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21:01
you can pretend to be anything you want in here
Anonymous
It won't really be wrong to say that everyone has at least some degree of sociopathy.
@Blue sounds like something a sociopath would say
"haha i'm totally normal bro"
Hi all, I think my question won't suit Physics.SE (I've tried asking here several times but never a response), but is too homework-like for the main-page. What else can I try?
What other sites* can I try
Anonymous
@Phase Psychopathy is the most interesting trait, however. You can almost never know that a person is a psychopath till you really know them
Anonymous
They do appear totally normal
21:05
@user55789 to risk stating the obvious, googling to see if there's an answer somewhere else on the internet?
Anonymous
@user55789 You can ask your question here in chat
@Phase Wouldn't bother you guys if I hadn't done that first. I've also asked other people, but I couldn't find anyone
Anonymous
There is also a dedicated problem-solving room
@Blue See above, I have asked like 4 times already xd
Ah I didn't know that
I will join that and see if anything fruitful comes from it:)Thx
Anonymous
@user55789 Ah, I see. Sometimes you need to wait, till someone who knows the answer comes along...
21:09
what's the question relevant to @user55789
Oh that one
Is calculating the line of regression for an exponential graph a silly thing to do or is it relatively simple?
I can do linear but I've never done an exponential
Anonymous
It should be simple. Just use the standard method..
Okay... I'll hunt down a formula or something :p
21:13
@CooperCape who cares if you're anything like me none of your data will ever be salvageable through LR anyway
Had to do Millikan's experiment the other week and my quantised charge was like a power of $10^7$ off
Anonymous
in Problem Solving Strategies, 59 secs ago, by user55789
So I should show that working with that inner product of this operator working on the four-body state should yield an eigenvalue $\frac 94 - \frac32$. I'm not getting that, my solution gives $\frac 94-\frac34$. You would think this is a simple factor 2 mistake somewhere. I could not find it. I simply could not.
Anonymous
In case someone can help user55789 ^
Uh
Okay ciol
Well I put it into Excel and it popped out with kx^-1.048
@Blue I mean, this is even an undergrad course, I can't remotely justify that I can't do this xd
An it's supposed to be -1
So I was pretty pleased just wanted to write something other than "Excel told me this"
21:16
But I will elaborate in the PSS chat
And break it down a little bit
@Phase better than cosmological constant wasn't that like 10^100 off
I think someone told me that or I read it in a book...
@CooperCape Are you thinking about ground state?
@Phase idk I just heard that somewhere I'm just a lil innocent highs cool equivalent of student
I think the theoretical result from early QED was like 10^100 and the observed value was like 10^-10
Idk though, my history of science isn't particularly breathtaking.
Ahh right
So a bit off, then
I'm sure my knowledge of science is even less breathtaking...
21:22
Eh, if I get my way I won't even be doing a science undergrad : p
I'll hopefully climb my way onto some Mathematical / Theoretical Physics masters or PhD program though.
Btw want a probably useless tip that's helped me out like, 4 times in my life?
Nvm I've probably already said it
Unmmmm
Sure?
While others apply... Phase 'climbs'
Dun dun dun
It's just a trick for remembering double angle theorem
Ooooh God not trig?
I'm pretty sure I said it before though, if not you can pretty easily derive a rotation operator for a vector in 2 dimensional space, then just use the fact that if $\hat R_\theta v = v'$, then rotating a vector and then rotating it again is obviously equal to rotating it once by the sum of the angles, so you end up with $\hat R_\theta \hat R_\phi v= \hat R_{\phi + \theta} v$ and then you can just use quick matrix multiplication to read off the double angle theorem
I.e. the upper left element of the 2x2 matrix will be $\cos(\theta)\cos(\phi) + \sin(\theta)\sin(\phi)$ which is equal to $cos(\theta + \phi)$ as the matrix on the right must be of the same form as each on the left
Helped me to remember them, since I could never remember the geometric proof / derivation
Anonymous
Why not just use Euler's for that? :P
21:30
Uhhhhh okay I understood little of that...
Anonymous
$e^{ia}e^{ib}=e^{i(a+b)}$
Anonymous
Take real and imaginary parts...
I guess you could but I dont like the idea of taking real and imaginary parts, it feels like an artificial step
Anonymous
@Phase Projection on x(real) and y(imaginary) axis of argand plane ;)
Anonymous
Alright, I agree
21:32
@CooperCape I have no idea how to format matrices in LaTeX, if I knew I'd show you. But if you recall the fact that the columns of a matrix are it's image, then the basis vectors $x = (1, 0)$ and $y = (0,1)$ get mapped to $(\cos(\theta),\sin(\theta))$ and $(-\sin(\theta)), \cos(\theta))$ by an anticlockwise rotation then just slap those two new basis vectors together to get the matrix
Anonymous
The rotation operator thingy and the Euler's method are actually equivalent if you think a bit.
Anonymous
Multiplying two complex numbers is actually rotating one complex number by the argument of the other
Yeah they are but I just dont like splitting imaginary and real parts artificially, it feels a bit like you already know what the result is and are just trying to get to it
rather than with rotation operators it's more just emergent from the properties of rotating a 2d vector
Imo at least
Anonymous
Imo even comparing certain elements of matrices, is as artificial, if not less :)
How so?
Anonymous
21:35
Matrix multiplication is totally artificial, unless you sit down to think what's actually happening in the background
It should follow naturally that the rotation matrix will be of the same form as any other
eh
I dont think that A-level students need to necessarily understand everything they use
It'd be nice if the syllabus allowed for that but it just doesn't
In fact, when I asked my maths teacher "is integration by parts just a reverse product rule" he said "i dont think so, no"
You just get taught things that you're expected to use for the most part. Or at least it was like that in my School
Anonymous
@Phase Either that guy is an hardcore analyst like 0celo, or ....
I think he was just a mix of "I dont remember that being the case" and "I really [redacted]ing hate you"
He really hated me
Even derided my drawing skills once in a completely unrelated-to-maths setting
22:18
@Phase ahh okay I think I kind of get what you're saying
And matrices are ez iirc
\begin{array}{pmatrix}
Idk dude it took me a while to understand matrix multiplication
Oh you meant in LaTeX
yeah
Lol
Not multiplication that's iccky
I stand by my point and @Blue 's though, to remember the rote method is easy but understanding it is weird
It's like making a composition of functions
Honestly I maintain that if you wanna look ahead into anything for fun, Linear Algebra will be worth your time. I'm headed to bed though, goodnight chum
Ahhh good night... :p I'll have a look into it
22:37
So getting back to my original question
What's out there that's similar to Physx.se where I can ask questions like these? :P
1 hour ago, by Blue
in Problem Solving Strategies, 59 secs ago, by user55789
So I should show that working with that inner product of this operator working on the four-body state should yield an eigenvalue $\frac 94 - \frac32$. I'm not getting that, my solution gives $\frac 94-\frac34$. You would think this is a simple factor 2 mistake somewhere. I could not find it. I simply could not.
What's wrong with physics SE?
I believe my question is not fit to be answered here
27
Q: My question was closed on Phys.SE. Can you recommend me another internet site where my question might be on-topic?

sigoldberg1My question was closed1 on Phys.SE. Can you recommend me another internet site where my question might be on-topic? Here we keep a list of other internet sites that might help students2 of physics. One site per answer. To keep the list at a reasonable size, please only include sites which fulfil...

If it's homework and exercises I believe physics forums have a different policy but idk
@EmilioPisanty I hit the rep cap. With fire and lightning.
Not the worst HNQ, but not my favourite answer ever by far :/
22:53
Thanks I think ToughSTEM is my best bet ("?)
I don't really know any of these sites so I couldn't tell
23:22
JohnRenne is right that I should never try to talk sensible to any crank. I felt like whatever stinging emotion I felt when this crank said:
15 hours ago, by internet-entity
oh well thanks for playing
yesterday, have mixed with my worry today about the interview and create a powerful nightmare last night that I felt like I will die in it should I had believed everything it said
This entrappement nightmare, as I call it, is even more powerful than that groundhog day dream I mentioned earlier. Had I never knew I don't sleep walk in reality, I would have already ingested the poisons of 3 snakes, and possibly died in the dream and in reality (at least that's how it felt)

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