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20:00
which means you'll get a circle
or something like that
Try to fix one of the coordinate and see which conic section time traces
I'm thinking if you look at the metric in each case in some coordinates it'll explain it, but he just said it as if it's obvious from looking at those
You can look up some (A)dS introductions for more details
@Semiclassical sorry was in writing mode
had to compile a reference list
@Semiclassical so the point is that you have $L^2$ functions whose distributional derivatives are also in $L^2$
20:08
and that's enough to ensure that integration by parts works in the expected way
this means that the derivatives are (i) functions (ii) don't grow too rapidly at infinity (iii) don't have deep singularities like $1/x$
@Semiclassical Yeah, the notation $$\int f'\varphi=-\int f\varphi'$$ is sensible for $f\in H^1$ and $\varphi\in C^1_c$
so we've excluded stuff like the step function, which would be a function but whose derivatives wouldn't be.
And then you can give it a norm by $||f||_{H^1}=||f||_{L^2}+||f'||_{L^2}$
@Semiclassical yeah
You can define the step function as an integral like that
But its derivative won't be
i get the idea, i suppose: if i'm doing quantum mechanics, i usually take for granted that the functions are nice enough to do integration by parts
one question: i've seen Sobolev stuff in one source, and it refers to (for instance) a "+1-index Sobolev space" @0celo7
how does that fit into this?
20:46
@Semiclassical The "Sobolev index" could refer to the number $s$ in $H^s(\Omega)$
probably
it's basically the number of derivatives you allow
hmm. so when you said
for $s\in\Bbb N$ it's rather obvious what it means
39 mins ago, by 0celo7
@Semiclassical so the point is that you have $L^2$ functions whose distributional derivatives are also in $L^2$
20:47
for other $s$ it's more tricky
the plural there was on functions, not derivatives
@Semiclassical I meant only the first derivative
But for $\Bbb R^n$ you have $n$ first derivatives
right
I was seeing reference to index $s=+1-\epsilon$, so presumably that requires something more subtle.
20:49
@Semiclassical Yeah you can define those spaces via Fourier transform, interpolation, or Riesz potentials
the source i have in mind was this one, btw: www-users.math.umn.edu/~garrett/m/v/pseudo-cuspforms.pdf
the automorphic stuff is outside my knowledge, but it tells a story about a (failed) proof of the Riemann hypothesis
I see
the negative order Sobolev spaces are often the duals of the positive ones, btw
i wondered.
20:52
by "often" I mean "it depends on the underlying space"
For example, it's true for $\Bbb R^n$ and for compact manifolds without boundary.
that source contains the following sentence: "Indeed, the Dirac delta on a two-dimensional manifold is in Sobolev spaces with index −1 − ε for all ε > 0."
For anything with a boundary, the dual depends on boundary functionals.
@0celo7 that's not what that word means
(=P)
@Semiclassical I read that which prompted my comment.
20:53
Negative order spaces are not function spaces!
They are true distribution spaces
I already got it
@Slereah is it interesting?
Depends on your interest
it has some interesting tidbits on non-Hausdorff manifolds, but not that much
most of it is about non-paracompact manifolds
20:59
yikes
no partition of unity
how is that supposed to work?
I didn't really read those parts, so who knows
Non-paracompact manifolds aren't terribly interesting really
there isn't really a lot of interesting continuous functions on non-paracompact manifolds anyway
Oh no it's a philosophical zombie
Someone is observing some object placed on a far away planet (big planet with a lot of gravity). What can we say about the instantaneous reference frame that object is in?
If i was observing an object in empty space accelerating, i could think of it switching inertial reference frames continuously, given the object was infinitesimal small.
Is there any connection between those two cases?
21:18
today was a humbling one. I had my balls handed to me by an argentinian back-end developer. He dumped some code on me and i had to live code et al. Not fun. At any rate after making me feel like a superior donkey he remotely took over my pc and configured the environment. Now I have to do the rest and some mods. Sexy times. . .
Hi folks, is this the right place to ask a question about trajectories?
Or is there antoher room specifically for that? I didn't find one.
Don't ask to ask, just ask
At any rate going to starbucks for a bit to hang out and build confidence again, then will be slapping code all night like a champ
Alright, well I have to calculate the necessary launching speed from a cannon of a projectile to hit a moving target when it passes infront. The distance to the point is known, the necessary flight time is known, the angle is known, the elevation of the cannon is known.
cows coded any interesting recently?
anything*
21:21
I'm not sure what to do, it seems like any formula I've googled demands a velocity from the start, without which I can't uhh.. find the velocity by "reverse-engineering it"
Jack of Blades, does the target stay in front or does it move?
that's the sort of question i really don't want to speculate without a picture
It moves, but what's important for the ball is to hit a certain spot at a certain time. It's about hitting a windshield with a tennisball of some sort.
The cannon won't move sideways, it's just fixed at a certain angle.
Nor will it turn around.
And it points across the road.
Anonymous
You just need $\vec{r(t)}_{\text{projectile}}=\vec{r(t)}_{\text{canon}}$ at a certain time $t$. Google for "trajectory of projectile"
21:31
Yes, I saw that earlier. I had my old physics textbook up from high school, but I didn't quite understand how to combine the various formulas. I would try this one for example: x = v0 * t * cos( a ), x being the distance to the area it should hit on a flat field, and then I remade it to this: x / (t * cos( a )) = v0
But this gave me irrational results when I entered the known values in there.
x = v0 * t * cos(a) , doesn't x here just get larger over time?
Anonymous
This is a good start: physics.ox.ac.uk/teach/FLAP/FLAP/P2.2.pdf to learn projectile motion
that seems to be the distance the projectile would travel over time without any gravity pulling on it
hence, it would never hit the ground
Anonymous
@pZombie No
Anonymous
That's just the x-coordinate
Anonymous
21:35
It hits the ground when y coordinate becomes 0
right
but that is not the formula to calculate when it hits the ground. Just the formula to calculate how far the object traveled in the x direction
so you need the formula now for how far the object traveled in the y direction
and then apply gravity to it, and see when y = 0
Sorry for the silence, I'm going through the pdf
except, now you are looking for v0... and you have y=0 or whatever height the object is at you are hitting
and you also have x i suppose
Anonymous
@JackOfBlades It's okay. It will take some time to digest that pdf
Anonymous
But after reading it you should be able to solve it
21:42
Yes. And I should maybe mention that the distance the car needs to travel and its speed are calculated and then send a time to the cannon to say "you have to hit that particular spot when this current moment + that given time arrives".
Jack Of Blades, the book you have from high school, does it have a formula for the y component of the trajectory?
Anonymous
@JackOfBlades Yeah, you'll need 3D coordinate geometry to deal with that.
Yes, let me see..
Anonymous
@pZombie Lol. If it doesn't it doesn't contain that formula it doesn't even deserve to be called a physics book =P
y = yo + vyo * t - 0.5 * g * t^2
21:46
there you go
you have y and yo, t and g. And you are looking for v
I'm still going through the link though, not on the clear with what I do with the two of these now. The velocities in the two aren't the same.
vyo is how fast it ascends if I understood it correctly
y should be the height of the projectile depending on how long it flew. Hence depending on t
Anonymous
It's not trivial. You need z-coordinate too.
yo if i understand correctly, should be the height of the cannon, which would be 0 if we assume the cannon to be at zero level.
21:50
so just assume the cannon is at yo=0 to make it easier
then later you can work on the more complicated case :D
I'll give it a go when I finish reading :P thanks
@Blue I think most physics books don't have that formula
Anonymous
@0celo7 What type of physics books do you read...
Anonymous
Even the worst school book I read had it
most intro level physics books will definitely have it
21:53
@Blue General relativity and quantum mechanics, mostly.
Anonymous
@0celo7 ........
i wondered if you were being that obtuse.
Anonymous
Projectile of electrons XD
Anonymous
Or projectile of black holes
Anonymous
21:54
(That's nonsense though)
I was wondering about the photons trapped in a weightless box with ideal mirrors thought experiment.
When you push the box with the photons inside, doesn't the energy of the photons increase?
hence the box gaining more rest mass?
@Semiclassical If you ever have to wonder if I'm being obtuse, don't.
ok, that question didn't work either
how about warp drives then?
the mini version
What about warp drives
i have been told and read that the physics on which warp drives are based on are sound, except that matter with negative mass might be a problem...
but we have casimir cavities which are supposed to be negative energy volumes of space
so cannot we build mini warp drives with casimir cavities just to check if it would allow us to send information back in time?
Anonymous
22:07
Plenty of pop-sci articles on that already I suppose
a warp drive certainly can be used as a time machine, if SR is correct
Anonymous
@pZombie Proof™?
you're not allowed to say that
Blue - it's in the warp drive's specs. Aren't those things supposed to be able to send matter to a space time location faster than light would travel to the same space time location?
Blue - the rest follows from SR directly if you check the math
Basically, accelerate to let's say v=0.5c relative to Alice on earth. Use your warp drive to send something at FTL towards a given space time location. For you it is just FTL, but for Alice it would be even faster... a distance done in negative time
turn around, and repeat the process into the other direction and voila, you arrived before you left
at least that is what SR tells us
now without thinking this fully through, some might be tempted to say that you do not really travel through spacetime when using a warp drive, but it does not really matter. What matters is the spacetime location you arrive at
@Blue See e.g. this answer for how FTL and causality/time machines are related
Anonymous
22:20
@ACuriousMind I get that. I was wondering about the physical plausibility. Also, I think pZombie needs GR for proof and not SR as SR doesn't allow faster than light travel (afaik)
Blue, no, SR is enough
Blue - basically, the very short answer in pictures would be this imgur.com/a/Qs1RK
if warp drives are possible, then what you see in this image would also be possible
and that is according to SR
you arrive 8 seconds before you left in this case
@Blue GR doesn't allow faster than light travel either but you need to be more careful about what "faster than light" means in GR ;)
$v>1$
I left 8 seconds before I arrived. How about that?
Anonymous
@ACuriousMind Yeah, I did read that "Apparent FTL is not excluded by general relativity, however, any apparent FTL physical plausibility is speculative" on Wiki
22:22
@ACuriousMind Can you disclose if SkullPatrol is still with us?
Riddle me that general relativists
@Blue Sure it's speculative, no one has built a warp drive
we don't know that for sure
Anonymous
@BalarkaSen You don't need GR for that. You left and you arrived again after 8 secs :P
it seems to only be an engineering problem to build a mini version of one, if a casimir cavity counts as negative energy region
22:24
@0celo7 What's there to disclose? You can look at his user profile yourself to see whether he's suspended or not (he's not).
the skull has a lot accounts
^
@ACuriousMind He might be using a sock
i don't know why 0celo7 wants that information tho
If no one can conceive how to do it, it's not an engineering problem.
@ACuriousMind Hi. (Finally could find you)
Can you help with the question I sent yesterday?
22:26
Semiclassi - I think there was a recent article about NASA planning to build a mini version of the warp drive
yesterday, by lılostafa
user image
Other components of $F$ are zero.
@0celo7 He might, yes. So?
@ACuriousMind Can you tell me if he is?
Anonymous
@0celo7 Why are you stalking skull?
@0celo7 No, I can't share information gained through moderator-exclusive tools.
22:27
@pZombie [citation-needed]
@Blue I'm not stalking anyone except for you
@ACuriousMind Fine
@lılostafa Ah. I don't really understand what's going on there. Normally, the magnetic field (which I assume is $B$) is related to the field strength as $F_{ij} = \epsilon_{ijk} B^k$ (the sign and the factor of two being normalization issues). I have no idea what the $\lvert B\rvert^3$ factor is doing there.
@ACuriousMind How do I say Euclidean properly?
Oh dear
I think I remember a lengthy conversation also involving Danu about that at the end of which we concluded that the English standard pronounciation is probably closer to the original Greek than the German one.
@ACuriousMind This is a Berry phase calculation for a simple two level system (spin) in a magnetic field. The magnetic field $B$ is the parameter here. We're calculating $A$ (Berry connection) and $F$ (Berry curvature) in the space of the magnetic fields.
22:35
Ahhh, it's not the field strength
Okay then
Berry phase
how I wish I understood thee
It should be a conversion from spherical to cartesian coordinates but I don't know how he gets a $\frac{\mathbf B}{2|\mathbf B|^3}$ (cartesian) from $\sin \theta$ (in spherical coords)!
@Semiclassical it's just bundle crap. Not worth it
@lılostafa I'm not even sure I understand what he means by "Cartesian coordinates" here
@ACuriousMind Is that a sign you've become too abstract?
22:43
I mean, the space of states is just a sphere, the Bloch sphere. There are no "Cartesian coordinates" on a sphere
You're so abstract you don't even know what Cartesian coordinates are :/
@0celo7 No, it means I don't know what "Cartesian coordinates" are supposed to mean when my space is a 2-sphere, not $\mathbb{R}^n$.
The only reason we need GR is because of gravity or mass/energy affecting spacetime itself if you want, right? SR can deal with any acceleration just fine if we neglect the effects mass or energy have on spacetime, right?
@ACuriousMind maybe it's meant in the sense of 3D as the ambient space? kinda silly, though
@ACuriousMind take out a point and stereographically project
22:46
@ACuriousMind Doesn't he mean to treat $(B_x,B_y,B_z)$ as $(x,y,z)$?
and $|B|$ as $r$ in spherical coordinates
but if one can view an accelerating spaceship, which SR can fully account for its behavior, as a spaceship being on the surface of a planet according to the equivalence principle, then why shouldn't SR be able to deal with a spaceship on a planet?
@lılostafa does ij have to be polar coordinates?
not that i have figured out how, but there has to be a way
@DanielSank Is it possible to apply the path integral formalism to quantum computing
@lılostafa I mean Cartesian
22:49
@0celo7 It seems Cartesian
@0celo7 Yes
@Slereah it seems like it should certainly be possible; the question is whether it's useful.
(and I dunno)
Well yes, that is what I'm asking
I am wondering if in the case of quantum computing it might reduce to a sum
at least within some limit
on this note
one thing I'm trying to do in Mathematica lately is time-dependent Schrodinger stuff
all 1D, because I'd prefer not to get a headache
aka the Schrodinger equation
but whenever I try to use NDSolve for that purpose i just get junk :/
22:52
It is pretty hard to get a good answer from Mathematica
Did you add assumptions?
if you cannot simulate it, you either didn't understand it or it is not physics
Usually it's best to add assumptions to Mathematica for solving differential equations
well, NDSolve doesn't use assumptions per se
but I presumably should be doing something with Method
No, but you can add them
Or can you?
I dunno
Assumptions is for simplifying symbolic quantities.
I don't doubt there's something smarter I should do with NDSolve
but I think it's to do with Method and such
Anonymous
22:54
@pZombie That's too strong a statement. Mathematica does have bugs
Blue - i wasn't really referring to the Mathematica issue, but rather made a general statement
@Blue i was expecting some know it all to come forward and tell me that i am wrong
@lılostafa Ah, yes, I managed to confuse myself. Okay, so we have $\sin(\theta) \mathrm{d}\theta \wedge \mathrm{d}\phi$ and need to convert that into Cartesian coordinates. So plugging in $\theta = \arcsin(z/r)$, $\phi = \arctan(y/x)$... (I'll post my result when I have it)
@Blue So in general, would you agree that if one cannot simulate something in a computer, he either did not understand the Physics fully, or it is not Physical at all?
depends on what one means by 'cannot simulate it'
"hasn't figured out how to simulate it" presumably doesn't count
@Semiclassi - yes, that wouldn't count if it is just lack of programming skills
22:59
@ACuriousMind $\arccos (z/r)$?
i also wouldn't count computational resources as a factor, e.g. "if I had X more disk space then I could compute it"
i made a spacetime twin paradox simulation btw. You can watch/download it here youtube.com/watch?v=up6AoUShGBE
and similarly time

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