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12:17 AM
"May there be light" Said the government contractor
 
@BernardMeurer LEGEND
 
@0celo7 See what I invested my ears in learning now? :p
 
@BernardMeurer can you do basic linear algebra?
 
@0celo7 Can you build phone chargers out of a lithium battery, a hand crank, some gears, a DC motor, using candles as light AND as soldering iron?
 
I don't believe that's possible
I'll need evidence
 
12:28 AM
You saw picture evidence
 
I saw some parts
 
Well it's stored away now, but I can make it work again tomorrow once I have a proper soldering iron
my candle solder didn't hold too long
 
I can solder.
It's not hard
 
With a candle?
 
12:53 AM
@BernardMeurer Never tried, I live in the first world.
 
1:35 AM
@ChrisWhite Hmm, I had an idea. So from the math treatment we know that we end up getting $i_X\omega$ in our integral (where $\omega$ is the volume form)
now we can show that this equals $\langle X,N\rangle i_N\omega$
now $i_X\omega$ is a positive form
so $\langle X,N\rangle i_N\omega$ has to be positive
so either $\langle X,N\rangle$ and $i_N\omega$ are both positive or negative
do you see where this is going :D
Nope, it's all wrong.
 
@0celo7 Shouldn't you be on a date?
 
@BernardMeurer no
crap, $i_X\omega$ need not be positive.
@ChrisWhite Is there anything special, in general, about the dot product of a timelike and a spacelike vector
@ChrisWhite Lol, Wald and Carroll claim opposite things regarding this.
@ChrisWhite I think I can get Wald's result, actually.
But not Carroll's
@ChrisWhite Ok, proof of what Wald says. Suppose the normal vector is timelike and we're looking at the divergence of the vector $X$.
Then either $X$ is timelike or it is normal to $N$. (not sure about this, working on a proof)
if it is normal, then we're done because the integral vanishes
Suppose it is timelike. Then if it is future directed, we have $\langle N,X\rangle<0$ by some theorem.
But then $i_N\omega$ is not a positive form.
Hmm
Continue to ignore me while I figure this out...
Ah! Split $X$ as $X^\top+X^\bot$, then $X^\bot=\alpha N$, $\alpha >0$.
Then $i_X\omega$ is positive!!
But since $i_N\omega$ is negative, we must really take $i_{-N}\omega$ as the positive thingie
but by a theorem in Lee this is the inward pointing vector
@ChrisWhite I'll write the proof shortly and answer the question.
 
2:57 AM
@ChrisWhite crap! Now I've just moved the sign to the orientation of $X$
@ChrisWhite How crazy it is it to just say "Wald is wrong"
o.o
Hawking-Ellis contradicts Wald
And THAT'S the result I can prove
 
Berkeley's funding me pretty well
I'm back to being confused now...
 
@FenderLesPaul I think Wald has a mistake
:/
I know Carroll does
There's the same theorem appearing in the three books and each says a different thing
I can prove the HE version.
but this is actually pretty strange.
the orientation of the volume form should not depend on this random other vector CRAP
also this approach will fail in the spacelike case
so maybe HE IS wrong
@FenderLesPaul Holy shit Wald AND HE are correct
@ACuriousMind I've proved it :D
100% sure this time
 
user54412
3:33 AM
@FenderLesPaul o.O
 
user54412
go to Berkeley for a couple years, then ragequit and switch to UCSB
 
user54412
we can move around cali together ;)
 
@ChrisWhite hahaha
yusss
that would be pretty dope
 
If I join will either of teach me how to cook?
 
I don't know how to cook
 
user54412
3:35 AM
@0celo7 Pretty sure there are spacelike vectors with nonzero time component in Minkowski...
 
Well but you hold the hand-writing selfie technique
 
user54412
I've been looking for an excuse to cook more.
 
I'm a human grinder
As in I eat a lot, not that I grind humans
 
user54412
One summer in college a group of us got together to cook every day (they didn't feed us during summer). We vowed to never eat the same thing twice. I miss those days.
 
user54412
Right now though I live alone, and too many ingredients are only sold in bulk.
 
3:38 AM
I liked the weather in Cali, you never sweat
 
0
A: Stokes theorem in Lorentzian manifolds

0celo7Not surprisingly, this has to do with the signature of the spacetime metric not being positive definite. Furthermore, this issue is very subtle. We will need a slew of theorems to understand it. We first state the preliminaries, proofs of which may be found in the excellent, J. Lee, Introduction ...

Comments appreciated.
 
I'd comment "first"
 
user54412
ur mathjax. it broke
 
@ChrisWhite where
 
but then I'd lose my precious little points
 
user54412
3:40 AM
ninja'd
 
I pulled a scumbag
"the other cases are left to the reader"
I'm sure there's some simple proof
I think mine is rather brute-force
Or deeply flawed...
someone gave me a +1
 
user54412
wonder who the OP is -- don't get many people asking advanced things but never giving answers
 
@ChrisWhite Did you read it? Are you convinced?
wait a moment, is this even right
where the heck does it actually depend on the metric not being positive definite o.o
No, this is the proof
I don't care any more.
 
user54412
"But since $\langle N, X \rangle$ is negative"?
 
@ChrisWhite so?
 
user54412
3:49 AM
I'm answering your question
 
the dot product can be negative on a Riem. manifold
SHIT
@ChrisWhite I think this is wrong
 
user54412
maybe that should be $X^\perp$?
 
@ChrisWhite doesn't matter because $\langle N,X^\top\rangle=0$
 
user54412
yeah, okay, so only in Lor. manifolds can the inner product between one vector and the part of another vector aligned with that one be negative
 
@ChrisWhite mb
ok, that's true.
well, no, it's not
AHHHHHH
I give up
@ChrisWhite Do you think the proof is correct?
 
user54412
3:55 AM
it's probably not flawed in any serious way :)
 
@ChrisWhite ok
now papa ACM needs to read it
 
4:09 AM
0
Q: Quantum Theory just lazy physics?

JG QuestionsIs it true that physicists decided that because they couldn't predict with certainty the location of an electron at any given time, that they just created equations using probability instead, still allowing them the ability to invent new technology and other things without actually stripping away...

~sigh~
@0celo7 Glad the daddy title stuck.
 
@DanielSank please read my proof
 
@0celo7 no way both Wald AND HE can be correct
those books are antagonistic as fuck
 
:P
 
@FenderLesPaul I'm super-dooper busy at the moment. Shouldn't even be typing this.
 
@DanielSank read my proof!!
 
4:22 AM
@DanielSank typing what?
haha
nvm I gotchu
 
@FenderLesPaul what?
I'm confused
 
@DanielSank did you read my proof
 
@0celo7 Of course not.
 
@DanielSank oh come on why not
 
5:19 AM
@DanielSank :(
 
6:03 AM
@0celo7 Because I'm making slides for a talk I have to give tomorrow that I had very, very short notice on.
I have this thing called "job" that prevents me from doing what you want at all hours.
4
Frowny faces have no bearing on that. Sorry.
 
 
1 hour later…
7:05 AM
@0celo7 proof for whay
 
 
1 hour later…
8:08 AM
-2
Q: Quantum Theory just lazy physics?

JG QuestionsIs it true that physicists decided that because they couldn't predict with certainty the location of an electron at any given time, that they just created equations using probability instead, still allowing them the ability to invent new technology and other things without actually stripping away...

@0celo7 is that you
So anyway
How many exact solutions of $\varphi^4$ theory are known
I can think of two classes of solutions
Three if we include the vacuum
 
8:28 AM
Hm a basic solution of $x'' - x^3 = 0$ is just $x^{-1}$
I wonder if it translates to PDEs
 
user116211
8:49 AM
@Slereah: o/
 
user116211
@Slereah hahaha
 
9:26 AM
Amazon wants to tempt me to buy "The global nonlinear stability of the Minkowski space"
They know what I like
 
I can understand that 1 kilo of fish is equivalent to 5 euro, which I denote 1 kg of fish = 5 eur. Normally, you say that price is 5 euros per 1 kg of product? What do you mean by dividing 5 euros with the weight? I see now that it is equal to 1. That is, if 1 kgf = 5 eur then, dividing both sides by 1 kgf I get 1 = 5 eur per 1 kgf. What does it mean?
 
10:21 AM
1
Q: It is on topic to ask about computer software useful to do some particular task?

A. A.I want to plot some phase diagrams that look professional (Example). I don't really know what tools are usually used to do this kind of diagrams, I've been looking around and found some alternative but I would like to know what is usually used by professional researchers to do this. I have seen ...

 
11:12 AM
http://physics.stackexchange.com/questions/1111/whats-the-difference-between-helicity-and-chirality

Chirality is determined by how the particle transform under the poncare group, on whether it is the right or left representation
-Paraphrased form wikipedia

This sentence sounds a lot less confusing ever since I learn some spectroscopy and symmetry groups
 
11:35 AM
89
Q: Can't find clit

j0hI have some lit files I want to convert from mircrosoft reader files to something my other devices can read. My friend says I should have clit, in $ which clit /usr/bin/clit but I cannot find it. I tried locate clit but the results are unrelated. So then I tried sudo apt-get install clit but ...

Puerile, I know :D
 
11:50 AM
By the way, I never understood that particular problem...honestly, it does not seem something so difficult to find
 
12:10 PM
@yuggib can confirm
@yuggib you should check out my proof
 
you are very anxious about your proof, but I have no idea which proof, and about what
 
@yuggib check my post history.
My latest one
I'm now going to shower, cleanliness is important.
 
12:31 PM
http://googology.wikia.com/wiki/Meameamealokkapoowa_oompa

For example, a large number
 
12:48 PM
@0celo7 seems ok, and quite boring as all geometric stuff
 
How is it boring
Coming from the person who does nitpicking math for a living...
 
I do fun math
geometry is boring
 
http://googology.wikia.com/wiki/Introduction_to_BEAF

*mind asplode*
 
Do we really need numbers this large?
for practical applications or proof related things?
 
12:57 PM
@Secret especially when I can give you very easily a number that is larger than all of those: $\omega$
 
ah yes, the first ordinal
 
and one that is $\omega \uparrow \omega$: $\varepsilon_0$
and those are still countable
 
@Secret No
Graham's number is the largest that had maybe some use and it has only been used once
 
I can also give you $\aleph_{\alpha}$, where $\alpha$ can be any ordinal (finite or infinite)
but in the end...who cares? It is important to know that numbers are well-ordered, the rest is just having fun
 
Is that all that numbers really mean?
 
1:07 PM
numbers are of course important
especially when they constitute a field, or a group, or whatever
but writing down with some bizarre notation a very large natural number is not so interesting in my opinion
far more important is that no matter how large a natural number could be, there is always another one that is finite and bigger, and an infinity of infinite ones (that are also obviously larger)
 
How far can "well-orderedness" be extended?
 
what do you mean?
every set can be well-ordered thanks to the axiom of choice (even if the well-ordering may be "impossible to write down")
the well-ordering of ordinals is pretty natural
 
http://googology.wikia.com/wiki/Inaccessible_cardinal

o and it seems they use that notation for these infinite things also

============
On a more related note, is it safe to say that we can define everything in maths with just relations?
 
the well-ordering of reals is a nightmare
 
That's what I mean: "impossible to write down."
 
1:14 PM
@Sᴋᴜʟʟᴘᴇᴛʀᴏʟ nevertheless, there is a well-ordering of the reals
 
https://en.wikipedia.org/wiki/Well-order

cannot wrote it down
 
@Secret relations are not enough to define "everything" in math
 
@yuggib have you watched any of professor Norman wildberger's vids?
 
relations are just something that is defined in mathematics (more precisely, in logic)
@Sᴋᴜʟʟᴘᴇᴛʀᴏʟ no, who is he?
 
He's done a lot on YouTube about the real numbers being a myth.
 
1:18 PM
why should they be a myth?
 
The reals are not proven to exist
 
?
why would that be?
 
You should check it out on YouTube :)
 
nah...I'm not interested in b******t
 
I stopped watching too.
They call him a hyper finitist
Infinity does not exist either.
 
1:24 PM
that is just a matter of axioms
 
He refuses the axiomatic approach
 
ok, so how could he get a position? (assuming he has one in mathematics, and not in philosophy)
 
Dunno, he works in an Australian university and has a PhD from Yale.
 
To be precise, my university
Though for me, I found his idea interesting
as I am that kind of guy who likes to collect ideas everywhere to analyse
 
1:31 PM
what is his approach then? what is a mathematical theory? something pre-existing in the platonic world of universals?
 
The biggest cardinality is the cardinality of the universal class, of course
 
If I recall, he is mostly interested in using surds to derive everything in trigonometry
 
$\text{Card}(V) = \text{Card}(P(V))$
 
I once, out of curiosity , entered his office to check out his rational trigonometry idea

Having said that, I am not a finitist because I like the weirdness of infinities
 
Rational trigonometry is a proposed reformulation of metrical planar and solid geometries (which includes trigonometry) by Canadian mathematician Norman J. Wildberger, currently an associate professor of mathematics at the University of New South Wales. His ideas are set out in his 2005 book Divine Proportions: Rational Trigonometry to Universal Geometry. According to New Scientist, part of his motivation for an alternative to traditional trigonometry was to avoid some problems that occur when infinite series are used in mathematics. Rational trigonometry avoids direct use of transcendental functions...
 
1:33 PM
@Secret that sounds absurds
 
The idea seemed useful enough in case you want to compute unit cell angles, at the cost of squaring all your length measurements
 
constructivism in mathematics is something that is not new
as well as intuitionism and finitism
however people in those worlds usually aim to try and reproduce everything (or most of the times just something) that mathematics has already proved by their different means
a work that is very well credited on this is the following by Bishop:
it is of the late sixties, so nothing extremely "new"
 
I have a book by a dude who built Newtonian mechanics without numbers or functions
 
indeed
 
Only Euclidian geometry
 
1:39 PM
@slereah O_O
 
(Well technically Hilbert's axioms)
It's not terribly useful
 
Someone can argue I sometimes think like an Intuitionism
Recall those crazy diagrams that I drew last year, one of these is a (foolish) attempt to draw one squary looking thing so that everything we know about linear algebra can be derived by geometric consideration on that diagram
 
intuitionists are not people that use intuition ;-P
 
and then some time later, when reading new scientist, I learnt the necessarity of need to go beyond our intuition that is hard wired into our brain in ordee to have chance to discovery even more weird mathematical objects
 
essentially, they reject everything that is not constructive and also the law of excluded middle
 
1:43 PM
@GPhys are you done with everything?
 
@yuggib so multivalued logic?
 
@yuggib upvote scrooge
 
Begging for up votes?
 
@yuggib what is the cardinality of the plane
@Sᴋᴜʟʟᴘᴇᴛʀᴏʟ yes
@Slereah why do you have this book
 
Put a link here and maybe you'll one from me pal.
 
1:47 PM
I'm not that desperate
I answered a question that had 10 upvotes, I expected more than two :V
 
For any questions, I only worry about downvotes
Because for each downvote I received, the more likely I will be question banned
otherwise I don't realy care if someone downvotes me
it's just a number
 
People shamelessly advertise their questions and answers all over the network.
 
Hi all
 
Has anyone here had magic mushrooms before?
 
How was it?
 
I did it twice last week and it's awesome. I had a different trip to weed. Really something everyone should do.
Awesome stuff.
 
Have you tried hash oil?
 
Would like to try acid, have never had that. But I here that the trip is much longer than shrooms, I prefer the duration of shrooms. 6-7 hours is enough.
No I haven't tried that.
 
1:59 PM
Work your way up slowly pal.
 
Yeah for sure. Hash oil not really something I have connections for.
 
A big part of addiction are those so called "connections."
 
@Sᴋᴜʟʟᴘᴇᴛʀᴏʟ yeah damn those horizontal distributions
 
What are those?
 
2:21 PM
@Sᴋᴜʟʟᴘᴇᴛʀᴏʟ I edited the answer, it's on the front page if you wanna take a look
@Sᴋᴜʟʟᴘᴇᴛʀᴏʟ I think this answer suffers from "very technical syndrome"
 
2:36 PM
0
A: Do any quantum gravity theories deal with closed timelike curves?

John Duffield Do any quantum gravity theories deal with closed timelike curves? No. As far as I'm aware, there are no quantum gravity theories that deal directly with closed timelike curves. As far as I know that's correct. Some of them (like canonical QG, CDT and LQG) forbid them outright, ...

@Slereah :DDDDDD
You got an answer
 
@Secret no, not essentially
they just refused the implication of excluded middle
@0celo7 the plane $\mathbb{R}^2$ has the same cardinality as $\mathbb{R}$, i.e.: ......?
 
@0celo7 Hm
He doesn't get awarded the bounty if he has 0 votes, right?
Not sure I'll get any real answers really :p
Igael's answer is probably the best I can hope for I think
 
2:53 PM
http://philosophy.stackexchange.com/questions/32409/why-did-only-science-and-religion-became-widespread-instead-of-magic

they should really terminate downvoting if the question is closed
now I am in danger of gettign quesiton banned on philosophy stack exchange
 
I only have one fear: Not being able to ask questions
 

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