The h Bar

0ßelö7

00:46

@Jasper ...2?

Jasper

@0ßelö7 Well, I count that as 3, lol.

Bernardo Meurer

@Jasper You're aware a monitor doesn't constitute a computer, right?

Jasper

@BernardoMeurer Yes, I think we need to count the CPU, lol.

Bernardo Meurer

No, you can have a workstation with 2 CPUs and it's still one computer

Jasper

Oh, this gets interesting.

So how do we really count the number? lol

Bernardo Meurer

00:59

I think counting motherboards is easy

But even that can not be true

One can argue that a supercomputer is one computer, although it has hundreds of distinct separate motherboards and CPUs

Jasper

Hmm, the plot thickens.

So do you have a good definition then for the number we seek?

Bernardo Meurer

I'd say a computer is a set of hardware that performs computations with some degree on unity

Hmm and you probably need to add come constraints for that to make sense

Jasper

I see.

Anyway, I am going to sleep, so I will see you guys in my dreams, lol.

Anonymous

01:36

@0ßelö7 Sounds like a brilliant idea to warm your feet and kill your PC. Two birds with one stone. :P

0ßelö7

02:14

@Phase yes

for a certain interpretation of all of those words, somewhat

@BernardoMeurer $\oplus$

BAYMAX

04:10

Hi! actually we have $\frac{v}{c } << 1$ and have to prove $K << m_{0}c^2$,tried asking in maths chat room perhaps I should try here

John Rennie

04:26

@0ßelö7 You joke, but I used to use my server for ripening fruit. Even in winter if I put the fruit bowl on top of the server it would keep the fruit warm enough to ripen it in a few days.

Sadly, a couple of years ago I bought a newer more efficient server and it doesn't produce enough heat to ripen the fruit. Though on the plus side it did halve my electricity bills :-)

@BAYMAX what is $K$?

user228700

Hi, everyone! :-)

BAYMAX

Sorry I forgot to mention, $K$ is Kinetic energy of the moving particle, so we have to prove that when $\frac{v}{c}<<1$ then Kinetic energy o the moving particle is $<< m_{0}c^2$ @JohnRennie

user228700

My name is Kaumudi and I am screwed for my Physics exam is tomorrow and I understand horse crap! ::Whistles::

Leaky Nun

@Kaumudi.H hi

if you remember me

user228700

Oh, huh, I'm sorry, I'm afraid I can't seem to... :-/

Anonymous

04:31

@Kaumudi.H Dump physics. You're going to be a neuroscientist :P

user228700

Oh! Hi! :-) You've a new profile!

Leaky Nun

@Blue delete :)

user228700

@Blue Sadly, I must pass :-(

John Rennie

@Kaumudi.H: Morning. As it happens I know lots about horse crap since I used to work at a stables when I was a teenager.

user228700

Very funny indeed.

Balarka Sen

04:33

physics schmysics

John Rennie

It's true. I was a keen rider in those days.

0ßelö7

@JohnRennie AHA

So it was a horse, not a sheep

John Rennie

Horses are too tall. You'd have to stand on a stool.

user228700

Wow.

0ßelö7

JRHNBR

I know you know what that means @JohnRennie

Bernardo Meurer

04:34

Heya

@0ßelö7 lol

user228700

Yellow! :-)

Balarka Sen

did you mean yolo

user228700

@JohnRennie Wow, this I didn't know!

user228700

@BalarkaSen No, that is a variant of "Hello" :-P

Balarka Sen

rhetorical question

user228700

04:36

And now I must go out to buy food, even though I am running short on time. So, so, screwed. ::Whistles as she runs out in a panic::

John Rennie

@0ßelö7 actually I don't. JR Has No B- R- ??

user228700

@BalarkaSen Ah. Sorry :-P

Balarka Sen

"it's just a prank bro"

0ßelö7

@JohnRennie just the right height, no bucked required

John Rennie

Ah :-)

Oh my, now I wish I hadn't Googled that!!

@BAYMAX isn't that pretty trivial to prove?

BAYMAX

04:41

I forgot , it has been long since I was in touch with relativity@JohnRennie , any link or help?

John Rennie

Well start with the expression for the total energy: $$E^2 = p^2c^2 + m^2c^4 $$

Where $p$ is the relativistic momentum $p = \gamma m v$

BAYMAX

I see

John Rennie

Write the expression for $E$ and expand the square root using the binomial theorem.

You'll end up with $$E = mc^2 + O(\frac{v}{c})$$

In fact I'm pretty certain I did this in an answer on the site, though searching for it is going to be tricky

BAYMAX

$E^2 = m^2c^2 (\frac{v^2}{1 - \frac{v^2}{c^2}} + c^2)$

$E^2 = m^2c^2(v^2(1+\frac{v^2}{c^2}+\frac{v^4}{c^4}+... )+ c^2)$

$E^2 \approx m^2c^2v^2 + m^2c^4$

$E^2 \approx m^2 c^2(v^2 + c^2)$

$E^2 \approx m^2 c^4 (1 + \frac{v^2}{c^2})$

$E^2 \approx m_{0}^2 c^4 (1 + \frac{v^2}{c^2})$

$(m = m_0{})$

@JohnRennie

John Rennie

That looks fine. When you square root both sides the $(1+v^2/c^2)^{1/2}$ expands to $1 + \tfrac{1}{2}v^2/c^2$

You could have done it more directly. Write $$E^2 = m^2c^4\left(1 + \frac{v^2}{c^2 - v^2}\right)$$ and square root both sides then expand and you get the result in one step.

user228700

04:59

@JohnRennie Same :-(

John Rennie

The Internet can be a scary place :-)

user228700

Indeed.

user228700

It rained exactly when I went out, BTW, and I got wet :-( Ah, my luck!

John Rennie

Is the physics exam really that intimidating? You seemed to pick up the DSHO stuff faster than I could type it so I wonder if the outlook is as bad as you fear ...

Balarka Sen

oh i remember jrhnbr lol

took some time, that one

John Rennie

05:02

@Kaumudi.H my mother used to say You're not soluble. You won't dissolve. :-)

user228700

Hang on, eating.

John Rennie

At least the rain is warm in Kerala!!

@Kaumudi.H Bread? Nutella? Your room mate?

2

user228700

x'D

user228700

Two pieces of cake (w/ nutella) and a veg. sandwich!

BAYMAX

So $K = E_{0} - m_{0}c^2 =m_{0}c^2 \frac{v^2}{2c^2}$

$K << m_{0}c^2$

@JohnRennie

John Rennie

05:08

@BAYMAX Yes, that looks fine.

BAYMAX

Nice! thank you @JohnRennie

David Z

hi @rob

rob

@DavidZ Greetings. How's things?

David Z

Good, still busy... thankfully I concluded an apartment search today

rob

@DavidZ Moving?

David Z

05:14

Yeah, or I guess already moved, for the most part - the apartment search was the last big thing hanging over my head

i.e. I collected the keys and got access to the place today

rob

Best of luck to you in your new place, then.

user228700

@JohnR: That was a surprisingly nice meal!

David Z

@rob thanks. It looks really nice

rob

Will you invite hbar over for a housewarming party?

John Rennie

@Kaumudi.H You ate cake with Nutella and you're surprised it tasted good? :-)

though I might have added cream for the ultra orgiastic experience ...

David Z

05:17

@rob hehe I don't think we'd all fit... unless you mean virtually, in which case there's no internet access yet (but that'll be easy)

John Rennie

As for the veg sandwich, I suppose these things have to be done :-)

user228700

The "sandwich" was definitely worth its money! 9 pieces of fried cauliflower, a smidge of cheese and lettuce stuffed between two pieces of sweet hot dog buns! 20 rupees!

user228700

@JohnRennie :-P

David Z

@JohnRennie "orgiastic"?

Never heard that one before

John Rennie

Of or pertaining to orgies

Really? You didn't know that? Don't you go to orgies? :-)

user228700

05:19

I've decided to forgo lunch at the canteen and buy that sandwich on some days!

John Rennie

Academia has gone downhill since my day!

Actually the sandwich does sound good.

David Z

@JohnRennie I'm surprised you have to ask

lol

user228700

@JohnRennie YES!

Leaky Nun

Jan 8 at 7:39, by DHMO

I first saw this problem on the Google Labs Aptitude Test. A professor and I filled a blackboard without getting anywhere. Have fun.

0ßelö7

@JohnRennie really?

Can you please be decent. There are children here

rob

05:21

@LeakyNun True story: that cartoon was published a day after my PhD advisor and I had wasted an hour thinking about exactly that problem

user228700

I had a filling main course and more than enough dessert for Rs. 40! That's less than 1 dollar!

John Rennie

@LeakyNun if you're trying to conceal the fact you're DHMO that was a bit of a give-away. And with two mods in the room! :-)

Leaky Nun

@JohnRennie :c

David Z

@0ßelö7 oh. Yeah, I forgot, I replied because that message kind of stuck out to me.

user228700

@0ßelö7 Who, who are these children of which you speak?

John Rennie

05:22

@Kaumudi.H me! Mental age counts!

0ßelö7

@Kaumudi.H you

user228700

@0ßelö7 And you?

0ßelö7

Nope

I pay taxes

user228700

Well, I'm 18.

rob

@0ßelö7 My children pay taxes.

user228700

05:23

@JohnRennie :-)

0ßelö7

@rob you must be very proud

rob

"Daddy tax": one bite of whatever you're eating, especially dessert

John Rennie

Everyone is liable to tax. It's just that children don't usually have a high income.

rob

Early protest: "no, not a single Daddy tack"

Leaky Nun

@rob an hour :o

user228700

05:24

@JohnRennie It is, it is quite intimidating. I have 8 hours to go and 20 topics to cover. Screwed is an understatement, really.

0ßelö7

@DavidZ wot?

David Z

@0ßelö7 I'm needling John about talking about orgies in the chat

(or related things)

John Rennie

@Kaumudi.H well everyone will be in the same boat.

user228700

x'D Yes, that is true.

0ßelö7

I don't get what you're remembering

user228700

05:25

Alright, then, I'm off to tackle 'em all! (I will lurk. All day long)

John Rennie

What have you got to cover?

Everything except the DSHO presumably?

user228700

Nope, no, even that!

user228700

I don't think that I will be awarded marks if I go about it in ways other than the specific method mentioned in the textbook.

0ßelö7

@Kaumudi.H laaaaame

user228700

Yeah.

0ßelö7

05:28

Seriously, what is with your school's middle school mentality

You need to put these professors on the spot

user228700

@0ßelö7 The profs. correcting our papers won't be from the same dept. and will be using an answer key specific to the reference textbooks.

0ßelö7

@rob Yuri knows I don't pay attention in his class

user228700

@JohnRennie I'd upload a picture of my list but it would take too long :-(

0ßelö7

@rob he scowls at me when he hands me the attendance sheet

Bernardo Meurer

@JohnRennie I'm having Linux problems

user228700

05:30

@JohnR: If you eventually hear pings from Hangouts, that would be a picture of the list.

0ßelö7

@Kaumudi.H from the textbook? Oh dear...

user228700

And now, I really must do something about my situation!

rob

@0ßelö7 That's nothing, I'm not even paying attention in chat.

John Rennie

@BernardoMeurer either use disinfectant and a wire brush or install Windows. Whichever is least painful.

rob

I'm posting from the world's least comfortable chair

John Rennie

05:31

@Kaumudi.H I'll keep an ear open ...

0ßelö7

@rob why are you in an uncomfortable chair?

Bernardo Meurer

@JohnRennie Pretty sure colonoscopy is better than installing Windows

0ßelö7

Windows is great

John Rennie

@BernardoMeurer I have only ever experienced one of those two :-)

0ßelö7

@JohnRennie is a colonoscopy not standard procedure in the U.K. when one is your age?

rob

05:33

@0ßelö7 Hospital recliner. My wife had a complicated hysterectomy Friday. Probably two more nights here.

John Rennie

@0ßelö7 That's a good question, and I have to concede it shows one of the pitfalls of a (cash strapped) national health system.

Bernardo Meurer

@rob Oh no, how is she?

0ßelö7

@JohnRennie +1 for anarcho capitalism

@rob yikes, sorry to hear that

rob

@BernardoMeurer Improving, thanks.

John Rennie

@0ßelö7 In theory routine colonoscopies at age 50 would save lives because it would spot early signs of cancer. In practice the NHS simply can't afford to do it.

0ßelö7

05:35

@JohnRennie yeah, and you're a couple decades beyond that :/

John Rennie

Though you would get a (free) examination if there were any reason to suspect you might be at risk of colon cancer.

And of course I could pay a private clinic if I were worried about it (which I'm not).

Anonymous

@Kaumudi.H Wut...

Anonymous

Answer key?

John Rennie

@0ßelö7 :-) Not quite!

Anonymous

Is it an MCQ test?

0ßelö7

05:37

I would offer my services for free but the plane ticket would be unfree

Bernardo Meurer

@rob My prayers would be with her if I prayed, which is why I have already texted my grandmother asking for prayers!

0ßelö7

@Blue serious question, do Indians love acronyms and abbreviations?

Anonymous

@0ßelö7 By "service" you mean colonoscopy ? :P

rob

@BernardoMeurer That's very kind. Thanks.

Anonymous

@0ßelö7 ofdd

0ßelö7

05:38

@Blue come again?

Bernardo Meurer

@rob Hope she recovers well :)

0ßelö7

@Blue I mean whatever @JohnRennie wants me to do 😇

Anonymous

@0ßelö7 of course dey do (dey not only luv abbvn's bt also wrng spllngs)

0ßelö7

Gotta sleep, cheers

@Blue you're an awful troll

Anonymous

@0ßelö7 I'm just following your foot-steps, master.

Anonymous

05:40

;)

Anonymous

@0ßelö7 Goodnight

John Rennie

@0ßelö7 I would get suspended for posting the obvious response to that :-)

user228700

Wokay, I return with a very important question I need answered to move on in this chapter! Do help if possible _/\_

Anonymous

Go on

user228700

::Uploading photo::

user228700

05:54

user228700

Praise the Lord!

user228700

Right, my question is this: I derived the path length to be $2\mu t\cos r$ in another case, in which the two glass plates were parallel.

user228700

I don't understand why the same may be used here.

Anonymous

Basically one part of the incident beam travels an extra optical path of $2\mu t \cos(r)$

user228700

Right, how?

John Rennie

06:01

What is $r$?

Anonymous

@Kaumudi.H What happens when a light beam is incident on upper surface of film shaped wedge wedge?

user228700

@JohnRennie $r$ is the angle of refraction.

Anonymous

A part of it gets reflected and a part of it gets transmitted. Right?

user228700

@Blue Well, some of it bounces back and the rest refracts through to the other medium.

user228700

Right.

John Rennie

06:02

Aha! And we're assuming refraction can be ignored since the light is approximately normal.

user228700

Approximately normal?!

John Rennie

So on effect it's like two parallel plates with normal incidence.

@Kaumudi.H $\theta$ is small.

user228700

@JohnRennie I don't understand this.

Anonymous

The part which gets transmitted again reflects partly from the bottom surface again.

John Rennie

@Kaumudi.H $i = \theta$. Yes?

Anonymous

06:04

When light travels from optically rarer medium to denser it has a path of $\lambda/2$ added to it

John Rennie

($i$ = angle of incidence)

user228700

@Blue: Dude, I understand the workings of it, what I don't understand are the assumptions made.

Anonymous

@Kaumudi.H JR mentioned the assumption

user228700

And the Math.

user228700

@Blue Right, I don't understand it. Hang on.

John Rennie

06:05

1 min ago, by John Rennie

@Kaumudi.H $i = \theta$. Yes?

Anonymous

If you want we can derive it without making any assumptions. But you'll get a slightly different formula.

user228700

@JohnRennie Yep! (Sorry about the delay)

John Rennie

@Kaumudi.H And $\theta$ is small so $i$ is small. And if $i$ is small then $r$ is also small.

user228700

Right.

John Rennie

And if $r$ is small then $\cos r \approx 1$.

user228700

06:09

Right, and we use the formula I derived for a glass slab because..?

John Rennie

The point is that in the limit of $\theta \to 0$ you get parallel plates. If $\theta$ is small then you get nearly parallel plates so the parallel plate formula still approximately applies.

user228700

Hmm, but I didn't derive that formula for a pair of parallel plates; that was a glass slab!

user228700

No air in b/w, you see.

John Rennie

Oops, parallel surfaces ...

user228700

Right, but my point still holds; those two setups are different from each other in that there is air in b/w but we're still using the same formula derived for one of them for both!

John Rennie

06:11

If the thickness of a film is $t$ the path length is $\mu t$ and for light that crosses the film twice it's $2\mu t$.

With two parallel plates the formula is the same but $\mu=1$ because the air between the plates has refractive index equal to one.

user228700

@JohnRennie OK, you're generalizing it, nice. Where's the $\cos r$ coming from, then?

user228700

Ah.

John Rennie

@Kaumudi.H I'd have to draw a diagram, which I don't have time to do since I have to start work, but since the light isn't normally incident on the top plate there will be some refraction. We're just saying that the effect of the refraction is too small to worry about.

user228700

No, yes, I understand it now!!

user228700

THANKS, guys! _/\_

user228700

06:15

Ah, if only my teacher knew half the things you do.

user228700

OK, I have one more question: the light ray reflected at the top glass plate, it too has a path difference of $\lambda/2$, no?

user228700

(Since it is being reflected at the glass surface, which is optically denser than its own medium, air)

John Rennie

It isn't a glass plate remember, it's a solid glass wedge.

Anonymous

@Kaumudi.H Yes, there are many intricacies here which your book skipped. We neglect the reflection from top surface of upper plate. (Experimental reason: Reflection coefficient for that surface is low and also that upper plate is very thin)

Anonymous

@JohnRennie It's an air wedge

Anonymous

06:27

It's written on the heading

John Rennie

The top reflection is off a air-glass interface and the bottom off a glass-air interface.

Ah, OK.

Anonymous

In reality it should like this ^

John Rennie

I guess the glass plates are assumed to be infinitely thin i.e. thin compared to the wedge dimensions so they can be ignored.

user228700

@Blue YES!

Anonymous

06:29

We are considering thin air wedge, so for interference we consider reflection from bottom of top plate and top of bottom plate only.

Anonymous

Also, the reason of reflection coefficient which I mentioned above

user228700

@Blue Wait...what?

user228700

Oh, wow.

John Rennie

It isn't an air wedge - despite the section title.

Anonymous

Basically we consider only that interference which consists of reflected rays of maximum intensity.

Anonymous

06:31

@JohnRennie Lol. Her book is crap :P

user228700

@Blue Yes, it is in my destiny to always be prescribed terrible books.

user228700

@Blue Wow, right, I understand.

Anonymous

@Kaumudi.H I usually don't buy the books which my professors recommend till I feel that they are good enough.

Anonymous

You should try learning from MOOCs and PDF books online too. If you feel that a certain book is good enough only then you should buy it.

user228700

Ah, but like I said:

user228700

06:35

1 hour ago, by Kaumudi. H

@0ßelö7 The profs. correcting our papers won't be from the same dept. and will be using an answer key specific to the reference textbooks.

Anonymous

@Kaumudi.H My god....

Anonymous

I have no words :P

Anonymous

They treat you like school children!

user228700

@Blue Me neither. Just a ball of anger and disappointment deep inside my soul.

Balarka Sen

well definitely just suicide that

user228700

06:40

@BalarkaSen Huh?

Anonymous

@Kaumudi.H Flee from India after your UG is over. Lol. :P

Anonymous

Higher education is screwed here

user228700

^ That is the plan.

Anonymous

Only IISc, TIFR and a handful of other places are doing good research nowadays

user228700

True. There is a C.N dept. in only two good colleges (IISc and IIT Kanpur, I think) here and even there, I doubt if active research is taking place.

user228700

06:47

OK, I have another question. One of the applications of this setup is to check the planeness of a surface.

user228700

This is the paragraph describing how this is done:

user228700

> It is characterised by a particular value of $n$ (in the formula for constructive interference, $2t=(2n-1)\lambda/2$) and hence follows those parts of them film where $t$ is a constant

user228700

I have absolutely no clue what this is s'posed to mean.

Anonymous

Optical flat

An optical flat is an optical-grade piece of glass lapped and polished to be extremely flat on one or both sides, usually within a few tens of nanometres (billionths of a meter). They are used with a monochromatic light to determine the flatness (surface accuracy) of other surfaces, whether optical, metallic, ceramic, or otherwise, by interference. When an optical flat is placed on another surface and illuminated, the light waves reflect off both the bottom surface of the flat and the surface it is resting on. This causes a phenomenon similar to thin-film interference. The reflected waves interfere...

Anonymous

07:02

Also: what-when-how.com/metrology/…

user228700

Wtf...

user228700

Wow, thanks, man, but I was only wondering what that particular sentence meant ::sheepish smile::

Anonymous

@Kaumudi.H Did you understand the concept behind optical flat?

Anonymous

The sentence is written badly

user228700

@Blue No, but I'm not prepared to spend 15 minutes understanding it :-( I cannot, for I don't have the time!

user228700

07:06

I was wondering about that particular sentence alone...

Anonymous

For certain value of $n$, you get a $t$. If $t$ is constant...

Anonymous

$t$ refers to the distance between plates

user228700

Right. If it's constant..?

Anonymous

@Kaumudi.H You get a constant path difference :P

Anonymous

$2\mu t +\lambda/2$

user228700

07:11

And this is relevant because..?

Anonymous

@Kaumudi.H We are measuring the flatness of surface...for a flat surface $t$ would have to be constant...

user228700

Ah. ::Head-desk:: Thanks!

Anonymous

07:26

@Kaumudi.H What chapters do you have for the exam?

user228700

A bunch of optics and oscillations.

Anonymous

I see. Good luck. Shouldn't be too tough. :)

user228700

Oh, derivations in Oscillations are too much and my textbook is crappy. The exam won't be tough, learning will be.

user228700

Thanks :-)

user228700

08:27

@JohnR: Are you around?

user228700

Dang, you're not :-( Is anybody around?

Anonymous

Is your book being crappy again?

Anonymous

:P

user228700

:-P Well, no, I suspect that my brain is.

Anonymous

Okay?

user228700

08:30

For the equation ${\alpha}^2+2k\alpha+{{\omega}_o}^2=0$, two values of $\alpha$ arise.

Anonymous

Yes

Anonymous

So?

user228700

The goal is to substitute the value of $\alpha$ in $x=Ae^{\alpha t}$

Anonymous

Okay

Anonymous

What's the problem?

John Rennie

08:32

@Kaumudi.H this is the DSHO again. Yes?

user228700

My textbook has done it like this: $x=A_1e^{{\alpha}_1t}+A_2e^{{\alpha}_2t}$

user228700

@JohnRennie AH, you're here! Yes, yes it is :-/

Anonymous

Linear combination of solutions to a DE is also a solution to the DE. Probably that's what they mean.

user228700

Where ${\alpha}_1$ and ${\alpha}_2$ are the two solutions to the equation I said before.

user228700

I don't understand how they were able to write this.

John Rennie

08:33

The solution gives us an eqaution like $$x(t) = exp(-kt \pm i\omega t)$$

Anonymous

Anyhow, I need to go for lunch. JR will be able to help you out surely.

user228700

@Blue OK, thanks :-) Bye!

user228700

@JohnRennie Right, I remember.

John Rennie

Where $k$ and $\omega$ come out of the solution to the quadratic.

user228700

Yep.

user228700

08:34

What I don't understand is how they were able to substitute the value of $\alpha$ like that.

John Rennie

And in a differential equation any sum of solutions is also a solution.

user228700

> Any sum of solutions is also a solution

user228700

Huh.

Leaky Nun

the solutions form a vector space

closed under addition

user228700

I have no idea what that means.

user228700

08:36

Oh, it's alright, I s'pose I will take it as it is and move ahead :-/

John Rennie

Differential operators are linear, so $d^2/dt^2(a(t) \pm b(t)) = d^2/dt^2(a(t)) \pm d^2/dt^2(b(t))$

Leaky Nun

since y -> y'' + 2ky' + ω0^2y is a linear operator

sniped

@Kaumudi.H I'm intentionally throwing terms lol, ignore them

(x+y)'' + a(x+y)' + b(x+y) = x''+ax'+bx + y''+ay'+by

so if x and y satisfy the differential equation, so would x+y

user228700

@JohnRennie Ah, hmm.

user228700

I s'pose I understand it a little bit. It's OK, I will move on.

user228700

Thank you :-)

John Rennie

08:38

OK. Shout if you want to come back to it.

user228700

@JohnRennie I will :-) Or other stuff. There's lots of stuff :-P

John Rennie

@Kaumudi.H Ping me on Hangouts as I may not have the chat open

user228700

Wokay!

Balarka Sen

08:50

@JohnRennie Well, if it's a linear DE! Which the equation in question is...

user228700

09:21

4 page derivation. Friggin' hell.

user228700

Someone give me a medal.

Anonymous

@BalarkaSen can give you a meme instead

user228700

Lol.

user228700

Lunchtime! Bread and nutella. Sigh...

Balarka Sen

K is a normie though so maybe she'd prefer normie memes

Anonymous

09:25

I'm in between normie and hipster. Is there a name for me?

Balarka Sen

yes. proprietary malware

Anonymous

Malware is fine. I'm not proprietary. :'D

Avantgarde

bread and nutella for lunch?

Balarka Sen

jesus christ. what kind of oddballs ship restaurants

ACuriousMind

09:41

42 things in the close queue again

In the 10 hours this UTC day has had, only a single review has happened. This isn't good

Balarka Sen

@0ßelö7 @BernardoMeurer This is beautiful

John Rennie

@ACuriousMind gimme a break! With fixing servers and K's revision I haven't stopped since 5 a.m.!

I'll do it now ...

ACuriousMind

@JohnRennie How dare you do your job instead of reviewing things on the site!

John Rennie

:-)

But first, someone is wrong on the Internet (specifically the PSE) :-)

Anonymous

@ACuriousMind An AI should be able to complete reviewing stuff in nano-seconds. You need more training. :D

John Rennie

09:54

Cor, 30 close votes to review!!! :-(

ACuriousMind

@Blue Oh, I can clear the close queue all on my own, but as a mod I'm not supposed to

Review is supposed to be community review, not my review.

3

user228700

@BalarkaSen -_-

user228700

@Avantgarde Yeah :-/ #LTD

Avantgarde

LTD?

Anonymous

@ACuriousMind Ah, I see. But is that a rule or is it just followed to minimize moderator intervention ?

user228700

09:56

@JohnRennie :-) <3

user228700

@Avantgarde Living The Dream, man :-P

Balarka Sen

@Avantgarde LSD (bass boost plays at the background)

ACuriousMind

@Blue It is a rule generally followed on "mature" sites where the community is supposed to be large enough to review on its own, but it's not written in stone anywhere

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