, though, I feel like it's probably illuminance.
@Semiclassical yeah, I can see why you'd include it, but still
@EmilioPisanty well, in the context of the problem, it is: it ensures that the eigenvalues are all either real or occur in complex conjugate pairs
In neuroscience and psychophysics, an absolute threshold was originally defined as the lowest level of a stimulus – light, sound, touch, etc. – that an organism could detect. Under the influence of signal detection theory, absolute threshold has been redefined as the level at which a stimulus will be detected a specified percentage (often 50%) of the time. The absolute threshold can be influenced by several different factors, such as the subject's motivations and expectations, cognitive processes, and whether the subject is adapted to the stimulus.The absolute threshold can be compared to t...
> A second absolute threshold for vision involves the minimum photon flux (photons per second per unit area). In this case the light covers a wide field over an extended period of time instead of being concentrated on one spot on the retina in a short burst. Knowing the pupil diameter and the wavelength of the light, the result can be described in terms of luminance (~0.000001 candela per square meter or 10−6 cd/m2) or retinal illuminance (~0.00002 Trolands).
which ensures that the actual partition function you get (which would be something like $\sum_n e^{-\beta \lambda_n}$ where $\lambda_n$ is an eigenvalue of that potential) is real and therefore sensible
@Semiclassical no, as in: you say that you're doing PT-symmetric QM like it's not digging you further into a pit
19:02
lol. well, there's a reason why I emphasize that this isn't really a QM problem
I dunno, this is too confusing for me at the moment. I'll look into all this later.
and that's because I don't put a lot of stock in PT-symmetric QM as really having much to do with QM
the fun bit was that, despite the potential being non-hermitian, you could still do stuff like Bohr-Sommerfeld quantization and compute the level splitting via Gamow's formula
with the ground-state energy telling you, for instance, the pressure of the coulomb gas and the first splitting telling you about the energy barrier for charge transport across the (1D) system
that said, the functions involved in that are definitely weirder than Mathieu
simply by virtue of the non-hermiticity
There's a reason why we focused on what the eigenvalues were and not the eigenfunctions.
@Semiclassical yeah, that doesn't help them at all
It's like saying "oh, it's like a Meijer $G$ function but it's definitely weirder"
i mean, you can still move to Fourier space and compute eigenvalues by numerical diagonalization. so computing the spectrum is not actually so bad
but getting an analytical handle on them? oof, no thx
@Semiclassical anyways, that's nicely close to the combination of RCP $\omega$ $+$ LCP $2\omega$ that's so close to my heart =)
19:11
lol
we did a few other examples like (+3,-1), (+3,-2)
eh
I've never really seen anything truly nontrivial coming out of those
at least, anything that you couldn't get from (1,2)
well, in terms of math stuff there's some neat stuff. for physics, though, you may be right

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