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00:02
@dmckee Oh, no, the important stuff I referred to is Cornell and UPenn admissions 20 hours and 58 minutes from now
@BernardMeurer Oh. That's different.
56 minutes now
Just out of curiosity
what are the CS schools currently?
Stanford, Berkeley, MIT, and CMU?
Pretty much yeah
That's a very fair list for the schools
cool so I guess things haven't changed much since the olden days
when I wanted to do CS
00:08
TRAITOR
@BernardMeurer did you apply for anywhere else?
@JoshuaLin I applied to UIUC, UCB UCSD UCD, Waterloo, VA Tech, GA Tech, Cornell, UPenn, Minnesota Twin Cities
im waiting for some application results too lol
@BernardMeurer did you apply to CMU btw?
oh I guess that answers my question too
Why did you apply to mainly public schools?
00:10
@FenderLesPaul Couldn't afford CMU in a million years
yeah CMU is batshit expensive I agree
they gave me zero financial aid and I had to pay like 60 grand a year
I was like fuck that
@FenderLesPaul They tend to be affordable (apart from UC)
fair point
and there's a company here that gives scholarships for students going abroad that likes to pick the ones going to public schools for some reason
there are some public schools that I forget are public schools
like Berkeley and Michigan and UIUC
00:17
Agreed
@BernardMeurer because it's cheaper
00:41
@FenderLesPaul It's not a big, but Harvey Mudd shouldn't be left off the list. And you get Claremont credentials out of it which is a pretty big deal if you are trying to get into a non-geeky management-track.
Not that most people in the h bar are trying that, but it is the way to go if you want to end up getting really big bucks.
@dmckee the list of top CS schools?
Yeah.
I applied there, back in bronze age.
Isn't Harvey Mudd an undergraduate only school?
I keep forgetting who is thinking about grad school and who is just talking about college in general. Of course it's all undergrad.
Yeah it's a cacophony in here right now in terms of where people are headed in life haha
00:54
@FenderLesPaul I have a dilemma
of where to go in life
starbucks
or not
You never go to Starbucks if you know there is a reliably good local cafe open.
Just on principle.
@0celo7 Starbucks is a place for desserts in the format of drinks
find an actual cafe instead
If you don't know that then, sure, go to Starbucks. It won't summon the devil or anything.
@dmckee I get free starbucks with my meal plan
@BernardMeurer I stand there with my drip coffee or waiting for my dry cappuccino wondering why people order those things when there is perfectly good coffee on the menu.
(Aside: I've always liked my coffee roasted almost until it screams, so Starbucks works for me.)
00:59
currently drinking a nonfat cafe latte
@dmckee I wouldn't say perfectly good, but definitely it's a decent coffee
had two cups of dark roast earlier in the day
@0celo7 are you worried about your weight?
You want to know a place with perfectly good coffee? Dunkin Donuts
@BernardMeurer I remember the bad old days when they served battery acid. Then, around 2000 it all changed.
01:01
Their coffee is just great now, love it
@3075 I can't taste the difference between skim and full fat, so why drink full fat?
@0celo7 seriously?
although I have lost about 20 pounds since I came to college
Yeah. And it happened over night, too. People started getting coffee when they bought shift donuts and I wondered what was wrong with them.
After enough people had told me it was different I went and tried it and it really was drinkable.
for some reason I feel sick when I have coffee.
I begin shaking and feeling dizzy.
lol
01:03
I'm brazilian, so I like espresso, but on a normal cup
@3075 SO that could be too much caffine (if you're getting a lot somewhere else) or it could be an allergy to something in the coffee.
Can you drink tea or cola?
As close to just eating coffee beans as it gets
@dmckee yeah
it's a recent occurrence though, i could drink coffee fine before.
Sometimes I get labyrinthitis after my 3rd cup in a row
@BernardMeurer That's the one thing I don't often get at Starbucks. They just aren't consistent enough to drink it straight.
When I want espresso I draw my own shots at home.
01:05
I remember the first time it happened.
Jan 28 at 2:07, by 3507
I think I'm becoming allergic to coffee because the last 3 coffees I had made me feel nauseous.
I also hate sugar on my coffee
which lots of places seem to love
I don't put sugar in mine
I do. :D
@BernardMeurer what's that
Labyrinthitis, also known as otitis interna, vestibular neuronitis and vestibular neuritis, is inflammation of the inner ear. It results in vertigo and also possible hearing loss or ringing in the ears. It can occur as a single attack, a series of attacks, or a persistent condition that diminishes over three to six weeks. It may be associated with nausea, vomiting. Vestibular neuronitis may also be associated with eye nystagmus. The cause is often not clear. It may be due to a virus, but it can also arise from bacterial infection, head injury, extreme stress, an allergy, or as a reaction to...
01:07
0
Q: Creation of a new tag for books/resource recommendation and having a resource library for physics.SE

Janus BoffinI agree that users of physics.SE (new and/or old) can't curb their need to ask for resources based on this question (based on the tag), as explained herein. However, many users still ask questions which are duplicate. For example, this thread. So, would it be possible to create a new tag so as to...

go away meta
no one likes you
damn algebra by artin is expensive.
I bought it though. :'(
@0celo7 Did you download War Thunder?
01:28
@BernardMeurer nope, never heard of it
Go get it then
Give me one good reason
We'll play together and it's an awesome game
also it's free
time to work on HE some more...
01:49
@Slereah I finally understand Lemma 4.5.2
bleh now i have to teach all of linear algebra to a bunch of 13 year olds in an hour.
do you even know linear algebra
wow.
well I know the basics.
xD
ok, please write a proof showing that equivalent norms define the same topologies and I'll put it on the blog
I want a nice proof of that there
calm down.
01:53
@ACuriousMind I need a commutative diagram on the blog for [reasons]
How do I go about doing this
draw your own?
save it as an eps file.
idk if wordpress allows eps though.
I basically need this one
02:09
> Amazingly, you really can use all that math from
high school that you thought you never would!
Even better (or worse), it’s actually not as hard as
you thought it would be.
What high school math is used in Jackson??
@0celo7 yes?
@AlfredCentauri hahah that's pretty dope
Do Jackson problems legitimately take 24 pages?
They're pretty bad
from what I know
03:06
> Trying to do Jackson problems alone, without help
from your fellow classmates, is like trying to push
an 18 wheeler out of the mud by yourself wearing
flip flops and with a broken leg.
::chortle::
And the time break-down is pretty funny too.
I made it my mission to only have to get help on one problem per assignment.
I might even have realized that goal. Once.
> As a matter of fact, completing
a course on Jackson Electrodynamics places you in
a special club for students who survived Jackson.
You are now connected, in a very special way, to
everyone else who has ever taken a course with
that infamous text book –
professors and graduate
students alike. It will be
a subject of conversations
with physicists you meet from far away places
Absolutely true.
The biggest single lesson I learned from Jackson is to never, never erase any work. If you want to try another approach you do so on a fresh sheet of paper.
That way, if it turns out your new approach is even worse (which will happen) you can return the easier place where you were stuck before.
@0celo7 I don't know if I ever got as high as 24 pages, but it is easy to spend more than 10 on the "neat" version that you turn in. That doesn't count the dead-ends that land in the pile next to your desk.
Multiple transformations, substitutions and integrations by parts as you go along are just an expected part of the work.
vzn
vzn
03:44
(plz +1 if you believe in creativity + CS!)
04:04
@user507974 That's pretty awesome
04:16
@dmckee that's still ridiculous
there's a problem in Weinberg to quantize scalar electrodynamics and calculate a bunch of cross sections
something like that might take 10+ pages
Jackson sounds like a real asshole
you know who's a real asshole
Hawking and Ellis
^all HE proofs
@Slereah
@ChrisWhite Why would one use const ints instead of preprocessor directives?
#define yadda yadda
holy shit the snapchat emoji next to Rebecca is no longer a heart DDDDDDD:
@0celo7 Snap knows
user54412
04:23
@BernardMeurer blarahgnn&!(#(
@ChrisWhite What? :p
he's fallen and can't get up
call the Princeton PD
user54412
preprocessor directives add another layer of abstraction that makes everything that much more difficult to parse
user54412
(for people)
user54412
also, #define for constants is a gateway drug
04:24
Pff, we built XML and people still complain about things being difficult to read
XML is so good neither man nor machines can read it
It should be used as bloody encryption really
@ChrisWhite is there like some cheat sheet floating around GR grad school that explains HE proofs
user54412
next you'll #define max(x,y) x > y ? x : y
"gateway drug"?
@ChrisWhite Whats wrong with that! Perfectly readable expression
so short and beautiful
:D
user54412
I... don't know if you're joking
Yes and no
Yes because I know people dislike that
no because I love it
user54412
04:26
it's really dangerous
user54412
without parens around all x's and y's, you'll run afoul of operator precedence when x and y are expressions themselves
user54412
and without parens around the whole thing similar stuff happens
user54412
basically preprocessor directives destroy operator precedence at a local level
Kind of like those pesky people that don't put braces on if statements then? i.e the apple encryption bug
user54412
04:28
worse, because that at least is readable
user54412
also, if you use a text editor without auto-indent turned on, you get what you deserve
user54412
(that's right, I don't brace single-expression conditionals)
Monster!
@BernardMeurer It's also fails horribly in all kinds of ways.
Alright alright I'll stop with my preprocessor magic, I just always thought it looked neat
Haven't used it in any of my C++ tho, only in my from-the-depths C stuff
user54412
04:30
My adviser reminisced to me about when the C preprocessor first came out and it was the most beautiful magic of the time
@ChrisWhite And even with all the right parens, if either of the substitution strings (they're not really arguments) have side effects then those side effects will be multipll applied.
user54412
indeed: max(a++,b)
Mine you I wrote a little unit-testing framework in cpp, but it is an abomination.
I'm very much liking C++
I feel like it's as if someone had gotten C and stripped the devil out of it
Pay no attention to the new devils behind the curtains.
Though if you listen to some experienced coders about what feature to either not use or use only with great caution you can avoid most of them.
user54412
04:33
@FenderLesPaul I mean nice profs will give you an honest opinion that could be very valuable. Of course they might not know you well enough to answer, or they might have ulterior motives. There's nothing inherently wrong with asking, it's just a matter of putting the right weight to the response.
At this point I wouldn't choose plain c over c++ without a driving external factor.
I just stick with Python and Bash for most of my stuff
god I love shell code
user54412
I do all C++ these days, but I really miss C
I only bring C and C++ when it gets hardcore
user54412
C++ just isn't sublime in the same way
04:35
@ChrisWhite No it's not. But if you use the right subsets it can be safer and can get stuff done in less programmer time.
C is sublime? Jolly goodness you lost it haven't you
@BernardMeurer Nope. The only thing more zen-like in programming is lisp.
LISP, oh yes that's sublime
Bloody thing has been alive forever
I dare say Haskell might be more sublime than LISP
C has the same kind of purity. It's just you an abstracted model of a 1970s processor.
user54412
@dmckee and then someone writes a line with auto and iterators and magic pointers that no one on earth can tell what they're up to, only to realize it was invoking the move constructor rather than the copy constructor and you curse the day language designers stopped being hardware people
04:37
Meh I never quite got the hang of using pointer sorcery
And if you tell it to blow your foot off, it will happily do it.
user54412
@BernardMeurer I... have a container of coffee beans on my desk. For eating...
@ChrisWhite Picture; also, will you be my friend?
Dang it, why didn't I apply to princeton
user54412
user54412
so few left :(
04:50
Damn those look good
user54412
they're really popular with the observers in the department
user54412
perfect sustenance for a 15 hour observing run in the middle of a 36 hour day
Trying to find them down here in this moment
because if I don't get into UPenn or Cornell tomorrow I'll need them to stay up breaking stuff
and if I do I'll need them to stay up dancing
stuff as in code of course, switching semicolons for identical greek characters and spaces for tabs
user54412
why not add windows-style line breaks while you're at it, monster
Good one!
CRLF for the win!
Did you get the pun there?
CRLF for the win
haha
::cries a little::
05:00
You could always use mac classic line breaks instead. Just to see who is a software historian around you.
I'm not sure I even have a tool for fixing those anymore. I might have to read the tr man-page or something.
CR only?
just call awk, it must have some way of solving that
05:22
@ChrisWhite are those chocolate covered?
 
4 hours later…
09:40
can someone tell me, why we always use $y=f(x-vt)$ as wave function
"In fact, given a timelike curve $\gamma$ connecting the pair $(p, q)$ there are open neighborhoods $U \ni p$, $V \ni q$ such that if $\tilde p \in U$, $\tilde q \in V$ , then there exists a timelike curve $\tilde \gamma$ connecting $\tilde p$ and $\tilde q$
(say, $U$, $V $can be chosen as $I^−(p_1) \cap U_p$, $I^+(q_1) \cap U_q$, where $U_p$, $U_q$ are convex neighborhoods of p, q which contains $p_1$, $q_1$, resp., and these points are chosen such that $\gamma$ runs consecutively $p$, $p_1$, $q_1$, $q$)"
Hm
Wait, how can we know that $I \cap U$ is open
The point is to prove that $I$ is an open set
@ramsay Hecht's Optics chapter 2 will give you a good feel for wave functions like that
Oh wait
@bolbteppa let me check out :-)
There's a special theorem for I in a normal neighbourhood
@Slereah browsing the paper that came from, that looks like it's part of the proof that $I^+$ is open in $M \times M$
10:41
It is
There is a local version of that theorem, which explains it
BUT
The proof is in another book still
>:|
@0celo7 this is why the world needs the Book
author doesn't say *why* should we substitute $x$ by $x-vt$
or i might have misunderstood
@ramsay look at the picture, did you follow the discussion leading up to this page?
hmm, let me read one dimensional wave again
O'neil's Semi Riemannian geometry seems pretty good too
Apparently the proof is basically that $I$ is an open set in Minkowski space
So you should be able to map open sets to open sets in a normal neighbourhood
Yeah, just trying to re-phrase it in a more natural obvious way
10:56
Or something I dunno
what does it mean:"has shape of cases" ? (sorry)
Where does it say that?
on page 11 of the book!
Doesn't say that, maybe reading it wrong?
see the end of right hand side paragraph
11:09
Yeah, then the next page says "a bell"
but the functions are different in page 11 function is $f(x)=e^{-ax^2}$
and in page 12 function is $f(x)=e^{-a(x-vt)^2}$
On page 11 he says that the profile, at time $t = 0$, has the shape $e^{-ax^2}$, after a time $t$ the wave will have moved to a new position but it will retain it's shape, so in a new coordinate system $(x',t')$ the wave will, at time $t' = 0$, look exactly like it did before $e^{-ax'^2}$, but how do you relate this to the old coordinate system? $x' = x - vt$ as in the picture
God I hate these overly formal proofs, all the guy is trying to say is that points nearby points that can be connected by timelike curves can be connected by timelike curves in the most general way possible
@bolbteppa hmm, ideas are poping in my mind(this is making sense!)
@ramsay great!
11:27
thank you!
11:54
@Slereah let's write the book
what is the first proof of the book
So I think I need to get SW, BEE and O'neil
Also why are convex normal neighbourhood called "starshaped"
Stars are concave
@Slereah here's a first shot at stating it, can clean it up if needed:
Consider two points $p$ and $q$ in spacetime that can be connected by a (collection of) timelike curve(s) $\gamma$ (or $\gamma^i$). We want to show that we can find a point $\overline{p}$ 'near' to $p$ and $\overline{q}$ 'near' to $q$ such that we can connect $\overline{p}$ and $\overline{q}$ by a (collection of) timelike curve(s) $\overline{\gamma}$.
@Slereah ONeil explains that.
To find these points, consider some $p_1$ on $\gamma$ not equal to $p$ or $q$, then consider the set $I^-(p_1)$ containing points that live on timelike curves that have $p_1$ as it's *endpoint*. Next, since spacetime is open, consider any convex neighbourhood $U_p$ of $p$ that contains $p_1$, i.e. a set such that we can connect $p$ to $p_1$, and then restrict the points of this convex set to those which live on some timelike curve that has $p_1$ as their endpoint, i.e. $U_p \cap I^-(p_1)$.
Thus the convex set allowed us to find points 'near' $p$ in Minkowski space, intersecting it with $I^-
Thus given any points $p$ and $q$ connected by a timelike curve we can find nearby points $\overline{p}$ and $\overline{q}$ connected by a timelike curve $\overline{\gamma}$, showing that the set $I^+$ of all points $(p,q)$ such that $p$ can be connected to $q$ by a timelike curve is open.
It's because if v is in the neighborhood, tv is as well
For t between 0 and 1
12:01
@Slereah "Starshaped" is a standard expression in analysis for a region which has a "midpoint" to which every other point can be connected by a straight line inside the region (convince yourself that a typical star shape is such a region).
In the Riemannian context, the natural generalization is "straight line" -> "geodesic".
@bolbteppa : Well the part I find difficult to prove is proving that $U_p \cap I^-(p_1)$ is an open set
Which is sort of proven in O'neil
although in a pretty handwavy way
It basically says "Eeeeh look at the properties of the exponential map"
Also he shows that $I^+$ is open in Minkowski space
So I guess you need to show that $I^+(p) \approx \exp_p(I^+(0))$
Or something
Hope this is coherent - So $U_p$ is a convex neighbourhood, i.e. an open set of Minkowski space, and $I^-(p_1)$ is the set of all points in Minkowski space that live on timelike curves that end at $p_1$, so if $I^-(p_1)$ is an open set in Minkowski space then the intersection of open sets is an open set, so I guess the concern is why is $I^-(p_1)$ an open set?
Well, every point of it is an interior point, meaning given any point $s$ of $I^-(p_1)$ you can find a neighbourhood of $P$ that is a subset of $I^-(p_1)$, where your neighbourhood is a portion of a (collection of) timelike curve(s), this is basically your notation in words I think.
Any help with this?:
Using $\sum u \overline{u} - v \overline{v} = 1$ in the Dirac Hamiltonian, We Have

$\mathrm{H} = \int d^3x(\pi \partial_0 \psi - \mathcal{L}) = \int d^3x(i\psi^+ \partial_0 \psi) = \int d^3x(\overline{\psi} i \gamma^0 \partial_0 \psi) $

$ \ \ \ = \int \dfrac{d^3p}{(2\pi)^3}(\hat{\overline{\psi}} \varepsilon \hat{\psi}) = \int \dfrac{d^3p}{(2\pi)^3} \varepsilon (\hat{\overline{\psi}} \gamma^0 (\sum u\overline{u} - v \overline{v}) \gamma^0 \hat{\psi}) $

$ \ \ \ = \sum \int \dfrac{d^3p}{(2\pi)^3} \varepsilon [(\hat{\overline{\psi}} \gamma^0 u) ( \overline{u} \gamma^0 \hat{\psi} ) - ( \h
Can't get the same thing to work for

$Q = \int d^3 x \overline{\psi} \gamma^0 \psi = \int d^3 x \psi^+ \psi$

Trying

$Q = \sum \int \dfrac{d^3 p}{(2\pi)^3} ( b^+ b - d^+ d) + C = \sum \int \dfrac{d^3 p}{(2\pi)^3} (b^+ b + d d^+) $

$ \ \ \ = \sum \int \dfrac{d^3 p}{(2\pi)^3} [(\int d^3 x e^{ipx} \overline{\psi} \gamma^0 u)(\int d^3 x e^{-ipx} \overline{u} \gamma^0 \psi) + (\int d^3 x e^{-ipx} \overline{\psi} \gamma^0 v) (\int d^3 x e^{ipx} \overline{v} \gamma^0 \psi)] $

$ \ \ \ = \sum \int \dfrac{d^3 p}{(2\pi)^3} [ \hat{\overline{\psi}} \gamma^0 u \overline{u} \gamma^0 \hat{\psi} + \hat
12:31
@Slereah what proof do you need, my child
as long as it's not 4.5.10, I can probably answer
I want to tell my prof to bring in his own damn copy of HE, he keeps leaving it at home
then he grabs mine
@Slereah what is $U_p$
some convex normal neighbourhood
Around $p$
that's the intersection of two open sets, no?
a CNN is open because its existence is derived from the inverse function theorem.
Well $U_p$ is an open set
yes, and $I$ is also open
$I(p)$ that's a thing you have to prove
12:34
is the intersection of open sets not open?
@Slereah oh, that proof is in BEE
and Wald
Yeah and in O'neil, apparently
Wait
very likely, yes
Are you aware that this is part of a proof to prove that $I^+$ is open
but
globally
This section only requires to prove that $I$ is open on a normal neighbourhood
you can use a convex normal neighborhood to prove that $I$ is globally open though
Which I think O'neil does by saying that $I$ is open in Minkowski, so you can map $I(0)$ in $T_p$
12:36
You might need some smoothing argument now that I think about it...
Well the proof requires you to say that $a \ll b$ and $b \ll c$ implies $a \ll c$
which yadda yadda
@Slereah yes, that intersection should be open
So yeah I think I got a grasp on the proof
Tho I should try to show it in detail
according to BEE, it's because
>first line
>cf penrose
That's a spacetime topology proof alright
12:38
I don't think @ACuriousMind believes us
Every other proof is literally "cf. Penrose" or "cf. HE"
And Penrose and HE are not any more enlightening
what happened to intellectual integrity
Yeah, that seems nontrivial...
let's see what SW has to say
As said, O'neil does an okay proof of that
what page
Or was it Michel what's his name
Well you kinda need both I suppose
sanchez
12:41
I literally just fleshed out his proof
0
Q: Dirac Charge by Factoring?

bolbteppaUsing $\sum u \overline{u} - v \overline{v} = 1$ in the Dirac Hamiltonian, We Have $\mathrm{H} = \int d^3x(\pi \partial_0 \psi - \mathcal{L}) = \int d^3x(i\psi^+ \partial_0 \psi) = \int d^3x(\overline{\psi} i \gamma^0 \partial_0 \psi) $ $ \ \ \ = \int \dfrac{d^3p}{(2\pi)^3}(\hat{\overline{\p...

> The following result is standard, and relies on the possibility to deform any
causal curve which is not a lightlike geodesic without conjugate points in a timelike
one (see, for example, [2, Cor. 4.14], [27, Prop. 4.5.10] or [40, Prop. 2.20]). As
discussed below Theorem 2.27, all these elements are conformally invariant, and
the result is stated consequently.
> [27, Prop. 4.5.10]
I don't even need to look at the bibliography to tell you what [27] is!!
Do u mean [40]
no
[27] is HE
Because I've been trying for WEEKS to figure out Prop. 4.5.10
But there is no [20] in your quote.
But there's no [20] in what you posted
12:47
where have you been
[27] I guess
what's so funny
Basically we need to Frankenstein all the proofs of the 20 big GR books together into a single book
@Slereah wait until you get BEE
they reference JOURNAL ARTICLES
12:48
That's... okay?
Most books do it
It's pretty easy to get these days
Legally
wink
You should see the biblio of Stephani
Straumann has WRONG things in his biblio
Do u mean like Mein Kampf
what?
there's nothing wrong with that
I mean the references are incorrect
...you see nothing wrong with a GR book referencing Mein Kampf? oO
@ACuriousMind why would I, maybe there's a nice passage in there on the scientific method or something
12:54
The worst kind of references are "Private correspondance"
Fuck you Hawking, if you write that I'll have to go through your mail
"Jews really aren't that bad." Hitler, A. Private correspondence.
BREAKING NEWS : CRAZY MAN BROKE IN STEPHEN HAWKING'S HOUSE, RIFFLED THROUGH HIS PRIVATE CORRESPONDANCE
@0celo7 Yeah, that seems likely :P
I will also steal his "unfinished articles"
@ACuriousMind I haven't read it.
or maybe the author is a Nazi
Plenty of reasons to quote MK
12:58
You know I never read the whole "100 scientists against Einstein"
@Slereah We need to figure out Prop. 4.5.10
It's the key to all of GR.
Hundert Autoren gegen Einstein

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