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4:05 PM
Should group names like SU(2) be mathjaxed? If so $SU(2)$ or $\mathrm{SU}(2)$?
 
IMO the latter looks best
 
Hm
 
@JohnRennie I am of the opinion that they should be, in \mathrm
 
I don't think the complete feather can be embedded in a manifold unless it's like $\Bbb R^\omega$, even if we identify the adjacent points
 
I find it jarring to have SU(2) in text just talking about the group and then $\mathrm{SU}(2)$ (or $SU(2)$, if you don't care about upright names) when you want to write down e.g. a map $f:\mathrm{SU}(2)\to X$.
 
4:08 PM
the basic feather would be embedded in $\Bbb R^2$ and look like the upper half space
Double feather in $\Bbb R^3$
etc etc
 
@ACuriousMind hmm, Qmechanic disagrees
 
$\mathrm{Qmechanic}$
 
@JohnRennie Many do. I'm on the extreme end of the scale when it comes to reserving not-mathrm'd letters only for variables.
 
mathrm for groups I'd say, yes
and mathfrak for the algebra :p
I'm not sure what mathscr would be for
 
He disagrees?
With the upright thing?
 
4:12 PM
$\mathscr{SU}(2)$
gross
 
It's universally accepted that it should be upright
Just as -+++ is universally accepted
 
:: remains silent ::
 
The only good way to do GR is with octonions, of course
I wonder what the metric looks like in that GR with octonion paper
let's see
 
3
Q: Why doesn't thermal radio emission from a DSN "hot dish" completely swamp the benefits of a cold LNA?

uhohThe 70 meter DSN dishes are often used to receive the weakest signals, and so their receiver LNAs have cryogenic front-ends in an assembly that also contains a LHe refrigerator and vacuum system. If I understand correctly these are located in the "feed cones" pointed at the Cassegrain secondary r...

needs some physics attention?
 
"ON FACTORIZATION OF EINSTEIN'S FORMALISM INTO A PAIR OF QUATERNION FIELD EQUATIONS"
oh it was quaternions
 
4:18 PM
Hey guys! Been stuck with this for a long time now, please do help
3
Q: On reducing complex ODE's to Bessel's form

Naveen BalajiI am trying to reduce the following ODE to Bessel's ODE form and solve it: $$x^{2}y''(x)+x(4x^{3}-3)y'(x)+(4x^{8}-5x^{2}+3)y(x)=0\tag{1} \, .$$ I tried to solve it via the standard method, i.e., by comparing it with a generalised ODE form and finding the solution from then on. The general form (...

 
The quaternion metric is expressed as $$g^{\mu \nu} (x) = - \frac 14 \mathrm{Tr} (q^\mu \tilde q^\nu + q^\nu \tilde q^\mu)$$
where $q$ is a quaternion
it's the best metric
Though to be fair, I think this is basically thinly disguised GR with spinors
Since quaternions are $\approx \mathrm{SU}(2)$
 
Quaternions are good.
 
Basically the quaternion $q$ is just $\sigma^\mu e_\mu$
Where $\sigma$ is the Dirac matrix/imaginary units
So it's basically $q^\mu = e^\mu_t + e^\mu_x i + e^\mu_y j + e^\mu_z k$
 
@Slereah Who are you talking to?
 
The room
Feel free to respond at any time
 
4:29 PM
Okay.
 
Hi, everybody.
 
Hello
 
Hello
 
Any help on this ? SAXS is preferred for nano material characterization then that of XRD
 
nanomaterials are very small
I would use my tiniest hammer
 
4:34 PM
:)
any reference will help too! I searched but got none ><
 
Whatever happened to quaternions
They were all the rage in physics and then everyone forgot about them
though we still use them a lot, we just call them Dirac matrices now
 
Yeah, I was just about to say that.
Quaternions play a huge role in the physicists everyday life.
 
it just has become unfashionable to call them quaternions
How does one represent spinors with quaternions, I wonder
 
using the spinor-quaternion lemma
 
@AccidentalFourierTransform definition?
 
4:42 PM
something about vector spaces
 
@ACuriousMind if you were to teach an intro QM class would you try to insert any Rigor?
Haha my phone autocorrected to a capital R
 
considering the rigor needed for QM that might make for a long class
also you'd be mostly loss when reading QM books
Considering that for most physics books, the adjoint means "just replace $i$ by $-i$"
 
You have to do an incredible amount of work to show there's an eigenbasis
(In certain cases)
 
also the eigenbasis isn't even an eigenbasis for most physics applications
is $\hat x$ even an observable, since you can't really have a particle in an $\vert x \rangle$ state
 
4:51 PM
Can you
 
for example, let $\hat x=\sigma_z$ and $|x\rangle=|+\rangle$
 
What
 
I just fixed QM
you thank me later
 
4:52 PM
What if I let $\mathrm{AccidentalFourierTransform} = \mathrm{A smelly man}$
 
Use \text ffs
 
You're not my mom
 
@BAYMAX the X-ray scattering angle is inversely proportional to the size of the object doing the scattering. Nano structures tend to be around a few nanometres in size, and the scattering angles for this size range are smaller than the angles easily measurable in XRD.
That's why we tend to use small angle scattering for nano sized structures.
 
I should make a latex shortcut for ^{-1}
 
5:00 PM
Hii @JohnRennie
 
I use it a lot
 
So is a spinor field just a section of a vector bundle?
 
It is written ' Last seen 12 hours ago' . Does it mean he was online .
 
Maybe spinorial regularity isn't that hard
Oh wait spacetimes are noncompact
 
5:01 PM
Ignore that
 
@Koolman Hi
 
@JohnRennie see my above problem
 
thank you@JohnRennie
 
@Koolman I can't see it. Have you got the link?
 
so in XRD it cannot measure small angles!
 
5:04 PM
@JohnRennie You can't see what .
 
like small in sense 0.1 to 10 degrees
@JohnRennie
 
@Koolman the above problem that you mentioned.
 
3 mins ago, by Koolman
It is written ' Last seen 12 hours ago' . Does it mean he was online .
 
@Koolman oh, I thought you mean you had a question about physics. I have no idea what the last seen date in profiles means.
@BAYMAX The diffraction angle is given by Bragg's Law $$2d\sin\theta = n\lambda$$ where $n=1$ for the first order scattering.
 
Okay
 
5:08 PM
So put $d = 1-10$ nm and $\lambda$ = whatever the X-ray wavelength is.
 
@ACuriousMind hi
 
then $\theta $ ?
ok
 
@BAYMAX I'm sure you can do the sums ...
 
yes,ok.
 
5:24 PM
I looked up a post on spinors in quaternion representation, saw the math and then closed it
It's too late for so much algebra
 
5:47 PM
so what's new in the Land of Mathematical Rigor?
@0celouvskyopoulo7 Yes...a section of the spin bundle. So the manifold must be spin in order to have spinors on it
Some people might call it a Clifford bundle? I'm not sure
Some people call it the square root of the tangent bundle...yay!
 
Can anyone point me to a wiki page or source about actually calculating penetration of light with Lead as a function of energy?
 
probably not
sounds more like engineering
 
The Bethe formula describes the mean energy loss per distance travelled of swift charged particles (protons, alpha particles, atomic ions) traversing matter (or alternatively the stopping power of the material). For electrons the energy loss is slightly different due to their small mass (requiring relativistic corrections) and their indistinguishability, and since they suffer much larger losses by Bremsstrahlung, terms must be added to account for this. Fast charged particles moving through matter interact with the electrons of atoms in the material. The interaction excites or ionizes the atoms...
@Phase ^ perhaps?
 
I don't see why it wouldn't be a part of physics
Thanks!
 
@BenNiehoff those were self musings. I'm having think about spinorial PDE
I don't expect to find the answers I need here
It's just that elliptic PDE in vector bundles on closed manifolds is well understood
Open ones or with boundary, who knows
And on a Lorentz manifold everything is bad
 
5:56 PM
what do you mean by spinorial PDE?
you mean finding Killing spinors?
 
I'd have to look up what that is again, but I don't think so
 
or maybe something with the spectrum of a Dirac operator?
those two examples basically exhaust my knowledge of actual occurences of spinorial PDEs
I recently submitted something to a journal that asked me to recommend reviewers
it was so bizarre
 
@BenNiehoff your topic was probably too obscure for them :D
 
it was part of their standard submission procedure
 
@BenNiehoff I'm looking into (generalizations of) Witten's positive mass theorem.
One of the basic PDE's is...fuck how do I Feynman notation
 
6:02 PM
oh, cool! I had to learn that for a paper once
 
Been too long since I've physics'ed :D
 
oh no, don't do that slash bullshit
 
@BenNiehoff Witten's original paper doesn't actually contain a proof that his equation $\sigma^a\nabla_a \psi=0$ has a solution for the boundary conditions
(which are asymptotic conditions)
And I have to work with a metric that's only in $C^{1,1}$ as well
Pretty terrible
 
what is $C^{1,1}$?
 
$C^1$ with first derivatives locally Lipschitz
There are some papers on this by Tam and others but they're far more complex than what Witten did
 
6:06 PM
so, I don't remember the paper very well, is \psi a spinor?
 
And I have to investigate manifolds with ends
Currently massively stuck on a paper by Li and Tam
@BenNiehoff It's a spinor field, yeah
 
but anyway, I'm not sure that Witten could be expected to prove something that isn't true
not every manifold has a spinor satisfying $\nabla_a \psi = 0$
in fact, very few do!
 
The goal of Witten's proof was to express the ADM mass as an integral of a certain positive spinor quantity
 
yes
 
@BenNiehoff I think $\sigma^a\nabla_a\psi=0$ is weaker
 
6:08 PM
ah, ok
 
The condition is that it's "asymptotically constant"
and you need two linearly independent ones
Quite a hard problem!
On a compact manifold it should be easy. Although I'm not sure how many compact Lorentzian 4-manifolds are spin (maybe they all are lol)
 
well, compact Lorentzian manifolds are not of any interest to physics anyway
 
My manifold is $\Bbb R^4$ anyway so topology is not an issue
I want to deal with the PDE without having to worry about some subtle algebraic topological issue
 
there are certainly compact Lorentzian manifolds which are not orientable
 
The problem is: consider a compactly supported perfect fluid in $\Bbb R^4$. Suppose the spacetime is static. Then the spacetime is rotationally symmetric.
 
6:11 PM
so I would guess that it's reasonable to assume they could also fail to be spin
 
Well IIRC you can't have a spin structure if it's not orientable
 
that's the opposite of the Birkhoff theorem, right?
 
*Compactly supported on spatial sloces
@BenNiehoff it's a partial (?) converse
 
@Slereah Indeed, so the interesting question is whether compact orientable Lorentzian manifolds can fail to be spin. In 4d
 
Oh, I think I have a paper on that topic somewhere
I think it's from Geroch or some other guy
 
6:13 PM
but yeah, proving theorems in GR is hard
 
Yes Geroch has a paper on it
 
because spacetime is generally non-compact
 
Tell me about it
Geroch has a paper on everything
 
and Lorentzian, etc.
 
-4
Q: Bose Condensate Computer

Winterstorm DI designed a computer that is a spherical shell, with descending spherical shells one underneath another and stop at some distance from the center. In all the spherical shells beneath the outer surface, will be drilled holes in a 2d four sided symmetrical diamond pattern that's the same as the o...

 
6:14 PM
well if it's not Lorentzian it's not a very good spacetime
 
@BenNiehoff Well...the problem is on spatial slices. So it's actually a Riemannian problem.
But still noncompact
So Witten's theorem doesn't really apply
 
As I was young, I've thought about these people, that they are maniacs
 
there are some methods in 3D by Schoen and Yau
gtg
 
Now I think, they see something, what we can't.
 
@peterh who?
 
oh, I often don't follow links, lol
 
@Ben Intrasite links in the case of the PSE have negligible security risk.
 
it's not because of security risks, I'm just lazy
 
@Ben He has thought a lot on quantum computers, neural networks, robots. And wrote, essentially, an essay. And posted it as a question.
 
sounds like the hottest new thing for crackpots to do!
 
6:19 PM
@Ben My big fear that I will be the same as I will be old
 
it's possible
 
I miss obe...
Everyone's leaving the chat these days
 
maybe the weather's getting nicer?
somewhere else?
certainly not here!
 
@Ben It depends on your continent. In EU, it is joking
 
6:23 PM
I'm in Belgium, weather currently sucks :(
 
goddammit inverting matrices is hard
I give up
 
lol
I literally spent 2 weeks of my life inverting a matrix recently
how big of a matrix are you dealing with?
 
its like $A_{ab}^{cd}\sim c_{ab}\delta_a^{c+1}\delta_b^{d-1}+\cdots$
with Kronecker deltas
so it should be easy
but its infinite-dimensional so there's that
 
sometimes that's easier
other times it's impossible
it could have a left inverse but not a right inverse, for example
 
I guess we'll never know
 
6:27 PM
I need a native Greek speaker
Bye
 
so I've been playing this computer game Hollow Knight
 
qft is so mental, it's all so mental
 
@AccidentalFourierTransform because it's fun?
 
6:42 PM
no it isnt
 
you don't like computer games?
or just that one?
 
I dont like you
 
well, obviously
 
JUST
 
6:46 PM
Wow that makes a lot of sense
 
I was just in a PDE seminar where one prof assumed it was a presentation on an undergrad thesis but it was a PhD student talking
 
and how did that work out?
 
He asked her advisor lol
 
asked her advisor what?
 
If she was an undergrad
 
6:48 PM
ah, ok
 
It's sad because she got a grad fellowship the other day and he was at the ceremony
 
lol
 
cruz crew qft
 
sounds vaguely like sexism
 
6:53 PM
^ that
 
Nah
She was just presenting a small part of the overall (in progress) thesis
He misunderstood and thought it was the whole project
 
It's half analysis and half numerical, she only talked about the analytical bit
Something like that
 
how do PhD programs work in math, anyway? My vague understanding is that mathematicians write much fewer papers than physicists
 
Idk, I'm a sophomore
 
6:58 PM
oh, well you seem to know a lot
 
I'm not even sure how I'm supposed to write my undergrad thesis
I looked at what people do and they look like things I could crank out in a weekend
(slight exaggeration)
 
as long as you do it in word
 
I published 5 papers during my PhD (and I felt like that wasn't really enough)...my thesis was basically the papers stapled together, with some extra chapters at the beginning for background material
 
(half the people in my class did their undergrad thesis in word)
 
7:00 PM
be a true hipster and do it on an antique typewriter
leaving space to handwrite equations
 
In combinatorics you can get one out very quickly if you are lucky, and a few more
 
in fountain pen
 
7:12 PM
> I'm not exactly great at formulas and stuff like that
 
7:27 PM
@ACuriousMind Can you move this message to the trash? I think it is not correct.
 
dude who cares lol
$E=mc^3$
see, its fine
 
This is more subtle
 
well yes, because $c=1$
 
I'm not sure the notion of mass really makes sense
Mass isn't the fundamental concept, it's more $m^2$
As in $p^2 = -m^2$
 
7:33 PM
$\sqrt\cdot$ is smooth though
 
Things get dicier if you have spacelike momentum, though
 
(👁 ͜ʖ👁)
 
--🤠
💪🏻👕👍🏻
--👖
-👢👢
 
you should delete the first line and use my face
 
Sorry I don't have a butt emoji
 
7:39 PM
oh no
rekt
 
Walked right into that one
 
👨🏻‍🔬👨🏻‍🔬👨🏻‍🔬👨🏻‍🔬👨🏻‍🔬👨🏻‍🔬👨🏻‍🔬👨🏻‍🔬👨🏻‍🔬
Let's make some science baby
It's kind of weird that generally, physicists are the foremost scientists in the popular conception of what a scientist is, but for some reason the image of the scientist is always a chemist or biologist
I guess because physicists don't wear a uniform
Can't just show a bearded guy in an ugly sweater
 
scuse me
all my sweaters are beautiful
 
Well you have to post a photo now
I warn you
There is only one beautiful sweater
 
Oh god
Why?!?!
eBay descriptions are the Yahoo Answers of typesetting
 
8:41 PM
@Danu it was indeed easy :)
 
lol
"Our idea to develop artificial inducement of local space warp was based on naturally occurring phenomena and heretofore unexplained cases in aviation. After researching some reports of pilots that had flown through thunderstorms, several cases indicated that these pilots experienced a linear displacement in terrestrial space.[7][9]
The total linear displacement varied from 100 to 300 miles. Forensic weather studies for these cases were created and analyzed. It was found that very large thunderstorms produce copious amounts of energy and antimatter which might explain pilot reports. "
the only actual scientist on that team is a meteorologist
judging from that sentence, not a very good one
 

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