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17:00
Trying to decide how silly it would be for me to sit in on this talk: math.umn.edu/seminar/automorphic-harmonic-oscillator
It’s for the Automorphic Forms and Number Theory seminar...so that bodes poorly
But automorphic harmonic oscillator sounds neat?
attend it and teach me about it afterwards
:)
lol okay
I may have a leg up on that, actually, compared with most people in physics here
The stuff they do involves Laplace’s equation with domain as the upper half plane
And then you can ask spectral questions like eigenvalues / scattering solutions etc
Same stuff you ask in QM but in a less familiar setting
Of course once they start talking Sobolev spaces I’ll be lost
@JohnRennie One of the (two) eggs that was boiling in water spontaneously burst apart with a rather loud sound!
Since the egg was a symmetric object before the process and lost its symmetry after that, this could classify as an example of spontaneous symmetry breaking in classical systems :P
pretty sure gravity had already broken that symmetry :)
17:19
That looks interesting but I'd say it'll be too abstract and end up being dissappointed :(
on automorphic functions
Is it me, or is there a ton of homework lately?
Anonymous
exam season probably =P
mid-terms or something?
or maybe we just hit the semester in full stride
SEDE kinda agrees
Anonymous
Oct-Nov is usually the exam season in Asian countries. Also March-April
Anonymous
Moreover, most of the traffic comes from Asian countries, so...
Anonymous
17:26
That's just a guess though
@Blue does it actually?
source?
and what do you understand by Asian? Indonesia through Turkey?
not that I don't think it's true, but it's easy to go with the assumptions without checking
Anonymous
@EmilioPisanty So many of the hw questions I see are Indian competitive exam questions
Anonymous
I'm just guessing
@Blue you said traffic though
Anonymous
17:29
@EmilioPisanty Sure. I think the highest number of users are from India and US (as they are English speaking)....followed by Europe
"Poincaré explains how he discovered Fuchsian functions:
For fifteen days I strove to prove that there could not be any functions like those I have since called Fuchsian functions. I was then very ignorant; every day I seated myself at my work table, stayed an hour or two, tried a great number of combinations and reached no results. One evening, contrary to my custom, I drank black coffee and could not sleep. Ideas rose in crowds; I felt them collide until pairs interlocked, so to speak, making a stable combination. By the next morning I had established the existence of a class of Fuchsian
@Blue so.... source?
Sid
Sid
@EmilioPisanty Observations
it's definitely not in the 25k+ analytics
17:30
@Sid what? you've MITM'd all the traffic into SE?
Anonymous
China doesn't use English sites much
@Blue That's completely irrelevant
The question is about traffic to this specific site
Anonymous
@EmilioPisanty I already saying I'm making an educated guess from my daily interaction with this site. Moreover, this site is in English so that's a reasonable guess I think
Sid
Sid
@EmilioPisanty See the homework questions you speak of. And verify, if possible, with their respective nationalities
@Blue well, compare your stats with the ones for SO insights.stackoverflow.com/survey/2017
US tops India by a factor of two
17:33
Ahhh, a function which has the same value at infinitely many points, by the identity principle, must be a constant, hence discontinuous groups of transformations are considered with automorphic functions, old books strike again
@bolbteppa Er? No? Consider $e^z$, which takes the same value at every multiple of $2\pi$, say.
Anonymous
But I haven't seen many US guys asking hw type questions, really. Most of the people whose hw questions I see seem to be from India/Bangladesh/Pakistan/Iran. Obviously some part are also also from Europe and US too.
Anonymous
@EmilioPisanty That's not PSE anyway
identity theorem needs an accumulation point
Right.
17:35
Sorry meant in a neighbourhood of the point (identity principle)
It has to be a non-discrete infinite set
same value at infinitely many points within a neighborhood of a specific point?
Sid
Sid
@EmilioPisanty I can bet my best jeans that the ones for SO and the ones for PSE(Physics) would vary by a lot
@Blue Indeed it's not. Which then leaves us with the fact that the data you linked to is irrelevant and there is as yet no relevant data on evidence.
Seriously. Stop making unfounded guesses.
"There is at least one cow in Scotland, of which one side appears to be brown."
Anonymous
17:37
I already mentioned I'm guessing. I don't see anything wrong with it. If you feel it is totally wrong you can feel free to ignore.
@BalarkaSen cringe
Sid
Sid
@EmilioPisanty Are you sure about that? For one, maybe there are some mod tools that can check HW questions to users?
(Even if those users are deleted or something)
If they agree in a domain on a set of points where the domain contains an accumulation point for the set en.wikipedia.org/wiki/Identity_theorem
Which is what we both said, indeed.
17:39
The old book says it a bit looser in the footnote archive.org/stream/introductiontoth00forduoft#page/37/mode/1up
@Sid Maybe there are. Until any relevant evidence gets brought up in this conversation, there will not have been any relevant evidence brought up in this conversation.
I'm not saying that there are no credible sources of evidence out there.
I'm saying go and find them.
Sid
Sid
Give me 20k rep. I will find them. :P
this conversation is not really going anywhere...
@Sid 20k rep won't give you analytics access (it's 25k) but I can assure you that there is no geographical traffic breakdown in there
@BalarkaSen Postmsome memes
17:44
@0sselo this is a custom meme you might like
Who is going math with emojis?
Hi, everybody.
I just spent two hours wondering how to solve a question 'cause I was pretty sure it was just $\frac{\cos (t)}{\sin (t)}=\tan (t)$ but the answer was 1 which puzzled me... Turns out it's a typo and that $\cos (t)$ was supposed to be $\sin (t)$ (sighs)
18:00
@DanielSank hiya Dan
did you wake up early to see the launch? =P
@EmilioPisanty Nope.
18:15
Compare the complicated way this is stated and explained:
In mathematics, the uniformization theorem says that every simply connected Riemann surface is conformally equivalent to one of the three Riemann surfaces: the open unit disk, the complex plane, or the Riemann sphere. In particular it implies that every Riemann surface admits a Riemannian metric of constant curvature. For compact Riemann surfaces, those with universal cover the unit disk are precisely the hyperbolic surfaces of genus greater than 1, all with non-abelian fundamental group; those with universal cover the complex plane are the Riemann surfaces of genus 1, namely the complex tori or...
@EmilioPisanty yo, how would I typeset this?
to the elementary calculus student explanation here:
Incredible
How do I align the (i) (ii) and (iii) like that?
@0ßelö7 ah
what is it you care about
typesetting
or your sanity?
in \begin{align} you have to use a couple of &'s
18:16
typesetting
@bolbteppa but I don't want it to be in math mode
@0ßelö7 I take it enumerate aligns to the left?
3
Q: Right alignment of description items (similar to default enumerate)

Md Kutubuddin SardarLet us consider the following example : \documentclass[12pt,twoside,a4paper]{book} \usepackage[left=.45in,right=.45in,top=.6in,bottom=.6in,headheight=14.5pt] {geometry} \usepackage{enumerate} \begin{document} Under 'enumerate' environment : \begin{enumerate}[(i)] \item Text \item Text \item Tex...

@EmilioPisanty Ah, I forgot about enumerate. How do I get it to enumerate with Roman numerals?
^ looks like what you want
\text{(1)}& &u_{\alpha} \to u_{\infty} \ &\text{in } H^1, \\
\text{(2)}& &u_{\alpha} \to ...
something like that?
@0ßelö7 \begin{enumerate}[label={(\roman*)}]%[(i)]
probably using enumitem
18:18
@EmilioPisanty trying...
if it's for a single use, though, \item[(i)] is often simpler
error
"option clash for package geometry"
oh c'mon
who the hell puts margins on a TeX.SE code snippet
Why can't wikipedia just say it's the analogue of finding parametric equations for a surface given it's implicit or explicit representation...
those people are aliens
@EmilioPisanty noice
Your font is weaker
18:23
@0ßelö7 congratulations, you now officially care more about typesetting than about your sanity
speaking of, the middle space in a.e. looks too big
also, one of your arrows dropped half its arrowhead on its way in from home
@EmilioPisanty that is on purpose
Terminology question
Half arrow denotes convergence in the weak topology
@0ßelö7 =P the too-big space too?
I dunno. Should the e be more left?
18:28
@0ßelö7 how are you typesetting it?
a.e.
math or text? space or no space?
@Semiclassical yes?
@EmilioPisanty text, no space.
I'm trying to remember what the definition of a node of a wavefunction is; I'm used to the case where you've got a bound eigenstate and the nodes are where the wavefunction vanishes, but is that the actual definition of a node?
@0ßelö7 hmmm. then I guess it should be fine
18:30
To me the nodal set in PDE just means the set where it's zero
Hrm.
yeah, i think that's right; i was misinterpreting something I had computed
18:47
hmm, here's a question I don't know a good answer for
Suppose I have a sequence of polynomials $\{P_n(x)\}$ of degree $n$ each. (I have Hermite polynomials in mind, but I'm not sure how general to be.)
ugh, I think what I'm doing is too general. oh well, proceeding
suppose I take a linear combination $f(x;z) = \sum_{n=0}^m c_n P_n(x)z^n$
let me further specify that the coefficients are real and the polynomials have real coefficients.
when $z=1$, I get $m$ roots in the complex plane; moreover, these roots are all either real or in complex conjugate pairs. let me further suppose they're all in complex conjugate pairs.
I ordered a laser and didn't get a confirmation email
I hope I didn't fall for a laser scam
The oldest trick in the book
if I now smoothly continue $z$ around the unit circle, the roots will move around. But upon returning to $z=1$ I should have the same roots as I started with, so all this is doing is permuting the roots.
what I'm trying decide is if there's any good gauge for whether any of those trajectories cross the real axis.
If something is 'tangent' to the x-axis does this just mean it's $y=0$. I feel like it's an odd thing to say?
it means the tangent line is $y=0$
so if that's what you're asking, then yes
Huh... seems strange to me.
19:09
My copy of the reprint of MTW was delivered today!
This classroom is so cold I'm compiling the kernel and my CPU is only at 40C
Oh is MTW out?
It's not!
Who are you @GPhys
Do you have secret access to the reprint
Okay, here's the question I should've had in mind earlier. If I've got an excited eigenstate of a confining potential, then it has at least one node (as per the node theorem).
my Amazon order was delivered today :)
What's MTW?
19:13
By contrast, if I take a linear combination, it's not hard to get a examples where the wavefunction doesn't have a node.
@BernardoMeurer General Relativity bible
@Semiclassical ur mom has a node suka
oh wait
it is on amazon apparently?
anyways.
19:14
But it also says "Hardcover – October 24, 2017"
I guess the soft cover is out
I got the hardcover
Well, let's try to order it I guess!
I preordered it on Amaazon months ago, and the delivery date has been slowly creeping back since I ordered it
however, if I allow the wavefunction to evolve in time, the examples I was coming up with all end up having a node at some time in the evolutiono.
19:15
Gravitation (Anglais) Relié – 3 octobre 2017
weird
The french and US site show different dates
I'm trying to decide whether or not that's inevitable.
Maybe it's only out in Europe???
for me I can reorder the hardcover and get two day shipping
I live in nyc
then I don't know
Oh well
Let's order it
this hard cover is good quality
I am surprised for the price
19:16
I'm just too used to getting totally ripped on textbook printing quality I guess
@GPhys the real truth is that physics books are way overprice and could be sold at basically a tenth of the price!
It is ordered
I now own MTW and I didn't even have to pay $400 for a used copy
hurray
19:33
today's purchase were all science baby
Breadboarding kit, laser and MTW
Tried getting an oscilloscope but they are expensive
19:49
What's always confused me is the one's where paperback is 3x the hardback price?
@GPhys pics or you're a dirty liar
175
A: How to silence the voice that tells you you're being financially irresponsible by spending 4 to 6 years doing a PhD?

Federico PoloniWhen you go to the industry, how do you silence the voice that tells you you could be spending your time advancing the knowledge of humanity, rather than devising new ways to make people look at an internet ad, or helping big stock exchange companies aimlessly move money from account A to account...

This answer has a total vote of +175, but there's a comment under it that says $-1$, with a score of +164! Does anyone have +1k rep in AcademiaSE to see the vote count?
This amazon.com/Molecular-Biology-Cell-Bruce-Alberts/dp/0815344325 or hardcover Peskin or Cosmology is one of the best books to just possess
Peskin is a meme
BBS is a great book to own
perfect size to put a computer on
@lılostafa +204-29
In my experience a lot of people will uptick a comment that mentioned voting without casting such a vote. For both + and - votes.
20:00
@dmckee I was stupid and didn't sync my TeX correctly and now github is freaking out
how do I resolve this crap
Personally I discourage people for explicitly mentioning votes in comments at all. It basically doesn't serve any purpose.
2
@dmckee the damage is already done
@0ßelö7 Then read the hover-over text. And ask around until you find someone who's friend actually understands the underlying model.
@dmckee I clicked some buttons and it seems to work now
@0ßelö7 All problems with list environments should be tackled with enumitem before doing anything else. It's nearly magic.
20:05
@dmckee interesting... under %20 of them have actually downvoted it (assuming all of the downvoters have upvoted that comment)
@dmckee ^ what I did
Nice. That syntax is suggests to me that you have enumitem.
@lılostafa OK. I admit it. So I have a mancrush on that cartoon.
@dmckee No, Emilio's link said to use the package enumerate.
@0ßelö7 Oh. Well, enumerate is deprecated by enumitem which does all that the earlier package does and more.
20:10
Git has its own logic. My coworkers typically prefer the rm -rf, git clone method to solve its problems.
I use github desktop
Apparently the laser shop I ordered from is in China
I hoping I wasn't bamboozled by a chinese laser swindle
@Slereah should I get MTW?
y tho
isn't it a meme?
20:19
it's a big heap of GR stuff
Not very well organized but there's a lot of nice content
@BernardoMeurer If I want to hook up my laptop to the server like I did my desktop, do I do the same thing?
or do I have to merge the things in a nontrivial way?
just do conflict resolution
20:51
Hm
Once i get the laser
What else do I need for a basic interferometer
Some mirrors
lenses mb
one of them transparent mirror
half-silvered mirror
Jesus it's expensive
How did Michaelson and Morley do it?
ebay has some cheap ones
@Slereah are you trying to find the aether?
yeah, that sort of stuff
home experiments
for fun
Hey, université de Nantes
i wonder if I know him
oh, he's in the math department
Odds are low
21:08
I got the second one
it has a summary of the global stability proof
Alas I blew my money on lasers right now
And MTW
And some electronics
No cash for more GR
I need to wait for some money before I buy MTW
when will u buy the lasers though
then we can conquer the world
@Slereah let's make a wormhole bomb
Did I ever show you that Eric Davis paper
Where he proposes using a nuke for a wormhole
That guy's insane
Although...
The lecture mentions the paper
but I've never found it
21:14
it was probably classified
E. W. Davis, 1997 : Generate wormhole-inducing ultrahigh-intensity magnetic field (borderline exotic) by nuclear magnetic-compression explosion
He does work for the US Airforce
It's not impossible it's just a crazy proposal he sent to his superiors
borderline exotic lol
'The author (Davis, 1998, 1999, 2004) proposes using nuclear explosion magnetic compression or ultrahigh-intensity tabletop lasers to explore the possibility of creating a wormhole in the lab."
@0ßelö7 That's fancy talk for $T_{\mu\nu} k^\mu k^\nu = 0$
Apparently the proposal might be in Davis, E. W. (1998), “Interstellar Travel by Means of Wormhole Induction Propulsion (WHIP),” in Proc. of the 15th Symposium on Space Nuclear Power and Propulsion, AIP Conference Proceedings 420, ed. M. S. El-Genk, AIP Press, pp. 1502-1508
Let's see
6 pages?
Hm, can't seem to access it
sci hub is acting weird
let's try a mirror
nope
Can you access it?
21:21
scihub is blocked by the university
I found this power point
Hey other people of the room who are not @0ßelö7
Does anyone have access to aip.scitation.org/doi/abs/10.1063/1.54779
@Slereah that looks like a crank pdf
Well it is Eric Davis
He has questionable research things
But I want to read a paper about using nuclear explosions for wormholes
although that is not even the weirdest topic he has written on
He has written about PSYCHIC TELEPORTATION
He mentions a chinese experiment about psychic chinamen using their mind powers to teleport objects
oh no
the worst argument
Yvonne pulls this crap too
You have something like $$\frac{dr}{dt}=-\int_M (R-s)^2\, d\mu$$
you need to show that it $\to 0$ at $\infty$
21:36
The paper is apparently
Kongzhi, S., Xianggao, L. and Liangzhong, Z. (1990), “Research into Paranormal Ability to Break Through Spatial Barriers,” Chinese J. Somatic Sci., First Issue, 22 [translated into English by the Defense Intelligence Agency]
So you integrate and get $$r(\infty)-r(0)=-\int_0^\infty \int_M (R-s)^2\, d\mu\, dt<\infty$$
so your options are: the integrand goes to 0 at infinity or it has no limit
He says that the experiments were very repeatable but apparently only chinese labs did it, which make me fairly suspiscious of chinese wizardry
but you prove it has a limit, so it must be zero
it's really stupid
the paper, apparently
man look at that photo quality
cia.gov
my god
21:40
where else do u get your papers on CHINESE MIND WIZARDS
"this article uses strict scientific procedures"
ah government science
Davis says that this was all very proper science and all but apparently he did not theorize the possibility that maybe it's the scientists involved making shit up
In some kind of science swindle
"During the process of these experiments we were aided by chairman Zhang Zhenhuan and comrade Qian Xuelin."
Ah, still before China cooled it with communism
Also of note
This is 1990
Why do they still have 1950's photo quality
What kind of lab do they run
can't they import a Kodak from America
I have a clusterf*** of a last night dream: Imagine that, a Groundhog day style dream where it repeats more than 6 times and you try so hard to wake up!
@dmckee @EmilioPisanty Damn!
the ams proof environment doesn't like enumerate
the box gets kicked to a new line
22:03
@Secret you're from China, no
Tell us about your mind powers
Will in a sec, when ready I will post a blog link to that dream
I am currently speedloging it down
wow the price of all the used copies of mtw on Amazon have already dropped dramatically
:|
a lot of amazon sellers use softwares to set prices
So if there's a lot of cheap MTW
They have to drop it too
Supply and demand
Yes iirc there was a bug in one of the programs that caused the program to war with itself and caused a bunch of products to get their price down to one penny
Or sometimes causes them to go up to thousands of dollars
22:18
I want to know who these academics are that pay 300 for math books
I think prices are mostly set so that the university has to buy them
22:36
@Slereah want to compute some functional derivatives?
Do I?
I mean you can show it
But it's 00:30
actually it might be in besse
@DavidZ Consider this question and the answers therein. Could you please explain how that is more on-topic than the one we are discussing about? And how the answers therein are not in the direction of giving away the solution? And as I said, could you please explain why you deleted my second comment, which suggested an improvement in the solution already given by the OP?
@Slereah I want to compute the derivative of $$F(g)=\frac{1}{(\mathrm{vol}\,g)^k}\int_M R\, d\mu$$
but subject to a conformal constraint
I need to make sure I have the right functional for the gradient flow
So $$\frac{\int R \sqrt{-g} d^nx}{\int R (\sqrt{-g})^k d^nx}$$
22:43
...no
$$\frac{\int R\sqrt g\, dx}{(\int\sqrt{g}\,dx)^k}$$
No?
Oh
Is the rule on divisions for functional derivatives the same as derivatives?
functional derivatives are just Gateaux
so yes
but one has to be careful with the constraint
what's the constraint
the variation should be $s\mapsto e^{u(s)}g$
and $u(0)\equiv 0$
22:46
this is a long calculuation
yeah
sounds like it
wish me luck...
break a leg
$$E'=-\int G^{ij}\delta g_{ij}$$
where $E$ is the EH action
@Slereah this calculation is something every GR person should do once a year
I still haven't done the EH one even
I should do it
22:53
there are many proofs
Hi, everybody.

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