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01:37
Are the vectors in SR a distinct mathematical object from the vectors in GR since SR vectors need to transform under Lorentz transformations and GR vectors have more general transformations?
Actually I guess they're all the same, just dependent on the metric being used
02:25
I would describe them as a special case. Special relativity is general relativity in the limit of weak gravitational effects (i.e. flat space-time), so the four-vectors of special relativity are a sub-set of those in general relativity.
On the other hand it is a subset characterized by enough additional guarantees that it might be seen to warrant separate study.
vzn
vzn
02:56
@danielunderwood for an answer try looking at the vectors in here :) arxiv.org/abs/1603.07655
03:07
Thanks I'll check out that paper. I've actually been wondering if there's anything like a modern view on ether theory and that looks like it may be in that direction

I think they may be the same as far as the question that was in my head. I struggled for a while to figure out what vectors and tensors are, only to realize that the mathematical notion is a bit different than the physical notion and was confused by jumping between the two without knowing. What I was wondering here is if a similar thing may be happening where physical vectors were different based on context. I think they may b
vzn
vzn
03:46
@danielunderwood think your questions cut to the heart of the problem. there are ways of thinking of the GR vectors that are considered nonphysical under conventional wisdom but candidly, suspect conventional wisdom may be wrong. we've had several debates in the room on this subj, search transcript if you have some spare time. heres a recent related question to ponder, maybe somewhat inspired by similar considerations...
18
Q: Does light really travel more slowly near a massive body?

John RennieIt is a routine problem for beginners in general relativity to calculate the coordinate velocity of light for the Schwarzschild metric. Starting from the metric: $$ ds^2 = -\left(1-\frac{r_s}{r}\right)c^2dt^2 + \frac{dr^2}{1-\frac{r_s}{r}} + d\Omega^2 $$ We use the fact that light travels on a ...

...
just had to share this with room, another tragic-yet-riveting story about unrestrained young testosterone? o_O Thailand cave search: Divers close in on missing soccer team / cnn
04:46
downvote for lack of detail — Secret 14 secs ago
Probably one of the most honest driven downvotes I have ever casted
05:44
Someone upvoted this? Really?
1
Q: What is a good vacuum that can go from carper to floor and can pick up pet hair w/o a problem?

Edward MorrisonRight now I have a Eureka light weight and it doesnt do me a bit of good. The fliter becomes clogged with pet hair before the canister is even 1/16 full.

 
2 hours later…
07:31
Been coding all day yesterday . . on and off. Thinking about attempting some very very very very trivial baby in diapers math proof that I can't seem to do. Will spend some time thinking about it in the morning. For now, I will retire for the day . .
Anonymous
@ACuriousMind Thanks. josh's answer was helpful!
Anonymous
@JohnRennie Morning. I'm confused about a very basic QM thing. Is it possible to experimentally distinguish between two states $\Psi$ and $e^{i\theta}\Psi$?
Anonymous
Is it possible to detect the global phase?
You're asking two different questions.
The global phase is just a gauge because you can choose any origin for $\theta$ that you want.
But if you're asking whether you can detect a phase difference then of course you can.
Anonymous
@JohnRennie Yes, that's what I meant
Anonymous
07:45
What would be the experimental method for that?
Anonymous
Actually take something simple like $|0\rangle$ and $e^{i\theta}|0\rangle$
@Blue Young's slits?
Anonymous
Umm, how exactly? Say I have a qubit (using electron spin) in state $|0\rangle$ and another electron spin in state $e^{i\theta}|0\rangle$
Anonymous
Or you could use the differently polarized lights
Anonymous
Actually, I should explain the context of the question first maybe:
Anonymous
07:51
1
A: Why should state of the "control register" change in the Phase estimation algorithm?

DaftWullieImagine you have an eigenvector $|u\rangle$ of $U$. If you have a state such as $|1\rangle|u\rangle$ and you apply controlled-$U$ to it, you get out $e^{i\phi}|1\rangle|u\rangle$. The phase isn't attached to a specific register, it's just an overall multiplicative factor. Now let's use a superpo...

Anonymous
DaftWullie says in the comment that there is no way to distinguish between a composite state $(|0\rangle)_A \otimes (e^{i\theta}|0\rangle)_B$ and $(e^{i\theta}|0\rangle)_A \otimes (|0\rangle)_B$
Anonymous
There is no physical difference. Think about it this way: what experiment would you do to distinguish the two? If there's a physical difference, there must be a way to distinguish them. — DaftWullie 58 mins ago
Anonymous
in The Classical Channel, 48 mins ago, by Blue
@DaftWullie Interesting. So, I can't think of any experiment to distinguish the "phase". But one thing which is still a bit of unsatisfactory to me: Why is it just that our failure to create an experiment which can distinguish the phase, dictate on which qubit that phase actually should be in? Why should physics depend on our restrictions at all?
Anonymous
in The Classical Channel, 47 mins ago, by DaftWullie
physics doesn't. quantum theory is our description of physics (as best we know it), and it doesn't contain the possibility to distinguish it. Perhaps there's a different theory that does permit it.
Anonymous
"Think about it this way: what experiment would you do to distinguish the two?" i.e. $(|0\rangle)_A \otimes (e^{i\theta}|0\rangle)_B$ & $(e^{i\theta}|0\rangle)_A \otimes (|0\rangle)_B$ ----- is that true, in the first place? That's why I asked the question about whether we can distinguish the presence of a phase difference
Anonymous
07:59
@JohnRennie I mean what we need to detect is not just the presence of the phase difference, but in fact the relative phase difference. That is, does qubit A have a phase of $e^{i\theta}$ w.r.t qubit B or does qubit B have a phase of $e^{i\theta}$ w.r.t qubit A
Anonymous
Such an experiment would help to distinguish between $(|0\rangle)_A \otimes (e^{i\theta}|0\rangle)_B$ and $(e^{i\theta}|0\rangle)_A \otimes (|0\rangle)_B$
08:11
Guys, I was thinking about a voltage divider with a load (= resistor) and what we can do is sum the second resistor with the load resistor (which are in parallel) and we get an equivalent one, after that we can view the system as if there was no load and no current going out of the output?
Anonymous
@NovaliumCompany Why would there be no current and no load?
Anonymous
Can you draw the situation?
Ok, let me simplify my question. If I wanted to build a voltage divider, where I have initial 9V and I want my load to receive 0.1A and 5V how can I do that? How can I calculate what resistors I would need?
(I made the numbers up (0.1A, 5V...), I don't know if they'll work)
Anonymous
$9 V = (1.5 A)R$
Anonymous
$R=?$
Anonymous
08:15
Trying to see if they can be put in series
So first I find the resistance of the load?
ups
nvm.
Wait, my book explains that, let me read again and I'll come back after 5 mins.
Anonymous
If net resistance of load is less than 6 ohms it can be put in series with another resistance such that the net is 6
Anonymous
If it is more than 6, we'll have to device some other branching
My book gives an example where load is taken into consideration but it talks about some 10 percent rule, $Vout = Vin\frac{R2}{R1 + R2}$ won't work anymore.. and it just gets complicated. The exercise is: You have a 10V supply, create a voltage divider to supply a load that is rated at 3V and draws 9.1mA.
Anonymous
It's rated 3V and draws 9.1 mA. Find its resistance first
Anonymous
08:25
Simple V=IR
R = 27.3mOhms.
Anonymous
Fair, now solve for $r$ from $10 V=(27.3 m\Omega + r)(9.1 mA)$ I guess?
What is that, why?
I now know the resistance of the load and the desired voltage.
And I need to find resistor values?
Anonymous
Sid
Sid
@NovaliumCompany are you sure about that calculation?
08:32
No, my book says different...
My book says 330ohms.
for the load resistance.
Anonymous
If your load is $R_2$, then you need to find $R_1$
Sid
Sid
I ask because if the current is in mA, the Resistance is usually in kilo-ohms..
Anonymous
In the above diagram
Anonymous
@Sid Yeah, that calculation @NovaliumCompany did looks wrong
@Blue we don't have R2 yet.
Anonymous
08:35
R2 is your load resistance
Anonymous
Which you calculated wrongly
Anonymous
8 mins ago, by Novalium Company
R = 27.3mOhms.
no, I need to find R1 and R2. We know Rl.
Anonymous
@NovaliumCompany Can you show your circuit diagram? I don't know what $R_1$ and $R_2$ is supposed to mean in your context.
Anonymous
Anonymous
Here there is no $R_L$ separately
That's a wrong diagram then xD
The book is using some sort of 10 percent rule...
which is confusing even more.
Anonymous
Anonymous
So, basically their constraint is $I_2=0.1 I_L$
Anonymous
Now it's just solving a couple of simultaneous linear equations
Anonymous
08:42
Write down the KVL equations
$I_2=0.1 I_L$ confuses me.
Why would you want your I2 to be 10% of IL?
Anonymous
Apparently it minimizes some power loss
Can we first do an example without that complication?
(on the same diagram)
Anonymous
We'll have to do the math, to check if their claim is actually true
So lets first calculated the resistance of the load?
Anonymous
08:46
@NovaliumCompany You could try, Unfortunately, I need to leave now. Anyhow, as far as minimizing power loss is concerned that rule doesn't seem accurate to me (you could ask on the main site though)
Oh, ok. See you then :)
I'll have to leave as well.
 
3 hours later…
11:41
youtube.com/watch?v=JGXdi7XcQi8 At 17:36. What I don't understand is why if we want to keep the voltage at 3V across R2 (and Rload), why the resistance of R2 has to be 100 times less than the resistance of the load?
12:58
If reality is a pond, and particle are the ripples from the splashes, what exactly is water?
and moreover, how meaningful we can go down this rabbit hole before it ceased to be relevant
13:44
hmm, test
$\mathbf{\sigma}$
dang, no boldface
$\sigma$
$\boldsymbol{\sigma}$---okay, that one works
I have stupidly written \mathbf{\sigma}'s in my notes so much there's no way I would even try to fix them all to make them look better with the better \boldsymbol{\sigma}'s :(
What else am I doing wrong :p
14:01
lol
i noticed it while typing up lots of $\boldsymbol{\sigma}\cdot\mathbf{a}$
I was originally doing $\vec{\sigma}\cdot\hat{a}$ (b/c a is actually a unit vector) but wanted to be able to write $\hat{A}=\boldsymbol{\sigma}\cdot\mathbf{a}$
though in retrospect I could've just done $\hat{A}=\vec{\sigma}\cdot\vec{a}$, since I'm already saying in the text that $\mathbf{a}$ is a unit vector
Here's a question, I guess. A simple but handy formula for a singlet state $|\psi\rangle$ is that $$\langle \psi | (\boldsymbol{\sigma}\cdot \mathbf{a})\otimes (\boldsymbol{\sigma}\cdot \mathbf{b})|\psi\rangle = -\mathbf{a}\cdot\mathbf{b}$$
What's the simplest way to prove that?
The proof I know uses the fact that the singlet state is rotationally symmetric to choose $\mathbf{a}=\hat{z}$, $\mathbf{b}=\hat{z}\cos\theta+\hat{x}\sin\theta$ without loss of generality
Think I need to just replace \mathbf{•} with \boldsymbol{•} from now on for everything
One then only has to show that $\langle \psi | \sigma_z\otimes \sigma_z|\psi\rangle = -1$ and $\langle \psi|\sigma_x\otimes \sigma_z|\psi\rangle=0$
@bolbteppa apparently \boldsymbol is a bit outmoded for Latex, actually:
331
Q: How can I get bold math symbols?

Michael UnderwoodTo make Latin-letter variables bold I can use e.g. \mathbf{a}, but while putting Greek letters or symbols such as \nabla inside \mathbf doesn't cause any errors or warnings, it also doesn't do anything else. What is the best way to make bold math symbols, in particular Greek letters and \nabla?

that said, only \boldsymbol works in Mathjax
so that's what I"m using so that I cut-paste to/from here as necessary
hmm. if I write the above as $F(\mathbf{a},\mathbf{b})$, I can use antisymmetry of the singlet wavefunction to claim that $F$ itself is symmetric
not convinced that really helps tho
(I mean, there's an argument to be made that one must have $F(\mathbf{a},\mathbf{b})=f(\cos\theta)$. The fact that $F(\mathbf{a},\pm \mathbf{a})=\mp 1$ when $\mathbf{a}$ is a unit vector is then enough for a linear ansatz)
Anonymous
14:53
@Semiclassical An alternative to \boldsymbol is \pmb I think
Anonymous
Works in LaTeX
Anonymous
$\pmb{X}$
Anonymous
$\boldsymbol{X}$
Anonymous
Slightly different
Anonymous
287
A: How can I get bold math symbols?

Mark MeckesThe AMS Short Math Guide recommends the \boldsymbol and \pmb commands (and suggests that you use the bm package for the former to get a more powerful version than provided by amsmath).

Anonymous
14:57
Oh, it's given in this answer, lol
$\pmb{\sigma}$
works here too
$\pmb{\sigma}$ vs. $\boldsymbol{\sigma}$
They're obviously not quite the same, but not in any crucial way
15:45
Aw mexico played too horrendously
hmmm...left my NLP thing running over the weekend...somehow it paused midway through...odd
vzn
vzn
@Secret argh looks interesting thx for sharing, maybe aligned with fluid paradigm? alas, paywalled, can only read intro, otherwise have to subscribe yearly, looking to buy 1 issue online, seems their apple app wont currently download in US? & couldnt find it in barnes+noble nook. @#%& :( newscientist.com/app-download
For that particular link, the part that is cut off by the paywall is really just "reality as a pond and particles as ripples on it
so nothign in depth
vzn
vzn
@Secret did you read the whole article? lol got a link to work finally. this link "Download the app here: New Scientist Apple" fails for me because it says app is not available in US, but other link at bottom of page "get the app, download on the app store" downloaded their app. $5 per single issue. am thinking just gotta try this out because if JR says anything )( positive whatsoever about popsci content then thats a rare moment :P
I am subscribed to newscientist and hard copies are delivered to me
vzn
vzn
15:59
Dec 10 '17 at 17:40, by John Rennie
Anyhow, awaiting my attention I have:
1) an armchair
2) a glass of beer
3) this week's New Scientist
@Secret re "reality as pond, particles as ripples from splashes" did you ever look at this? vzn1.wordpress.com/2018/05/25/fluid-paradigm-shift-2018 am now gonna buy the issue just to read the article because of your tantalizing/ evocative paraphrase/ sound bite... o_O
but are we dealing with one kind of fluid, or every particle arises from the same fluid?
your blog had not say much on the nature of that fluid itself
I'd appreciate the 'fluid paradigm' suggestion more if those suggesting it actually provided quantitative statements
vzn
vzn
@Secret its one fluid and all the "particles" are emergent. this is not entirely outlandish if diverse knowledge is stitched together/ dots connected.
@Secret the blog post and earlier ones are full of bazillions of refs.
e.g. "the theory has this parameter in addition to the usual ones, and based on prior experiments we know that said parameter can't be bigger than X"
vzn
vzn
@Semiclassical they are given. see refs.
16:04
but why will we expect all quantum fields are emergent from the same source, is it because of unification?
vzn
vzn
@Secret unification is not yet understood. unification is not what physicists (currently) think it is. they are both wrong/ right, right now...
unification
it's so hot right now
vzn
vzn
@Semiclassical that is somewhat LHC centric (and therefore, to a degree anthropomorphic) thinking. aka "looking for keys under the lamppost". am not entirely ruling it out. it has worked for very well decades, nearly a century even (looking at earliest particle colliders) but think its nearing end of shelf life.
the hell it is.
@vzn the "how to think about particles" article is just a slightly garbled explanation of quantum field theory. There is nothing hydraulic about it.
16:08
being able to say what the parameters of your theory are and how those parameters affect the predictions of your theory is not "LHC-centric"
QFT
it's so hot right now
it is the basic difference between a theory and an interpretation
vzn
vzn
@JohnRennie secrets summary ("triggering my spider sense") was entirely/ utterly "fluid paradigmatical".
@vzn your monomania is getting the better of you again
the latter can be interesting to study (hence why I find Bohmian mechanics interesting) but one should not expect to 'test' an interpretation
one can use said interpretations as motivations to modify a theory (e.g. by introducing more physical quantities) and then test those
vzn
vzn
16:10
@JohnRennie lol, buy a ref you recommend and then you ding/ dis me in front of everyone. yeah, typical :( :P
but if you can't test it, it's not a question of physics
@vzn I don't recall recommending any references. If you're referring to New Scientist it is effectively a comic. Fun, but not to be taken seriously.
vzn
vzn
@Semiclassical we have been thru this a lot. think there is "moth + flame" dynamic going on here. now conclude you dont really seem to delve deeply into the exact theory youre interested in. (am not predicting future here + saying it will never happen.)
and, as usual, you assume that my unwillingness to agree with you signals my lack of knowledge
vzn
vzn
@JohnRennie lol just quoted you. guess you missed the big onebox there of your own words. opposite of egotism there? you had some other popsci refs lately.
16:12
"awaiting my attention" = "authoritative reference" now?
@vzn I saw the quote, but that was just a statement of fact not a recommendation.
That one likes watching Star Trek is not an endorsement of it as futurism
Though I suppose I would recommend New Scientist as a source of entertainment, though not as a way to learn about physics. It is irredeemably superficial.
vzn
vzn
@JohnRennie lol then for misinterpreting you there & getting ahead of your own words. guess noticed your other popsci n00b recommendations lately & got distracted.
vzn's reading of everything is so cursory and superficial that it's scary
5
a ten thousand vzns in the world could take over the scientific community with pseudoscience wikipedia fans
vzn
vzn
16:15
@BalarkaSen wow, its a complete tag team pile on now. lol at BS and his frequently expressed disinterest of Physics that rivals the legendary banished black sheep 0celo7
@vzn how about you give me one, then. not a list. one that you can consider as credible
getting a bit tense up in here
my attempts at humor have not paid off
vzn
vzn
@Semiclassical this is a game & dont feel like playing it right now. the refs are all laid out, dont think you are an ideal candidate to push the theory fwd right now. nothing personal, few such candidates exist anywhere right now.
I was not asking for your endorsement as a candidate to push the theory forward
I was explaining why I find presentations on it frustrating
vzn
vzn
@Semiclassical you disendorse me repeatedly in the room.
16:18
Is paradigm shift just pie in the sky???
:thonk:
wonder what I should do today...hmmm
2
vzn
vzn
@Semiclassical plz try to separate the frustration over the theory being incomplete (fyi shared by me too) with personal feelings wrt my own admittedly feeble attempts to complete it.
and instead of pointing to a specific paper which would rebut my complaint, you just say "see refs"
$\exists$ references
@enumaris I would start by drinking coffee. That always works for me :-)
vzn
vzn
16:20
@Semiclassical there are so many refs in my blogs. you guys dont click on any of em and then tell me its all bogus. think your guys facile rejections are what is really bogus.
mmm coffee
I'm not a big coffee guy
WHAT!
IMPOSTER!! GET OUT!!
3
I am not a machine to turn coffee into theorems.
16:21
my body is a temple bro, I don't put mind-altering substances in my body
(not really...but I just don't drink that much coffee lol)
On one of the SEs someone asked why academics drink so much coffee. But I've lost the link.
my adviser drank plenty
11
Q: Why do academics drink so much coffee?

Allure A mathematician is a device for turning coffee into theorems -- Alfréd Rényi All the universities whose staff lounges I've been to have had coffee machines with free coffee. I've seen academics refer to "coffee breaks" instead of tea / juice / cookie breaks etc. I've also witnessed one acade...

Aha! :-)
The spoilsports have put it on hold :-)
the signal-to-noise ratio of the world is exhausting at times
16:23
I recommend a cup of ambition over a cup of coffee
Or a cup of motivation
Whichever flavor you prefer
and that chaos will only become bigger as The Iluminati works behind the scenes
I just drink water...
and some lemonade and water
vzn
vzn
finds trying to overcome experts cognitive biases/ groupthink exhausting
@enumaris I wouldn't do that, fish wee in it
sometimes some root beer or ginger ale
or tea
16:24
Eventually, The Iluminati will liberate all humanity from a world ruled by the iron fist of classical determinism
@JohnRennie no drinking water? :P
I drank apple juice
@enumaris either put alcohol in it to sterilise it, or boil it - in which case you might as well add some coffee :-)
@vzn maybe it's not congnitive bias if it's backed with evidence
vzn
vzn
now musing with idea of taking up tequila early in morning
@vzn with some lime and salt, it's quite good
now, sprinkle that with some marijuna and you have a recipe for a wild trip
I lick salt, drink tequila, then suck on a lime
@BalarkaSen I knew I'd heard that somewhere before. It's from "9 to 5" by Dolly Parton.
vzn
vzn
16:28
@enumaris lol, all dogma is utterly backed by "evidence"
@BalarkaSen ooh, you country and western fan, you :-)
@JohnRennie Correct, in turn parodied by my boy Aesop here.
my philosophy is only, if two theories make the same predictions, use Occam's razor. If they don't make the same predictions, test it out, if it can't be tested...drink tequila
Nah I knew it was from that song by digging through the lyrics of that song I linked
Well, the tricky thing is what it means to "test" the predictions when the theory has adjustable parameters
16:31
@BalarkaSen those lyrics ... what was in that coffee?
Aesop Rock is a true poet
vzn
vzn
> Feynman tried marijuana and ketamine at John Lilly's famed sensory deprivation tanks, as a way of studying consciousness.[123][124] He gave up alcohol when he began to show vague, early signs of alcoholism, as he did not want to do anything that could damage his brain.[125] en.wikipedia.org/wiki/Richard_Feynman
@Semiclassical sounds like a good excuse to drink more tequila
In that case what you test is not so much "is the theory true or false" but "is the theory true with parameter X in a given testable range"
Hard to find rappers like him out there
16:32
@BalarkaSen one dark coffee f*** you PEACE
"large" not "dark" but yeah
gr8
Sid
Sid
@BalarkaSen Brazil won. duh.
damn, you're right
@Sid Yeah Mexico played terribly
Sid
Sid
Now. Let's go Inazuma Japan!
vzn
vzn
16:33
@enumaris lets start a new drinking game where everyone takes a shot whenever someone says fluid or paradigm (ps this line counts as 2) :P
Their ball slipped from the toes near the penalty region
Ochoa was still great as usual
@vzn stop trying to get us drunk. /s
@Sid England will play Japan in the final. You heard it here first.
sounds legit
LOL
@Semiclassical I have listened to his stuff so much over and over again for the past few months that I remember most by heart.
16:34
lol
France seems to be doing quite well, they knocked out Argentina with some sick goals
Uruguay also
tbh I could remember that line in my head and thought I had it right
though I remember the JD part of that song more clearly, for obvious reasons
Yup, Darnielle is amazing at the end
Great, great song
@Semiclassical John Duffield wrote a song??
16:35
haaaah
yes, of course, that's exactly what I meant :P
vzn
vzn
@Semiclassical lol sounds more like JR to me chat.stackexchange.com/search?user=37155&q=beer
I think the greatest song by Aesop, if I am to judge by lyricism, is
Stop that cheerin' and get another beer in
This is literally unreal.
I thought Captain Beefheart was the main man for random lyrics, but I can see I was wrong.
16:38
@JohnRennie what do you make of this? physics.stackexchange.com/questions/414758/…
also any other 10k'ers around
@EmilioPisanty 404
@Semiclassical hence the ping to the JR and 10k'ers ;-)
deleted by OP
yeah, makes sense now
16:40
@Semiclassical it's a question about this paper
> para todo mal, mezcal; para todo bien, también
mmm, berry curvature
It asks how angular momentum can be quantised for a free particle.
@Semiclassical now undeleted
thx
really? that gets starred?
16:44
is tempted to star
@BalarkaSen indeed
rip semiclassical
the stars that shine over the sky are too chaotic for you
When vitamin D taste like alcohol, you knew something is going wrong
Looks like it's time for star cleanup in aisle 71
oh thank goodness
Huh. I didn't even do anything :P
Something trolly this way comes
vzn
vzn
lol belated delight in sheer irony/ double meanings of phrase, has nice ring to it, maybe should throw it around more myself... irredeemably superficial
16:52
Hi to all. Could I ask for opinions, if anyone cares to give, about a possible transition from a physics bachelor to a theoretical mathematics(algebra, diff. geo.) master? Any thoughts are welcomed.
@ConstantineBlack If you want to do it, do it, but be sure that you know what you're getting into by taking some pure math classes ahead of time
@ConstantineBlack I think Danu did that. You might want to ask him about his experience.
alright, I better do some coding
drinks tequila
Better have some beer with that tequila
I see a fight with IT looming in the future
I need to get local admin rights for my PC and dual boot to linux...they aren't gonna be happy about it
FIGHT
16:56
@enumaris Is it Windows 10?
yeah it's currently windows 10
@ConstantineBlack ... and give a thought to what you will want to do with that degree once you have it.
I kinda doubt they will let me dual boot
@enumaris you can run Ubuntu in Windows using the Linux subsystem. It works really well.
what's that mean?
is that like dual booting?
I need CUDA support
16:58
@ACuriousMind Well, I' m currently reading geometry of surfaces and I have read algebraic structures(groups and some representations, rings, homomorphism theorems). I still need more analysis though to get to the exams.
@JohnRennie Well, where could I find him?
@EmilioPisanty Currently I'm thinking of it as a step to mathematical physics.
Ah, I'm not sure if the Windows unix subsystem supports CUDA ...
@enumaris That's the thing I linked to a while back
is it like a virtual machine?
I can't recall the link..
Similar, but more integrated with windows
I see... hmm

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