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05:00
@DanielSank hi
@Kaumudi.H: morning :-)
user228700
This will all be over in one month, @0celouvsky.
Till next year :-)
@Kaumudi.H until the next batch of you show up
user228700
@0celouvsky Erm, they're here already but you can hope that they stick to the JEE room :-P
05:01
I don't remember this happening last year
Anonymous
@JohnRennie I'm too annoyed. Okay, I'll try to exercise self control then.
@Kaumudi.H :|
The chat has got a lot more popular.
user228700
Yes, it has...
In a way these arguments are a sign of success.
05:02
@JohnRennie and yet we've lost many good members
Chris, Obliv, Obe, Duffield
@0celouvsky people come and go, and it's tempting to view people leaving as a downhill slide
there are probably more
Whether that's really true is debatable.
user228700
@0celouvsky Huh? Obe left again? :-| That's a bummer.
@0celouvsky $$\int_0 ^{f(x)} f(y) \, dy = f(x) \, . $$
05:03
@Kaumudi.H He deleted his account
@DanielSank I don't believe that for general $f$
Solve for $f$.
@DanielSank $f\equiv 0$
next question
user228700
@JohnR: How's the restraint on over-consumption of food going?
Find a non-constant $f$.
05:04
@Kaumudi.H Good! :-)
@Kaumudi.H Are we trying to lose weight?
user228700
Nice!
user228700
@DanielSank Nah, not me; JohnR is attempting not to eat everything he sees while at his Mum's over the Easter holidays.
@Kaumudi.H Yesterday I ate nothing but the main meal. And I plan to do the same today. On Easter day itself there may be some chocolate eggs eaten :-)
user228700
Cool :-)
05:06
The main meal being a fish pasta bake - very nice too!
@DanielSank Is there one? My preliminary calculation suggests it must satisfy $f(f(x))=1$.
@0celouvsky I have no idea. I just made it up.
@DanielSank $F(f(x))-F(0)=f(x)$. Take the derivative and divide by $f'(x)$ (assuming it's not zero), you get $f(f(x))=1$.
So...idk.
@0celouvsky is that one of those fixed point thing
user228700
BTW, @BalarkaSen: I know that you have an inherent dislike for YouTube videos but I believe you might enjoy the videos of this channel:
Why does balarka hate YT?
user228700
@0celouvsky I don't know if I'm correct about that but he does groan when I link to YouTube videos.
Anonymous
@Kaumudi.H Balarka himself links YT videos.
user228700
But he also groans when I do the same sometimes :-P
05:12
maybe he is groaning at your YT vids :P
user228700
Feb 17 at 11:31, by Balarka Sen
Articles available on internet definitely falls into the category I'd call "actual". I just don't like ideas which are communicated through videos in a flurry; I am not being derogatory towards analysis of stuff through youtube channels, I just don't like that sort of thing. A personal choice.
Anonymous
@Kaumudi.H He means educational videos I think
user228700
Obviously, yes.
Anonymous
On the other hand I find Youtube very useful. My teacher holds live physics sessions with us on Youtube.
user228700
@blue I'd have failed 12th std were it not for YouTube. I've learned a lot from many many channels; YouTube is baaaasially my life (:-P) and has shaped my life till now in significant ways.
05:14
did i miss anything?
Anonymous
@Kaumudi.H Same here :-)
PG, who can forget.
Anonymous
@SwapnilDas Exactly!
@Kaumudi.H Fair enough. What're the videos about?
user228700
@SwapnilDas Eh. Doc Schuster, WL, PatrickJMT, M-learning, R Shankar, the list goes on and on and on...
05:17
@Kaumudi.H R Shankar? Yale?
user228700
> Now You See It explores film themes and tropes. It's like a college film analysis class minus the lecture halls, essay assignments, and student loan debts.
Anonymous
@Kaumudi.H Shankar, yes! His videos helped me a lot while learning waves
MIT OCW is missing from your list! Walter Lewin!
user228700
@Yashas Yep.
Oh, the theoretical physicist.
Anonymous
05:18
Walter Lewin's videos are unclear
user228700
@Yashas WL=Walter Lewin :-)
Anonymous
Not good quality
Exactly^
@blue I frequently watch songs or uploaded movies or interviews of certain people I am interested in or talks, and youtube is a rich place to find those. I don't see a lot of analytical videos
Anonymous
05:18
MIT removed his videos
@Kaumudi.H Gotcha. I'll have a look, thanks.
Anonymous
@BalarkaSen I deduced that from the statement K linked.
Walter is mostly concerned for making you love physics, not learn physics.
Anonymous
@Yashas How's the quality?
05:19
I have WL's videos :D Downloaded them from iTunes before they were removed.
The video quality is low but the content quality is good.
Hey, hey, How could I forget Etoos? :P
@BalarkaSen How would I show that for $F\in K(X)$, there a VB $E$ over $X$ and a trivial bundle $N$ such that $F=E-N$ in the Grothendieck ring $K(X)$?
user228700
I've found many of his lectures to be excellent, actually. He approaches the concept in the rawest possible way (which is why some of them are unclear, perhaps), which has helped me to develop intuition even for the most non-intuitive concepts.
Anonymous
@SwapnilDas Yesh! I bought the whole course
Anonymous
It helped me a lot
05:21
Even I am to.
user228700
Huh. I've never liked Etoos all that much. And this isn't taking away anything from the quality but geez, all the shouting! :-P
@0celouvsky I am honestly not familiar with $K(X)$, so I will just pass on :)
Where do you get Etoos videos from?
I have seen some of them but they are sample videos.
Anonymous
@Yashas Buy them
Anonymous
From the website
user228700
05:23
I've only watched the ones available on YouTube.
Youtube has many
Are there isometries that aren't the identity or a translation/rotation of some sort
or reflection
@blue no $ to buy stuff; I use only the free stuff
@blue Sabne bola thik, maine bhi bola .. :P
and I don't like JEE videos
Anonymous
05:23
@Yashas Ask papa
Anonymous
:-)
The isometry group of the plane is $\Bbb R^2$ semi-direct product $\mathrm{SO}(2)$
Anonymous
They are really really good
So, no for that one
Or do I mean $\mathrm{O}(2)$
I mean for a general manifold
Anonymous
05:24
And the professors are from IISC and IITs
@blue IISc?
user228700
@Yashas Me neither. I've found that they skim over the concepts too fast and only focus on those parts of it that yield problems in JEE.
@Slereah hyperbolic isometries are insane
Anonymous
@SwapnilDas Yes. One teacher is from IISC. I forget the name.
@Kaumudi.H I focus on going beyond JEE so that I can hack in the exam.
05:24
Let's investigate
AV sir?
@blue
Eg, inversion about circles
Anonymous
@SwapnilDas Maybe. Got to check.
@Slereah ^
Ah, there are dilations
user228700
05:25
@Yashas Oftentimes, their attitude is Samajh me nahi aya? No problem. Itna samajh ke problems kar sakte ho :-/
@SwapnilDas @blue I think this discussion on JEE should be moved to JEE room before people get annoyed.
Anonymous
@Yashas Nothing more to discuss
@Kaumudi.H The goal of JEE courses is to make the student score as much as possible.
user228700
I know. It makes sense and all but it's annoying.
05:26
I have seen Resonance's books; Their coordinate geometry has 123123123123 formulae. They don't even give the derivation.
They expect students to learn the formulae and use it in the exam.
Anonymous
@Yashas wtf
user228700
@Yashas Lol. I use Resonance, which is why I've had to hang around here so much to understand the derivations I think are important.
Anonymous
those are crappy books
Anonymous
i don't use any book
Some students really learn it as it is and some students try to derive it themselves.
05:27
@BalarkaSen I bet I'm not lucky enough that trivial $\oplus$ trivial is again trivial, am I?
user228700
@JohnR can attest to this fact :-P
I don't trust the magical $\oplus$
user228700
Aaanyhoo...
@0celo Huh? Of course.
@Kaumudi.H :-)
05:32
@Kaumudi I watched their societal fears on film vid. It's not bad I suppose.
@BalarkaSen I just can't wrap my head around the algebra. I can't go from $F\oplus E=X\times\Bbb C^N$ in $\mathrm{Vect}(X)$ to $F=E-N$ in $K(X)$
The notation is $N$ for $X\times\Bbb C^N$
I find that most analysis of the horror genre oversimplifies it somehow. Not unanticipated, given that it has became quite tedious with raw slasher/gore-fests once again after the pre-80's campy monster movies.
@0celouvsky Remind me what $K(X)$ is?
user228700
I really can't comment because I don't even watch movies. I watched their video on Opening Shots and liked the way in which it was analysed but couldn't add to the conversation because like I said, I don't watch movies that often.
Is this "vector bundles upto stable equivalence"?
In which case it's trivial.
@BalarkaSen That's the idea, I'm working on the proof of that.
05:36
Hm
If I do a book with everything about CTCs
I guess I have to talk about Ronald Mallett
Without being rude
@Kaumudi That's fair. I of course advocate watching good movies, but... tastes vary. :)
The actual definition is $K(X)=\mathrm{Vect}(X)\times\mathrm{Vect}(X)/\sim$ where $(F_1,F_2)\sim (F_1',F_2')\implies (F_1\oplus G,F_2\oplus G)=(F_1'\oplus G',F_2\oplus G')$ for some $G,G'\in\mathrm{Vect}(X)$.
user228700
@BalarkaSen I'd like to watch good movies but my feed is cluttered with crap movies from the cinema industries in my immediate surroundings; Bollywood, Kollywood, Mollywood etc.
Oh god
Ronald Mallett has some autobiography
05:39
tough luck for black history that their GR dude is Ronald Mallett
well depending on what you want to watch i can recommend something but i can't guarantee that'd be interesting to you. i watch weird things.
you should also probably study for jee. sorry :P
user228700
@BalarkaSen I've noticed :-P
@Slereah what?
user228700
Lol, I'll ask about it again after JEE.
He's not the GR fellow with the best reputation
05:44
sounds like a plan
@Kaumudi.H After JEE you are learning measure theory
user228700
@0celouvsky After JEE, I am sleeping for 10 days straight, that's what I'm doing.
that's not healthy
we will assume you died
and have a funeral
user228700
x'D
$\dagger$ RIP $\dagger$
05:46
wtf am I even trying to prove
it's pretty late
you're trying to prove that you don't exist
K-theory is the only way to do it
$\neg \exists @0celouvsky $
that reminds me of that crazy vixra paper
@BalarkaSen so you're saying trivial + trivial is trivial?
It makes sense
Some papers on vixra aren't obviously crazy
The proof should be trivial
05:50
This one?
Totally obviously crazy
@0celouvsky it is.
He literally proves the value of Avogadro's number in his theory
Definition 1. $\circ$ denotes origin of truth. Define $\circ$ as all the most complete everything.
"nothing is telling something about everything"
05:52
I just proved every bundle is trivial.
Can I haz Fields?
Definition 2. $\theta$ denotes an alaya. Dividing $\circ$ by dimensions, the total contents of every $\aleph_1$ dimensions of $\circ$ can form an alaya $\theta$. The nature of $\theta$ is the great mirror wisdom, the wisdom has ability to map contents into their mirror images
sounds like Hinduism
yeah I think it's rooted in some crazy religious thing
Definition 60. According to Buddhist world view, Sumeru Mountain and Saline sea are on the earth wheel, the water wheel is under the earth wheel, the wind wheel is under the wind wheel. Jambudvipa located on the Saline sea in the south of Sumeru Mountain. Human beings are the people living on Jambudvipa. Define this kind of world as small world.
proof by Hinduism?
I'm retarded
$F\in K(X)$ is a pair $(F_1,F_2)$ mod the equivalence relation. Let $G$ be a bundle such that $F_2\oplus G=N$ is trivial. Then...nope, still wrong
Argh
well, I think this still works
Then $(F_1\oplus G,F_2\oplus G)=(E,N)$ if we define $E=F_1\oplus G$
05:58
Not knowing fiber bundle theory is the first sign of mental retardation
2
so then that's in the equivalence class
@BalarkaSen Is $\oplus$ associative?
yes
'cause it's associative fiberwise...
indeed
06:26
I just wasted 30 minutes of my life
The proof was Trivial all along
@BalarkaSen Ok now I proved that $[E]=[F]$ in $K(X)$ iff $E\oplus N=F\oplus N$ for some $N$.
So...stable isomorphism
Is that what that's called?
ya
N is a trivial bundle, I hope.
Yes, $N:=X\times \Bbb C^N$
Time to sleep
cheerio
heh
Reichenbach has some wormhole-like space sort of experiment
Series of concentric shell
First shell is measured
The experimenter goes to the second shell
The second shell is smaller than the first shell
He deduces that the first shell contains the second shell
He then goes down to the third shell
It is the same size as the first
DUN DUN DUUUN
That's the classic Morris Thorne wormhole
although I think it's supposed to be a 3-torus of some kind
06:38
is wormhole even a thing
define "a thing"
i hear it's consistent with GR. is there any evidence in real life?
Wormholes require weird topology, and so far as we can tell, the topology of space is just $\Bbb R^3$
Anonymous
06:39
I don't know even if black holes have any evidence in real life
Anonymous
Does it?
Black holes have some evidence
Anonymous
@Slereah Like?
Depending what you mean by "black hole"
Anonymous
@Slereah The same as Wikipedia definition
06:40
Well there are regions that have matter behaving exactly as it would around a black hole
spurts of electromagnetic radiation out of nowhere, or something like that iirc. i dunno
Yeah, jets, X ray emission, gravitational lensing, redshifting
all that stuff
and no star in the middle
Anonymous
@Slereah Can you name the constellation or galaxy nearby any known black hole ?
Anonymous
Or any links?
The most famous black hole is the one at the core of the galaxy
So it would be located within the milky way, sky-wise
I don't know the location of any other
Anonymous
06:42
A supermassive black hole (SMBH) is the largest type of black hole, on the order of hundreds of thousands to billions of solar masses (M☉), and is found in the centre of almost all currently known massive galaxies. In the case of the Milky Way, the SMBH corresponds with the location of Sagittarius A*. == Description == Supermassive black holes have properties that distinguish them from lower-mass classifications. First, the average density of a supermassive black hole (defined as the mass of the black hole divided by the volume within its Schwarzschild radius) can be less than the density of water...
Anonymous
This ^ ?
Anonymous
Sagittarius A* (pronounced "Sagittarius A-star", standard abbreviation Sgr A*) is a bright and very compact astronomical radio source at the center of the Milky Way, near the border of the constellations Sagittarius and Scorpius. It is part of a larger astronomical feature known as Sagittarius A. Sagittarius A* is thought to be the location of a supermassive black hole, like those that are now generally accepted to be at the centers of most spiral and elliptical galaxies. Observations of the star S2 in orbit around Sagittarius A* have been used to show the presence of, and produce data about, the...
Anonymous
Ah, I love astronomy :-)
There has been some wormhole detection experiments but so far none of them found any
Not too surprising
Even if wormholes were around, they are generically unstable
any wormhole would just collapse to a mostly undetectable size
how can it be unstable? isn't the topology of the spacetime not going any undergoing change?
06:43
By "unstable", I mean that the size of the throat collapses
so, like, the metric near it changes?
under some analysis they might be stable when they reach about Planck size, but that's not v. detectable
The heuristic argument isn't too hard to see
cool stuff.
Wormholes take converging geodesics and turn them into diverging geodesics
Just imagine radial curves going in the wormhole
In the optical approximation to GR, that behaviour is associated with negative energy densities
yeah that makes sense
Anonymous
06:46
Anonymous
Is this what theory predicts as the shape of wormholes ? ^
@blue that's a highly misleding picture.
IIRC without negative energy wormhole throats collapse exponentially with time
Anonymous
@JohnRennie I doubted so...
Anonymous
Any better picture?
06:47
It shows a Morris-Thorne wormhole, but GR tells us nothing about what parts of the apcetime are linked.
there's a paper that has actual wormhole behaviour simulated
@blue I've answered questions on this several times. Leet me do a quick search ...
Anonymous
@Slereah Can you link that paper? (I won't understand the maths though...)
Anonymous
I find this topic very interesting
watch Interstellar, you'll know everything about wormholes
4
A: Do wormholes only allow FTL travel in "folded" spacetime?

John RennieThere is nothing in physics that describes the sort of folding shown in your picture. I'm afraid it is an invention of the Science-Fiction community. The best tool we currently have for describing spacetime is general relativity, but GR does not and cannot tell us anything about the global topol...

Interstellar is pretty terrible for wormholes
3
A: How would you connect a destination to a wormhole from your starting point to travel through it?

John RennieWhen you are thinking about wormholes you are probably picturing something like this: The problem is that the best theory of gravity we have, general relativity, can only tell us about half of this image. General relativity is a local theory that relates the local curvature of spacetime to th...

Anonymous
@BalarkaSen Really? I've heard many people saying it is not accurate.
Here's an example of a wormhole raytracer
06:49
@blue of course it's not, it's a movie
Anonymous
@JohnRennie Thanks...will read through :-)
from the hollywood
For the basic Morris Thorne wormhole
4
A: Are wormholes really a valid shortcut to distant points in the universe?

John RennieBefore we get into the issue of travel time we need to point out the science fiction idea of wormholes is rather different to general relativity. There are several kinds of wormhole metrics known in GR, but they just connect two asymptotically flat regions of spacetime. If we use a rubber sheet m...

Anonymous
@Slereah Thanks!
06:49
That's probably the most complete answer - start there.
For the simplest Morris Thorne wormhole (the Ellis Bronnikov wormhole), you basically see two regions
one of them is like a deformed mirror
It's the ring you see
The interior region is the other size of the wormhole
Although it is usually a bit more complicated
Several rings might be involved
Also red/blue shifting
if we assume any old topology for the spatial section of the universe then there might be wormholes, but they might not be detectable
Due to the topological censorship theorem
so basically they are useless
Remember the magnet falling through a copper tube experiment. Well someone has managed to do it with a superconducting tube.
Now that's a cool (literally :-) experiment.
An excellent use of the physicists time and the research council's money :-)
how accurate is the description of superconductors, anyway
People always brag about how they have 0 resistance but that seems like an approximation
For a start a current going round it would lose energy by Brehmstrallung
if nothing else
07:05
A superconductor works because an energy gap opens up between the ground state and first excited state of the Cooper pairs. As long as this gap is much greater than kT the pairs cannot be scattered.
But there must be some thermal excitation through the gap even if it's very improbable.
So I don't think a superconductor can have exactly zero resistance, though the resistance can be immeasurably small.
heheh
Reichenbach's thought experiments with a 3-torus involves the covering space
0
Q: Ways of promoting questions on PhysicsStackExchange

PinkuIs there way of promoting our questions to seek attention without bounties. I have seen people changing titles,keeping weird and strange titles("The Dark Black Holes "),sometimes even challenging titles("Solve it if you can") and these titles really get a lot of attention. But these are against P...

The experiments involving spatial geometry for Reichenbachs involve the geometry of the world itself, the forces acting upon measuring apparatus, and the "causal anomaly" you would get from such things as the torus space
Where everything is repeated
so that you may still use euclidian geometry for any weird manifold, but only at a terrible awkward price!
Basically using the Pauli-Fierz description of the gravitational field and going to the covering space of the manifold
I'd send him an email to tell him about this but he's been dead for 60 years
it would be awkward
though so far he has not explained how to save euclidian geometry from the appearance of singularities
Since this is a 50's book I'm not sure that was a concern back then
Anonymous
07:53
@Yashas Ah...the insect is gone? =D
Anonymous
Back to the pink avatar =P
Anonymous
I actually liked it
09:34
"In order to exclude such a contradiction, we must make the assumption that there are no closed causal chains."
Reichenbach does not approve of CTCs
user228700
10:27
@JohnR: Biriyani & potato chips for lunch today! :-)
Anonymous
@Slereah Why isn't the pdf opening ? I clicked on the blue button and the link given therein. It is going back to the same page.
Anonymous
Anonymous
I clicked on that blue link ^
Anonymous
And the "pdf" on the left
Anonymous
Doesn't work!
Anonymous
10:31
Do I have to buy it or something?
Anonymous
@JohnRennie I read through both of your answers. They are interesting. But I am looking for a more rigorous article that covers the reasoning as to why wormholes are actually supposed to work and the science behind it. Do you know any such web resource for beginners ?
Anonymous
@JohnRennie Do I have to start with general relativity ?
5
Q: Is there a Virasoro group?

pre-kidneyOn page 14 of the survey article Kac-Moody and Virasoro algebras in relation to quantum physics by Goddard and Olive, the authors show that smooth selfmaps of the circle form a Lie group corresponding to the Virasoro algebra. I didn't fully follow their argument, and then I became more confused ...

Temporarily locked question to avoid migration cf. meta discussion about on-topicness of math questions. Input to how we proceed in this question is welcomed. ...[June 15th, 2017: Unlocked.]
@blue yes
Anonymous
10:53
@Slereah Why is the paper not opening?
because you have to buy it
(or pirate it)
Anonymous
@Slereah You should have said that earlier =P
Anonymous
Anyhow, I don't think I can buy it at present...
hint hint
wink wink
nudge nudge
Taps nose knowingly
Anonymous
@Slereah aaahhhhhhhhhh
Anonymous
10:58
it works
Anonymous
wtf
Anonymous
that's called piracy...but I'm ok with it =D
Anonymous
lol
11:17
@Kaumudi.H Biriyani is nice - whether it's the same as pilau or not!
@JohnRennie you cannot compare Biryani with pulao,Biryani has its own taste.
@Fawad I'm not knowledgable enough about Indian cooking to comment, but there seems to be disagreement about this point.
@Qmechanic I like the question, and I think that the Virasoro algebra is sufficiently "physics" that it should be on-topic here. The question itself can be phrased as a pure math question but the specific case of the Virasoro algebra is so inextricably linked to conformal field theory that we should not migrate it.
I suspect part of the problem is that the terms biryani and pilau are not strictly defined, so differegnt people mean different things by them.
11:32
@JohnRennie sorry,I never tasted pilau,only Biryani...Sorry..
Anonymous
@Fawad pilau=pulao....you really never had pulao?
@blue yes,never (・へ・)
Anonymous
@Fawad But it is made in almost all wedding ceremonies, isn't it?
Anonymous
Okay, nevermind.
Anonymous
I recommend it though. It is a nice dish.
11:51
"Let us imagine that numerous mass points are whirling about at random in empty space. On each of these points there is an observer and these observers can communicate with each other by signals. With the aid of these signals they now want to establish a space-time order"
What a charming picture
@Slereah As long as they don't name it The First Order...

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