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16:00
Well, you will need the addition theorems, no?
okay, almost done, quick question: what's sin(x)*sin(y)?
i can't remember for the life of me
Just leave it as that.
Don't simplify anything.
alright
Seriously, don't simply anything at all yet.
one moment, let me type it out
16:02
@ACuriousMind heather's result will be whatever it is. If we use the angle addition fomulae, then we'll see it's equal to what I wrote, proving $R(\theta)R(\phi) = R(\theta + \phi)$, which is nice. As a bonus, and to me the more interesting thing, this provides a lightning quick way to derive the addition formulae if you forget them.
@ACuriousMind IIRC, it is possible to define $\sin,\cos$ through the addition "theorems" (that is, they are not theorems anymore). It is fun: there are thousands of different ways to define trig functions, from ODE's to series to integrals, etc.
@DanielSank I remember the addition formulae by looking at $\exp(\mathrm{i}\phi)\cdot \exp(\mathrm{i}\theta)$, there I don't even have to do matrix multiplication ;)
@ACuriousMind That's not any faster, tbh.
It's almost the same thing.
Yeah, I agree
16:04
Real/imaginary parts = x/y components.
so whatever, they're similar.
@ACuriousMind oh no, you're one of those too
@AccidentalFourierTransform What are "those"?
I am fascinated by the fact that ACM used a Roman "i"...
...why...?
@DanielSank well, you use $|v\rangle$ to denote vectors.
To be honest, I can't recall the last time I needed an addition formula, though :D
even when doing abstract algebra
and ACM writes $\mathrm i$ instead of $i$
16:05
oh, darn
@AccidentalFourierTransform Meh, it works.
@AccidentalFourierTransform yeah that one is weird to me.
@DanielSank Because it's not a variable. $i$ is a variable, $\mathrm{i}$ is the imaginary unit (although it is of course good style to avoid using the variable $i$ when having an imaginary unit around)
you two disgust me
with your weird notation :-)
@ACuriousMind Meh. Ok.
I buy that.
I dont
it looks awful
16:07
@AccidentalFourierTransform I also write $\mathrm{e}$ not $e$ for Euler's number :)
I can see the logic in that.
I will never argue against clear notation.
For any reason.
@ACuriousMind yeah I do that too. But its not the same
ack
what have I done
@heather what are you doing haha
@AccidentalFourierTransform, I have no idea =P
I thought I'd typed it right
16:07
Does bmatrix work in mathjax?
@AccidentalFourierTransform Now, if I had an upright $\pi$...
I used it on all the earlier ones @DanielSank
@DanielSank Yes
@ACuriousMind $$\text{p}$$
@ACuriousMind lol
16:08
$\begin{bmatrix}
(\cos(\phi))(\cos(\theta))+(\sin(\theta))(-\sin(\theta))&(-\sin(\phi))(\cos(\theta))+(\cos(\phi))(-\sin(\theta))\\(\cos(\phi))(\sin(\theta))+(\sin(\phi))(\cos(\theta))&(-\sin(\phi))(\sin(\theta))+(\cos(\phi))(\cos(\theta))\end{bmatrix}$
where've I gone wrong...
I have the & in there
Not sure but that's a lot of unnecessary parentheses.
begin and end
yeah the code it looks fine
@DanielSank yeah
16:09
You might need spaces around the &
$\begin{bmatrix}(\cos(\phi))(\cos(\theta))+(\sin(\theta))(-\sin(\theta)) & (-\sin(\phi))(\cos(\theta))+(\cos(\phi))(-\sin(\theta)) \\ (\cos(\phi))(\sin(\theta))+(\sin(\phi))(\cos(\theta)) & (-\sin(\phi))(\sin(\theta))+(\cos(\phi))(\cos(\theta))\end{bmatrix}$
oh, lol
Also around the `\\`
Put spaces around the `\\`
goodness, there
okay
16:10
\(^.^)/
now delete all the parentheses
i was wondering what crime I'd committed
@DanielSank scheme might have tainted her ;)
@AccidentalFourierTransform will do
lolololol
16:10
@ACuriousMind no, it's just a bad habit I've got =P
ok, where were we?
I think it has something to do with $\mathrm e^{i\pi}+1=0$
right?
Well, @heather take the top left element of your matrix.
$\begin{bmatrix}\cos(\phi)\cos(\theta)+\sin(\theta)-\sin(\theta) & -\sin(\phi)\cos(\theta)+-\cos(\phi)\sin(\theta) \\ \cos(\phi)\sin(\theta)+\sin(\phi)\cos(\theta) & -\sin(\phi)\sin(\theta)+\cos(\phi)\cos(\theta)\end{bmatrix}$
It should be equal to the top left element of my matrix.
So, $$\cos \phi \cos \theta - \sin \theta \sin \phi = \cos(\theta + \phi) \, .$$
@heather ah, almost. If you delete the parentheses you have to move the minus sign to the front: $(a)(-b)=-ab$
16:12
@AccidentalFourierTransform, gotcha
...which is exactly the angle addition formula for cosine.
So, we just proved something neat: if you compose two rotation matrices, it's the same as a single rotation matrix for the sum of the angles.
whoa
well, okay, now I'm questioning: how'd you get your matrix?
Oh, I just used the rotation matrix you got and stuck $\theta + \phi$ in for the angle.
You derived the form of an arbitrary rotation matrix and I applied to the case of an angle $\theta + \phi$.
@DanielSank but you didn't prove that if $\theta,\phi$ are a pair of angles, then so is $\theta+\phi$
@AccidentalFourierTransform Huh?
16:15
you might get problems with the domain of definition and global obstructions
@DanielSank Im just messing with you lol
I have no idea what you mean.
:|
but why is it $\theta +\phi$ instead of something else whacky?
i mean, i guess it makes sense intuitively
Like all cats, it seems the Fourier transformed version is also a bit of a troll ;)
@ACuriousMind, lol
If I rotate by 10 degrees, and then by 4 degrees, I better get a rotation by 14 degrees.
I gotta go.
16:16
@DanielSank, well, thanks, that was awesome!
have a good day
you too
or morning or whatever
morning
@DanielSank thanks =)
@DanielSank right, because you're only two hours behind me
Take some time to digest what we did.
16:17
will do
@ACuriousMind and @AccidentalFourierTransform can help.
obviously
@heather Nah, I'm on east coast at the moment.
well, there is something else that is fun
@heather what is the rotation matrix for $\theta=\pi/2$?
@DanielSank bye
well, you just sub in pi/2 for theta
and then simplify
16:18
@heather yep
Let's call that matrix $I$
so $\begin{bmatrix}0&-1\\1&0\end{bmatrix}$
$$I=\begin{pmatrix}0&-1\\+1&0\end{pmatrix}$$
yes, thats it
right
well, what is fun is that the matrix $I$ is essentially the same thing as the complex number $i$
16:20
for example, can you calculate $I^2=II$?
(just matrix multiply $I$ with itself)
sure, one moment
okay, it'd be
$\begin{bmatrix}-1&0\\0&-1\end{bmatrix}$
i believe
exactly, $I^2$ is minus the identity
oh, huh, yeah
$I^2=-1$, just like the complex number $i$
huh
that's interesting
but are there any other similarities?
16:23
yes
for one thing, the rotation matrix $R(\theta)$ from before
can be written as
$$\begin{pmatrix}\cos\theta & -\sin\theta \\ \sin\theta & \phantom{-}\cos\theta \end{pmatrix}=\begin{pmatrix}1 & 0 \\ 0 & 1\end{pmatrix}\cos\theta+\begin{pmatrix}0 & -1 \\ +1 & 0\end{pmatrix}\sin\theta$$
right?
what's going on? why isnt it working?
The $I$ would be called a linear complex structure in mathematics, because you can essentially define multiplying a vector by $a+b\mathrm{i}$ by saying it's the same as applying $a E+ b I$ to it, where $E$ is the identity matrix.
@AccidentalFourierTransform spaces around the & and the slashes!
@AccidentalFourierTransform =P
709
A: What are imaginary numbers?

Clive NewsteadLet's go through some questions in order and see where it takes us. [Or skip to the bit about complex numbers below if you can't be bothered.] What are natural numbers? It took quite some evolution, but humans are blessed by their ability to notice that there is a similarity between the situati...

^this answer connected something else in for me...
"$90^∘$ rotation to be multiplication by $i$"
this is a 90 degree rotation matrix, right?
@AccidentalFourierTransform huh, that's interesting
the point is, you can think of rotations in abstract
and you can represent them with matrices, but also with complex numbers
16:31
okay, question: when watching that 3Blue1Brown video, it represented imaginary numbers with rotations...does $i$ equal that matrix as well as the square root of -1?
(if that makes any sense)
@heather Well, $\mathrm{i}$ can't really "equal" that matrix - one is a number and the other is a matrix, they can't be equal in the formal sense of the word.
The matrix is closely related to the imaginary unit and in some sense equivalent, but not equal
hmm. okay.
^ that. We could say that our $I$ is equivalent to $i$. They are different objects but represent the same concept
wait, they can or can't be?
$I=i$ or $I\neq i$?
$I\neq i$. The left-hand side is a matrix, and the right hand side is a complex number
you can write $I\sim i$ or something like that
16:35
oh, okay.
gotcha.
its rotations all the time, but different ways of expressing them mathematically
i love how higher level math makes lower level math make so much sense
definitely, yes
its a steep learning curve
but its gets much more interesting with time
and in the end everything fits together
anyway, Im not sure what else Daniel wanted us to discuss
I guess he'll have something else to add when he comes back
16:41
@AccidentalFourierTransform, @ACuriousMind, thank you both for your help
@heather don't mention it :-)
17:09
@heather do you understand all the things now?
@DanielSank i do think it makes sense, yes =)
@AccidentalFourierTransform I mostly just thought it would be useful for heather to see rotation matrices, how they compose, and how they relate to trig identities.
The stuff about complex numbers is the obvious next step, as you guys already discussed.
It's no accident that the eigenvalues of $R(\theta)$ are $\exp(\pm i \theta)$.
@DanielSank also, what $\mathrm e^{I\theta}$ means. As, the matrix exponential and all that. Maybe something about De Moivre's formula? or somethign about infinitesimal generators of rotations? =P
There are many interesting things we could say but I don't want to overwhelm her
this all sounds quite interesting
It is.
17:18
@DanielSank $\exp(\pm i\theta)$?
what does that even mean?
$\exp(x) \equiv e^x$
It's just notation.
I use it for inline formulas to avoid the fact that superscripts are small and hard to read.
For example, $$e^{\frac{1}{2 \cos(x)}}$$ is harder to read than $$\exp \left[ \frac{1}{2 \cos(x)} \right]$$
especially when it doesn't compile properly
ah, okay
$e^{\pm i\theta}$...that looks similar to $e^{i\pi}$
yep.
Of course. It's just the case where $\theta = \pi$.
17:24
oh, true
interesting
But you don't really know about eigenvalues yet, right?
sort of
eigenvectors are those that stay on the original vector's span during a linear transformation
and the eigenvalue is by how much they are stretched
if i remember right
Wow. You do know about them
Yeah that's exactly right.
The rotation matrix $R(\theta)$ has eigenvalues $\exp(\pm i \theta)$.
What's interesting about that, to me, is that when you multiply a complex number by $\exp(\pm i \theta)$ you rotate that complex number by $\theta$ about the origin :D
huh, that's interesting
Yeah this is what @AccidentalFourierTransform was talking about earlier.
Any complex number can be written as $z = |z| e^{i \theta}$.
in other words, the magnitude multiplied by a phase factor.
17:31
but we like the unitary gauge where $\theta\to 0$.
So, if you multiply this by a pure phase... $$e^{i \phi} z = |z|e^{i \theta} e^{i \phi} = |z| e^{i (\theta + \phi)}$$
@AccidentalFourierTransform unitary gauge?
He's being silly.
what else is new =P
1 hour ago, by ACuriousMind
Like all cats, it seems the Fourier transformed version is also a bit of a troll ;)
17:32
hahahahaha
@DanielSank well, maybe you're using the wrong basis for your analysis, then, and you'd be better off using $(\hat{\mathbf e}_x\pm i \hat{\mathbf e}_y)/\sqrt{2}$ for rotations about $\hat{\mathbf e}_z$ instead.
0
Q: Usage of some special formatting commands

InquisitiveMindWhat is the difference between This and this ? When are they supposed to be used ?

@EmilioPisanty indeed
@EmilioPisanty, sorry, but your edit to the meta question doesn't really improve readability and it bothers grammar lovers (the space between the end of the sentence and question mark).
thanks
17:57
Hi.
Late Nights are wonderful, you get a lot of silence, lot of that.
18:29
oh hi friends
@mochacat, hello
18:50
[Division by zero] current progress. Outlook good
shaded entries of the same color must have the same numbers
green=associativty verified
@Secret what is this?
Some abstract algebra hobby investigation I am doing. That is a composition table, otherwise known as a multiplication table. It tells you what you get when you pick any two elements and add or multiply them together
more details here:

 Zero term algebra

All discussions on the ongoing project of algebraic structures...
Currently trying to make it at least left distributive and associative
otherwise that will suggest division by zero is not associative
@vzn, hello
vzn
vzn
20:17
@heather hello
20:47
Howdy
You know, I just realized. @DanielSank is the only person I know here who uses his real name.
Oh wait, except heather
Fourier Transform is the worst name for a child
I use me mothers surname though
yeah, I had a very hard childhood
So your name is Fourier, and last name is Transform?
thats why Im a physicist ;-)
yep
AND I WAS AN ACCIDENT!
20:51
We only learned about fourier transforms a few days ago, and I'm already forgetting what they are...
my real name is mochacat. my parents are from swaziland
I remember telling my parents I wanted to be a mechanic because I thought it referred to people like @Qmechanic
@Qmechanic g'evening
@AccidentalFourierTransform : Good evening
20:58
hello again, everyone
@SirCumference, how do you know "heather" is my real name...? =P
@heather Plot twist!
heather is just a stage name so nobody knows that shes a heater
Heather reveals she's really 0celo
it's actually 35h23t0-3r9
@mochacat uh...nope
for the record, i'm being sarcastic here =)
so you really are a heater
this belongs in the world-building SE
21:05
no, us 3r9-ers are an advanced processor chip.
the singularity has begun
developed to ::short circuits::
i'm sorry, what were we talking about?
@mochacat what? No, just the clone wars.
i should leave before you take me off the grid
man everyone on the great outdoors SE is basically bear grylls
i'm on this thread about removing fishhooks from humans and some guy suggested using fresh spiderwebs to seal the wound
21:12
@SirCumference yeah. I'm legit.
I did that so that if folks want to decide how much to trust my answers, they can google me and find out that I'm a real scientist.
So far there's only been one occasion where I regretted having my name here.
engineer at boeing or electrical engineer at google?
when was that?
21:26
@mochacat huh?
@mochacat o_O
@DanielSank Which is?
@mochacat 0_0
21:56
this is golden:
The Wicked Bible, sometimes called Adulterous Bible or Sinners' Bible, is the Bible published in 1631 by Robert Barker and Martin Lucas, the royal printers in London, which was meant to be a reprint of the King James Bible. The name is derived from a mistake made by the compositors: in the Ten Commandments (Exodus 20:14), the word "not" in the sentence "Thou shalt not commit adultery" was omitted, thus changing the sentence into "Thou shalt commit adultery". This blunder was spread in a number of copies. About a year later, the publishers of the Wicked Bible were called to the Star Chamber and...
22:23
just lost the game in world-building SE
@mochacat i've heard of that
but i decline to play it
because it bothers me to no end
Throughout history, printers' errors and peculiar translations have appeared in Bibles published throughout the world. == Manuscript Bibles == === The Book of Kells, circa 800 === The genealogy of Jesus, in the Gospel of Luke, has an extra ancestor at Luke 3:26 (the second name on this illustrated page). The reason for this error is that the transcriber of the Book of Kells read "QUI FUIT MATHATHIAE" as "QUI FUIT MATHATH | IAE," in which he considered IAE an additional individual (and so he added another QUI FUIT), rather than the Latin ending of "Matthew." Matthew 10:34b should read "I came not...
@EmilioPisanty Huh...
History is interesting
 
1 hour later…
23:38
@EmilioPisanty Every time I think of it, I wonder if the "bugger alle this" bible described in Good Omens (which also describes the instance you link to above) is a real thing. But not enough to actually do any research on the matter.
Thankfully someone else (or likely several someones) have already done it for me: en.wikipedia.org/wiki/Bible_errata
Hmm... alas there is no reference to it outside of Pratchett and Gaiman's book. ::sigh::
nice hat @dmckee

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